
Use implicit differentiation to find the equation of the tangent line to the curve xy^3+2xy=9 at the point (31). The equation of this tangent line can be written in the form y=mx+b where m is

Use implicit differentiation to find the equation of the tangent line to the curve xy^3+xy=5 at the point (4,1) . The equation of this tangent line can be written in the form y = mx+b where m is:? and where b is:?

Use implicit differentiation to find the slope of the tangent line to the curve y/x+6y=x^2–6 at the point (1,–5/31) . Again i think i'm messing up with the algebra here. I used quotient rule to get [(x+6y)(y')(y)(1+6y')]/(x+6y)^2=2x I don't know how

Use implicit differentiation to find the equation of the tangent line to the curve xy3+xy=14 at the point (7,1) . The equation of this tangent line can be written in the form y=mx+b i don't seem to no how to find m or b

Use implicit differentiation to find an equation of the tangent line to the curve at the given point x^2 + xy + y^2 = 3, (1,1)


I am unsure of how to take the derivative of this equation. It may be the exponents that are giving me trouble but I'm not sure exactly. Find the equation of the tangent line to the curve 4e^xy = 2x + y at point (0,4). On the left side, is the "xy" the

Use implicit differentiation to find an equation of the tangent line to the curve y^2 = x^3 (26 − x) at the point (1, 5).

use implicit differentiation to find an equation of the tangent line to the curve at the given point. 9x^2+xy+9y^2=19, (1,1) (ellipse)

Use implicit differentiation to find an equation of the tangent line to the curve y^2 = x^3 (26 − x) at the point (1, 5).

use implicit differentiation to find the slope of the tangent line to the curve of x^2/3+y^2/3=4 at the point (1,3sqrt3)

Use implicit differentiation to find an equation of the tangent line to the curve at the given point. x^2/3 +y^2/3 =4 (3sqrt(3),1) (astroid)

Use implicit differentiation to find an equation of the tangent line to the curve 3xy^3+4xy=63 at the point (9,1)(9,1).

Use implicit differentiation to find an equation of the tangent line to the curve at the given point. x^2+y^2=(2x^2+4y^2−x)^2 (0, 0.25) (cardioid)

Use implicit differentiation to find an equation of the tangent line to the curve at the given point. x^2+2xyy^2+x=6 , (2,4) (hyperbola)

Use implicit differentiation to find an equation of the tangent line to the curve at the given point. x2 + 2xy − y2 + x = 17, (3, 5) (hyperbola)


Use implicit differentiation to find the slope of the tangent line to the curve at the point (4,1) 1x^2  4xy + 3y^3 = 29 I differentiated both sides and solved for dy/dx and got 2x4y/9y^24x. Then I plugged in X and Y and got 4/7 but when i enter my

Alright so implicit differentiation is just not working out for me. Use implicit differentiation to find the slope of the tangent line to the curve at point (4,1). y / (x2y) = x^3 + 4 Tried quotient rule to get the derivative of the left side, then got

Write the equation of the line tangent to the curve x^2 − 4y^2 + 192 = 0 at (8, 8) Thank You

Use implicit differentiation to find an equation of the tangent line to the curve at the given point x^2+2xy+4y^2=12. Point (2,1). (Eclipse)

Use implicit differentiation to find the slope of the tangent line to the curve 2(x^2) + 2xy + 2(y^3)= 18

use implicit differentiation to find the slope of the tangent line to the curve (y)/(x7y)=x^6+5 at the point (1,6/43)

Use implicit differentiation to find the slope of the tangent line to the curve y/( x + 4 y) = x^4 – 4 at the point (1,3/13)

Use implicit differentiation to find the slope of the tangent line to the curve y/( x + 4 y) = x^4 – 4 at the point (1,3/13)

(y/(x+9y))= (x^2)7 at the point (1, 6/55) Use implicit differentiation to find the slope of the tangent line to the curve

Use implicit differentiation to find the slope of the tangent line to the curve XY^3 + XY = 5 at the point (3,2) .


Use implicit differentiation to find the slope of the tangent line to the curve (y/x+8y)=x^8 +9 at the point (1,10/79).

use implicit differentiation to find the slope of the tangent line to the curve (y)/(x7y)=x^6+5 at the point (1,6/43)

use implicit differentiation to find the slope of the tangent line to the curve of x^2/3+y^2/3=4 at the point (1,3sqrt3)

Use implicit differentiation to find the slope of the tangent line to the curve –2x^2–2xy–1y^3=–3 at the point (–1–1).

implicit differentiation Find the slope of the tangent line to the curve xy^3 + 2y  0.76 =0 at the point (3, o.7) I'm lost. so 3xy^2 * y' + 2y = 0 right?

find the equation of the tangent to the curve 3xy^2 4+2y=29 at the point (1,3)using implicit differentiation.

