# Verify the trigonometric identity: [(1–sin²x)/sin²x]–[(csc²x–1)/cos²x]= -tan²x I still can't figure this out.

15,314 results
1. ## Trigonometry

find sin2x, cos2x, and tan2x if sinx= -2/sqrt 5 and x terminates in quadrant III

pls. help: prove the identity sin2x+sin2y=2sin(x+y)cos(x-y)

Express sec2x in terms of tanx and secx I know you have to sec(2x) = 1/cos(2x) = 1/(cos²x - sin²x) But how do you split that. Like how to simplify that?

4. ## Trigonometry

Simplify the expression using trig identities: 1. (sin4x - cos4x)/(sin2x -cos2x) 2. (sinx(cotx)+cosx)/(2cotx)

Which of the following are identities? Check all that apply. (Points : 2) sin2x = 1 - cos2x sin2x - cos2x = 1 tan2x = 1 + sec2x cot2x = csc2x - 1 Question 4. 4. Which of the following equations are identities? Check all that apply. (Points : 2) Question 5.

6. ## pre-calculus

tanx= -12/5 x in quadrant 2 find; sin2x= cos2x= tan2x=

7. ## dai so

chung minh dang thuc (1+Sin2x)/Cos2x=Tan(pi/4+x)

8. ## trigonometry

if sin2x=3sin2y, prove that: 2tan(x-y)=tan(x+y) ( here, in sin2x, 2x is an angle., like there's a formula:sin2x=2sinxcosx and sin2y=2sinycosy; ....)

9. ## Math

Solve the equation 2cos2x = √3 for 0°≤x≤360° I did this: cos2x = √3 /2 2x=30 x=15 x=15, 165, 195, 345 Is this correct? Solve the equation √3 sin2x + cos2x = 0 for -π≤x≤π No idea how to approach this one Thanks a bunch for the help!

10. ## trig

sinx = 4/5 and x terminates in Quadrant II Find sin2x and cos2x How to get the answers, which are sin2x = -24/25, cos2x = -7/25?

11. ## Pre-Calc Help!!!!!!!!

1+sin2x/sin2x=1+1/2(secx)(cscx)

12. ## trigonometry

Prove cotx-1/cotx+1=1-sin2x/cos2x

13. ## trigonometry

1-tanx/1+tanx=1-sin2x/cos2x

14. ## math

sin2x-cotx = -cotxcos2x Using the various trigonometric identities(i.e. double angle formulas, power reducing formulas, half angle formulas, quotient identities, etc.) verify the identity. I first added cotx to both sides to get sin2x = -cotxcos2x+cotx

15. ## trig

secx = 4 in Q2 find sin2x,cos2x,tan2x

16. ## PreCalculus

Sin5x cos2x + cos5x sin2x=

17. ## Trigonometry

Prove: 1-tanx/1+tanx=1-sin2x/cos2x

18. ## trig

Verify the trigonometric identity: [(1–sin²x)/sin²x]–[(csc²x–1)/cos²x]= -tan²x I still can't figure this out.

19. ## Pre-Calc/Math

Prove Identity: (1-cos2x/ tan x) = sin2x

20. ## Trig

Verify the identity: tanx(cos2x) = sin2x - tanx Left Side = (sinx/cosx)(2cos^2 x -1) =sinx(2cos^2 x - 1)/cosx Right Side = 2sinx cosx - sinx/cosx =(2sinxcos^2 x - sinx)/cosx =sinx(2cos^2 x -1)/cosx = L.S. Q.E.D.

21. ## Pre-calculus

prove the identity sin2x-sin2y/sin2x+sin2y=tan(x-y)/tan(x+y)

22. ## trigonometry

Been trying this forever so it says: Simplify 1+sin2x+cos2x/1+sin2x-cos2x ive tried this problem so many times I need help with it...

23. ## Trig

help please!: (sinx + sin2x +sin3x) / (cosx + cos2x + cos3x) = tan2x

24. ## Calculus

How do you find the derivative of f(x)=sin2x/cos2x

25. ## math

Prove the identity: 1-cos2x/sin2x = 1+tanx/1+cotx I simplified the RS to tanx. LS:(1-2cos²x+1)/2sinxcosx (2+2cos²x)/2sinxcosx How do I simplify the rest?

