
find integral using table of integrals ) integral sin^4xdx this the formula i used integral sin^n xdx =1/n sin^n1xcosx +n1/n integral sin^n2 using the formula this is what i got: integral sin^4xdx=1/4sin^3xcosx+3/4 integral sin^2xdx= 1/2sinxcosx+1/2

That's the same as the integral of sin^2 x dx. Use integration by parts. Let sin x = u and sin x dx = dv v = cos x du = cos x dx The integral is u v  integral of v du = sinx cosx + integral of cos^2 dx which can be rewritten integral of sin^2 x = sinx

integral from 0 to 2pi of isin(t)e^(it)dt. I know my answer should be pi. **I pull i out because it is a constant. My work: let u=e^(it) du=ie^(it)dt dv=sin(t) v=cos(t) i integral sin(t)e^(it)dt= e^(it)cos(t)+i*integral cost(t)e^(it)dt do integration by

i'm having trouble evaluating the integral at pi/2 and 0. i know: s (at pi/2 and 0) sin^2 (2x)dx= s 1/2[1cos(2x)]dx= s 1/2(xsin(4x))dx= (x/2) 1/8[sin (4x)] i don't understand how you get pi/4 You made a few mistakes, check again. But you don't need to

Hello, I'm having trouble with this exercise. Can you help me? Integral of (x* (csc x)^2)dx I'm using the uv  integral v du formula. I tried with u= (csc x)^2 and used some trigonometric formulas, but the expression became too complicated, I couldn't


s integral endpoints are 0 and pi/2 i need to find the integral of sin^2 (2x) dx. i know that the answer is pi/4, but im not sure how to get to it. i know: s sin^2(2x)dx= 1/2 [1cos (4x)] dx, but then i'm confused. The indefinite integral of (1/2) [1cos

I have two questions, because I'm preparing for a math test on monday. 1. Use the fundamental theorem of calculus to find the derivative: (d/dt) the integral over [0, cos t] of (3/5(u^2))du I have a feeling I will be able to find the derivative easily,

I'm trying to find the convolution f*g where f(t)=g(t)=sin(t). I set up the integral and proceed to do integration by parts twice, but it keeps working out to 0=0 or sin(t)=sin(t). How am I supposed to approach it? integral (sin(u)sin(tu)) du from 0 to t.

I need to find the integral of (sin x)/ cos^3 x I let u= cos x, then got du= sin x (Is this right correct?) I then rewrote the integral as the integral of du/ u^3 and then rewrote that as the integral of  du(u^3). For this part, I wasn't sure how to

How would I integrate the following by parts: Integral of: (x^2)(sin (ax))dx, where a is any constant. Just like you did x^2 exp(x) below. Also partial integration is not the easiest way to do this integral. You can also use this method. Evaluate first:

Evaluate the integral. S= integral sign I= absolute value S ((cos x)/(2 + sin x))dx Not sure if I'm doing this right: u= 2 + sin x du= 0 + cos x dx = S du/u = ln IuI + C = ln I 2 + sin x I + C = ln (2 + sin x) + C Another problem: S ((sin (ln x))/(x)) dx I

1. integral oo, oo [(2x)/(x^2+1)^2] dx 2. integral 0, pi/2 cot(theta) d(theta) (a) state why the integral is improper or involves improper integral (b) determine whether the integral converges or diverges converges? (c) evaluate the integral if it

Use the identity sin^2x+cos^2x=1 and the fact that sin^2x and cos^2x are mirror images in [0,pi/2], evaluate the integral from (0pi/2) of sin^2xdx. I know how to calculate the integral using another trig identity, but I'm confused about how to solve this

Use the identity sin^2x+cos^2x=1 and the fact that sin^2x and cos^2x are mirror images in [0,pi/2], evaluate the integral from (0pi/2) of sin^2xdx. I know how to calculate the integral using another trig identity, but I'm confused about how to solve this

