# Write the standard equation for the parabola with the given characteristics. vertex:(0,0) directrix:y= -1.

71,839 results
1. ## algebra 2

a quadratic equation can be written in vertex form or in standard form. sometimes one form is more beneficial than the other. identify which form would be more helpful if you needed to do each task listed below and explain why. a. factor the equation. b.

2. ## algebra 2

A quadratic equation can be written in vertex form or in standard form. Sometimes one form is more beneficial than the other. Identify which form would be more helpful if you needed to do each task listed below and explain why a. factor the equation b.

3. ## algebra

Suppose a parabola has a vertex (-4,7) and also passes through the point (-3,8) Write the equation of the parabola in vertex form. f(x)=a(x-h)^2+k I believe h=-4 k=7 Not sure what to do from here.

4. ## algebra

Can someone check my answers please and if Im wrong please explain. 1) graph 4x^2+4y^2=64. what are the domain and range? domain;all real numbers range;-4

5. ## algebra

A few more question Id like for someone to check please. 1) what are the vertex, focus, and directrix of the parabola with the given equation? x^2-8x-28y-124=0 vertex (4,-5) focus (0,7) directrix y=-12 2) write an equation of a circle with given center and

6. ## Algebra

Suppose a parabola has an axis of symmetry at x = -2, a minimum height at -6, and passes through the point (0, 10). Write the equation of the parabola in vertex form.

7. ## algebra

Suppose a parabola has vertex (-4,7) and also passes through the point (-3,8), write the equation of the parabola in vertex form.

8. ## Math

Write an equation in standard form for each parabola. Vertex (0, 0) and directrix y = 6. y = -1/24x^2?

9. ## algebra 2 pls help

A quadratic equation can be written in vertex form or in standard form. Sometimes one form is more beneficial than the other. Identify which form would be more helpful if you needed to do each task as listed below and explain why. a. Factor the equation b.

10. ## Math/Algebra

Find the vertex, Focus,and Directrix of the parabola. Graph the equation. y^2=12x

11. ## Algebra2

Write an equation of an ellipse in standard form with center at the origin and with the given vertex and co-vertex vertex at (-3,0) and co-vertex at (0.2)

12. ## precalculus

Find the equation of a Parabola with Vertex: (-2,4) and directrix: y=7

13. ## math

A parabola passes through the point (3, 5) on its way to the vertex at (7, 11). Determine the equation in vertex form that represents this parabola.

Write the equation for a parabola with a focus at (-6,0) and a directrix at x=-2 ***PLEASE SET AS "x="***

15. ## Algebra2

Write an equation of a parabola with a vertex at the origin and a directrix at y=-5. my answer is focus 6,0, directrix =-6

16. ## Geometry

Write an equation of an ellipse in standard form with the center at the origin and with the given characteristics: Vertex (-3,0) and co-vertex (0,2)

17. ## Algebra

A parabola can be drawn given a focus of (9, -2)(9,−2) and a directrix of x=3x=3. Write the equation of the parabola in any form.

18. ## Geometry

Can someone please help me with these? 1. What are the focus and directrix of the parabola with the equation y=1/12 xsquared 2. what is an equation of a parabola with a vertex at the origin and directrix y=19/4 3. What are the focus and directrix of the

19. ## College Algebra

Find the standard form of the equation of the parabola with the given characteristics and vertex at the origin. Passes through the point (-5, 1/8); vertical axis. There is no focus of the parabola or equation given, so how am I suppose to solve this

20. ## pre cal

What is the center of the conic whose equation is x^2 + 2y^2 - 6x + 8y = 0 2.Which one of the following equations represents a hyperbola? (5 points) A) 3x^2 + y^2 + 12x - 7 = 0 B) 3x^2 + 3y^2 + 12x - 7 = 0 C) 3x^2 + y + 12x - 7 = 0 D) 3x^2 - 3y^2 + 12x - 7

21. ## math

Write the equation for a parabola with a focus at (-3,-5)(−3,−5) and a directrix at x=-7

22. ## CAlculuss

Find, in standard form, the equation of : the parabola with focus at (3,5) and directrix at x=-1

