if tanx+cotx=2 then the value of tan^5x + cot^10x is
5,250 results-
Math
1)A piano tuner uses a tuning fork. If middle C has a frequency of 264 vibrations per second, write an equation in the form d=sinw(t) for the simple harmonic motion. 2) Verify the identity tan^2X-cot^2X/tanX+cotX=tanX-cotX I'm not completely sure on the -
arithmetic
if tanx+cotx=2 then the value of tan^5x + cot^10x is -
Pre-Calc
How do I solve this? My work has led me to a dead end. tan(45-x) + cot(45-x) =4 my work: (tan45 - tanx)/(1+ tan45tanx) + (cot45 - cotx)/(1 + cot45cotx) = 4 (1-tanx)/(1+tanx) + (1-cotx)/(1+cotx) = 4 Then I found a common denominator, giving me this: -
Trig
Verify that each of the following is an identity. tan^2x-sin^2x=tan^2xsin^2x I can get it down to cos^2 on the right, but cannot get it to work out on the left. secx/cosx - tanx/cotx=1 On the left I got down to 1-tan^2, but that clearly doesn't equal 1.... -
trignometry
tanx+cotx=5 than find the value of tan^2x+cot^2x -
trig
verify the identity: tan^2x(1+cot^2x)=1/1-sin^2x Verify the Id: tanx + cotx/ tanx-cotx = (1/sin^2x-cos^2x) -
TRIGONOMETRY *(MATHS)
Q.1 Prove the following identities:- (i) tan^3x/1+tan^2x + cot^3x/1+cot^2 = 1-2sin^x cos^x/sinx cosx (ii) (1+cotx+tanx)(sinx-cosx)/sec^3x-cosec^3x = sin^2xcos^2x. -
TRIG..............
Q.1 Prove the following identities:- (i) tan^3x/1+tan^2x + cot^3x/1+cot^2 = 1-2sin^x cos^x/sinx cosx (ii) (1+cotx+tanx)(sinx-cosx)/sec^3x-cosec^3x = sin^2xcos^2x. -
trig
If tanx + cotx =5 tgen find tan^2x +cot^2x -
Pre Cal
could someone please tell me what the other angle identity of tan is? Thank you much! "...other angle identity of tan x"? in relation to which "other" ? there are many identities dealing with the tangent. The most important is probably tan x = sin x/cos x -
trigonometry
How do you find: cot(-5pie/4)? you have to know that cotx = 1/tanx so you could just trustfully change your calculator to radians enter 5*pi/4, press =, press +/-, then press Tan, =, then the 1/x key you should get -1 or... you could do it the more -
Math-Trig
1. Create an algebraic expression for sin(arccosx-arcsin3x) 2. The cosx=4/5, x lies in quadrant 4. Find sin x/2 3.Determine all solutions in (0,2pie) for sin4xsin^2x=3, cot^2v(3-1)cotx=v(3), cos^2x=cosx, and tan^2x-6tanx+4=0 4. Solve; sin(∏/2-x)=1/sec 5. -
Trigonometry
For this question, they want me to use fundamental trig identities to simplify the expression. The problem is as follows; (tanx/csc^2x + tanx/sec^2x)(1+tanx/1+cotx) - 1/cos^2x I got as far as this; tanx(1/csc^2x + 1/sec^2x)(1+tanx/1+cotx) - sec^2x. I -
pre-calc
Can someone help me find the exact value of 4csc(3pi/4)-cot(-pi/4)? Thanks! cotx =1/tanx cscx = 1/sinx If you find it easier to conceptualize in degrees, realize that pi/4 radians is 45º and 3pi/4 is then 135º If you know the CAST rule, it is easy to see -
Trigonometry
Simply: cot(-x)-1/1-tan(-x) Is it -cotx? The other answer choice is: cotx. -
Trigonometry
Given that a^2+b^2=2 and that (a/b)= tan(45degee+x), find a and b in terms of sinx and cosx. I don't know what i'm supposed to do, and i don't come to an answer! Help, thanks! my workings: tan(45+x)= (1+tanx)/(1-tanx) a/b = (1+tanx)/(1-tanx) -
Trigo
Given that a^2+b^2=2 and that (a/b)= tan(45degee+x), find a and b in terms of sinx and cosx. I don't know what i'm supposed to do, and i don't come to an answer! Help, thanks! my workings: tan(45+x)= (1+tanx)/(1-tanx) a/b = (1+tanx)/(1-tanx) -
math
solve each identity algebraically 1)(1-tanx)/(1-cotx)=-tanx 2)(1+cotx)/(1+tanx)=cotx -
a math
Prove cotx-1/cotx+1 = sec2x - tan2x I prove till cotx-1/cotx+1 =1/1+tanx - tanx/1+tanx -