26. ## trig

tanx = 5/12 and sinx

27. ## Calculus

Evaluate using integration by parts, substitution, or both if necessary. the intergral of cos 2x ln(sin 2x) dx My work: w= sin2x dw= 2cos2xdx 1/2 dw= cos2xdx 1/2 integrsl sign ln(w)dw u= lnw u'= 1/w v= w v'=1 1/2 [(lnw)(w)- integral sign (1/w)(w) dw] 1/2

28. ## Precalculus

Determine the solutions to the equation 2sinx − cos2x = sin2x for 0 ≤ x ≤ 2π . How do I start this question?

29. ## trig

Use the double angle formula to verify the identity cotxsin2x=1+cos2x

30. ## Trig

Prove the following functions: (sinx+sin2x)/(1+cosx+cos2x)=tan x (cos3x/sinx)+(sin3x/cosx)=2cot2x tan2x=(2/cotx-tanx) theses are due in the am. Fastness would be great?

31. ## MATH

veify that each equation is an identity cos2x+tan2xcos2x=1 sin4x-cos4x/sin2x=1-cot2x

32. ## math

d2y/dx2+9y=cos2x+sin2x

33. ## trig

Which expression is equivalent to tan(-x)cos^2x? -sin xcos x sin xcos x tan x + sin2x tan x − sin2x -tan x − sin2x

34. ## Identities

Verify the following identity cos2x/sin2x+sinx/cosx=csc2x

35. ## math

Short Answer: Type your answer below each question. Show your work. 1 Verify the identity. Show your work. cot θ ∙ sec θ = csc θ 2 A gas company has the following rate schedule for natural gas usage in single-family residences: Monthly service charge

solve for (

37. ## MATH

Simplify: Sin2x/1-Cos2x

38. ## Calc

Verify that the trigonometric equation is an identity. 1/2 sin 2 x − sin^2x over sinxcos2x = 1 over sinx+cosx Verify that the trigonometric equation is an identity. cotx over 1-sinx =secx(cscx+1) Can someone please Help!!! these are so hard for me to

39. ## Pre-Calculus

Verify the following identity: (sin2x)/sin - (cos2x)/cosx=secx

40. ## calculus

find sin2x, cos2x, and tan2x if sinx= -1/sqrt 5 and x terminates in quadrant II

41. ## Trigonometry

Solve the trigonometric equations. 1.) SIN²x(CSC²x-1) 2.) COT x SEC X 3.) COS²[(π/2)-x]/COS X (Note: These mathematical problems are somewhat tricky, but useful for students as of learning how to their fundamental identities. Let's enjoy solving these

42. ## Calculus

Find the derivative of y with respect to x: y=(1+cos²x)^6 y'=6(1+cos²x)^5 How do you derive inside the brackets? The answer says -sin2x, but wouldn't it be -2sinx, using the chain rule.

43. ## calculus

d/dx(e^sinx2x)= a)-cos2xe^sinx2x b)cosxe^sin2x c)2e^sin2x d)2cos2xe^sin2x e)-2cos2xe^sin2x

44. ## Math

prove identity Sin2x - sinx/cosx + cos2x= sinx/cosx + 1

45. ## Math

simplify (cos4x-cos2x)/(sin4x+sin2x) the answer choices are : cotx, tanx, cotxtanx, or 1

46. ## trig

I need HELP Verify the identity Cot3X/CSCX=cosX(csc2X-1)

47. ## trig

Solve the triginometric equation analytically. Use values of x for 0 less then or equal to x less then 2pi The equation for this question is sin2x + cos2x = 0

48. ## Maths

Prove that sin2x+cos2x-1/sin2x+cos2x+1=tanx

49. ## trig

write sin4xcos2 as the sum or difference of two functions. answers: 1/2(cos6x+cos2x), 1/2(cos2x-cos6x), 1/2(sin6x+sin2x), sin6x-sin2x

