# how do you start this equation i've been tryng it for 20min. sec^6x(secxtanx)-sec^4x(secxtanx)=sec^5xtan^3x ec^6x(secxtanx)-sec^4x(secxtanx)=sec^5xtan^3x Factor out a sec^5 tan and divide thru. Left is sec^2 x = Tan^2 x Then this should reduce to sin^2 x = cos^4 x take

52,655 results
1. ## Check Math

Old Isaac took a little nosedive from his perch on Mrs. Cohen’s window ledge 25 feet above ground. Given that he fell as a result of a gentle tap to his noggin, how fast is Isaac traveling when he hit’s the ground? (gravity is -32ft/sec^2).

2. ## math;)

What is a simplified form of the expression (sec^3 theta) - (sec theta/cot^2 theta)? a. 0 b. sec theta-tan theta c. cos theta d. sec theta***** Every time I attempt to work out this problem I end up with one. I know the answer is sec theta, but I do not

3. ## Calculus

The base of a triangle is decreasing at the rate of 1 ft/sec, while the height is increasing at the rate of 2 ft/sec. At what rate is the area of the triangle changing when the base is 10 ft and the height is 70 ft? a) -25 ft^2/sec b) -45 ft^2/sec c) -50

4. ## calculus

The length of a rectangle is decreasing at the rate of 2 cm/sec, while the width w is increasing at the rate of 3 cm/sec. At what rate are the lengths of the diagonals changing at the instant that l=15 cm and w= 8 cm? Are the diagonals increasing or

5. ## math

Prove the trigonometric identity. tan x+cot x/csc x cos x=sec^2 x __= sec^2x __= sec^2x __ = sec^2x __= sec^2x __ = sec^2x 1/cos^2x=sec^2x sec^2x=sec^2x

6. ## Math

Starting from 130 feet away, a person on a bicycle rides towards a checkpoint and then passes it. The rider is traveling as a constant rate of 25 feet per second. The distance between the bicycle and the checkpoint is given by the equation d=|130-25t|. At

7. ## Calculus

Solve: The posistion of a particle moving along a coordinate line is s=sqrt(5+4t), with s in meters and t in seconds. Find the particle's velocity at t=1 sec. A) 2/3 m/sec B) 4/3 m/sec C) -1/3 m/sec D) 1/6 m/sec Thank you!

8. ## Math

What is a simplified form of the expression sec^2x-1/sin x sec x ? a)cot x b)csc x c)tan x d)sec x tan x Please help me :(

9. ## algebra. help!

Start from 110 feet away, a person on a bicycle rides towards a checkpoint and then passes it. The rider is travelling at a constant rate of 30 feet per second. The distance between the bicycle and the checkpoint is given by the equation d=|110-30t| at

10. ## Bubbles

starting from 105 feet away a person on a bicycle rides towards a checkpoint and then passes it. the rider is traveling at a constant rate of 35 feet per second. THe distance between the bicycle and the checkpoint is given by the equation d= [105-35t] at

11. ## Calculus

I'm having trouble with the following problem: Find the volume of the solid generated by revolving the region about the given line. The region is in the first quadrant bounded above by the line y= sqrt 2, below by the curve y=secxtanx, and on the left by

12. ## Science

a ball is thrown upward at a speed of 12 m/s. It will reach the top of its path in about: a) 0.6 sec b) 1.2 sec c) 1.8 sec d) 2.4 sec Please explain how you find the answer!!! I cannot figure it out

13. ## Chemistry Ap

A sprinter completes the 100 yard dash in 9.30 seconds. How long would it take her to complete 100. meters if she continued at the same speed? 1. 10.2 sec 2. 10.9 sec 3. 10.7 sec 4. 9.30 sec

14. ## Calculus

A sphere is increasing in volume at the rate of 3(pi) cm^3/sec. At what rate is the radius changing when the radius is 1/2 cm? The volume of a sphere is given by V=4/3(pi)r^3. A. pi cm/sec B. 3 cm/sec C. 2 cm/sec D. 1 cm/sec E. .5 cm/sec

15. ## physics

a train starts from rest and accelerates uniformly to achieve a velocity of 20m/sec in 10 sec.then train maintains this speed for next 200 sec.the breaks are then applied and train comes to rest in next 50 sec.calculate a)acceleration in first 10 sec.

16. ## calculus

a bridge is 10 m. above a canal. A motorboat going 3 m/sec passes under the center of the bridge at the same instant that a woman walking 2 m/sec reaches that point. How rapidly are they separating 3 sec. later?

