Evaluate lim>4 sin(2y)/tan(5y) Here is what I have so far. I am not sure the next steps. Can someone help me? 1. sin(2y)/(sin(5y)*cos(5y)) 2. (sin(2y)*cos(5y))/sin(5y)
12,420 results
PreCal
Find sin 2x, cos 2x, and tan 2x from the given information. [1]. sin x = 8/17, x in Quadrant I 1). sin 2x =________. 2). cos 2x =________. 3). tan 2x =________. [2]. sin x = 5/13, x in Quadrant III 1). sin 2x =________. 2). cos 2x =________. 3). tan 2x

math
Find the values of sin θ, cos θ, and tan θ for the given right triangle (in the link below). Give the exact values. www.webassign.net/aufexc2/85003.gif sin θ= cos θ= tan θ= my answer is c^2 = a^2 +b^2 c^2 = 5^2+12^2 c^2 = 169 c= √(169) c= 13 I

Precalculus help
I have two problems I am stuck on, if you could show me how to solve the problems it would be much appreciated. 1) Find sin 2x, cos 2x, and tan 2x from the given information. tan x = − 1/6, cos x > 0 sin 2x = cos 2x = tan 2x = 2) Find sin 2x, cos 2x, and

CALCULUS LIMITS
What is the following limit? lim as n goes to infinity of (pi/n) (sin(pi/n) + sin(2pi/n) + sin(3pi/n) +...+ sin(npi/n)) = I.) lim as n goes to infinity sigma (n and k=1) of pi/n sin(kpi/n) II.) Definite integral from 0 to pi of sin(x)dx III.) 2 A.) I only

Calc 1
Evaluate the limit. lim x → 1 ln x/sin 5πx

math
lim x→0 of [tan(3x^2) + sin^2(5x)] / (x^2)

precalculus
Verify the identity: sin(A+B)/sin(AB) = tan(A)+tan(B)/tan(A)tan(B) Explain steps

Calculus
Use the graph to estimate the limit: lim x>0 sin(3x)/x When x is in degrees lim x>0 sin(3x)/x = ________ I thought the the answer was (3*180)/pi but it's not... please help... Thanks

mathematics
evaluate each of the following..sin 130.tan 60/cos 540.tan 230.sin 400

MathsSs triG
Consider sin(x360)sin(90x)tan(x)/cos(90+x) 1.A.SIMPLIFY sin(x360)sin(90x)tan(x)/cos(90+x) to a single trigonometric ratio B.hence or otherwise without using a calculator,solve for X if 0

calc
Let F(x) = ∫ sin(t^2) dt from 0 to x Evaluate the limit lim x>0 (F(x)/x^2)

calc bc (condensed
is the limit as x approaches 0 of sin3x over 3x equal to zero? sorry basically this is my problem: lim [sin 3x / 4x) x> 0 ~~~~I multiplied& eventually got to .75* lim (sin 3x / 3x) x> 0 ~so i figured since (lim (sinx/x) x> 0 was equal to zero, then

Maths
Evaluate in simple surd form the following: (1) Sin 225 (2) Cos 195 (3) Sin 345 (4) tan 195

MathLimits
sqrt(1+tan x)sqrt(1+sin x) lim all divided by x^3 x>0 Use that Sqrt[1+x] = 1+ 1/2 x + 1/2 (1/2)/2 x^2 + 1/2(1/2)(3/2)/6 x^3 + O(x^4) You can thus write the numerator as: 1/2 [tan(x)  sin(x)]  1/8 [tan^2(x)  sin^2(x)] + 1/16 [tan^3(x)  sin^3(x)] +

Precalculus
Use one of the identities cos(t + 2πk) = cos t or sin(t + 2πk) = sin t to evaluate each expression. (Enter your answers in exact form.) (a) sin(19π/4) (b) sin(−19π/4) (c) cos(11π) (d) cos(53π/4) (e) tan(−3π/4) (f) cos(π/4) (g) sec(π/6+ 2π)

maths (trigonometry)
calculate the following: 1)sin 50 degreesin 70 degree+sin 10deg. 2)cos square 48 deg. sin square 12 deg. 3)tan 20 deg.+tan 40 deg.+root 3 tan 20 tan 40 Plz. Solve these