23. ## calculus

write the vertex form equation of each parabola. 1) Vertex:(-5,8), Focus:(-21/4, 8) 2) Vertex:(-6,-9), Directrix: x= 47/8 3)Vertex(8,-1) y- intercept: -17 4) Open left or right, Vertex: (7, 6), passes through:(-11,9) 5)Focus(-63/8, -7), Directrix: x= -65/8

24. ## algebra

6. Find the equation of each parabola described below. a) parabola with vertex (0,0) and the focus (0,7) b) parabola with focus (-3,0) and directrix x=3 c) parabola with vertex (3,3) and directrix x=-1 d) parabola with focus (-2,-1) and directrix y=5 e)

25. ## MATH

a. Write an equation compared to the equation of the standard parabola that satisfies the description of each parabola. 1. A parabola whose vertex is (0, -3) 2. A parabola whose vertex is (5, 1) 3. A parabola that opens down and is compressed vertically by

26. ## Math

Find the vertex, focus, and directrix of the parabola. x^2 - 2x + 8y + 9 = 0 x^2 - 2x +1 = -8y + 9+ 1 (x-1)^2 = -8(y-1.25) vertex:(1,1.25) focus:(1,-.75) directrix: y=3.25

27. ## Algebra

The directrix of a parabola is y=9 . The focus of the parabola is (2,5) . What is the equation of the parabola? y=−1/8(x−2)^2+7 y=1/8(x−2)^2−7 y=1/8(x−2)^2+7 y=−1/8(x−2)^2−7

28. ## Math

Find the vertex, focus and directrix of the parabola. 4x - y^2 - 2y - 33 = 0 y^2+2y+1 = -4x+33+1 (y+1)^2 = -4(x+8.5) vertex:(-1,-8.5) focus:(-2,-8.5) Directrix: x=0 Is this correct?

29. ## Math

Find the vertex focus directrix and axis of symmetry of each parabola y²–8x–6y–3=0

30. ## maths

Given that the equation of the parabola is 5y^2 + 24x = 0. Find (1)The Axis and vertex of the parabola (ii)The focus and the directrix (iii)The distance from the directrix to the focus

31. ## College Algebra

Find the standard form of the equation of the parabola with the given characteristics and vertex at the origin. Passes through the point (-1, 1/8); vertical axis. There is no focus of the parabola or equation given, so how am I suppose to solve this

32. ## Algebra

Find an equation of a parabola with a vertex at the origin and directrix y= -4

33. ## precalculus

y=−3x2−4x+1 (a) Write the equation of the parabola in standard form (b) Identify the vertex of the parabola C)Is the vertex a minimum or a maximum? many thanks

34. ## Algebra 2

The equation of a parabola is 12y=(x-1)^2-48. Identify the vertex, focus, and directrix of the parabola.

35. ## precalculs

Explain what each of the following represents, and how equations (a) and (b) are equivalent. (a) y = a(x - h)2 + k, a ≠ 0 (b) (x - h)2 = 4p(y - k), p ≠ 0 (c) (y - k)2 = 4p(x - h), p ≠ 0 can you check my work and explain how equations (a) and (b) are

36. ## math

Find the vertex AND factored form equation for both situations 1) A parabola has vertex (-1, 3) and goes through point (2, 5). 2) Write the equation for the parabola with x-intercepts (0, 1) and (0, -3) and stretched by a factor 4.

37. ## pre cal

write the standard form equation of the parabola with vertex (-2,-2) that goes through point (-1,0) y= a (x-b)^2 + c b has to be -2, that gives the shift to the left. y=a( x+2)^2 + c when x=-2, y=-2, that makes c -2 y=a( x+2)^2 -2 finally, put the point

38. ## precalculus

.Find the standard form of the equation of the parabola with focus(8,-2) and directrix x=4

39. ## MATH! Urgent

umm suppose a parabola has a vertex at (0,2) and points (1,1) how would I derive the equation and focus, i've been trying to understand this for so long, I can't get it. Does this parabola have the equation (y-2)^2 = x and a focus of 1/4?? Is that

40. ## Math

Find the vertex, focus, and directrix of the parabola. x^2 - 2x + 8y + 9 = 0 x^2 - 2x +1 = -8y + 9+ 1 (x-1)^2 = -8(y-1.25) vertex:(1,1.25) focus:(1,-.75) directrix: y=3.25 My teacher said that I have sign errors. I do not know where I went wrong.