trigonometry (please double check this)
Solve the following trig equations. give all the positive values of the angle between 0 degrees and 360 degrees that will satisfy each. give any approximate value to the nearest minute only. a.) ( I got confused doing this 1 can you help me with it.) 3 sin -
trig
Verify the trigonometric identity. Please show all steps. tanx-cotx/tanx+cotx=sin^2x-cos^2x -
trig
{tan^2x+cotx divided by tanx-cotx} is equal to {1 divided by sin^2x-cos^2x} -
trig
verify the identity (tanx+cotx) (1) __________ = ______________ (tanx-cotx) (sin^2x-cos^2x) -
Math - Trigonometry
Verify the following: 1. cos x/(1-sinx)= sec x + tan x 2. (tanx+1)^2=sec^2x + 2tan x 3. csc x = )cot x + tan x)/sec x 4. sin2x - cot x = -cotxcos2x -
Trigonometry
Can you please help me verify these? >sin7x-sin5x= tanx(cos7x-cos5x) >(1-cosx)cot(1/2x) = sinx >1+tanx tan(x/2) = secx Its very confusing because of all the double-half angle formulas >_ -
Trig.
sec^2xcotx-cotx=tanx (1/cos)^2 times (1/tan)-(1/tan)=tan (1/cos^2) times (-2/tan)=tan (-2/cos^2tan)times tan=tan(tan) sq. root of (-2/cos^2)= sq. root of (tan^2) sq. root of (2i)/cos=tan I'm not sure if I did this right. If I didn't, can you show me the -
Math
So I have a math problem where I need to solve an equation for x where x is within (0, 2pi) I have it simplified down to cotx+cot^2x=0 and cotx-cot^2x=0 but I don't know where to go from here -
Grd 12 Math
Can someone please help me work out how to get to the answer of: tanx + tan (pi-x) + cot (pi/2+x) = tan (2pi-x) -
precalc
tanx cotx ------- + ------- = 1 +secxcscx 1 - cotx 1- tanx prove the proof -
matj
prove that (cotx+tanx)(cotx-tanx) = 1/(sin^2 x) - 1/(cos^x) -
Trigonometry
Please review and tell me if i did something wrong. Find the following functions correct to five decimal places: a. sin 22degrees 43' b. cos 44degrees 56' c. sin 49degrees 17' d. tan 11degrees 37' e. sin 79degrees 23'30' f. cot 19degrees 0' 25'' g. tan -
trig
(tanx+cotx)over(tanx-cotx)=(1) over sin^2x-cos^2x) -
trigonometry
tanx-cotx/tanx+cotx=1-2cos squardx -
Pre-Cal
Perform the addition or subtraction. tanx - sec^2x/tanx tan^2(x)/tan(x) - sec^2x/tanx = tan^2x sec^2x / tanx then I use the identity 1+tan^2u=sec^2u I do not know what to do at this point. -
trig
it says to verify the following identity, working only on one side: cotx+tanx=cscx*secx Work the left side. cot x + tan x = cos x/sin x + sin x/cos x = (cos^2 x +sin^2x)/(sin x cos x) = 1/(sin x cos x) = 1/sin x * 1/cos x You're almost there. thanks so -
Pr-Cal/Trig
1)if the graph of f(x)=cotx is transformed by a horizontal shrink of 1/4 and a horizontal shift left pi, the result is the graph of: a) g(x)= cot[1/4(x-pi)] b) g(x)=cot[1/4(x+pi)] c) g(x)=cot[4(x-pi)] d) g(x)=cot[4(x+pi)] e) g(x)=cot[4x+pi] please include -
math
1. (sinx/cscx)+(cosx/secx)=1 2. (1/sinxcosx)-(cosx/sinx)=tanx 3. (1/1+cos s)=csc^2 s-csc s cot s 4. (secx/secx-tanx)=sec^2x+secxtanx 5. (cosx/secx-1)-(cosx/tan^2x)=cot^2x -
Math
Im really struggling with these proving identities problems can somebody please show me how to do these? I'm only aloud to manipulate one side of the equation and it has to equal the other side of the equation at the end Problem 1. (1-tanx) = -
math
how do I simplify these? 1. (Cot/1-tan) + (Tan/1-Cot) - Tan - Cot 2. (1+cos) (csc-cot) -
Calculus - Integration
Hello! I really don't think I am understanding my calc hw. Please help me fix my errors. Thank you! 1. integral from 0 to pi/4 of (tanx^2)(secx^4)dx It says u = tan x to substitute So if I use u = tan x, then my du = secx^2 then I have integral of (u^2) -
