# is x=15 degrees a solution of radical 3/3 cos2x+sin2x=0

39,728 results
1. ## Trigonometry

find sin2x, cos2x, and tan2x if sinx= -2/sqrt 5 and x terminates in quadrant III

2. ## Math

Solve the equation sin2x=2cos2x, for 0 degrees

Express sec2x in terms of tanx and secx I know you have to sec(2x) = 1/cos(2x) = 1/(cos²x - sin²x) But how do you split that. Like how to simplify that?

4. ## Trigonometry

Prove: 1-tanx/1+tanx=1-sin2x/cos2x

5. ## Trigonometry

Simplify the expression using trig identities: 1. (sin4x - cos4x)/(sin2x -cos2x) 2. (sinx(cotx)+cosx)/(2cotx)

6. ## trigonometry

if sin2x=3sin2y, prove that: 2tan(x-y)=tan(x+y) ( here, in sin2x, 2x is an angle., like there's a formula:sin2x=2sinxcosx and sin2y=2sinycosy; ....)

7. ## dai so

chung minh dang thuc (1+Sin2x)/Cos2x=Tan(pi/4+x)

8. ## trig

sinx = 4/5 and x terminates in Quadrant II Find sin2x and cos2x How to get the answers, which are sin2x = -24/25, cos2x = -7/25?

9. ## PreCalculus

Sin5x cos2x + cos5x sin2x=

10. ## Math

Solve the equation 2cos2x = √3 for 0°≤x≤360° I did this: cos2x = √3 /2 2x=30 x=15 x=15, 165, 195, 345 Is this correct? Solve the equation √3 sin2x + cos2x = 0 for -π≤x≤π No idea how to approach this one Thanks a bunch for the help!

11. ## math

angle x lies in the third quadrant and tanx=7/24 determiner an exact value for cos2x determiner an exact value for sin2x

12. ## math

Solve sin2x + sin4x = cos2x + cos 4x for x in the interval[0,2pi) Hint: the following substitution should come in handy: sin3x= cos3x . tan3x

13. ## Trig

Simplify: (cosx + cos2x + cos3x + cos4x + cos5x + cos6x) / (sinx + sin2x + sin3x + sin4x + sin5x + sin6x) into a single Cotangent function. Using the sum-to-products, I was able to get remove some of the addition in attempts to get full multiplication, but

14. ## algebra

solve the equation or formula for the indicated variable R=ts^2+3 a)s=under radical R-3/t (not under radical b)s=everything under radical R-3/t c)s=R (under radical)-3/t d)s=everything under radical R/t-3 Thanks again I feel really stupid not being able to

Which of the following are identities? Check all that apply. (Points : 2) sin2x = 1 - cos2x sin2x - cos2x = 1 tan2x = 1 + sec2x cot2x = csc2x - 1 Question 4. 4. Which of the following equations are identities? Check all that apply. (Points : 2) Question 5.

16. ## trig

tanx = 5/12 and sinx

17. ## MATH

Simplify: Sin2x/1-Cos2x

18. ## pre calculus

were doing sum and difference identities tan (225 degrees+60 degrees) i got to the part where its 1+radical 3/1-radical 3 ..now what?

19. ## trigonometry

1-tanx/1+tanx=1-sin2x/cos2x

20. ## trigonometry

Been trying this forever so it says: Simplify 1+sin2x+cos2x/1+sin2x-cos2x ive tried this problem so many times I need help with it...

21. ## maths

prove that 1+sin2x-cos2x / sin2x+cos2x = tanx

22. ## math

sin2x-cotx = -cotxcos2x Using the various trigonometric identities(i.e. double angle formulas, power reducing formulas, half angle formulas, quotient identities, etc.) verify the identity. I first added cotx to both sides to get sin2x = -cotxcos2x+cotx

23. ## Pre Calculus

Establish the following identity Sin2x/1+cos2x=tanx

24. ## Maths

Prove that sin2x+cos2x-1/sin2x+cos2x+1=tanx

25. ## trig

write sin4xcos2 as the sum or difference of two functions. answers: 1/2(cos6x+cos2x), 1/2(cos2x-cos6x), 1/2(sin6x+sin2x), sin6x-sin2x

26. ## Pre-Calc/Math

Prove Identity: (1-cos2x/ tan x) = sin2x

27. ## Pre-Calculus

Find all solutions to the equation in the interval [0, 2pi) cos4x-cos2x=0 So,this is what i've done so far: cos4x-cos2x=0 cos2(2x)-cos2x (2cos^2(2x)-1)-(2cos^2(x)-1) No idea what to do next.