17. ## Calc

If f(x)= sec x, find f"(Pi/4) I am not sure how to take the 2nd derivative? f'(x)= sec x tan x f"(x)=??? Is it f"(x)= (sec x tan x)(sec^2x)??? Please Help!

18. ## Calculus

A car leaves an intersection traveling west. Its position 5 sec later is 22 ft from the intersection. At the same time, another car leaves the same intersection heading north so that its position 5 sec later is 27 ft from the intersection. If the speed of

19. ## Trig

Find secx if sinx = -4/5 and 270 < x < 360. tan^2x+1=sec^2x (-4/5)^2+1=sec^2x 16/25+1=sec^2x 17/25=sec^2x sqrt 17/5 I don't know if it should be positive or negative.

20. ## Math

Starting from 105 feet away a person on a bicycle rides towards a checkpoint and then passes it. the rider is traveling at a constant rate of 35 feet per second. THe distance between the bicycle and the checkpoint is given by the equation d= [105-35t] at

21. ## Trigonometry

Simplify each expression using the fundamental identities. 1. Sec x csc x / sec^2x+csc^2x 2. Sec x + tan x / sec x + tan x - cos x

22. ## Calculus

Given f '(x) = (x − 4)(4 − 2x), find the x-coordinate for the relative maximum on the graph of f(x). a) 12 m/sec; 22 m/sec^2 b) 22 m/sec; 18 m/sec^2 c) 22 m/sec; 6 m/sec^2 d) 14 m/sec; 3 m/sec^2

23. ## Calculus PLEASE check my work ,

1.) which of the following represents dy/dx when y=e^-2x Sec(3x)? A.3e^-2x sec(3x) tan (3x)-2e^-2x Sec(3x)

24. ## Math

starting from 105 feet away a person on a bicycle rides towards a checkpoint and then passes it. the rider is traveling at a constant rate of 35 feet per second. The distance between the bicycle and the checkpoint is given by the equation d= [105-35t] at

25. ## Physical Science

Suppose that you are running down the street at 6 m/sec. You see your dog ahead and speed up to 10 m/sec over 20 sec to catch him. What is your acceleration in m/s2?

26. ## Chemistry 2

For a second order reaction A B, calculate the t1/2 (half life) and the k(constant) and also fill in the blanks. A (concentration) t(time) 20 0 sec 10 ? 5 40 sec 3 ? ? 200 sec t1/2=? k=?

27. ## math

What is the conversion factor sequence for units from ft./sec. to km./hr.? Is (ft/sec) x (sec/min) x (min/hr) x (m/ft) x (km/m) correct?

28. ## physics

A bomb is dropped from a plane flying at constant horizontal velocity at an altitude of 600m. Where is the bomb after 2 sec? 5 sec? 10 sec? what are the velocities said period?

29. ## physics

A point moving on a straight horizontal line with an initial velocity of 60 fps to the right is given an acceleration of 12 fps2 to the left for 8 sec. Determine (a) the total distance traveled during the 8-sec interval; (b) the displacement during the

30. ## physics

car accelerates from 0 to 60 mi/hr in a time of 5.8 secs. a. What is the acceleration of car in m/s squared? need help setting up the problem, thanks acceleration = (speed change)/(time interval) To get the answer in m/s^2, the speed change of 60 mi/hr

31. ## Integration

Intergrate ¡ì sec^3(x) dx could anybody please check this answer. are the steps correct? thanks. = ¡ì sec x d tan x = sec x tan x - ¡ì tan x d sec x = sec x tan x - ¡ì sec x tan^2(x) dx = sec x tan x + ¡ì sec x dx - ¡ì sec^3(x) dx = sec x tan x

32. ## Math

Starting from 105 feet away, a person on a bicycle rides towards a checkpoint and then passes it. The rider is traveling at a constant rate of 35 feet per second. The distance between the bicycle and the checkpoint is given by the equation d = 105 - 35t.