Hello Everyone, I need help with Calc II. 1. Integral from 0 to 1 of (sin(3*pi*t))dt For this one, I got 1/3pi cos (9 pi^2) + 1/3pi 2. indefinite integral of sinxcos(cosx)dx I got sin(cosx) + C 3. Indefinite integral of x over (root (1x^4))dx I don't


Hi, could someone please help me with this hw question asap? Given that the integral of (e^x*sin(5x))dx=((e^x)/26)*(sin(5x)5cos(5x))+c, evaluate the integral from 1 to e^(pi/10) of sin(5ln(x))dx

Hello, I have some calculus homework that I can't seem to get started..at least not on the right track? I have 3 questions 1. integral of [(p^5)*(lnp)dp] I'm using the uvintegral v du formula So first, I'm finding u and I think it's lnp.......so du is 1/p

These questions are related to de moivre's theorem: z^n + 1/z^n = 2cosntheta z^n  1/z^n = 2 isin ntheta 1. Express sin^5theta in the form Asintheta + Bsin3theta + Csin5theta and hence find the integral of sin^5theta. 2. Express sin^6theta in multiples of

Integral of cos(x)*a^sin(x) + C dx = Integral of cos(x)*sin(x)^a + C dx = Let a be a fixed positive number. I'm clueless is to how to solve for a...

F(x) = cos(x) • the integral from 2 to x² + 1 of e^(u² +5)du Find F'(x). When i did this, i got: 2xsin(x)e^((x²+1)² + 5) But my teacher got: sin(x) • the integral from x² + 1 of e^(u² +5)du + 2xcos(x)e^((x²+1)² + 5) Do you know why the

Evaluate the definite integral. S b= sqrt(Pi) a= 0 xcos(x^2)dx I'm not sure if this is right? u= x^2 du= 2xdx du/2= xdx S (1/2)cos(u) S (1/2)*sin(x^2) [0.5 * sin(sqrt(Pi))^2]  [0.5 * sin(0)^2] 0  0 = 0, so zero is the answer?

Calculate the integrals if they converge. 10.) Integral from 1 to infinity of X/4+X^2 dx 14.) integral from Pi/2 to Pi/4 of Sin X / sqrt cos x dx 22.) integral from 0 to 1 of ln x/x dx I'm having problems with working these out to figure out if they

Evaluate the integral using any method: (Integral)sec^3x/tanx dx I started it out and got secx(1tan^2x)/tanx. I know I just have to continue simplifying and finding the integral, but I'm stuck on the next couple of steps. Also, I have another question

Generalize this to fine a formula for the integral: sin(ax)cos(bx)dx Could someone tell me what they got for an answer so I can check it to see if my answer is right. My answer: 1/2sinasinbx^21/3acosaxcosbx^3+ integral 1/3 a^2cosbx^3sinax..I'm not sure

find the area between the xaxis and the graph of the given function over the given interval: y = sqrt(9x^2) over [3,3] you need to do integration from 3 to 3. First you find the antiderivative when you find the antiderivative you plug in 3 to the


In the interval (0 is less than or equal to x which is less than or equal to 5), the graphs of y=cos(2x) and y=sin(3x) intersect four times. Let A, B, C, and D be the xcoordinates of these points so that 0<A<B<C<D<5. Which of the definite

1. Find the indefinite integral. Indefinite integral tan^3(pix/7)sec^2(pix/7)dx 2. Find the indefinite integral by making the substitution x=3tan(theta). Indefinite integral x*sqrt(9+x^2)dx 3. Find the indefinite integral. Indefinite integral

I need help with this integral. w= the integral from 0 to 5 24e^6t cos(2t) dt. i found the the integration in the integral table. (e^ax/a^2 + b^2) (a cos bx + b sin bx) im having trouble finishing the problem from here.