Math
Evaluate *Note  We have to find the exact value of these. That I know to do. For example sin5π/12 will be broken into sin (π/6) + (π/4) So... sin 5π/12 sin (π/6) + (π/4) sin π/6 cos π/4 + cos π/6 sin π/4 I get all those steps. The part I am

Trig
Given: cos u = 3/5; 0 < u < pi/2 cos v = 5/13; 3pi/2 < v < 2pi Find: sin (v + u) cos (v  u) tan (v + u) First compute or list the cosine and sine of both u and v. Then use the combination rules sin (v + u) = sin u cos v + cos v sin u. cos (v  u) = cos u

Trigonometry
Find the exact value of tan(ab) sin a = 4/5, 3pi/2

Maths complex numbers
Find tan(3 theta) in terms of tan theta Use the formula tan (a + b) = (tan a + tan b)/[1  tan a tan b) in two steps. First, let a = b = theta and get a formula for tan (2 theta). tan (2 theta) = 2 tan theta/[(1  tan theta)^2] Then write down the equation

Calculus
Consider the function f(x)=sin(1/x) Find a sequence of xvalues that approach 0 such that (1) sin (1/x)=0 {Hint: Use the fact that sin(pi) = sin(2pi)=sin(3pi)=...=sin(npi)=0} (2) sin (1/x)=1 {Hint: Use the fact that sin(npi)/2)=1 if n= 1,5,9...} (3) sin

calculus
1. integral oo, oo [(2x)/(x^2+1)^2] dx 2. integral 0, pi/2 cot(theta) d(theta) (a) state why the integral is improper or involves improper integral (b) determine whether the integral converges or diverges converges? (c) evaluate the integral if it

trig
evaluate the following in exact form, where the angeles alpha and beta satisfy the conditions: sin alpha=4/5 for pi/2 < alpha < pi tan beta=7/24 for pie < beta < 3pi/2 answer choices A. sin(beta+alpha) B. tan(betaalpha) C. cos(alphabeta)

Math
If tan(x)= (3/4) and x is obtuse, evaluate sin(2x). How do I get started on this question?

Limit Calculas
Evaluate lim>4 sin(2y)/tan(5y) Here is what I have so far. I am not sure the next steps. Can someone help me? 1. sin(2y)/(sin(5y)*cos(5y)) 2. (sin(2y)*cos(5y))/sin(5y)

calculus
Evaluate lim>4 sin(2y)/tan(5y) Here is what I have so far. I am not sure the next steps. Can someone help me? 1. sin(2y)/(sin(5y)*cos(5y)) 2. (sin(2y)*cos(5y))/sin(5y)

Calculus
Below are the 5 problems which I had trouble in. I can't seem to get the answer in the back of the book. Thanks for the help! lim (thetapi/2)sec(theta) theta>pi/2 Answer: 1 I am not sure what to do here. lim (tan(theta))^(theta) theta>0+ Answer:1

precalculus
For each of the following determine whether or not it is an identity and prove your result. a. cos(x)sec(x)sin^2(x)=cos^2(x) b. tan(x+(pi/4))= (tan(x)+1)/(1tan(x)) c. (cos(x+y))/(cos(xy))= (1tan(x)tan(y))/(1+tan(x)tan(y)) d.

Trigonometry
1.Solve tan^2x + tan x – 1 = 0 for the principal value(s) to two decimal places. 6.Prove that tan y cos^2 y + sin^2y/sin y = cos y + sin y 10.Prove that 1+tanθ/1tanθ = sec^2θ+2tanθ/1tan^2θ 17.Prove that sin^2wcos^2w/tan w sin w + cos w tan w =

Calculus
1. Use a graph to estimate the limit. Use radians unless degrees are indicated by θ°. (Round your answer to four decimal places.) lim θ → 0 θ/tan(7θ) 2. Assuming that limits as x → ∞ have the properties for limits as x → c, use algebraic

Calculus
What is the following limit? lim as n goes to infinity of (pi/n) (sin(pi/n) + sin(2pi/n) + sin(3pi/n) +...+ sin(npi/n)) = I.) lim as n goes to infinity sigma (n and k=1) of pi/n sin(kpi/n) II.) Definite integral from 0 to pi of sin(x)dx III.) 2 A.) I only

