
the width of a rectangle is 4cm and the length is 8 cm if both the width and the length are increased by equal measures, the area of the rectangle is increased by 64 cm 2. find the length and width of the larger rectangle

the dimensions of a rectangle are such that its length is 3 inches more than its width. if the length were double and if the width were decreased by 1 inch, the area would be increased by 66inches ^2. What are the length and width of the rectangle?

The dimensions of a rectangle are such that its length is 3 in. more than its width. If the length were doubled and if the width were decreased by 1in., the area would be increased by 150 in.^2. What are the length and width of the rectangle?

10. a rectangle has width the same as a side of a square whose perimeter is 20m. the length of the rectangle is 9m. find the perimeter of this rectangle. 34. The width of a rectangular picture is onehalf the length. The perimeter of the rectangle is 72

Can someone help me set up the equations thanks. Directions: Solve each of the following applications. Give all answers to the nearest thousandth. Problem: Geometry. The length of a rectangle is 1 cm longer than its width. If the diagonal of the rectangle


The dimensions of a rectangle are such that it's length is 9 in. more than its width. If the length were doubled and if the width were decreased by 4 in., the area would be increased by 110 in^2. What are the length and width of the rectangle?

the dimensions of a rectangle are such that its length is 5 in more than its width. If the length were doubled and the width were decreases by 2 in, the area would be increased 136 in^2,what are the length and width of the rectangle

a rectangle is twice as long as it is wide. if both of its dimensions are increased by 4m, its area is increased by 88m^2 find the dimensions of the original rectangle Original rectangle = w for width and 2w for length. Area = w x 2w Larger rectangle = w+4

THE LENGTH OF THE RECTANGLE EXCEEDS ITS WIDTH BY 3 CM. IF THE LENGTH AND WIDTH OF EACH INCREASED BY 2 CM, THEN THE AREA OF NEW RECTANGLE WILL BE 70 SQ. CM MORE THAN THAT OF THE GIVEN RECTANGLE. FIND THE LENGTH AND WIDTH OF THE GIVEN RECTANGLE.

the length of a rectangle is 2cm longer than the width. if its length and width are both increased by 4cm, its area is increased by 72 cm^2. find the dimensions of the original rectangle.

the length of a rectangle is 2cm longer than the width. if its length and width are both increased by 4cm, its area is increased by 72 cm^2. find the dimensions of the original rectangle.

The width of a rectangle is three fourths of the length. The perimeter of the rectangle becomes 50 cm when the length and the width are each increased by 2 cm. Find the length and the width.

The width of a rectangle is three fourths the length. The perimeter of the rectangle becomes 50 cm when the length and the width are each increased by 2cm. Find the length and the width. Draw a diagram and convince yourself that the perimeter P=2(L+W)

A rectangle has width the same asa a side of a square whose perimeter is 20m.the length of the rectangle is 9m. Find the perimeter of this rectangle. 34. The with of a rectangular picture is onhalf the length . The perimeter of the rectangle is 72inches.

The width of a rectangle is three fourths of the length. The perimeter of the rectangle becomes 50 cm when the legth and the width are each increased by two cm. Find the length and the width


The length of a rectangle is 3 times the width. If the length is increased by 4 cm and the width is decreased by 1 cm,the parimeter would be 102 cm, find the dimensions of the original rectangle.

The width of a rectangle is 1/6 the length. If the length and the width are each increased by 4 cm, the new perimeter is 70. Find the original length and width.

The length of a rectangle is twice the width. If the length is increased by 4 inches and the width is decreased by 1 inch, a new rectangle is formed whose perimeter is 198 inches. Find the dimensions of the original rectangle.