41. ## Algebra

The focus of a parabola is (0,−4) . The directrix of the parabola is the line y=−5 . What is the equation of the parabola? y=−1/4x^2+4 y=1/2x^2−9/2 y=−1/2x^2−9/2 y=1/4x^2−4

42. ## MATH PLS HELP

Write the equation of the parabola in vertex form. vertex (1, 3), point (2, -4) f(x)=

43. ## math

Find the standard form of the equation of the parabola with the given characteristics. Vertex: (-9, 8); directrix: x = -16

44. ## Pre Cal

write the equations of the parabola, the directrix, and the axis of symmetry. vertex: (-4,2) focus: (-4,6) if someone could explain how to do this problem then that would be great! thanks in advance! Formats to help you find the equation for a parabola: (x

45. ## precallcuslus

can you check my work and explain the last question because I do not uderstand. Explain what each of the following represents, and how y = a(x - h)2 + k, a ≠ 0 and (x - h)2 = 4p(y - k), p ≠ 0 are equivalent. The equation (x - h)2 = 4p(y - k), p ≠ 0

46. ## Math

Identify the equation of a parabola whose focus is at (5,-1) and whose directrix is x=3. vertex=(-5,-1) p=-6 4p=-24 (x-5)=(-24)(y+1)^2 I got it wrong

47. ## Algebra 1 parabola's

I have a graph with a parabola on it and asked to write the function for f(x) in standard form. I know that standard is y=ax^2+bx+c obviously, since the points are on the graph we know x and y so a,b and c need to be found. The vertex is on (4,-4) the

48. ## math

write an equation for the parabola with focus (1,3) and vetex (0,3) See the paragraph Analytic Geometry Equations. You will have a choice of equations, you did not state whether the axis of symettry was parallel to x or y axis.

49. ## Math

Write the equation of a parabola, in standard form, that goes through these points: (0, 3) (1, 4) (-1, -6) ax^2 + bx + c = y a * 0^2+b*0+c = 3 a*1^2+b+1+c = 4 a*(-1)^2+b(-1)+c = -6 c = 3 a + b + c = 4 a – b + c = -6 a + b + 3 = 4 a – b + 3 = -6 Graph

50. ## algebra II

Can you please help me with the these problems. 8.Write an equation in standard form of the parabola that has the same shape as the graph of f(x) = 11x^2, but which has its vertex at (2, 9). 10. Use the vertex and intercepts to sketch the graph of the

51. ## math

A parabola has the equation y = 4(x-3)^2-7 Choose 2 true statements: A) The parabola has a minimum value B) The parabola has a maximum value C) The parabola does not cross the y-axis D) The parabola does not cross the x-axis E) The vertex of the parabola

52. ## algebra 2

Find the vertex, focus, axis, directrix and latus rectum of the parabola x^2+ y = 6x - 14

53. ## math

Write the standard equation for the parabola with the given characteristics. vertex:(0,0) directrix:y= -1.

54. ## Algebra II

Write an equation for the parabola with focus (1,3) and vertex (0,3). I cannot find any example in my book that works a problem with the vertex, all of the examples that I have to go by give only the focus and directrix. Thanks.

55. ## Alg II/Trig

A parabola has a vertex at (0,0); a horizontal axis; and the point (12,6) is on the parabola. Write the equation of the parabola in standard form.

56. ## Math

determine vertex, focus and directrix of parabola. then graph the parabola. first equation: y^2 -2x-8=0 second equation: y^2 -4y -12x= 8 please show your work!