33. ## Science

From the below information Speed(m/sec) 2m at 0 sec, 4m at 2 sec, 6m at 3 sec, 8m at 4 sec, 10m at 5 sec. Calculate acceleration. Distance (I am getting answer as 27m but as per book it is 30m. Here as per table velocity is not uniform.) Plz confirm me the

1.) which of the following represents dy/dx when y=e^-2x Sec(3x)? A.3e^-2x sec(3x) tan (3x)-2e^-2x Sec(3x)

35. ## chemistry; kinetics

Use the following table to determine the average rate during the period 800 to 1200 seconds for the decomposition of H2O2. 2 H2O2(l) → 2 H2O(l) + O2(g) Time (sec) (H2O2)M 0 2.32 400 1.72 800 1.30 1200 0.98 1600 0.73 a] 1.2 x 10-3M/sec b] 1.6 x 10-3 M/sec

36. ## Trig verifying identities

I am having trouble with this problem. sec^2(pi/2-x)-1= cot ^2x I got : By cofunction identity sec(90 degrees - x) = csc x secx csc-1 = cot^2x Then split sec x and csc-1 into two fractions and multiplied both numerator and denominators by csc and got: sec

37. ## calculus trigonometric substitution

∫ dx/ (x^2+9)^2 dx set x = 3tan u dx = 3 sec^2 u du I = 3 sec^2 u du / ( 9 tan^2 u + 9)^2 = 3 sec^2 u du / ( 81 ( tan^2 u + 1)^2 = sec^2 u du / ( 27 ( sec^2 u )^2 = du / ( 27 sec^2 u = 2 cos^2 u du / 54 = ( 1 + cos 2u) du / 54 = ( u + sin 2u / 2) / 54 =

38. ## Science

Predict when a fast toy car can pass a slower toy car . I marked off a distant of 1.5 meters and recorded the time it took the cars to reach the finish line. How do I create a graph and make a prediction? The fast car times were .87 sec. ,.94 sec. ,and .97

39. ## math

Determine all the possible values of x where 0 deg is more than or equal to x and x is more or equal to 360 deg such that i'm not sure the solution, please correct it and how to find the x value, 2 tan x - 1 = cot x solution: (sec x -1)(sec x + 2) = 0 sec

40. ## calculus

Use integration by parts to evaluate the integral of x*sec^2(3x). My answer is ([x*tan(3x)]/3)-[ln(sec(3x))/9] but it's incorrect. u=x dv=sec^2(3x)dx du=dx v=(1/3)tan(3x) [xtan(3x)]/3 - integral of(1/3)tan(3x)dx - (1/3)[ln(sec(3x))/3] - [ln(sec(3x))/9]

41. ## calculus

the height in feet of a rocket from ground level is given by the function f(t)= -16t^2+160t. what is the instantaneous velocity of the rocket 3 seconds after it is launched? A 32 feet/sec B 64 feet/sec C 12 feet/sec D 10 feet/sec E 8 feet/sec

42. ## calculus

Me again. One last question! Again, just needed my answer verified with any explanation or walk-through. The position of a particle moving along a coordinate line is s=√(3+6t) with s in meters and t in seconds. find the particle's acceleration at t=1

43. ## science

I need help constructing a graph showing and predicting when two toy cars traveling at different speeds when the fast car can pass the slower car.The fast car traveled 1.5 meters in .87 sec.and .94 sec and .97 sec in three trials. The slow car traveled 1.5

44. ## Pre-Cal

I'm trying to do this identities homework and i can't figure this one out. sec^4x + (tan^2x)(sec^2x)= sec^4x

45. ## calc: simpson's rule & arc length

i'm still getting this question wrong. please check for my errors: Use Simpson's Rule with n = 10 to estimate the arc length of the curve. y = tan x, 0

46. ## calculus

find the general solution to the differential equation. dy/dx=secxtanx-e^x

47. ## calculus

The length l of a rectangle is decrasing at a rate of 5 cm/sec while the width w is increasing at a rate of 2 cm/sec. When l = 15 cm and w = 7 cm, find the following rates of change: The rate of change of the area: Answer = cm^2/sec. The rate of change of

48. ## physics

a cyclist start from rest and accelerate uniformly to achieve a velocity of 12m/sec in 5 sec.immediately he applied brake and come to rest in next 4 sec .calculate a)distance traveled during acceleration b)distance traveled during retardation. c)total

49. ## trig

(sec(x) / (sec(x)-1)) - (sec(x) / (sex(x)+1)) = 2cot(x)csc(x)

50. ## Calc

Hello im trying to integrate tan^3 dx i have solved out the whole thing but it doesnt match up with the solution.. this is what i did: first i broke it up into: integral tan^2x (tanx) dx integral (sec^2x-1)(tanx) dx then i did a u substitution u = secx du