Use implicit differentiation to find the slope of the tangent line to the curve at the point (1,3) 4x^2+4xy2y^3=46 m=____? ty guys so much!

Use implicit differentiation to find the slope of the tangent line to the curve y/(x–9y)=x^6–2 at the point (1,1/8). Can someone please help me? I don't understand

a)The curve with equation: 2y^3 + y^2  y^5 = x^4  2x^3 + x^2 has been linked to a bouncing wagon. Use a computer algebra system to graph this curve and discover why. b)At how many points does this curve have horizontal tangent lines? Find the

Given that x²cos ysin y=0 ,(0,π): a)verfiy that given point is on the curve. b)use implicit differentiation to find the slope of the above curve at the given point. c)find the equation for tangent and normal to the curve at that point.


Use implicit differentiation to find the slope of the tangent line to the curve sqrt of x + sqrt of y = 8

using implicit differentiation find the equation of the tangent line to the graph of the following function at the indicated point x^2 y^3 y^2+xy1=0 at (1,1)

Use implicit differentiation to find an equation of the tangent line to the cardioid at the point (0,0.5) x^2+y^2=(2x^2+2y^2x)^2 Y=

Use implicit differentiation to find an equation of the tangent line to the cardioid at the point (0, 0.5). x^2 + y^2 = (2x^2 + 2y^2  x)^2

Use implicit differentiation to find an equation of the tangent line to the graph at the given point. x + y − 1 = ln(x^5 + y^5), (1, 0)

If ln(x^215y)=x5+5 and y(4)=1 find Y prime(4) by implicit differentiation thus the equation of the tangent line to the graph at the point (4,1) is y=

Regard y as independent variable and x as dependant variable and find the slope of the tangent line to the curve (4x^2 + 2y2)^2  x^2y = 4588 at point (3,4). Correct answer is 0.668827160493827 Here's what I did: 2(8x(dy/dx) + 4y) 2x(dx/dy)y + x^2 = 0

Find the slope of the tangent line to the curve (a lemniscate) 2(x^2+y^2)^2=25(x^2–y^2) at the point (–3,1) . I know that we are supposed to use chain rule for this problem but i think i am messing up on the algebra. Can someone please help me, i keep

Please help this is due tomorrow and I don't know how to Ive missed a lot of school sick Consider the curve given by the equation x^3+3xy^2+y^3=1 a.Find dy/dx b. Write an equation for the tangent line to the curve when x = 0. c. Write an equation for the

Could someone please help me with these tangent line problems? 1) Find the equation of the line tangent to the given curve at the indicated point: 3y^3 + 2x^2 = 5 at a point in the first quadrant where y=1. 2) Show that there is no point on the graph of


Use implicit differentiation to find the slope of the tangent line to the curve y/(x2y) = y^3 +9 (1,10/21) ive done this problem around 10 times and i still cant get it.... when i did it the last time i got 9y^3/ 3y^2 x  8y^3  19 and the slope around

Use implicit differentiation to find the slope of the tangent line to the curve y/(x2y) = y^3 +9 (1,10/21) ive done this problem around 10 times and i still cant get it.... when i did it the last time i got 9y^3/ 3y^2 x  8y^3  19 and the slope around

1 A particle is moving in a stright line with the position at any time t is given by s= t³–9t²+3t+1,where s in meters and t in second. Find its position and acceleration when velocity is ¯24m/s 2. Given that x²cos y_sin y=0,(0,π). A. Verify that the

Use implicit differentiation to write the slopeintercept equation of the tangent line to the graph of (x^2+4)y=8 at the point (2,1):

The equation of the line tangent to (x^2+y^2)^4=16x^2y^2 at (x,y)=(−1,1) is ay = bx + c, where a, b and c are positive integers. What is the value of a+b+c?

Use implicit differentiation to write the slopeintercept equation of the tangent line to the graph of (x^2+4)y=8 at the point (2,1):

Consider the implicit equation 2xy1=(x+y+1)^2 a) Compute and solve for the derivative dy/dx as a function of x and y. b) Find the equation of the tangent line to the graph of the above when y=1. For part a, I found the derivative being equal (x+1)/(y+1)

Sorry but I've got a lot of problems that I don't understand. 1) Let f(x)= (3x1)e^x. For which value of x is the slope of the tangent line to f positive? Negative? Zero? 2) Find an equation of the tangent line to the oven curve at the specified point.