Trigonometry
Evaluate each expression: a) ( tan π/12 + tan 7π/4 ) / ( 1  tan π/12 x tan 7π/4) b) cos π/4 cos π/12 + sin π/4 x sin π/12 c) sin 7π/5 cos π/15  cos 7π/5 sin π/15

Calculus
Consider the function f(x)=sin(1/x) Find a sequence of xvalues that approach 0 such that (1) sin (1/x)=0 {Hint: Use the fact that sin(pi) = sin(2pi)=sin(3pi)=...=sin(npi)=0} (2) sin (1/x)=1 {Hint: Use the fact that sin(npi)/2)=1 if n= 1,5,9...} (3) sin

Trigonometry
IM STUCK ON THESE :( 1. What is the equation for shifting the standard sine curve +2 units horizontally? A. y = sin (x + 2) B. y = sin x + 2 C. y = sin x − 2 D. y = sin (x − 2) 3. What is tan¹ √3/3 ? A. π/4 B. π/3 C. π/6 D. π/4 4. cot–1

Trigonometry
IM STUCK ON THESE :( 1. What is the equation for shifting the standard sine curve +2 units horizontally? A. y = sin (x + 2) B. y = sin x + 2 C. y = sin x − 2 D. y = sin (x − 2) 3. What is tan¹ √3/3 ? A. π/4 B. π/3 C. π/6 D. π/4 4. cot–1

calculus
what is the integral of {sin(x)tan(x)} i tried turning tan(x) into sin(x)/cos(x) then doing u substitutions but i always have an extra sin(x) left. can you help me pleeeease

triggggg help
Let cos 67.5° = [√(2(+√2)]/2, find tan 67.5°. Show work and simplify. I'm not too sure if i'm doing this correct. I know that the given is cos 67.5° = [√(2(+√2)]/2 sin^2 x + cos^2 x = 1 x=67.5° sin^2 67.5° + cos^2 67.5° = 1 sin^2 67.5° = 1 

Calculus
Okay so I have a question on my assignment that says: You are given that tan(y) = x. Find sin(y)^2. Express your answer in terms of x. I know its derivatives, and I've tried taking the derivatives of both etc, and got them both to come out as cos(y)^2,

trigonometry
1) Find the exact value of the expression: tan−1(tan(−120651/47π))... How do you find Tan(120651/47pi)? I don't know how to find exact values, if it's not a recognizable value. 2)Find a simplified expression for tan(sin−1(a/5))... Because tan = y/x

PreCal
Given that lim x> f(x)=6 and that lim x> g(x)= 4, evaluate the following limit. Assume that c is a constant. lim 2f(x)  12 / g(x). x>. I did 2(6)  (12/4) 12  (3) 12 + 3 9

math
the limit of cuberoot((3x^3+5x+2)/(x^21)) as x approaches 3 is the problem. how could (3x^3+5x+2) so it would be factored out with denominator? thanks! If you read the answer I gave for the previous question, then you can take the limit inside to get

L'Hopitals Rule
5) Use the L’Hopital’s method to evaluate the following limits. In each case, indicate what type of limit it is ( 0/0, ∞/∞, or 0∙∞) lim x→2 sin(x^2−4)/(x−2) = lim x→+∞ ln(x−3)/(x−5) = lim x→pi/4 (x−pi/4)tan(2x) =

math
i need some serious help with limits in precalc. here are a few questions that i really do not understand. 1. Evaluate: lim (3x^32x^2+5) x> 1 2. Evaluate: lim [ln(4x+1) x>2 3. Evaluate: lim[cos(pi x/3)] x>2 4. Evaluate: lim x^2+x6/x^29 x> 3

Calc
I have a test soon.. and I really need to know how to do this problem.. please help!!! lim as x>0 sin^2(x)/tan(x^2) the answer is 1, but I have no clue how to get that! Use series expansions. Look up Taylor expansion on google and study that topic first.

calculus
using the squeeze theorem, find the limit as x>0 of x*e^[8sin(1/x)] what i did was: 1