57. ## Math

determine vertex, focus and directrix of parabola. then graph the parabola. second equation: y^2 -4y -12x= 8

58. ## math

determine vertex, focus and directrix of parabola. then graph the parabola. first equation: y^2 -2x-8=0 second equation: y^2 -4y -12x= 8

59. ## Algebra

I am supposed to write the standard equation of the parabola with the directrix x=1, and the vertex 6,2. I got y-6=1/4p(x-2)^2. Is this correct? I am supposed to graph y+3=-1/12(x-1)^2. I tried to find p, and I got 36. I don't think this could be correct,

60. ## Math

determine vertex, focus and directrix of parabola. then graph the parabola. second equation: y^2 -4y -12x= 8 Please help me this is do 2day bc i forget to turn it in to my teacher

61. ## math

Write the equation in standard form, given the following information. vertex(-2,4), directrix y=1

62. ## Algebra

Find an equation of a parabola with a vertex at the origin and directrix y =–4

63. ## algebra 2

Directions: The focus and directrix of a parabola are given. Write an equation for each parabola. (2,4) y = 6 May you explain the procedures on how to solve this equation? Please be detailed on each step.

64. ## Pre-Calc

for the conic y=5x^2-40x+78 find an equation in standard form and its vertex, focus, and directrix

65. ## algebra

How would one write the equation of a parabola whose directrix is y=-6 and location of the focus is (-3,2)

66. ## Algebra 2

Point (-6,-2) lies on a parabola that has its vertex at (0,1). Write the equation of the parabola. Indicate whether the graph opens up or down.

67. ## algebra

A parabola has x-intercepts at 3 and 7, a y-intercept at -21, and (5,4) for its vertex. Write the parabola’s equation

68. ## Math 11

write the equation in vertex form, of a parabola with vertex (5, -1) and that passes through the point (6, 8)

69. ## Vertex, Focus, & Directrix of Parabolas

Find the Vertex, Focus, and Directrix of the parabola: x^2 -12x-48y+276=0 Thank you so much

41. Compare the parabola defined by each equation with the standard parabola defined by the equation y = x². Describe the corresponding transformations, and include the position of the vertex and the equation of the axis of symmetry. y = 3x² - 8 (4

71. ## Math Help

With the given information below, write the standard form equation for the parabola. 1.) Vertex: (-1,2) Focus(-1,0) 2.) Vertex: (-2,1) Directrix x=1

72. ## MATH

Write the equation of a parabola with a vertex at (-5, 2) and a directrix y = -1.

73. ## Honors Algebra 2

Write an equation in standard form of the parabola that has the characteristics below. Vertex at (1,-8); passing through the point (3,12) So I started the problem and now I'm stuck as of what to do next. Y=a(x-h)+k 12=a(3-1)^2-8 12=a(2)^2-8 12=4a-8 4=4a

74. ## Algebra

Can you please help me with the below question: The vertex of a parabola is located at (-12, -1). The parabola also passes through the point (-10, 5). Write the equation of this parabola in both vertex form and standard form. Vertex form: Standard form:

75. ## Pre-cal

Sketech the graph of the equation y^2+4y+2x+10=0. Identify the vertex, the focus and the equation for the directrix. Use the completing the square to put the equation into standard form as your first step. This is what I did. y^2 + 4y = -2x-10 y^2 + 4y + 4

76. ## Math

Write the standard form of the equation of the parabola whose directrix is x=-1 and whose focus is at (5,-2)? a) (y+2)^2 = 12(x+2) b) y-2 = 12(x+2) c) x+2 = 1/12(y+2)^2 d) x-2 = 1/12(y+2)^2 I get A and D? confused!

77. ## PreCalculas check

Write the equation of the parabola 1.Vertex(2,5) Focus(2,-3) 2.Directrix=x=3/4 Focus(5/4,-3) For 1. i got(x-2)^2=32(y-5)^2 For 2. i got y=8x^2-20x-61/60

78. ## PreCalculas

Write the equation of the parabola 1.Vertex(2,5) Focus(2,-3) 2.Directrix=x=3/4 Focus(5/4,-3) For 1. i got(x-2)^2=32(y-5)^2 For 2. i got y=8x^2-20x-61/60

79. ## Pre Cal Check

focus: (0,p) vertex: if not given, then it is assumed (0,0) Directrix: k+p or k-p, i'm not sure I think these are the general equations for the focus, vertex, and directrix of a parabola, but i'm not sure. could someone please check this? thanks.