Use implicit differentiation to find the slope of the tangent line to the curve y/(x+7y)=x^5+7 at the point (1,(8/55). can anyone help me work out the problem step by step? y (x+7y)1 = x5 +7 dy(x+7y)1y((x+7y)2*(dx +7dy)=5x4 multiply it out, gather the

Use implicit differentiation to find the slope of the tangent line to the graph of 18*x^(1/2)+5y^(1/2)+14 at(81/324,1)


If F(x)=x^3−7x+5, use the limit definition of the derivative to find FŒ(5), then find an equation of the tangent line to the curve y=x^3−7x+5 at the point (5, 95). FŒ(5)= The equation of the tangent line is y = x + . Check your answer for

How do I find the normals to the curve xy+ 2x  y = 0 that are parallel to the line 2x + y = 0

original curve: 2y^3+6(x^2)y12x^2+6y=1 dy/dx=(4x2xy)/(x^2+y^2+1) a) write an equation of each horizontal tangent line to the curve b) the line through the origin with the slope .1 is tangent to the curve at P. Find x and y of point P.

original curve: 2y^3+6(x^2)y12x^2+6y=1 dy/dx=(4x2xy)/(x^2+y^2+1) a) write an equation of each horizontal tangent line to the curve b) the line through the origin with the slope .1 is tangent to the curve at P. Find x and y of point P.

. Given that x²cos y_sin y=0,(0,π). A. Verify that the given points on the curve. B.use implicit differention to find the slope of the above curve at the given point. C.find the equation of tangent and normal to the curve at that.

I do not understand implicit differentiation. One of the problems are: find y' by implicit differentiation xy+2x+3x^2=4. I would appreciate any help that can be offered.

I do not understand implicit differentiation. One of the problems are: find y' by implicit differentiation xy+2x+3x^2=4. I would appreciate any help that can be offered.

Find the slope of the tangent line to the curve √(1x+2y) + √(1xy) = 8.24 at the point (2,8)? I know you have to use implicit differentiation, but the radicals keep making me mess up algebraically. Is the changing the radicals to exponents the

The line has equation y=2x+c and a curve has equation y=82xx^2. 1) for the case where the line is a tangent to the curve, find the value of the constant c. 2) For the case where c = 11, find the xcoordinates of the points of intersection of the line and

Linear approximation: Consider the curve defined by 8x^2 + 5xy + y^3 = 149 a. find dy/dx b. write an equation for the tangent line to the curve at the point (4,1) c. There is a number k so that the point (4.2,k) is on the curve. Using the tangent line


Consider the curve defined by 2y^3+6X^2(y) 12x^2 +6y=1 . a. Show that dy/dx= (4x2xy)/(x^2+y^2+1) b. Write an equation of each horizontal tangent line to the curve. c. The line through the origin with slope 1 is tangent to the curve at point P. Find the

Find the equation of the tangent to the curve y=1/2x^24x3at the point where the curve intersects the yaxis.

original curve: 2y^3+6(x^2)y12x^2+6y=1 dy/dx=(4x2xy)/(x^2+y^2+1) a) write an equation of each horizontal tangent line to the curve b) the line through the origin with the slope .1 is tangent to the curve at P. Find x and y of point P. when plugging y as

Find the slope of the tangent line to the curve at (2,1). x/y +x^2y^2=6

sketch the curve using the parametric equation to plot the points. use an arrow to indicate the direction the curve is traced as t increases. Find the lenghth of the curve for o<t<1. Find an equation for the line tangent to the curve at the point

for the parametric curve defined by x=32t^2 and y=52t ...sketch the curve using the parametric equation to plot of the point. use an arrow to indicate the direction of the curve for o<t<1. Find an equation for the line tangent to the curve at the

How do you use imlicit differentiation to differentiate e^(xy)? I have the problem "use implicit differentiation to find dy/dx. e^(xy)+ x^2  y^2 = 10. I've gotten to the point whereI have d/dx(e^(xy)) + 2x  2ydy/dx = 0, but I can't go any further because

Consider the curve given by y^2 = 2+xy (a) show that dy/dx= y/(2yx) (b) Find all points (x,y) on the curve where the line tangent to the curve has slope 1/2. (c) Show that there are now points (x,y) on the curve where the line tangent to the curve is

Write the equation of lines tangent and normal to the following function at (0, π). To find derivative, use implicit differentiation. x^2cos^y  siny = 0

Find the area of the region bounded by the parabola y=x^2, the tangent line to this parabola at (1,1) and the xaxis. I don't really get what this question is asking. It looks like the area of right triangle to me...try the graph, and shade the area under


find an equation of the tangent line to the curve at the given point. graph the curve and the tangent line y=x/x1 at (2,2) )

Find the coordinates of a point on the curve y=6x^2 at which the tangent of the curve at the point is perpendicular to the line y=1/4x+1.

given the equation of the curve as y=82x^2 (a) find equations of tangent and the normal to this curve at the point where x=a. (b) find the value of a for which this tangent is parallel to the line with equation 3xy+6=0

Suppose f(x)=5/(x2). f'(5)=5/9. Use this to find the equation of the tangent line to the curve y=5/x2 at the point (5,(5/3)). write your answer in the form y=mx+b where m is the slope and b is the yintercept. The equation of the tangent line is.....

the curve: (x)(y^2)(x^3)(y)=6 (dy/dx)=(3(x^2)y(y^2))/(2xy(x^3)) a) find all points on the curve whose xcoordinate is 1 and write an equation for the tangent line of each of these points b)find the xcoordinate of each point on the curve where the

find the equation of the tangent line to the curve y=5xcosx at the point (pi,5pi) the equation of this tangent line can be written in the form y=mx+b where m= and b= what is the answer to m and b?