50. ## trig

write sin4xcos2 as the sum or difference of two functions. answers: 1/2(cos6x+cos2x), 1/2(cos2x-cos6x), 1/2(sin6x+sin2x), sin6x-sin2x

51. ## Trigonometry

Verify the identities. 1.) √1-COSθ/1+COSθ= 1+SINθ/SINθ 2.) SEC X SIN(π/2-X)= 1 3.) CSC X(CSC X-SIN X)+SIN X-COS X/SIN X + COT X= CSC²X 4.) CSC^4 X-2 CSC²X+1= COT^4 X 5.) CSC^4 θ-COT^4 θ= 2 CSC²θ-1 6.) TAN^5 X= TAN³X SEC²X-TAN³X 7.) COS³X

52. ## Math

Required to Prove the following trig identity: (cos2x)^2 + (sin2x)^2 = 1

53. ## Calculus II

How does one obtain cos2x = cos^2(x) - sin^2(x) by differentiating the identity sin2x = 2sinxcosx

54. ## Trigonometry

Verify the identities algebraically. 1.) TAN^5 X= TAN³X SEC²X-TAN³X 2.) COS³X SIN²X= (SIN²X-SIN^4X)COS X

How do I verify this identity? (I've tried a lot but it's just not working) (sin2x + sin2y) = 2sin(x+y)cos(x-y)

56. ## Math

prove sin2x+cos2x+1 tan(pi/4+x) ______________ = __________ sin2x+cos2x-1 tanx so what I did tan(x) (1+cos(2x)+sin(2x)=tan(pi/4+x) (-1+cos(2x)+sin(2x)

57. ## math

what does sin2x/cos2x equal to?

58. ## MATH

Simplify: Sin2x/1-Cos2x

59. ## maths

d2y/dx2+9y=cos2x+sin2x

61. ## Maths

if a=cos2x + sin2x and b=cos2y + isin2y.then find (a + b)

62. ## trig identites

since sin2x+√3cos2x=2sin(2x+60) find the general solution for the equation sin2x+√3cosx=0 thank you

63. ## Math (Trig)

Rewrite the following expression in terms of tan3x: (sin2x + sin4x)/(cos2x + cos4x)

64. ## calculus

f(x)= 1/4 * (sin2x)^2 find dy/dx d/dx (1/4 * (sin2x)^2)= (sin2xcos2x)/ 2 ?

65. ## math

Solve sin2x + sin4x = cos2x + cos 4x for x in the interval[0,2pi) Hint: the following substitution should come in handy: sin3x= cos3x . tan3x

solve algebreically the equation cos2x=1-sinx also cosx=cosx-1 and please also sin2x=3sinx

67. ## Trigonometry

Let's solve this fun trigonometric fun math problem! 1.) SEC²X-1/SIN²X

68. ## trig

Verify the trigonometric identity: [(1–sin²x)/sin²x]–[(csc²x–1)/cos²x]= -tan²x I can't figure this out.

69. ## pre-cal

find all solutions in interval [0,2pi] tan²x = -3/2 secx This question may look tricky, but its actually quite simple. First: rearrange the pythagorean identity tan²x+1=sin²x so that it reads tan²x=sin²x-1 Then replace the tan²x in the original

70. ## Calculus

Solve identity, (1-sin2x)/cos2x = cos2x/(1+sin2x) I tried starting from the right side, RS: =(cos²x-sin²x)/(1+2sinxcosx) =(cos²x-(1-cos²x))/(1+2sinxcosx) and the right side just goes in circle. May I get a hint to start off?

71. ## math

sin2x − cos2x − tan2x = 2sin2x − 2sin4x − 1/ 1 − sin2x for x = 45

72. ## Trigonometry

Verify the identity. sin2x/cosx + sinx = 2sinx Solve for all values of x: 6cos2x-7cosx-3=0 If f(x)=cos1/2x-sin2x find the value of f(pi)

73. ## pre-calc

tanx= -12/5 x in Q 2. find sin2x= cos2x= tan2x=

74. ## calc

Where do I start to prove this identity: sinx/cosx= 1-cos2x/sin2x please help!! Hint: Fractions are evil. Get rid of them. Well, cos2x = cos2x - sin2x, so 1-coscx = 1 - cos2x - sin2x = 1 - cos2x + sin2x You should be able to simplify this to 2*something