The length of a rectangle is twice the width. If the length is increased by 4 inches and the width is diminished by 1 inch, a new rectangle is formed whose perimeter is 198 inches. Fine the dimensions of the original rectangle.

the length of a rectangle is twice it's width. if it's length is decreased by 3 cm , and it's width is increased by 5 cm the result will be a square , then the perimeter of this rectangle will equal ...... cm

The length of a rectangle is 3 times the width. If the length is increased by 4 cm and the width is decreased by 1cm the parimeter will be 102 cm. find the dimensions of the original rectangle. I don't know the equation, please show the work. Not just the

All these are either rectangles or squares 1.Rectangle. 5 is length and 10 is width 10x5=50 2.Square. 5 is length and 5 is width 5x5=25 3.Rectangle. 6 is length and 8 is width 8x6=48 4.Square. 10 is length and 10 is width 10x10=100 5.Rectangle. 40 is

Perimeter of a rectangle. The width of a rectangle is three fourths of the length. The perimeter of the rectangle becomes 50 cm when the length and the width are each increased by 2 cm. Find the length and the width.

the length of a rectangle is 5 times its width. if the length is decreased by 3 meters, and the width is increased by 10 meters, the perimeter will be 374 meters. find the length of the original rectangle.

represent the given condition using a sing variable, x. The length and width of a rectangle whose length is 12 centimeters more than its width. the width of the rectangle is _____. The length of the rectangle is ____.


The length of a rectangle is 5 inches less than 3 times the width. The perimeter of the rectangle is 14 inches. Find the length and width of the rectangle. I did this: Length 3x5; width 3x Then I did guess and check and came up with X=2 solving the

The perimeter of a rectangle is 60cm. The length (L) of the rectangle can be represented by (2x7). What are the dimensions? A) length=10 width=14 B) length=6 width=18 C) length=9 width=15 D) length=10 width=1 or 15

The length of a rectangle is twice the width. If the length is increased by 6, and the width is doubled, a new rectangle is formed whose perimeter is 20 more than the perimeter of the original rectangle. Find the dimensions of the original rectangle.

Length of rectanngle is 1 cm more than width. If length of rectangle is doubled the area is increased by 30cm2. find dimensions of original rectangle.

Suppose that the length of a rectangle is 3 inches longer than the width and that the perimeter of the rectangle is 78. Set up an equation involving only L, the length of the rectangle. Solve this equation algebraically to find the length of the rectangle.

The length of a rectangle is 5 in. more than twice its width.? How do I find the width of the rectangle. The length = (2 x width) + 5 inches. Do you have any other information about the rectangle such as the area or the perimeter. I don't think there is

The area of a rectangle of length x is given by 3x2 +5x. Find the width of the rectangle. The area of a rectangle with width t is given by 33t  t 2. Factor the expression and determine the length of the rectangle in terms of t length times width=area, so

the length of a rectangle is 6 cm more than its width. the area is 11 cm squared. find the length and width. look at the post by anonymous at 8:55, it is almost the same as yours. Do it the same way. length= x+6 width=x x(x+6)=11 x^2 + ^x =11 x^2+6x11=0

The area of a rectangle is shown below The area of the rectangle is 56 Which of the following are possible values for the length and width of the rectangle? A.length=6cm and width=9cm B.length=7cm and width=8cm C.length=14cm and width=14cm D.Length=28cm

the perimeter of a rectangle is 70m. if the width were doubled and length were increased by 24m, the perimeter would be 142m. what are the length and width of the rectangle?


The perimeter of a rectangle is 46m. If the width were doubled and the length were increased by 12m, the perimeter would be 82m. What are the length and width of the rectangle?

The area of a rectangle of length x is given by 3x^2+5x find the width of the rectangle a=l*w =x*(3x+5) I stoped here I am not sure if I am correct i was taken the 3x+5 as the width and x as the length but i am not sure if the 3x+5 should be the area and

A rectangle has length & width in the ratio of 3:2.If the length is increased by 8 & width is increased by 50%.The ratio of new perimeter to original perimeter is 8:5.Find the area of new rectangle

The length of a rectangle is 6 cm more than four times the width. If the perimeter of the rectangle is 42 cm, what are its dimensions? a. length = 18 cm; width = 3 cm b. length = 18 cm; width = 9 cm c. length = 6 cm; width = 9 cm d. length = 3 cm; width =

Okay one last one that I've spent all night truing to figue out. 2. The width of a rectangle is 6 cm longer than its length. Its perimeter is more than 36 cm. Let l equal the length of the rectangle. a. for the width in terms of the length. W= l + 6=

The length of a rectangle is 8 feet more than its width. If the width is increased by 4 feet and the length is decreased by 5 feet, the area will remain the same. Find the dimensions of the original rectangle.