calculus
1/tanx + 1/cotx =tanx +cotx verify -
Pre-Calculus
Hello, I need help with solving these trig identities. All help is appreciated! 1. Establish the Identity: (cos(2x)/1+sin(2x)) = ((cotx-1)/(cot+1)) 2. Establish the Identity ((sec²x-tan²x+tanx)/(secx)) = (sinx+cosx) -
PreCalculus
Hi I need some assistance on this problem find the exact value do not use a calculator cot[(-5pi)/12] Here is my attempt RT = square root pi = 3.14... -
Math
Perform the multiplication and use the fundamental identities to simplify. (cotx + cscx)(cotx-cscx) I know that you have to foil first so cot^2x - csc^2x and then use the pythagorean identity 1+cot^2u = csc^2u but I do not know how to simplify. -
Pre-Cal
Perform the multiplication and use the fundamental identities to simplify. (cotx + cscx)(cotx-cscx) I know that you have to foil first so cot^2x - csc^2x and then use the pythagorean identity 1+cot^2u = csc^2u but I do not know how to simplify. -
Trigonometry
Verify the identity algebraically. TAN X + COT Y/TAN X COT Y= TAN Y + COT X -
Math
Evaluate each of the following. Leave results as exact values. (a) tan(5π/6) = (b) tan(4π/3) = (c) cot(7π/4) = (d) sec(2π/3) = (e) csc(3π/4) = My answers (a) tan(5π/6) = -.577350 (b) tan(4π/3) = 1.732051 (c) cot(7π/4) = -1 (d) sec(2π/3) = -2 (e) -
Math
Im really struggling with these proving identities problems can somebody please show me how to do these? I'm only aloud to manipulate one side of the equation and it has to equal the other side of the equation at the end Problem 1. Sinx/(cotx+1) + -
calculus
If limit as delta x approaches 0 of tan(0+Δx)-tan(0)/Δx =1 which of the following is false: d/dx [tanx]=1 the slope of y = tan(x) at x = 0 is 1 y = tan(x) is continuous at x = 0 y = tan(x) is differentiable at x = 0 -
trig
Verify that each equation is an identity. 16. 1+tanx/sinx+cosx =secx ok i have a clue on how to do it. i multiplyed the denominator by sinx-cosx and i also did the top but when i do i get this weird fraction with all these cos and sin and then i get -
Calc
Hello im trying to integrate tan^3 dx i have solved out the whole thing but it doesnt match up with the solution.. this is what i did: first i broke it up into: integral tan^2x (tanx) dx integral (sec^2x-1)(tanx) dx then i did a u substitution u = secx du -
Calc
Hello im trying to integrate tan^3 dx i have solved out the whole thing but it doesnt match up with the solution.. this is what i did: first i broke it up into: integral tan^2x (tanx) dx integral (sec^2x-1)(tanx) dx then i did a u substitution u = secx du -
drwls
My previous question: Verify that (secx/sinx)*(cotx/cscx)=cscx is an identity. (secx/sinx)*(cotx/cscx) = (secx/cscx)(cotx/sinx) = (sinx/cosx)*cotx*(1/sinx) "The last steps should be obvious" Not to me. I can convert (sinx/cosx) to tanx if that's even what -
Trig
Use the fundamental identities to simplify the expression: cot beta sec beta I used 1+tan^2u=secu since cot is the inverse of tan. I flipped the tangent, then so it was 1+ (1/tan). But the book's answer is the cosecant of beta. Where did this come from?? -
Trig
Prove the following functions: (sinx+sin2x)/(1+cosx+cos2x)=tan x (cos3x/sinx)+(sin3x/cosx)=2cot2x tan2x=(2/cotx-tanx) theses are due in the am. Fastness would be great? -
Math
Are these correct? 5. is sin θ = -7/13 and cos θ = 12/13, find tan θ and cot θ using Quotient Identities. answers: tan (θ) = -(7/12) cot (θ) = -(12/7) -
verifying identities
how do you veriy tan x + Cot y -------------- = tan y + cot x 1-tan x cot y sin^4x + cos^4x = 1- 2cos^2x + 2cos^4 -
trigonometry...........