51. ## Calc

Hello im trying to integrate tan^3 dx i have solved out the whole thing but it doesnt match up with the solution.. this is what i did: first i broke it up into: integral tan^2x (tanx) dx integral (sec^2x-1)(tanx) dx then i did a u substitution u = secx du

52. ## Math

Derivative of y=sec(tanx)? I don't get how it is secxsecx*secxtanx*tanxtanx. Where does an extra tanx come from? Derivative of sec(tanx) is just secxtanx*tanx (and then multiply the inside as well so)* sec^2(X) as derivative of tanx. I have 2 tanx, where

53. ## calculus

Did I do this problem right? Find the first and second derative-simplify your answer. y=xtanx y'= (x)(sec^2 x)+(tanx)(1) y'= xsec^2 x + tanx y"= (x)(2secx)(secxtanx)+sec^2 x + sec^2 x y"=2xsec^2 x tanx + 2 sec^2 x

54. ## calculus

The problem is to evaluate the integral 10secxtanx dx, from -1/7 pi to 3/8 pi. What I've done so far is evaluated the integral since secxtanx is a trig identity, so the integral of that is secx. I took out the 10 since it was a constant which leaves me

2- given the curve is described by the equation r=3cos ¥è, find the angle that the tangent line makes with the radius vector when ¥è=120¨¬. A. 30¨¬ B. 45¨¬ C. 60¨¬ D. 90¨¬ not sure A or D 2.) which of the following represents dy/dx when

56. ## Calculus

If Y = SecXTanX, find y" 4y' 4y. I can easily do the second part of the question if I could if only I could find d first and second derivative of SecXTanX, pls do help.

57. ## Pre-Calculus

How do you make one side equal to the other side? (secx/secx-tanx)=sec^2x+secxtanx

58. ## Math

Starting from 130 feet away, a person on a bicycle rides towards a checkpoint and then passes it. The rider is traveling as a constant rate of 25 feet per second. The distance between the bicycle and the checkpoint is given by the equation d=|130-25t|. At

59. ## Calculus

How do I find the critical values? y= 4/x + tan(πx/8) What I did is I simplified it to y= 4x^-1 + tan(πx/8) then I took the derivative y'= -4x^-2 + (π/8)(sec(πx/8))^2 Then I simplied it y'= -4/x^2 + (π/8)(sec(πx/8))^2 then I found a common denomiator

60. ## Calculus AP

I'm doing trigonometric integrals i wanted to know im doing step is my answer right? ∫ tan^3 (2x) sec^5(2x) dx =∫ tan^2(2x) sec^4(2x) tan*sec(2x) dx =∫ (sec^2(2x)-1)sec^4 tan*sec(2x) dx let u=sec x, du= 1/2 tan*sec(2x) dx =1/2∫ (u^2(2x)-1) u^4 du

61. ## calculus (check my work please)

Not sure if it is right, I have check with the answer in the book and a few integral calculators but they seem to get a different answer ∫ sec^3(x)tan^3(x) dx ∫ sec^3(x)tan(x)(sec^2(x)-1) dx ∫ tan(x)sec(x)[sec^4(x)-sec^2(x)] dx ∫

62. ## statistics

The time (sec) that it takes a librarian to locate an entry in a file of records on checked-out books has an exponential distribution with lambda symbol=0.5. a)What proportion of all location times are less than 20 sec? At most 20 sec? Atleast 25 sec/

63. ## calculus

find dy/dx y=ln (secx + tanx) Let u= secx + tan x dy/dx= 1/u * du/dx now, put the derivative of d secx/dx + dtanx/dx in. You may have some challenging algebra to simplify it. Use the chain rule. Let y(u) = ln u u(x) = sec x + tan x dy/dx = dy/du*du/dx

64. ## Calculus

could anybody please explain how sec x tan x - ¡ì sec x tan^2(x) dx = sec x tan x + ¡ì sec x dx - ¡ì sec^3(x) dx What I don't understand about your question is what is ¡ì ? i just want to know if those two equations are equal, if yes, how did one

65. ## math

How do I derive the secant reduction rule? Integral (sec x)^n dx = Integral (sec x)^(n-2) * (sec x)^2 dx = Integral ((tan x)^2 + 1)^(n/2-1) * (sec x)^2 dx Doing a substitution with: u = tax x du = (sec x)^2 dx = Integral (u^2 + 1)^(n/2-1) * du At this

66. ## math

i need to integrate: (secx)^4 dx let u = sec x dv =sec^3 x dx Start with this. Then, you will have to deal with the integral of sec. You should be able to solve it after a few steps. Looks a little messy.