The length of a rectangle is 8 feet more than its width. If the width is increased by 4 feet and the length is decreased by 5 feet, the area will remain the same. Find the dimensions of the original rectangle.

The area of a rectangle is found by multiplying the length by the width: A = lw. A certain rectangle has an area of x2 + 7x + 12. Factor the trinomial to find the length and width of the rectangle. In the form of a paragraph, describe the process necessary

the length of a rectangle is 8 cm more than its width. If the length is decreased by 9 and the width is tripled, the area is increased by 50%. What was the area of the original rectangle?

The rectangle below has an area of 30k^3+6k^2 The width of the rectangle (in meters) is equal to the greatest common monomial factor of 30k^3 and 6k^2 What is the width and length of the rectangle? Width:6k^2 Length: I couldn't find the length I need to be


a rectangle has a width of 4 cm less than it's length. if a new rectangle is formed by increasing the width 5 cm and decreasing the length 3 cm, the area of this resulting rectangle is 177 cm squared. what are the dimensions of the original rectangle?

the function for the perimeter of a rectangle is given as P=4x+6 a) Give an expression for the length of the rectangle in terms of the width. b) If the width is half the length, state a function for both the width and length describing the domain for which

the function for the perimeter of a rectangle is given as P=4x+6 a) Give an expression for the length of the rectangle in terms of the width. b) If the width is half the length, state a function for both the width and length describing the domain for which

the width of a rectangle is 25% of the length. The perimeter is 250 cm. Find the width and the length of the rectangle. (length = 100 cm and width = 25cm)

The length of a rectangle is twice the width. The area is 242 yd^2. Find the length and the width of the rectangle. The width would be? The length would be? I am not sure if I am to take 242 and sqrt it to give me 58,564 and then divide by 4 or what. I am

Directions: Solve each of the following problems. Be sure to show the equation used for the solution. The length of a rectangle is 2in. more than twice its width. If the perimeter of the rectangle is 34 in., find the dimensions of the rectangle. Let L =

Can you help me figure this? The area of a rectangle is 14 square meters. Find the length and width of the rectangle if it's length is 5 meters greater than its width. Use an equation and the formula for the area of a rectangle=(width)(length). Thank you.

A rectangle is bounded by the xaxis and the semicircle y=ã(25x^2). Question is, what length and width should the rectangle have so that its area is a maximum, and what is the maxuimum area? Area= length*width = 2x*y= 2x*sqrt(25x^2) Now, take that,

The area of a rectangle of width ycm is 140cm^2. If the width is reduced by 2cm, the length increases by 3cm, and the area decreases to 136cm^2 to form an equation that enables you to determine the value of Y and hence, find the diagonal of the original

The length of a rectangle is 3 cm and the width is 2 cm. find the length of the diagonal. Is there a formula to do this? The length of a rectangle is 3 cm and the width is 2 cm. find the length of the diagonal. Is there a formula to do this? The diagonal D


Solve algebraically using only variable: The length of a rectangle is two less than three times its width. If the area of the rectangle is 65, find the length and the width. (The area of a rectangle is equal to its length times its width.

the length of a rectangle is 8cm more than the width and its area is 172cm^2 .Find a) the width od the rectangle; b) the length of the diagonal of the rectangle, giving your answer correct to 2 decimal places

Can someone help me just to do the setup of this the two equations. I can do the rest is just the step up THAT I AM HAVING DIFFICULTY. The length of a rectangle is 2in. more than twice its width. If the perimeter of the rectangle is 52in. wHAT IS THE

THE LENGTH OF A RECTANGLE IS 3M MORE THAN 2 TIMES ITS WIDTH. IF THE AREA IF THE RECTANGLE IS 99CM^2, FIND THE DIMENSIONS OF THE RECTANGLE TO THE NEAREST THOUSANDTH. If L = length and W = width, L = 2W + 3 and LW = 99 Substitute and solve for either L or W.