Calc: Limits
how to calculate the limit: *I got confused especially with the square root. 1. lim as x approaches 2 (squareroot x^2 +5)3 / (x2) 2. lim as θ (theta) approaches zero (tan^2 (5θ) / (sin (3θ) sin (2θ) )

calculus
Lim sin2h sin3h / h^2 h>0 how would you do this ?? i got 6 as the answer, just want to make sure it's right. and i couldn't get this one (use theorem 2) lim tanx/x x>0 and also this one (use squeeze theorem to evaluate the limit) lim (x1)sin Pi/x1

CalculusLimits
Okay, i posted this question yesterday, however, I did not really understand the answer I received. If your the one who answered my question, could you please elaborate. If not, could you try to answer this tough, for me, question. Thanks a lot. lim x>0

MathLimits
How do we evaluate limit of, lim x> 0 [ln(x+1)/( (2^x)  1)] I tried using the substitution x+1 = e^k , when x tends to 0 so does k, which gave out, lim k>0 [ k/((2^((e^k)  1)) 1 ) ] which I simplified into( for the ease of use let e^k =a) lim k>0

math
find the value... lim (tan 2x x)/(3x sin x) x>0

Trig
Evaluate the following expression: sin(cos^1(12/13)) tan(sin^1(3/5)) I do not know what the inverse values would be...how would I work through this?

Help me check my calc answers?
Can someone check my answers: 1) Use geometry to evaluate 6 int 2 (x) dx where f(x) = { x, 2

Check Calculus answers please
Can someone check my answers: 1) Use geometry to evaluate 6 int 2 (x) dx where f(x) = { x, 2

Pre calc
Evaluate by using the Pythagorean identities Find sin θ and cos θ if tan θ=1/6 and sin θ >0

Trigonometry desperate help, clueless girl here
2. solve cos 2x3sin x cos 2x=0 for the principal values to two decimal places. 3. solve tan^2 + tan x1= 0 for the principal values to two decimal places. 4. Prove that tan^2(x) 1 + cos^2(x) = tan^2(x) sin^2 (x). 5.Prove that tan(x) sin(x) + cos(x)=

Maths Calculus Derivatives
Find the first derivative for the following functions 1) f(x) = sin(cos^2x) cos(sin^3x) 2) f(x) = ( tan 2x  tan x ) / ( 1 + tan x tan 2x ) 3) f(x) = sin { tan ( sqrt x^3 + 6 ) } 4) f(x) = {sec^2(100x)  tan^2(100x)} / x

CALCULUS
What is the following limit? lim as n goes to infinity of (pi/n) (sin(pi/n) + sin(2pi/n) + sin(3pi/n) +...+ sin(npi/n)) = I.) lim as n goes to infinity sigma (n and k=1) of pi/n sin(kpi/n) II.) Definite integral from 0 to pi of sin(x)dx III.) 2 A.) I only

math
Use the exact values of the sin, cos and tan of pi/3 and pi/6, and the symmetry of the graphs of sin, cos and tan, to find the exact values of sin pi/6, cos 5/3pi and tan 4pi/3. I have found the answers to the first three using the special tables sin pi/6

Mathematics  Trigonometric Identities
Let y represent theta Prove: 1 + 1/tan^2y = 1/sin^2y My Answer: LS: = 1 + 1/tan^2y = (sin^2y + cos^2y) + 1 /(sin^2y/cos^2y) = (sin^2y + cos^2y) + 1 x (cos^2y/sin^2y) = (sin^2y + cos^2y) + (sin^2y + cos^2y) (cos^2y/sin^2y) = (sin^2y + cos^2y) + (sin^2y +

calculus
use L'Hopital's Rule to evaluate lim (4x(cos 8x1))/(sin 8x  8x) as x>0

Calc 1
Find the limit. Use l'Hospital's Rule if appropriate. If there is a more elementary method, consider using it. lim x→0 (7x−sin 7x)/(7x−tan 7x)

trig help much appreciated! :))
1. Find the complete exact solution of sin x = . 2. Solve cos 2x – 3sin x cos 2x = 0 for the principal value(s) to two decimal places. 3. Solve tan2 x + tan x – 1 = 0 for the principal value(s) to two decimal places. 4. Prove that tan2 – 1 + cos2

