Could someone please explain this to me? Differentiate. h(u)= 10^(sqrt(u)) h'(u)= 10^(sqrt(u))*log(10)(d/du(sqrt(u))) h'(u)= 10^(sqrt(u))*((1)/(2*sqrt(u)))*log(10)
34,047 results
algebra
Simplify: 2 sqrt (3) + 6 sqrt(2)  4 sqrt(3) + sqrt (2) a) 8 sqrt(2)  3 sqrt(3) b) 6 sqrt(2)  8 sqrt(3) c) 5 sqrt(6) d) 7 sqrt(2)  2 sqrt(3) the answer i picked was d

Math:)
A person is on the outer edge of a carousel with a radius of 20 feet that is rotating counterclockwise around a point that is centered at the origin. What is the exact value of the position of the rider after the carousel rotates 5pi/12 radians? a.

algebra
am I right? 1. Simplify radical expression sqrt 50 5 sqrt ^2*** 2 sqrt ^5 5 sqrt ^10 5 2. Simplify the radical expression sqrt 56x^2 28x 2x sqrt 14*** 2x sqrt 7 sqrt 14x2 3. Simplify the radical expression. sqrt 490y^5w^6 2 sqrt 135y^2 2y sqrt 135*** 27

Math
Which is the exact value of the expression sqrt 32 sqrt 50 + sqrt 128 2 sqrt 7 7 sqrt 2 22 sqrt 2 2 sqrt 55

Calculus
In these complex exponential problems, solve for x: 1)e^(i*pi) + 2e^(i*pi/4)=? 2)3+3=3i*sqrt(3)=xe^(i*pi/3) MY attempt: I'm not really sure of what they are asking. For the 1st one I used the e^ix=cos(x)+i*sin(x) and got 1+sqrt(2) +sqrt(2)i 2) I solved

Algebra
Which of these expressions is in simplified form? A. a ^3 sqrt 4  b ^3 sqrt 2 / 2 B. sqrt 1/2x + sqrt 1/2z C. x^2  3x sqrt y / sqrt 3 D. sqrt 125x  x^2

Calculus
show lim x>3 (sqrt(x)) = (sqrt(c)) hint: 0< sqrt(x)sqrt(c)= (xc)/(sqrt(x)+sqrt(c))

Calculus
show lim x>3 (sqrt(x)) = (sqrt(c)) hint: 0< sqrt(x)sqrt(c)= (xc)/(sqrt(x)+sqrt(c))

Math
1. The length of the hypotenuse of a 306090 triangle is 7. Find the perimeter. A) 7/2+21/2 sqrt 3 B) 21+7 sqrt 3 C) 7+21 sqrt 3 D) 21/2 + 7/2 sqrt 3 Could someone please help me, I don't know how to do this. Thank you!

Calculus
Evaluate the integral by changing to spherical coordinates. The outer boundaries are from 0 to 1. The middle one goes from sqrt(1x^2) to sqrt(1x^2) The inner one goes from sqrt(1x^2z^) to sqrt(1x^2z^) for 1/sqrt(x^2+y^2+z^2) dydzdx I don't

MATH
For each set of numbers, draw your own number line on a piece of paper, taking care to plot each pair of irrational numbers. Then write a statement comparing the position of the two given numbers on a number line. Also write an inequality comparing the two

Calculus  Second Order Differential Equations
Solve the initialvalue problem. y'' + 4y' + 6y = 0 , y(0) = 2 , y'(0) = 4 r^2+4r+6=0, r=(16 +/ Sqrt(4^24(1)(6)))/2(1) r=(16 +/ Sqrt(8)) r=8 +/ Sqrt(2)*i, alpha=8, Beta=Sqrt(2) y(0)=2, e^(8*0)*(c1*cos(0)+c2*sin(0))=c2=2 y'(0)=4, c2=4

Algebra 2
Operations with Complex Numbers Simplify. 1. sqrt(144) 2. sqrt(64x^4) 3. sqrt(13)*sqrt(26) 4. (2i)(6i)(4i) 5. i13 6. i38 7. (5 – 2i) + (4 + 4i) 8. (3 – 4i) – (1 – 4i) 9. (3 + 4i)(3 – 4i) 10. (6 – 2i)(1 + i) 11. (4i)/(3+i) 12. (10+i)/(4i)