If the trend continued, in how many years would the median home value be $170,000? Show how obtained your answer using the linear equation you found in part c) Suppose that the width of a rectangle is three feet shorter than length and that the perimeter

jennifer has made a rectangle using 48 square titles. if she adds the length and width of her rectangle together she gets a prime number . what is the length and width of jennifers rectangle??

For a constant area, the length of a rectangle varies inversely as its width. The length of a rectangle is 27 ft when the width is 10 ft. Find the width of a rectangle with the same area if the length is 18 ft.

Mike has made a rectangle using 48 square tiles. If he adds the length and width of his rectangle together he gets a prime number. What is the length and width of the rectangle?

Solve by setting up the proper equation to describe the facts given and then carrying out the mathematical calculations to solve for the unknown variable(s). The length of a rectangle is 3 times the width. The difference between the length and the width is

Solve algebraically using only variable: The length of a rectangle is two less than three times its width. If the area of the rectangle is 65, find the length and the width. (The area of a rectangle is equal to its length times its width.


what would the dimensions of a retangle be whose perimeter is 50(P=50)inches when the length is 2x5 ane the width is unknown The width must be 25  (2x5) = 302x, since the sum of the length and width must be half the perimeter. You do not have enough

Find each product. { this means the square root sign. 1. (3+2{20)(5+3{45) 2. The length and width of the rectangle are x5 and 2x6 a. Write a trinomial that represents that area of the rectangle. b. What is the smallest integer value of x that will give

The length of a rectangle is 4 times the width. The perimeter is 50cm. Find the length and width. Write the equations. What is the length and width?

The length of a rectangle is 2 less than 5 times the width. The area is 39 square inches. What is the length and the width? I did this: Length = 5x2; width = 5x Then I solved the question and came up with x=3

Suppose that the width of a certain rectangle is 1 inch more than onefourth of its length. The perimeter of the rectangle is 32 inches. Find the length and width of the rectangle.

Suppose that the width of a certain rectangle is 1 inch more than onefourth of its length. The perimeter of the rectangle is 62 inches. Find the length and width of the rectangle.

The length of a rectangle is 5 inches longer than its width. Its perimeter is 45 inches. Let w equal the width of the rectangle. Write an expression for the length in terms of the width. Use expressions for the length and width to write an equation for the

Find each product. { this means the square root sign. 1. (3+2{20)(5+3{45) 2. The length and width of the rectangle are x5 and 2x6 a. Write a trinomial that represents that area of the rectangle. b. What is the smallest integer value of x that will give

And if a length of a rectangle is 3 more than twice the width and the are is 90 cm squared than what are the dimensions of the rectangle? The width of the rectangle is 43.5 and the length of the rectangle is 87. All together when you add it up it will make

The length, l, of a rectangle is 2 feet less than three times the width, w, of the rectangle. The area of the rectangle is 481 square feet. Find the length and width of the rectangle. how do i work this problem out?


the length of a rectangle is twice the width. The area is 200 yd^2 Find the length and the width. The length is _____ yd The width is ______ yd Could I get help please!!!!

A rectangle has a length of 4x and a width of 4x2. Its perimeter is 12 inches. Find the length and width. Write the equations. What is the length and width?

The width of a rectangle is 2ft less than the length. The area is 8ft^2.Find the length and the width. The width is__ ft. The length is __ ft.