Math(Please check!!!)
1) Evaluate (if possible) the sine, cosine, and tangent of the angles without a calculator. a) 10pi/3 Sin = sqrt 3/2 Cos = 1/2 Tan = sqrt 3 Are these correct ? I do not understand when to make them negative. b) 17pi/3 Sin = sqrt 3/2 Cos = 1/2 Tan = 

Precal (Please Check)
1) Evaluate (if possible) the sine, cosine, and tangent of the angles without a calculator. a) 10pi/3 Sin = sqrt 3/2 Cos = 1/2 Tan = sqrt 3 Are these correct ? I do not understand when to make them negative. b) 17pi/3 Sin = sqrt 3/2 Cos = 1/2 Tan = 

precal
Given that lim x>c f(x)=6 and that lim x>c g(x)= 4, evaluate the following limit. Assume that c is a constant. The x in front of the f is confusing me. lim [xf(x) + 3 g(x)]^2 x>c

Calc
Evaluate the limit if it exists, otherwise, write ∞,∞ or DNE as appropriate. (you may not use the L'Hospital Rule) lim e^cosx \squareroot(tan((3)/(4)x)+10) x> π Please show steps I am very confused!

Mathematics
Trigonometry : Practical application. If x is an acute angle, and tan x = 3\4, evaluate. cos x  sin x \cos x + sin x

CALCULUS
Evaluate each of the following. (a) lim x>0(e^x)1x/ x^2 (b) lim x>0 xsinx/x^3 (c) lim x>infinity (In x)^2/x (d) lim x>0+ (sinx)In x (e) lim x>0+ (cos3x)^5/x (f) lim x>1+ ((1/x1) (1/In x))

precalc
Find the exact value of each expression, if it exists: the 1 are representing the inverse functions! (a) sin 1 (√2/2) (b) cos−1 (−1) (c) sin( sin−1 (π)) (d) cos−1(cos(−4π/ 3)) (e) tan−1 (tan(0.6)) (f) cos−1(

Calculus..more help!
I have a question relating to limits that I solved lim(x>0) (1cosx)/2x^2 I multiplied the numerator and denominator by (1+cosx) to get lim(x>0) (1cos^2x)/2x^2(1+cosx) = lim(x>0)sin^2x/2x^2(1+cosx) the lim(x>0) (sinx/x)^2 would =1 I then substituted

trig 26
simplify to a constant or trig func. 1. sec ²utan ²u/cos ²v+sin ²v change expression to only sines and cosines. then to a basic trig function. 2. sin(theta)  tan(theta)*cos(theta)+ cos(pi/2  theta) 3. (sec y  tan y)(sec y + tan y)/ sec y combine

Trigonometry
Show that the following are not trigonometric identities 1.tan 2x = 2tan x 2. sec x= sqr rt 1+tan^2 x 3. sin(x+y)=sin x +sin y

Mathematics
If x is acute angle, and tan x=3 , evaluate cos x−sin x _ __________ 4 cos x+sin x

Math
Evaluate the identity (cos^2xsin^2x)/(1tan^2x)=cosx^2X

Trigonometry
evaluate cot 2x = 5/12 with 0

CALCULUS  need help!
Determine the limit of the trigonometric function (if it exists). 1. lim sin x / 5x (x > 0) 2. lim tan^2x / x (x >0) 3. lim cos x tan x / x (x > 0)

math
evaluate without using L'Hopital theorem the following limit lim x>0 [(sin(x)x)/(xtan(x))] the answer is 0.5 but I want to know the steps to calculate such a problem

math
evaluate without using L'Hopital theorem the following limit lim x>0 [(sin(x)x)/(xtan(x))] the answer is 0.5 but I want to know the steps to calculate such a problem

math
Using taylor series solve lim x→0 ((sin^1 6x)(sin 6x))/((tan^1)(6x)(tan 6x) I don't know how to start this problem