Algebra 2
Simplify the number using the imaginary unit i. (sqrt)of 28 •2(sqrt)7 •2 (sqrt)7 •i (sqrt)28 •2i (sqrt)7

Math(Roots)
sqrt(24) *I don't really get this stuff.Can somebody please help me? The square root of 24 is 4.898979485566356 I know that..lol,but it says not to use decimals.Here is an example they gave me. Ex.sqrt(18)=sqrt(2*3*3)=3sqrt(2) sqrt[24] = sqrt[4*2*3] =

TRig WIth LoGs help1!!
i have problem i can't solve and the book is no help.. anyone got osme hints or somehting i could start off doing? the problem is... Solve for x: log(x^3)= (log x)^3 Rewrite it as 3 log x = (log x)^3 The use algebra (divide each side by log x) to get (log

Inequality
When I solve the inquality 2x^2  6 < 0, I get x < + or  sqrt(3) So how do I write the solution? Is it (+sqrt(3),sqrt(3)) or (infinity, sqrt(3))? Why? Thanks. So would this work? abs x < ( sqrt 3 ) or  sqrt 3

MATH
I need to simply this equation, but I got stuck. h/(4sqrt(16+h)) = y First, I multiplied (4+sqrt(16+h)/(4+sqrt(16+h) to both sides, and I ended up with h(4+sqrt(16+h)/h. Is this correct? (I tried to graph both equations to see if I would get the same

Calculus  Second Order Differential Equations
Posted by COFFEE on Monday, July 9, 2007 at 9:10pm. download mp3 free instrumental remix Solve the initialvalue problem. y'' + 4y' + 6y = 0 , y(0) = 2 , y'(0) = 4 r^2+4r+6=0, r=(16 +/ Sqrt(4^24(1)(6)))/2(1) r=(16 +/ Sqrt(8)) r=8 +/ Sqrt(2)*i,

Math
So I am supposed to solve this without using a calculator: Sqrt[20]/10  Sqrt[10]/Sqrt[32]  Sqrt[0.3125] + Sqrt[3 + 1/5] You can put this into WolframAlpha as is to make it prettier. Answer given is 1/2 * SQRT(5) I really don't know where to start here. I

Surds
Solve in the exact form. (sqrt of 4x+1)+(sqrt of x+1)=2 Someone showed me to do this next: Square both sides..so.. 4x+1+2((sqrt of 4x+1)•(sqrt of x+1))=4 I do not understand where the 2 come from ..and why do we need to multiply the sqrt of 4x+1 and sqrt

Logarithms
I'm working on logarithmic equations and I'm stuck on how my book arrives at the next step. First, they use the change of base formula on, log(sqrt(2))(x^3  2) (sqrt(2)) is the base,changing to base 2 log(sqrt(2))(x^3  2)= log2(x^3  2)/(log2(sqrt(2)) I

algebra
Simplify: sqrt (21) (sqrt(7) + sqrt(3)) a) 7 sqrt (3) + 3 sqrt(7) b) 7 sqrt(3) + sqrt (3) c) sqrt (210) d) sqrt (147) + sqrt (63)''. a

ap calculus
Which of the following definite integrals gives the length of y = e^(e^x) between x=0 and x=1? All the answers are preceded by the integral sign from 0 to 1. (a) sqrt[1 + e^(2*(x+e^x))] dx (b) sqrt[1 + e^(4x)] dx (c) sqrt[1 + e^(x+e^x)] dx (d) sqrt[1 +

Calculus
Evaluate the integral by changing to spherical coordinates. The outer boundaries are from 0 to 1. The middle one goes from sqrt(1x^2) to sqrt(1x^2) The inner one goes from sqrt(1x^2z^) to sqrt(1x^2z^) for 1/sqrt(x^2+y^2+z^2) dydzdx I don't

linear algebra urgent
For the orthogonal matrix A = 1/sqrt(2) 1/sqrt(2) 1/(sqrt(2)) 1/sqrt(2) verify that (Ax,Ay)=(x,y) for any vectors x and y in R2. Can someone please explain this

Algebra
x^1/2 * y^1/6 *z^1/5. We are to use rational exponents to write an expression. The sqrt of x  the sqrt of y, over the sqrt of x + the sqrt of y. I need to simplify and use radicals as needed. I obviously do but what...?? Please assist. Thank you.