Prove the following identity:- (i) tan^3x/1+tan^2x + cot^3x/1+cot^2 = 1-2sin^x cos^x/sinx cosx -
Math - Trig
I'm trying to verify these trigonometric identities. 1. 1 / [sec(x) * tan(x)] = csc(x) - sin(x) 2. csc(x) - sin(x) = cos(x) * cot(x) 3. 1/tan(x) + 1/cot(x) = tan(x) + cot(x) 4. csc(-x)/sec(-x) = -cot(x) -
geometry
Identify tanX as a fraction and as a decimal rounded to the nearest hundredth. A. tan X = 6.4/9.6 ≈ 0.67 B. tan X = 7.2/9.6 ≈ 0.75 C. tan X = 6.4/7.2 ≈ 0.89 D. tan X = 7.2/6.4 ≈ 1.13 I think B if anything can someone help please. -
geometry
Identify tanX as a fraction and as a decimal rounded to the nearest hundredth. A. tan X = 6.4/9.6 ≈ 0.67 B. tan X = 7.2/9.6 ≈ 0.75 C. tan X = 6.4/7.2 ≈ 0.89 D. tan X = 7.2/6.4 ≈ 1.13 I think B if anything can someone help please. -
math
prove (tan^3x/1 tan^2x) (cot^3x/1 cot^2) = (1-2sin^2x cos^2x)/sinx cosx -
Math
Simplify the follow)ing to the simplest form (tan(x) +cot(x))/ (tan(x)*cot(x)) -
trigonometry repost
Reduce (csc^2 x - sec^2 X) to an expression containing only tan x. (is this correct?) csc x = 1/sin x sec x = 1/cos x tan x = 1/cot x sin^2 x + cos^2 x = 1 1 + cot^2 x = csc^2 x tan^2 x + 1 = sec^2 x csc^2 x - sec^2 x = 1 + cot^2 x - (1 + tan^2 x) = cot^2 -
Math
Solve and prove the identity (tan x+ cot (-x))/ (tan x - cot(-x))= 1-2cos^2(x) -
Math (Trigonometry)
We are working on verifing identities using trigonomic identities and such and of the about 50 or so problems we've had to complete i've been able to push through most except for these: 1.(COTx)(SECx)(SINx)=1 2.TANx + COTx = (SECx)(CSCx) 3.(COSt)(COTt) = -
math (2)
Solve each trig identity. a) sec2(x) = [sec^2(x)]/[2 - sec^2(x)] b) sec2(x) = [1 + tan^2(x)]/[1 - tan^2(x)] c) [cot(x) - tan(x)]/[cot(x) + tan(x)] = cos2(x) -
Trigonometry
Prove the following trigonometric identities. please give a detailed answer because I don't understand this at all. a. sin(x)tan(x)=cos(x)/cot^2 (x) b. (1+tanx)^2=sec^2 (x)+2tan(x) c. 1/sin(x) + 1/cos(x) = (cosx+sinx)(secx)(cscx) d. tan^2 (x)(1+1/tan^2 x) -
Trigonometry
How do you simplify these equations: 1.)(2/cot^3(x) - cot^2 (x)) + (2/cot (x)-2) 2.) (2/ tan^2 (x)) + (2/ tan(x) -2) -
math
Prove the identity: 1-cos2x/sin2x = 1+tanx/1+cotx I simplified the RS to tanx. LS:(1-2cos²x+1)/2sinxcosx (2+2cos²x)/2sinxcosx How do I simplify the rest? -
Math
A right triangle has acute angles C and D. If tan C=158 and cos D=1517, what are cot D and sin C? cot D=8/15 and sin C=8/17 cot D=8/15 and sin C=15/17 cot D=15/8 and sin C=15/17 cot D=15/8 and sin C=8/17 -
Trig/Precalc