67. ## physics

a train starts from rest and accelerates uniformly to achieve a velocity of 20m/sec in 10 sec.then train maintains this speed for next 200 sec.the breaks are then applied and train comes to rest in next 50 sec.calculate a)acceleration in first 10 sec.

68. ## physics

a train starts from rest and accelerates uniformly to achieve a velocity of 20m/sec in 10 sec.then train maintains this speed for next 200 sec.the breaks are then applied and train comes to rest in next 50 sec.calculate a)acceleration in first 10 sec.

69. ## acceleration estimate

t(sec) 1 1.5 2 2.5 v(ft/sec) 12.2 1.3 13.4 13.7 velocity of an object moving along a line at various times. How do I estimate the object's acceleration(in ft/sec^2) at t=1 TIA t(sec) 1, 1.5, 2, 2.5 v(ft/sec) 12.2 ,1.3 ,13.4 ,13.7 The second velocity of

70. ## math

How would you establish this identity: (1+sec(beta))/(sec(beta))=(sin^2(beta))/(1-cos(beta)) on the right, sin^2 = 1-cos^2, that factor to 1-cos * `1+cos, then the denominator makes the entire right side 1+cosB which is 1+1/sec which is 1/sec (sec+1) qed

71. ## Science

Plz help me plot on graph and also the solution. Q. When velocity is 20 m/s time is 0 and velocity 20 m/s time is 5 sec, velocity 10 m/sec time 7 sec, velocity 20 m/sec time 10 sec and velocity 0 time 15 sec. Calculate total distance showing each step and

72. ## physics

if a bird travels 150 cm for 10 sec then 100 cm for 10 sec and then 200 cm for 5 sec. What was the birds average speed?

73. ## physics

1\ Acar is moving with acceleration 200 m in 50 sec reached to velocity 10 m\sec .what the total distance the car moved in 60 sec

74. ## PHYICAL

Acar is moving with acceleration 200 m in 50 sec reached to velocity 10 m\sec .what the total distance the car moved in 60 sec.

75. ## Physica

Acar is moving with acceleration 200 m in 50 sec reached to velocity 10 m\sec .what the total distance the car moved in 60 sec.

76. ## calculations

convert the following times from seconds to minutes... 510 sec. 270 sec. 450 sec.

77. ## Physics

If a ball is launched into the air vertically with a velocity of 20 m/sec, how fast will it be moving after two seconds? (The gravity's acceleration is rounded to 10 m/sec/sec.)

78. ## physics

Need equation: Mass of 4.24 kg acted on by external force that reduces velocity from 8.5 m/sec to 4.1 m/sec in 3.0 sec. Find magnitude of the retarding force?

79. ## Precalculus

Prove that the equation is an identity. sec x/(sec x -tan x)=sec^2 x +sec x tan x

80. ## Pre Calculus

Prove that the equation is an identity. sec x/(sec x -tan x)=sec^2 x +sec x tan x

81. ## Calc 2

Ok, I have two questions first: 1. I'm asked to find a cartesian equation for the polar graph of this polar equation: r^2 = sin(2(theta)) The answer I got was (x^2+y^2)^2/(2xy) = 2 Is this the correct way to express it? 2. I need to find the cartesian

82. ## physical science

If a car goes along a straight road heading east and speeds up from 45 ft/sec to 60. ft/sec in 5 sec, calculate the acceleration. = 3-3 ft/sec 2 NESn/aW Note: If the speed were given in miles per hour, and the time were given in minutes, you could change

83. ## math

how would you create an equation for sec(2x) using both sec(x) and csc(x)? the steps i have so far are 1/(cos^2(x)-sin^2(x)) = 1/(1-1)/(sec^2(x)-csc^2(x)) but then i do not know what to do after this.

84. ## Physics

Which equation would you use to find displacement (d) if the following variables are known: Vi = 0 M/Sec Vf = 100 M/Sec a = 9.81 M/Sec^2 t = Unknown d = Unknown

85. ## pHysics

A ball of 250g hits the floor at a velocity of 2,50 m/s at an angle of 70* relative to the vertical. The vertical force in function with time between the floor and the ball is: from 0 to 50 N : from 0 to 1 sec. from 50 N to 100 N : from 1 to 2 sec.