28. ## Calculus

Solve identity, (1-sin2x)/cos2x = cos2x/(1+sin2x) I tried starting from the right side, RS: =(cos²x-sin²x)/(1+2sinxcosx) =(cos²x-(1-cos²x))/(1+2sinxcosx) and the right side just goes in circle. May I get a hint to start off?

29. ## trig

Verify the trigonometric identity: [(1–sin²x)/sin²x]–[(csc²x–1)/cos²x]= -tan²x I still can't figure this out.

31. ## pre-calculus

tanx= -12/5 x in quadrant 2 find; sin2x= cos2x= tan2x=

32. ## Pre-Calculus

Verify the following identity: (sin2x)/sin - (cos2x)/cosx=secx

33. ## math

Prove the identity: 1-cos2x/sin2x = 1+tanx/1+cotx I simplified the RS to tanx. LS:(1-2cos²x+1)/2sinxcosx (2+2cos²x)/2sinxcosx How do I simplify the rest?

34. ## calc

Where do I start to prove this identity: sinx/cosx= 1-cos2x/sin2x please help!! Hint: Fractions are evil. Get rid of them. Well, cos2x = cos2x - sin2x, so 1-coscx = 1 - cos2x - sin2x = 1 - cos2x + sin2x You should be able to simplify this to 2*something

solve for (

36. ## MATH

Sin2x/1-Cos2x

37. ## math

what does sin2x/cos2x equal to?

38. ## math

d2y/dx2+9y=cos2x+sin2x

39. ## trig

secx = 4 in Q2 find sin2x,cos2x,tan2x

40. ## Identities

Verify the following identity cos2x/sin2x+sinx/cosx=csc2x

41. ## trig identites

since sin2x+√3cos2x=2sin(2x+60) find the general solution for the equation sin2x+√3cosx=0 thank you

42. ## calc

sin2x = (radical 3)/ 2 solve each equation on the interval [0,2pi)

43. ## radical equation - no solution right?

radical sign (w + 5) = 2 In all my problems there are a letter variable on the end example: radical sign (-u + 30) = u I then square both sides, drop the radical sign then (u+6)(u-5)=0 then check to see if they are both true I guess my question is this is

44. ## Trig

Prove the following functions: (sinx+sin2x)/(1+cosx+cos2x)=tan x (cos3x/sinx)+(sin3x/cosx)=2cot2x tan2x=(2/cotx-tanx) theses are due in the am. Fastness would be great?

45. ## Geometry

1.If two different lines are perpendicular to the same plane, they are: a. Collinear b. Coplanar c. Congruent d. Consecutive I think the answer is B, is that correct? Also, this: 2. Express 3 radical 75 plus radical 27 all over3 in radical form. I

46. ## Math

Find the domain of the following functions. 1. y= radical(x-3) - radical(x+3) 2. y= [radical(2x-9)] / 2x+9 3. y= radical(x^2 - 5x -14) 4. y= [cubed root(x-6)] / [radical(x^2 - x - 30)] I'm terrible at finding domains.. so any help with these problems would

47. ## pre-calc

is x=15 degrees a solution of radical 3/3 cos2x+sin2x=0

Solve the equation of the interval (0, 2pi) cosx=sinx I squared both sides to get :cos²x=sin²x Then using tri indentites I came up with cos²x=1-cos²x Ended up with 2cos²x=1 Would the answer be cos²x=1/2???

49. ## trig

write sin4xcos2 as the sum or difference of two functions. answers: 1/2(cos6x+cos2x), 1/2(cos2x-cos6x), 1/2(sin6x+sin2x), sin6x-sin2x

50. ## trig

write sin4xcos2 as the sum or difference of two functions. answers: 1/2(cos6x+cos2x), 1/2(cos2x-cos6x), 1/2(sin6x+sin2x), sin6x-sin2x

51. ## trig

cotx = -2 and 0 less than or equal to x less than or equal to pi Find sin2x and cos2x How to get the answers of sin2x = -4/5, cos2x = 3/5?