I can't seem to figure this out. It is for my study guide. Please help. The length of a rectangle is 5 feet less than twice the width. The area is 25 sq feet. Using w as the variable, write an equation that can be used to calculate the width. Then find

The area of a rectangle of length x is given by 3x^2 + 5x. Find the width of the rectangle. Show me the formula and how to use it please. area= length times width 3x^2 + 5x = x * width divide both sides by x, then you have width.

the length of a rectangle is 3 yds more than twice it width and the area of the rectangle is 77yds find the dimensions of the rectangle the length and width

The length of a rectangle is 1 meter more than 5 times it's width. The perimeter of the rectangle is 98 meters. Find the length and width of the rectangle.

The length of a rectangle is two more than three times its width. The perimeter of the rectangle is 116. Determine the length and width of the rectangle.

The area of a rectangle is 20 square inches. The length of the rectangle is 1 inch longer than the width. What are the length and width of the rectangle?

1. What must be added to p to produce q? 2. What is the perimeter of the rectangle if the length is 2x3y and the width is x+2y? What is the area? 3. What must be subtracted to 7y to leave 5y+2z? 1. q = 1  p 2. Perimeter of rectangle = 2 length + 2


A rectangle has legth & width in the ratio of 3:2.If the length is increased by 8 & width is increased by 50%.The ratio of new perimeter to origial perimeter is 8:5.Find the area of new rectangle.

the length of a rectangle is 3 less than 5 times its width. Write a simpified algebriac expression for the perimeter of a rectangle. If the rectangle width is tripled and its length is doubled,the perimeter of new rectangle is 92cm greater than the

The perimeter of a rectangular carpet is 70feet. The with is three fourths the length .Find the width. 38. The length of a rectagular room is six times as the width . The perimeter 84 yards. find the width. 39. The width of a rectangle is 12 less than the

Suppose that the width of a certain rectangle is threefourths of its length, and the area of that same rectangle is 108 square meters. Find the length and the width of the rectangle If you put the correct subject in the subject line, you're likely to get

the length of a rectangle is 3 meters less than twice its width. write an equation to find the length of the rectangle. the length of the rectangle is 11 meters. what is the width of the rectangle

the base of a triangle is 2 cm shorter than the width of a rectangle. The rectangle's length is 4 times its width and the triangle's height is the same as the rectangle's length. find the area of both figures if the difference of the two areas is 30cm2

the length of a rectangle exceeds its breadth by 4 cm. if length and breadth are each increased by 3 cm, the area of the new rectangle will be 81 cm sqsq morthan that of the given rectangle. find the length and breadth of the given rectangle.

the length of a rectangle is twice the width. If the area is 72 metres squared, calculate the length and the width. length: width:

Can you please review to see if I am on the right track with this problem: The length of a rectangle is 2 centimeters less than two times the width of the rectangle. If the perimeter of the rectangle is 98 centimeters, what is the length of the rectangle?

Solve each system of equations by graphing. Check each solution. The perimeter of a rectangle is 24 ft. Its length is five times its width. Let x be the length and y be the width. What is the area of the rectangle?


The width of a rectangle is 12 units less than its length. If you add 30 units to both length and width, you double the perimeter. Find the length and with of the original rectangle.

The width of a rectangle is 12 units less than its length. If you add 30 units to both length and width, you double the perimeter. Find the length and with of the original rectangle.

I don't understand can you help me? Alicia has made a rectangle using 24 square tiles. If she adds the length and width of her rectangle together, she gets 11. What is the length and width of Alicia's rectangle?

The length of a rectangle is 1cm longer than its width. If the diagonal of the rectangle is 4cm, what are the dimensions(the length and the width)of the rectangle? L=W1 Diagonal = sqrt(L^2 + W^2) substitutuet for L in the second equation, solve for W.

the primeter of a rectangle is 24ft. the length is 2 ft longer than the width. Find the dimensions. Write a system of linear equations and solve the resulting system. Let x be the length and y be the width. is the answer for the length 14ft and the width