Identify u and du for the integral. 1. The integral of [(cosx)/(sin^(2)x)]dx 2. The integral of sec2xtan2xdx

Using an integration formula,what is the indefinite integral of (sign for integral)(cos(4x)+2x^2)(sin(4x)x)dx. Any help very much appreciated.

how do you start this problem: integral of xe^(2x) There are two ways: 1) Integration by parts. 2) Differentiation w.r.t. a suitably chosen parameter. Lets do 1) first. This is the "standard method", but it is often more tedious than 2) You first write

Here's my first question: (FIrst part courtesy of Count Iblis) Integral of x sqrt(19x7)dx ? Write the integral in terms of functins you do know the inegral of. Rewrite the factor of x as follows: x = 1/19 (19 x) = 1/19 (19 x  7 + 7) = 1/19 (19 x  7) +

Find the exact total of the areas bounded by the following functions: f(x) = sinx g(x) = cosx x = 0 x = 2pi I set my calculator to graph on the xaxis as a 2pi scale. The two functions appear to cross three times between x = 0 and 2pi. (including 2pi) Now,

can you help me get started on this integral by parts? 4 S sqrt(t) ln(t) dt 1 please help! thanks! Integral t^(1/2)Ln(t)dt = 2/3 t^(3/2)Ln(t) 2/3 Integral t^(1/2) dt = 2/3 t^(3/2)Ln(t)  4/9 t^(3/2) Simpler method: Integral t^(a)dt = t^(a+1)/(a+1)

1. Sketch the region of integration & reverse the order of integration. Double integral y dydz... 1st (top=1, bottom =0)... 2nd(inner) integral (top=cos(piex), bottom=(x2)... 2. Evaluate the integral by reversing the order of integration. double integral


d/dx integral from o to x of function cos(2*pi*x) du is first i do the integral and i find the derivative right. by the fundamental theorem of calculus, if there is an integral from o to x, don't i just plug the x in the function. the integral of the

If f(x) and g(x) are continuous on [a, b], which one of the following statements is true? ~the integral from a to b of the difference of f of x and g of x, dx equals the integral from a to b of f of x, dx minus the integral from a to b of g of x dx ~the

Find the Laplace transforms of the following functions. f1(t) = integral 0 from t (cos(ta)*(sin(a))da

Find the volume of the solid whose base is the region in the xyplane bounded by the given curves and whose crosssections perpendicular to the xaxis are (a) squares, (b) semicircles, and (c) equilateral triangles. for y=x^2, x=0, and y=0 (a) integral

Hello, I just wanted to verify if my work was good. Calculate the following integral by parts: ∫ upper limit is 1/5 and lower limit is 1/10. of 10sin^1 (5x)dx so first I named the variables: u = 10 sin^1 (5x) du = 50 / sqr(125x^2) dv = dx v = x so

find the derivative of the function integral from cosx to sinx (ln(8+3v)dv) y'(x)= (sin(8+3((sin(x)))+x)+sin(8+3sin(x)x))/2 Is this the right answer?????

I need to find the integral of e^(2x)sin(3x) I used integration by parts and I let u=e^2x and dv=sin(3x) My final answer was (3/8)(e^(2x))(cos(3x))  (1/8)(e^(2x))(sin(3x)) but it's wrong. Please help!!

d/dx integral from o to x of function cos(2*pi*x) du is first i do the integral and i find the derivative right. by the fundamental theorem of calculus, if there is an integral from o to x, don't i just plug the x in the function. the integral of the

A. Find the integral of the following function. Integral of (x√(x+1)) dx. B. Set up and evaluate the integral of (2√x) for the area of the surface generated by revolving the curve about the xaxis from 4 to 9. For part B of our question , the

Let f and g be the functions given by f(x)=1+sin(2x) and g(x)=e^(x/2). Let R be the shaded region in the first quadrant enclosed by the graphs of f and g. A. Find the the area of R. B. Find the value of z so that x=z cuts the solid R into two parts with


I am supposed to find the area of the region given two boundaries and two functions revolving about the x axis. x = 0 x = pi/2 y = cos(x/2) y = sin(x/2) Graphing those two functions made me select to use the washer method. Therefore, I set my definite

ok, i tried to do what you told me but i cant solve it for c because they cancel each others out! the integral for the first one i got is [sin(c)cos(x)cos(c)sin(x)+sin(x)+c] and the integral for the 2nd one i got is [sin(c)cos(x)+cos(c)sin(x)sin(x)+c] I

Evaluate the integral using method of integration by parts: (integral sign)(e^(2x))sin(5x)dx

Show that 0 <= [(integral)(integral, r to none)sin(pi)xcos(pi)y dA] <= 1/32 where R = [0,1/4]x[1/4]x[1,2]. Thank you.