Math
If f(x)= {5x+5x^2 1

Trig Identities
Proving identities: 1) 1+ 1/tan^2x = 1/sin^2x 2) 2sin^2 x1 = sin^2x  cos^2x 3) 1/cosx  cosx = sin x tan x 4) sin x + tan x =tan x (1+cos x) 5) 1/1sin^2x= 1+tan^2 x How in the world do I prove this...please help... I appreciateyour time thankyou soo

Trigonometry
Please review and tell me if i did something wrong. Find the following functions correct to five decimal places: a. sin 22degrees 43' b. cos 44degrees 56' c. sin 49degrees 17' d. tan 11degrees 37' e. sin 79degrees 23'30' f. cot 19degrees 0' 25'' g. tan

HS Calculus
1) Limit theta approaching zero sin squared theta/ tan theta 2) Lim x appraoches zero x + sin x/x x + sin x/x = x/x + sinx/x 0 + 1 =1 My answer : 1 Is this correct

HS Calculus
1) Limit theta approaching zero sin squared theta/ tan theta 2) Lim x appraoches zero x + sin x/x x + sin x/x = x/x + sinx/x 0 + 1 =1 My answer : 1 Is this correct

math
Use the exact values of the sin, cos and tan of pi/3 and pi/6, and the symmetry of the graphs of sin, cos and tan, to find the exact values of si pi/6, cos 5/3pi and tan 4pi/3. I have found the answers to the first three using the special tables

Calculus
lim x > pi/2 (sin(x/2)cos(x/3)) Evaluate Please help

Calculus help please
I have to evaluate the following: tan((sin^1)(2/7)) and sin^1 (sin(17pi/6)) Please help.

Calc 1
Evaluate the limit. lim x → 1 (ln x)/(sin 5πx)

calculus
Use l'hopital's Rule to evaluate lim x in 0 of (4x(cos 6x1 )) / sin 3x3x

Calculus I
evaluate and justify each step lim((xe^x)/tan x) as x approaches 1. i just need the over all jest of the problem because i don't know what to do to get rid of the 0 in the denominator. Thanks.

calculuslimits??
i keep on doing something wrong on this problem,i guess im forgetting to add or subtract some number. use f'(x)=lim h>0 f(x+h)f(x)/h to find the limit: lim h>0 sin^(3)4(x+h)sin^(3)4x/h

Calculus
Can you please help me get the solution to this limit without using squeeze theorem and l'hopitals rule lim x to 0 of x^3 sin(1/x) lim x to 0 of x^2 sin^2(1/x)

math
Calculate the value of the following, without using a calculator, leaving answers, where necessary, in simplified surd form: (a). sin 120° + tan 300° (b). tan 315° × cos330° / sin(240°) × sin 570°

Calculus
yes! tnk u ok? It's actually (x>0.) Find the limit of cot(x)csc(x) as x approached 0? Lim [cot(x)  csc (x)] ..x>0 = Lim [(cos x 1)/sin x] ..x>0 Use L'Hopital's rule and take the ratio of the derivatives: Lim (sin x/cos x) = 0 x>0 thank you very

calculus
Evaluate the expression : tan(sin^1(9/13)).

evaluation
Evaluate 1. sin(tan inverse sqrt(x^22x)) 2. tan (sec inverse 3y)

Inverse Functions & Trig. Equations
7. Evaluate sin[sin^1(1/2)]. a. 1/2 b. ð /6 c. 1/2 d.  ð /6 8. Evaluate cos[tan^1(5/12)]. a. 12/13 b. 12/5 c. 5/12 d. 5/13 9. Evaluate cos[sin^1(3/5)]. a. 4/5 b. 5/4 c. 4/5 d. 3/4

math, if i have correct answer
Prove the identity: tan^2O/ 1 + tan^20 = sin^20 I get 1=1, but others have got sin^2=sin^2 Who's right?? Because there is no answer for this question at the back of the book

math
Prove the identity: tan^2O/ 1 + tan^20 = sin^20 I get 1=1, but others have got sin^2=sin^2 Who's right?? Because there is no answer for this question at the back of the book

PreCalc Help!!!!!!!!
Evaluate the expression under the given conditions. sin (A+B); tan A= 12/5, A in quadrant 3, sin B= 3sqrt(10)/10, B in quadrant 4.