Two questions that I would really appreciate some hints on: 1) Circles with centers (2,1) and (8,9) have radii 1 and 9, respectively. The equation for a common external tangent can be written in the form y=mx+b with 0 -
Math
Evaluate cot@/cot@-cot3@ + tan@/tan@-tan3@ -
Math/Precal
How do i get left side to equal right side? (1-tanx)/(1-cotx) = -tanx -
math, trig, functions, proofs
prove that (tanx + tany) / (cotx + coty) = (tanx)(tany) -
Derivatives
Can you help me find the derivative of these problems...Every time I try doing these I don't get the right answer. All of these are fractions; (x)/(2+x)= (x^2+3)/(x^3-2)= (2π)/(x^2-x)= These are not fractions; (3x^3/2 tanx)= (3x^1/2 sinx)= (4secx tanx)= -
trig
Find the smallest positive value of x(in degree) for which tan(x+100°)=tan(x+50°)*tanx*tan(x-50°) -
advanced functions
Show that tanx = sinx / cosx can be written as tan(x+y) = (tanx + tany) / (1 - tanxtany) -
adv functions
Show that tanx= (sinx/ cosx) can be written as: tan(x-y) = (tanx - tany) / (1+ tanxtany) -
Trig check my work please?
tan(X+30)tan(30-x)=2cos2x-1 / (2cos2x+1) i just did (tanx)(-tanx)=-sin^2x/cos^2x would that work? -
maths
1÷(tanx+cotx)(tanx+cotx)dx -
trig
tanx=cotx -
PreCalculus
cotx + tanx= -
math
ʃ ( tanx + cotx )² dx -
math
1. (sec^2x-6tanx+7/sec^2x-5)=(tanx-4/tanx+2) 2. (sin^3A+cos^3A/sinA+cosA)=1-sinAcosA 3. csc^6x-cot^6x+1+3csc^2xcot^2x please help -
algebra 2
Please show how to do these problems so i understand. 1)Prove that sin^2 x (1+cot^2 x)=1 2)Prove that tan x (cot x+tan x)=sec^2 x -
algebra 2
Please show how to do these problems so i understand. 1)Prove that sin^2 x (1+cot^2 x)=1 2)Prove that tan x (cot x+tan x)=sec^2 x -
math
lim x--->pi/4 tanx - cotx / x - pi/4 -
trig
cotx/secx-tanx -
I dont think drawing a picture will help me drwls
Which expression is equivalent to tan theta-sec theta/sin theta? A)-cot theta B)cot theta C)tan theta-cot theta D)tan theta-sec^2theta just tell me what I need to know to set it up -
math
use the quotient and reciprocal identities to simplify the given expression cot t sin t csc t sin t tan t cot t cot t sec t -
Math
How do I solve this? tan^2x= 2tanxsinx My work so far: tan^2x - 2tanxsinx=0 tanx(tanx - 2sinx)=0 Then the solutions are: TanX=0 and sinX/cosX = 2 sin X Divide through by sinX: we have to check this later to see if allowed (ie sinX is not zero) cosX=1/2 -
trigonometry
(secx - tanx)(cscx+1) =cotx -
math
tanx +cotx=secx cscx -
Trigonometry
Given: tanx = 2.4, π/2 -
trig proofs
cotx+tanx=secx+cscx -
pre-calculus
y=tanx -2π≤x≤2π y=cotx -2π≤x≤2π y=cscx -2π≤x≤2π y=secx -2π≤x≤2π -
trignometry
how to find derivative of (2+cotx)/(7-tanx) -
Trigonometry
Prove that tanx+cotx=2sec(2x) Thank you! :) -
Precalc?
Suppose that Cot(theta) = c and 0