80. ## mathematics

Find the equation of the parabola with the vertex at the origin and directrix y =5

81. ## algebra

1)What is the distance between the museum and sailing club.I cant post the graph or anything but I have my numbers right its 53 but I used the distance formula so its either 53 units or the square root of 53 units. 2)Write the equation of the parabola y=

82. ## Algebra

Can someone tell me if I am right? I need to find the equation of a parabola. I am not sure if this is the correct way or if I have the correct answer. Vertex at origin, focus is at (0,3) Equation of parabola vertex (0,0) focus (0,3) focus (h,k+p) (0,0+3)

83. ## Algebra

Write the standard form of the equation of the parabola whose vertex is 1,2 and passes through the point 0,0. The answer according to my book is 0=a(0-1)^2+2. But which 0 in the equation is the first 0 fromn (0,0) and which one is the second? Thanks!

84. ## math

A parabola has the equation y = 4(x-3)^2-7 Choose 2 true statements: A) The parabola has a minimum value B) The parabola has a maximum value C) The parabola does not cross the y-axis D) The parabola does not cross the x-axis E) The vertex of the parabola

85. ## Algebra2

A quadratic equation can be written in vertex form or in standard form. Sometimes one form is more beneficial than the other. Identify which form would be more helpful if you needed to do each task listed below and explain why. a- factor the equation b-

86. ## Precalc

i need help with this equation anything help will be greatly appreciated find the standard equation of a parabola with a focus (-2,0) directrix x=3

87. ## ALGEBRA 1

Please check for me.Without drawing the graph of the given equation determine (a)how many x-intercepts the parabola has (b)whether it vertex lies above, below or on the axis. 1. y=x^2-5x+6 I use the determinant sqrt b^2 -4ac (-5)^2-4(1)(6))=1 There are two

88. ## Math

Using the following information for the Vertex and Directrix, write the standard form equation for the parabola with what is given below. Vertex: (-2,1) Directrix: x=1

89. ## pre cal

find the standard form of the equation of a parabola with the vertex (0,0) and the directrix y=6 find the standard form of the equation of the ellipse with center (0,0) and foci at (+- 4square root 3, 0) and verticies (+-8,0)

90. ## pre calculus

Find the equation of a Parabola with Vertex: (2,-1) and directrix: x= -2

Identify the equation of a parabola whose focus is at (5,-1) and whose directrix is x=3. vertex=(-5,-1) p=-6 4p=-24 (x-5)=(-24)(y+1)^2 I got it wrong

92. ## math

the points (-9,0) and (19,0) lie on parabola. a.) determine an equation for its axis of symmetry: X=5 b.) the y-coordinate of the vertex is -28. determine an equation for the parabola in factored form. c.)write your equation in part b) in standard form.

93. ## algebra problem

I need to find the equation of a parabola. I am not sure if this is the correct way or if I have the correct answer. Vertex at origin, focus is at (0,3) Equation of parabola vertex (0,0) focus (0,3) focus (h,k+p) (0,0+3) y=0-3 directrix y=-3 a=(1/4)(p)

94. ## pre-cal

what is the vertex and directrix of the parabola y=-1/2x^2 + 10 - 46

95. ## math

hi i was wondering how would you find the equation of a parabola with it's vertex at -2,0, and with no directrix or focus given. the parobala opens toward the left. the two choices in my multiple choice answer sheet that sound the most logical would be

96. ## ALGEBRA 1

Please check for me.Without drawing the graph of the given equation determine (a)how many x-intercepts the parabola has (b)whether it vertex lies above, below or on the axis. 1. y=x^2-5x+6 I use the determinant sqrt b^2 -4ac (-5)^2-4(1)(6))=1 There are two

97. ## Math

Write an equation for the parabola with focus (0, 0) and directrix y = 1. I got -x^2 - 2y + 1, but how do I get it in the form y - k = 1/4p(x - h)^2?

98. ## precalculus

can you check my work I really do not understand. Find the standard form of the equation of the parabola with focus(8,-2) and directrix x=4. answer= (y+2)^2=-16(x-12/8)

99. ## maths

In case of parabola y= x^2-2x-3 Find: a)Vertex: b)Axis: c)Focus: d)Directrix: e)Latus Rectum:

100. ## Pre-Calculus

How do I solve these equations? I need to create an equation given the characteristics? I have to be able to graph a parabola but first I need help solving this. 1.Focus (1.5,1); opens right; directrix x=0.5 2.Focus (1,4);opens down; contains (-3,1)