HARDER PARTS WAS 3(x^2+y^2)^2=26(y^2+y^2) Find the equation of the tangent line to the curve (a lemniscate) 3(x^2+y^2)^2=26(y^2+y^2) at the point (4,2). The equation of this tangent line can be written in the form y=mx+b where m is:? and where b is:?

Find the equation of the tangent line to the curve y=5xcosx at the point (pi,–5pi). The equation of this tangent line can be written in the form y=mx+b where m= and b=

Find dy/dx by implicit differentiation 1. x^3 xy+ y^2= 7 The given answer is (y3x^2)/ (2yx), but I'm not getting it. 2. How would I do this one? If I couldn't do the above one, which looks a heck of a lot simpler, I doubt I'll get through this one. x^

If f(x)=(3x)/(1+x^2) find f′(4). Use this to find the equation of the tangent line to the curve y=3x1+x2 at the point (4,0.70588). The equation of this tangent line can be written in the form y=mx+b where m is: and where b is:


Find the equation of the tangent line to the curve y=2sinx at the point ((pi/6), 1). The equation of the tangent line can be written in y=mx+b form, where m=sqrt3. What is b?

hey can someone explain to me the relationship between the chain rule and implicit differentiation? It would be very much appreicated, thanks The chain rule is utilized whenever you have a function within a function such as cos^2 x or (5x+1)^1/2. Implicit

Find an equation of the tangent line to the curve at the given point. y = 6 x sin x P= (pi/2 , 3pi) i know the slope of a tangent line is equal to the first derivative. For that I got 6xcosx + 6sinx but idk how to put that into the yy1=m(xx1) formula to

Find the equation of the tangent line to the curve y=6tanx at the point (pi/4,6). The equation of this tangent line can be written in the form y=mx+b where m is: and where b is:

PLEASE HELP , I DON'T UNDERSTAND find dy/dx by implicit differentiation a) xy + x^5y^2 + 3x^3  4 = 1 b) lny = cos x thank you

If f(x)=4x^(5/2), find f'(4) Use this to find the equation of the tangent line to the curve y=4x^(5/2) at the point (4,f(4)) . The equation of this tangent line can be written in the form y=mx+b where m is______ and where b is _____

Write the equation of lines tangent and normal to the following function at (0, π). To find derivative, use implicit differentiation. x^2cos^2y  siny = 0 Note: I forgot the ^2 for cos on the previous question. Sorry.

Find the equation of the tangent line to the curve: 2(x^2+y^2)^2 = 25(x^2y^2) at the point ( 3 , 1 ). The equation of this tangent line can be written in the form y = mx+b

Find the equation of the tangent line to the curve: 2(x^2+y^2)^2 = 25(x^2y^2) at the point ( 3 , 1 ). The equation of this tangent line can be written in the form y = mx+b

1) An equation of the line contains points (7/9, 7) and (7/9) is 2) Find the slope of the line tangent to the curve y=x^2 at the point (0.6, 0.36) and find the corresponding equation of the tangent line


Consider the function: (2x^2  2x4) y = 2x^2  x +10 Find y â€² using implicit differentiation. Do not solve for y. What is the slope of the tangent at (x,y) = (2,âˆ’1)? Find y â€² by solving for y and using the quotient rule. What is the

Consider the function:(2x^2 +3x 7) y= 2x^2x +3x +17 Find y ′ using implicit differentiation. Do not solve for y. What is the slope of the tangent at (x,y) = (−1,−1)? Find y ′ by solving for y and using the quotient rule. What is the slope of the

In this problem we consider drawing some straight lines which form a nice pattern. Consider joining the point (0.1,0) to the point (0,0.9) by a line segment; then joining (0.2,0) to (0,0.8) by a line segment; and so on. In general, consider joining the

Consider line segments which are tangent to a point on the right half (x>0) of the curve y = x^2 + 1 and connect the tangent point to the xaxis. If the tangent point is close to the yaxis, the line segment is long. If the tangent point is far from the

I found part B, but stuck on part A. Use implicit differentiation to find the points where the parabola defined by x^22xy+y^2+4x8y+24= 0 has horizontal and vertical tangent lines. A) The parabola has horizontal tangent lines at the point(s): B)The