52. ## trig

Verify the trigonometric identity: [(1–sin²x)/sin²x]–[(csc²x–1)/cos²x]= -tan²x I can't figure this out.

53. ## math

sin2x − cos2x − tan2x = 2sin2x − 2sin4x − 1/ 1 − sin2x for x = 45

54. ## Calculus

Find the derivative of y with respect to x: y=(1+cos²x)^6 y'=6(1+cos²x)^5 How do you derive inside the brackets? The answer says -sin2x, but wouldn't it be -2sinx, using the chain rule.

55. ## Math

prove sin2x+cos2x+1 tan(pi/4+x) ______________ = __________ sin2x+cos2x-1 tanx so what I did tan(x) (1+cos(2x)+sin(2x)=tan(pi/4+x) (-1+cos(2x)+sin(2x)

56. ## pre-cal

find all solutions in interval [0,2pi] tan²x = -3/2 secx This question may look tricky, but its actually quite simple. First: rearrange the pythagorean identity tan²x+1=sin²x so that it reads tan²x=sin²x-1 Then replace the tan²x in the original

Sin2x+cos2x

58. ## MATH

Simplify: Sin2x/1-Cos2x

59. ## physics

1)if y=e^x . cot x then dy/dx will be 2) f(x)=sin²x-cos²x then the value of f' (π/4)

60. ## maths

d2y/dx2+9y=cos2x+sin2x

61. ## precalc

How do i verify: cotx = (sin2x)/(1-cos2x)

62. ## Calculus

How do you find the derivative of f(x)=sin2x/cos2x

63. ## Maths

if a=cos2x + sin2x and b=cos2y + isin2y.then find (a + b)

64. ## calculus

Solve for x on the interval (0, 2pi] (sin2x + cos2x)^2 = 1

65. ## Math

How do you prove this identity? cos2x*tan(π\4-x)= 1-sin2x

66. ## pre-calc

tanx= -12/5 x in Q 2. find sin2x= cos2x= tan2x=

67. ## Math

Required to Prove the following trig identity: (cos2x)^2 + (sin2x)^2 = 1

68. ## gr 12. advanced functions

Trig identity Prove: cos2x tan(pie/4 - x) ------- = 1 + sin2x

69. ## Trig

help please!: (sinx + sin2x +sin3x) / (cosx + cos2x + cos3x) = tan2x

70. ## Algebra

I'm adding 2(radical 50) + 12 (radical 8). I began by breaking the radical fifty into two parts: the radical of 25 and the radical of two. The radical of twenty five can break down into five, and the radical of two stays the way it is. Now it should read 2

71. ## Calculus II

How does one obtain cos2x = cos^2(x) - sin^2(x) by differentiating the identity sin2x = 2sinxcosx

72. ## Precalculus

Determine the solutions to the equation 2sinx − cos2x = sin2x for 0 ≤ x ≤ 2π . How do I start this question?

73. ## Math (Trig)

Rewrite the following expression in terms of tan3x: (sin2x + sin4x)/(cos2x + cos4x)

74. ## math , help,algebra

i am up to this point in my problem but i don't know what to do next with it can someone show me. Directions: Simplify by combining like terms x radical(18) minus 3radical(8x^2) these are the steps that i've done so far. = x radical (2*9) -3radical

75. ## MATH

veify that each equation is an identity cos2x+tan2xcos2x=1 sin4x-cos4x/sin2x=1-cot2x

76. ## Math

simplify (cos4x-cos2x)/(sin4x+sin2x) the answer choices are : cotx, tanx, cotxtanx, or 1

77. ## Trigonometry

How do I find all solutions in the interval [0,2Pi): sin2x=cos2x answer choices are: a.)Pi/8 b.) Pi/8, 5Pi/8, 9Pi/8, 13Pi/8

78. ## math

I have to find an exact solutions on the interval [0,pi) for both of these problems-- 1) 2sin2x = sqrtx and 2) 1-2sqrt2 sinxcosx = 0 I know this much: 1) sin2x = (sqrt x)/2 = 2sinxcosx = (sqrt x)/2 What do I need to do next? 2) 1/(2 sqrt2) = sinxcosx =