75. ## Trig help

Can someone help me find ALL solutions in the interval [0,2π) for the given equations. Please show work. 1) sin2x = sin2x 2) tan2x +tanx = 0

76. ## precalc

How do i verify: cotx = (sin2x)/(1-cos2x)

77. ## maths

prove that 1+sin2x-cos2x / sin2x+cos2x = tanx

78. ## trig

write sin4xcos2 as the sum or difference of two functions. answers: 1/2(cos6x+cos2x), 1/2(cos2x-cos6x), 1/2(sin6x+sin2x), sin6x-sin2x

79. ## Pre Calculus

Establish the following identity Sin2x/1+cos2x=tanx

80. ## Math

How do you prove this identity? cos2x*tan(π\4-x)= 1-sin2x

81. ## Trigonometry

I can't remember what formula to use for these. Note- the X's may be replaced by a theta symbol. I just didn't have one on my keyboard. Use the given information to find sin2X, cos2X and tan2X if 0< X

82. ## trig

cotx = -2 and 0 less than or equal to x less than or equal to pi Find sin2x and cos2x How to get the answers of sin2x = -4/5, cos2x = 3/5?

83. ## gr 12. advanced functions

Trig identity Prove: cos2x tan(pie/4 - x) ------- = 1 + sin2x

84. ## math

Short Answer: Type your answer below each question. Show your work. 1 Verify the identity. Show your work. cot θ ∙ sec θ = csc θ 2 A gas company has the following rate schedule for natural gas usage in single-family residences: Monthly service charge

Solve the equation of the interval (0, 2pi) cosx=sinx I squared both sides to get :cos²x=sin²x Then using tri indentites I came up with cos²x=1-cos²x Ended up with 2cos²x=1 Would the answer be cos²x=1/2???

86. ## Pre calc

Please help me proof the identity. This isn't even math to me, I can not understand it so please show all work. God bless A)1-cos2x/sin2x=tanx B) sin4x/sinx=4cosxcos2x

87. ## math

solve for all real# sin2x(csc2x-2)=0

88. ## math

I have to find an exact solutions on the interval [0,pi) for both of these problems-- 1) 2sin2x = sqrtx and 2) 1-2sqrt2 sinxcosx = 0 I know this much: 1) sin2x = (sqrt x)/2 = 2sinxcosx = (sqrt x)/2 What do I need to do next? 2) 1/(2 sqrt2) = sinxcosx =

Sin2x+cos2x

90. ## MATH

Sin2x/1-Cos2x

91. ## physics

1)if y=e^x . cot x then dy/dx will be 2) f(x)=sin²x-cos²x then the value of f' (π/4)

92. ## calculus

Solve for x on the interval (0, 2pi] (sin2x + cos2x)^2 = 1

93. ## pre-calc

is x=15 degrees a solution of radical 3/3 cos2x+sin2x=0

Determine the derivative of the function (² = square): a) y = (x² + x - 1)Sin²x b) y = (x² + 1)/Sin²x

95. ## Calc

First make an appropriate substitution and then use integration by parts to evaluate the indefinite integrals: ∫ sinx cos³x e^(1-sin²x) dx I was going to substitute u= 1 - sin²x, but then i got du = ½ sinxcosx - ½ xdx, so im stuck. Thank you so

96. ## trig

(sec6x+sin2x)/(sin6x-sin2x)=tan4xcot2x

97. ## Trigonometry

How do I find all solutions in the interval [0,2Pi): sin2x=cos2x answer choices are: a.)Pi/8 b.) Pi/8, 5Pi/8, 9Pi/8, 13Pi/8

98. ## PreCalculus

Find all solutions to the given trigonometric equation in the interval 0, 2𝜋 : sin2x=cos2xsinx

99. ## Pre-Calculus

Find all solutions to the given trigonometric equation in the interval 0, 2𝜋 : sin2x=cos2xsinx

100. ## math

Prove the identity (sinx+cosx)^2 = 1+sin2x Thank you