Evaluate the definite Integral Integral [0 to pi/4] cos(2x)sec^2(pi/4 sin(2x))dx

integral of sin(x^2) dx i actually got the ans, but aftr differentiating the answer i am not getting back the question

Evaluate the indefinite integral. integral 2e^(2x)sin(e^2x) Note: Use an uppercase "C" for the constant of integration.

Evaluate the indefinite integral. integral of 8 sin^4 x cos x dx

S=integral sign S3x(4x^2)^1/2 use trig substitution I am confused I got x sin(sin^1(x/2))+cos(sin^1(x/2))

1.evaluate (integral sign)x cos 3x dx A.1/6 x^2 sin 3x + C B.1/3 x sin 3x 1/2 sin 3x +C C.1/3 x sin 3x +1/9 cos 3x +C << my choice. D. 1/2 x^2 +1/18 sin^2 3x +C 2.evaluate (integral sign)xe(power of 2x)dx A.1/6 x^2 e(to the power of 3x)+C B.1/2


Evaluate the indefinite integral. integral of 4e^(4x)sin[e^(4x)]dx

Evaluate the integral: 16csc(x) dx from pi/2 to pi (and determine if it is convergent or divergent). I know how to find the indefinite integral of csc(x) dx, but I do not know how to evaluate the improper integral, at the following particular step. I know

Use a comparison test to determine if the integral from 8 to infinity of sin^10(x)e^(x) converges or diverges? I am stuck on what to use to compare. Any help is appreciated! Thank you! I was thinking 1<sin<1 but then I get 1<sin^10<1 which

The prompt for this question is f(x) =sin(x^2) A)Write the first four terms of the Maclaurin series for f(x) B)Use the Maclaurin series found in Part A to approximate the integral from 0 to 1 of sin(x^2) dx C)How many terms are needed to find the value of

The prompt for this question is f(x) =sin(x^2) A)A. Write the first four terms of the Maclaurin series for f(x) B)Use the Maclaurin series found in Part A to approximate the integral from 0 to 1 of sin(x^2) dx C)C. How many terms are needed to find the

What is the following limit? lim as n goes to infinity of (pi/n) (sin(pi/n) + sin(2pi/n) + sin(3pi/n) +...+ sin(npi/n)) = I.) lim as n goes to infinity sigma (n and k=1) of pi/n sin(kpi/n) II.) Definite integral from 0 to pi of sin(x)dx III.) 2 A.) I only

Integrate the following: a. Integral from 0 to pi (sin^2)(3x)dx b. Integral of (x^2)/((x^2  4)^3/2)

What is the following limit? lim as n goes to infinity of (pi/n) (sin(pi/n) + sin(2pi/n) + sin(3pi/n) +...+ sin(npi/n)) = I.) lim as n goes to infinity sigma (n and k=1) of pi/n sin(kpi/n) II.) Definite integral from 0 to pi of sin(x)dx III.) 2 A.) I only

Find the integrals. (show steps) (integral sign) xe^(4x^2) I think this how is how its done: (integral sign) xe^(4x^2) it's a u du problem let u=4x^2 so, du=8x dx now you have an x already so all u need is 8 inside and and 1/8 outside the integral [1/8]

Evaluate the integral of (e^2x)*sin^3 x dx I let u = e^2x, du = (1/2)e^2x dx v= (1/3)cos^3 x , dv =sin^3 x dx When I used integration by parts and solved it all out I got: (37/36)intgral of (e^2x)*sin^3 x dx = (1/3)(e^2x)*cos^3 x + (1/18)(e^2x)*sin^3 x