86. ## physics

A ball of 250g hits the floor at a velocity of 2,50 m/s at an angle of 70* relative to the vertical. The vertical force in function with time between the floor and the ball is: from 0 to 50 N : from 0 to 1 sec. from 50 N to 100 N : from 1 to 2 sec.

87. ## Calculus 1A

I am trying to find: dy/dx for y = sec(tan x) I have the answer, but I have no idea how to get there. I know that the derivative of sec x = sec x tan x and that the derivative of tan x is sec^2 x. But sec doesn't have an x, so ...?

88. ## Calculus (fixed the typo )

A line rotates in a horizontal plane according to the equation theta=2t^3 -6t,where theta is the angular position of the rotating line, in radians ,and t is the time,in seconds. Determine the angular acceleration when t=2sec. A.) 6 radians per sec^2 B.) 12

89. ## physics

A bomb is dropped from a plane flying at constant horizontal velocity at an altitude of 600m. Where is the bomb after 2 sec? 5 sec? 10 sec? what are the velocities said period?

90. ## calculus

When a ball is thrown vertically upward into the air with a velocity of 79 ft/sec its height, y(t), in feet after t seconds is given by y(t) = 79t − 16t 2 . Find the average velocity of the ball over the interval from 3 to 3 + h seconds, h 6=/= 0. 1.

91. ## calculus

i have to integrate using u substitution, but i am not sure if i did it correct. çtan^3(5x)sec^2(5x)dx u=5x du=5dx 1/5du=dx 1/5çtan^3(u)sec^2(u)du 1/5tanusec^2u+c 1/5tan(5x)sec^2(5x)+c

92. ## math

1. (sinx/cscx)+(cosx/secx)=1 2. (1/sinxcosx)-(cosx/sinx)=tanx 3. (1/1+cos s)=csc^2 s-csc s cot s 4. (secx/secx-tanx)=sec^2x+secxtanx 5. (cosx/secx-1)-(cosx/tan^2x)=cot^2x

93. ## AP Calculus BC

Hi! Thank you very much for your help--- I'm not sure what the answer to this is; how do I solve? Find antiderivative of (1/(x^2))[sec(1/x)][tan(1/x)]dx I did integration by parts and got to (1/(x^2))[sec(1/x)] + 2*[antiderivative of (1/(x^3))(sec(1/x))dx]

94. ## maths

a spherical ballon is being inflated at the rate of 10 cu in/sec.find the rate of change of area when ballon has a radius of 6 inch. (a)3.33 in2/sec (b)3.67 in2/sec (c)3.11 in2/sec (d)none of these

95. ## Calculus

A sphere is increasing in volume at the rate of 3(pi) cm^3/sec. At what rate is the radius changing when the radius is 1/2 cm? The volume of a sphere is given by V=4/3(pi)r^2 A. pi cm/sec B. 3 cm/sec C. 2 cm/sec D. 1 cm/sec E. .5 cm/sec

96. ## trig

how do you start this equation i've been tryng it for 20min. sec^6x(secxtanx)-sec^4x(secxtanx)=sec^5xtan^3x ec^6x(secxtanx)-sec^4x(secxtanx)=sec^5xtan^3x Factor out a sec^5 tan and divide thru. Left is sec^2 x = Tan^2 x Then this should reduce to sin^2 x =

97. ## physics

1\ Acar is moving with acceleration 200 m in 50 sec reached to velocity 10 m\sec .what the total distance the car moved in 60 sec

98. ## Calculus

Differentiate to find critical numbers and leave function in fully factored form. g(x) = (x^2+1)^5(x^2+2)^6 g'(x) = (x^2+1)^5[6(x^2+2)^5(2x)] + (x^2+2)^6[5(x^2+1)^4(2x)] g'(x) = 2x(x^2+1)^4(x^2+2)^5[6(x^2+2)(2x) + 5(x^2+1)(2x)] g'(x) =

99. ## Engineering

i did A=pi(1/48)^2=.0014 2.5 ft/sec * .0014ft .0035 ft^3 450 galmin/1 ft^3/sec * .0035 ft^3/sec*15 min = 23.625 gpm

100. ## calculus

So I am suppose to evaulate this problem y=tan^4(2x) and I am confused. my friend did this : 3 tan ^4 (2x) d sec^ 2x (2x)= 6 tan ^4 (2x) d sec^2 (2x) She says it's right but what confuses me is she deriving the 4 and made it a three? I did the problem like