79. ## Pre calc

Please help me proof the identity. This isn't even math to me, I can not understand it so please show all work. God bless A)1-cos2x/sin2x=tanx B) sin4x/sinx=4cosxcos2x

81. ## Trigonometry

I can't remember what formula to use for these. Note- the X's may be replaced by a theta symbol. I just didn't have one on my keyboard. Use the given information to find sin2X, cos2X and tan2X if 0< X

solve algebreically the equation cos2x=1-sinx also cosx=cosx-1 and please also sin2x=3sinx

83. ## Calculus

In the interval (0 is less than or equal to x which is less than or equal to 5), the graphs of y=cos(2x) and y=sin(3x) intersect four times. Let A, B, C, and D be the x-coordinates of these points so that 0

84. ## trig

Solve the triginometric equation analytically. Use values of x for 0 less then or equal to x less then 2pi The equation for this question is sin2x + cos2x = 0

85. ## trig

on the same set of axes: (0 degrees is greater than or equal to x and x is less than or equal to 360 degrees) (a) sketch the graphs of y= sin degrees ,y=2sinx degrees and y=sin2x degrees

86. ## trigonometry

Prove cotx-1/cotx+1=1-sin2x/cos2x

87. ## math,correction

Can somoene helpme plz... Simplify radical 7 * radical 14 wouldn't it be radical (7*14) = radical (98) = 7radical (14) = 7 radical (2) The result is right, you erred on the next to last line. So how do i show that step that i am wrong in...

88. ## trig

I keep trying to find the power reducing formula for sin^4(x), but I can't seem to get all the fractional parts correct. The answer I should be getting is: sin^4(x)=(1/8)cos4x-(1/2)cos2x+(3/8) I can only get this far knowing feeling confident. When I go

89. ## math,correction

Find the area of the rectangle shown in the figure. length = radical (3) + radical (5) width = radical (3) + radical (5) My answer: a= 8 + 2 radical (15) or a = 15.75 agree, you seem to be able to do these should i leave it as the radical form or the

90. ## integral Calculus

ʃ (4sin²x cos²×/sin2x cos2x)dx i've got it from the book and it has an answer from the back page of the book but i want to know how to solve it..i really need it for practicing this subject...please please help..Thanks a lot.. the answer is: -1/2

91. ## Geometry, help!

Circle O has a radius 28. Radii OM and ON form an angle of 60 degrees. Find MN. A) 28 radical 2 B) 28 C) 56 D) 56 radical 3 Is it A) ?

93. ## math

Solve radicals. 1. √8 /√32 (radical 8 divided by radical 32) = √1/√4 (divided numerator & denominator by 4) = 1/2 (simplify radical 1 over radical 4) 2. √7 /√49 (radical 7 divided by radical 49) = √7 /7 (simplified radical 49 = 7, but kept

94. ## trig

how does this work? (Sin2x+cos2x+2sin²x)/(sinx+cosx) = (sinx+cosx

95. ## Math

prove identity Sin2x - sinx/cosx + cos2x= sinx/cosx + 1

96. ## trig

Sketch the graph of f(x)=sin(x+30 degrees) and g(x)=cos2x in the same system of axis [-180 degrees;180 degrees]

97. ## math,correction,plz

Perform the indicated division. Rationalize the denominator if necessary. Then simplify each radical expression. Problem #54 (6-radical(20))/(2) My answer: 3-radical(5) Problem #50 Find the area of the rectangle shown in the figure. width = radical (3) +

98. ## Pre-Calculus

Hi, I need a bit of help with verifying identities. The problems are as follows: sinx+cosx/cotx+1=sinx sin2x/sin - cos2x/cosx=secx 1-tan^2θ/1+tan^2θ=cos2θ

99. ## Precalculus

Please help!!!!!!!!!!! Find all solutions to the equation in the interval [0,2π). 8. cos2x=cosx 10. 2cos^2x+cosx=cos2x Solve algebraically for exact solutions in the interval [0,2π). Use your grapher only to support your algebraic work. 24. cos2x+sinx=0

100. ## algebra

3 radical x - 4 radical y divided by 3 radical x - 2 radical y = ( i think im supposed to use the distributive property, after the conjugate. but didn't know if i could just cancel? thanks.