What is the following limit? lim as n goes to infinity of (pi/n) (sin(pi/n) + sin(2pi/n) + sin(3pi/n) +...+ sin(npi/n)) = I.) lim as n goes to infinity sigma (n and k=1) of pi/n sin(kpi/n) II.) Definite integral from 0 to pi of sin(x)dx III.) 2 A.) I only

integrate: [ cos ^ 2 (x) * sin (x) / ( 1  sin(x) )]  sin (x)

Integrate (((cos^2(x)*sin(x)/(1sin(x)))sin(x))dx thanks

∫((cos^3(x)/(1sin^(2)) What is the derivative of that integral? I have been trying to use trig identities but can't find one to simplify this equation. I can't find one for (cos^3(x) or (1sin^(2)) My options sin(x) + C sin(x) + C (1/4)cos^(4)(x) +

The prompt for this question is f(x) =sin(x^2) A)Write the first four terms of the Maclaurin series for f(x) B)Use the Maclaurin series found in Part A to approximate the integral from 0 to 1 of sin(x^2) dx C)How many terms are needed to find the value of

what is the integral of {sin(x)tan(x)} i tried turning tan(x) into sin(x)/cos(x) then doing u substitutions but i always have an extra sin(x) left. can you help me pleeeease

calculate the indefinite integral 2sec^2x dx (cosx)/(sin^3x) dx calculate the definite integral interval pi/4, pi/12 csc2xcot2x dx

Evaluate the integral of (sin 2x)/(1+cos^2 x) 1. u=cosx and du=sinx *dx 2. evaluate the integral of 1/(1+u^2)*du 3. result is ln(1+u^2)+C Where did the sin2x dissapear too???

Find the area of the region bounded by y = x^2, y = 0, x = 1, and x = 2. I tried the integral from 1 to 2 of x^2 and got 3 as the answer. I tried (integral from 0 to 1 of √y + 1) + (integral from 0 to 4 of 2  √y) and got 13/3. What is wrong with the

I have 3 questions, and I cannot find method that actually solves them. 1) Integral [(4s+4)/([s^2+1]*([S1]^3))] 2) Integral [ 2*sqrt[(1+cosx)/2]] 3) Integral [ 20*(sec(x))^4 Thanks in advance.


I have 3 questions, and I cannot find method that actually solves them. 1) Integral [(4s+4)/([s^2+1]*([S1]^3))] 2) Integral [ 2*sqrt[(1+cosx)/2]] 3) Integral [ 20*(sec(x))^4 Thanks in advance.

(a) Find the indeﬁnite integrals of the following functions. (i) f (t) = 6 cos(3t) + 5e^−10t (ii) g(x) = 2112x^3/ x (x > 0) (iii) h(u) = cos^2( 1/8 u) (b) Evaluate: (this big F sign at the start, 5 at the top and 1 at the bottom) 5 1/4x (7

If f(x) and g(x) are continuous on [a, b], which one of the following statements is false? the integral from a to b of the sum of f of x and g of x, dx equals the integral from a to b of f of x, dx plus the integral from a to b of g of x dx the integral

LEt f and g be continous functions with the following properties i. g(x) = Af(x) where A is a constant ii. for the integral of 1 to 2 f(x)dx= the integral of 2 to 3 of g(x)dx iii. for the integral from 2 to 3 f(x)dx = 3A a find the integral from 1 to 3

LEt f and g be continous functions with the following properties i. g(x) = Af(x) where A is a constant ii. for the integral of 1 to 2 f(x)dx= the integral of 2 to 3 of g(x)dx iii. for the integral from 2 to 3 f(x)dx = 3A a find the integral from 1 to 3

LEt f and g be continous functions with the following properties i. g(x) = Af(x) where A is a constant ii. for the integral of 1 to 2 f(x)dx= the integral of 2 to 3 of g(x)dx iii. for the integral from 2 to 3 f(x)dx = 3A a find the integral from 1 to 3

Solve the equation for solutions in the interval 0<=theta<2pi Problem 1. 3cot^24csc=1 My attempt: 3(cos^2/sin^2)4/sin=1 3(cos^2/sin^2)  4sin/sin^2 = 1 3cos^2 4sin =sin^2 3cos^2(1cos^2) =4sin 4cos^2 1 =4sin Cos^2  sin=1/4 (1sin^2)  sin =1/4

I'm not sure how to solve this and help would be great! d/dx [definite integral from 0 to x of (2pi*u) du] is: a. 0 b. 1/2pi sin x c. sin(2pi x) d. cos (2pi x) e. 2pi cos (2pi x) This is the fundamental theorem, right? What's confusing me is the u and du

Evaulate: integral 3x (sinx/cos^4x) dx I think it's sec3 x , but that from using a piece of software, so you'll have to verify that. Using uppercase 's' for the integral sign we have S 3sin(x)/cos4dx or S cos4(x)*3sin(x)dx If you let u = cos(x) then du =

How do you integrate using substitution: the integral from 1 to 3 of: ((3x^2)+(2))/((x^3)+(2x)) There is a trick to this one that grealy simplifies the integral. Let u = x^3 + 2x. Then du = (3x^2 + 2)dx The integral then bemoces just the integral of du/u,


Posted by Paul on Friday, February 19, 2010 at 3:57am. I have the function f(x)=e^x*sinNx on the interval [0,1] where N is a positive integer. What does it mean describe the graph of the function when N={whatever integer}? And what happens to the graph and

∫ sin(x)sin(3x)dx find the integral

Find the integral of sin(x) cos(x)/sin^2(x)4 dx

How would I solve the following integral with the substitution rule? Integral of: [(x^3)*(1x^4)^5]dx Put 1x^4 = y Then 4x^3 dx = dy Integral is then becomes: Integral of 1/4 y^5 dy ok, thanks a lot! I got it now.

Using the identity: L{f(t)/t}=integral F(p)dp (s >infinity), find the integral of: sin(t)/t dt (0>infinity)

use te fundamental theorem of calculus to evaluate the integral Integral [0, pi/3] sin^2(x)dx I'm confused on what F(x) should be

integral of 2sin^3xcosx dx that is a sin cubed x. i think i use usubstituion, but im not quite sure how to do it. please help and thank you!

Differentiate (sin^3)x and use this result to evaluate the integral of sin^2 x cos x dx between pi/2 and 0. Thanks!

(integral) e^3x dx A. e^3x+C B. 1/3e^3x+C C. e^4x+C D. 1/4e^4x+C Evaluate (integral) dx/(Square root 98xx^2) A. sin^1(x+4/5)+C B. sin^1(x4/5)+C C. Ln(Square root 98xx^2)+C D. Ln(82x)+C

The problem tells us to approximate the integral using the midpoint rule. n=5, sin(x)2 dx 0 to 1. I understand that the answer is .2(sin(.1)^2 + sin(.3)^...). When I use my calculator to get the decimal answer, I cannot get the same answer the book has. I


integral of ((1+sin(2x))^0.5)/(sin(x)^2) I tried all kind of substitution, simplification but unable to solve it.Need a hint only no solution please.

Evaluate the integral of (x)cos(3x)dx A. (1/6)(x^2)(sin)(3x)+C B. (1/3)(x)(sin)(3x)(1/3)(sin)(3x)+C C. (1/3)(x)(sin)(3x)+(1/9)(cos)(3x)+C D. (1/2)(x^2)+(1/18)(sin)^2(3x)+C

Please can anyone help with the following problems  thanks. 1) Integrate X^4 e^x dx 2) Integrate Cos^5(x) dx 3) Integrate Cos^n(x) dx 4) Integrate e^(ax)Sinbx dx 5) Integrate 5xCos3x dx The standard way to solve most of these integrals is using partial

Use 2nd Fundamental Theorem of Calculus to find derivative of f(x) = integral of 2x^2 (at the top) to x5 (at the bottom) of square root of Sin(x)dx

a. Integral (x^2)/(sqrt(1+(x^2))) Would I separate these two into 2 separate integrals? Like: Integral of x^2 and the other integral of 1/sqrt(1+(x^2)) b. Integral (x^7)/(ln(x^4))dx Do I use integration by parts for this? I put u= lnx du = 1/x dv = x^7 v =