Math sequence
Let {An} be the sequence defined recursively by A1=sqr(2) and A(n+1) = sqr(2+An) for n is bigger and equal to 1. Show that An < 2. What is An? and how do I find it? Thank you for your time. An is the nth number in the sequence, and is defined by the

rationalizing
sqrt(18)  sqrt(17) How does this expression equal 1/(sqrt(18) + sqrt(17)) ? How would you change it like that? And why is this good to use when not using a calculator?

algebra
can someone tell me if i did the problem correct (solve by completing the square) 4x^2+2x3=0 x^2+(1/2)=3/4 x^2+(1/2)+(1/4)^2=3/4+(1/4)^2 (x+1/4)^2=13/16 x+1/4=+sqrt 13/16 x+1/4=+sqrt 13/4 x=1/4+sqrt 13/4 x=1+sqrt 13/4

Calculus
so we are doing integrals and I have this question on my assignment and I can't seem to get it, because we have the trig substituion rules, but the number isn't even so its not a perfect square and I just cant get it, so any help would be greatly

Math Help please!!
Could someone show me how to solve these problems step by step.... I am confused on how to fully break this down to simpliest terms sqrt 3 * sqrt 15= sqrt 6 * sqrt 8 = sqrt 20 * sqrt 5 = since both terms are sqrt , you can combine them. sqrt 3* sqrt 15=

math,algebra,help
Directions are simplify by combining like terms. x radiacal 18 3 radical 8x^2 can someone show me how to do these types of problems. thanks I cant determine the second term. For the first, I think you meant x sqrt(18) which reduces to x sqrt (9*3) or 3x

Calculus
Evaluate the indefinite integral: 8xx^2. I got this but I the homework system says its wrong:sqrt((x8)x)/(2*sqrt(x8)*sqrt(x))*(((sqrt(x8)*(x4)*sqrt(x))32*log(sqrt(x8)+sqrt(x))

Math
How do you find a square root of a number that's not a perfect square? I'm very confused. The book doesn't explain it too well. You can approximate it or simplify it in terms of (products of) square roots of smaller numbers. E.g. consider sqrt[117] The

Calculus
Please look at my work below: Solve the initialvalue problem. y'' + 4y' + 6y = 0 , y(0) = 2 , y'(0) = 4 r^2+4r+6=0, r=(16 +/ Sqrt(4^24(1)(6)))/2(1) r=(16 +/ Sqrt(8)) r=8 +/ Sqrt(2)*i, alpha=8, Beta=Sqrt(2) y(0)=2, e^(8*0)*(c1*cos(0)+c2*sin(0))=c2=2

Calculus
S=Integral xdx/sqrt(x1). I have proceeded thus Put sqrt(x1)=u then x=u^2+1 and dx/sqrt(x1)=2du. S=(u^2+1)2du/u =(2u+2/u)du=u^2+2 log u +C =(x1)+ 2 log sqrt(x1)=(x1)+log(x1)+C Required answer is 2/3*(x+2)sqrt(x1)+C Have I proceeded correctly and if

Algebra
Evaluate sqrt7x (sqrt x7 sqrt7) Show your work. sqrt(7)*sqrt(x)sqrt(7)*7*sqrt(7) sqrt(7*x)7*sqrt(7*7) sqrt(7x)7*sqrt(7^2) x*sqrt 7x49*x ^^^ would this be my final answer?

Math/Calculus
Solve the initialvalue problem. Am I using the wrong value for beta here, 2sqrt(2) or am I making a mistake somewhere else? Thanks. y''+4y'+6y=0, y(0)=2, y'(0)=4 r^2+4r+6=0, r=(4 +/ sqrt(164(1)(6))/2 r=2 +/ sqrt(2)*i , alpha = 2, beta = 2(sqrt(2))

Algebra 2: Radicals URGENT!!
Could some kind, saintly soul help me solve this problem? Simplify: 8w sqrt(48w^5)  x^2 sqrt(3xw^2) . . =8w(√16)(√3)(√w^4)(√w)  x^2(√3)(√x)(√w^2) =32w^3(√3w)  wx^2(√3x) not much of a "simplification" really 8w sqrt(16*3w^5)  x^2 w

math;)
Find the unit vector in the direction of u=(3,2). Write your answer as a linear combination of the standard unit vectors i and j. a. u=3[sqrt(13)/13]i+2[sqrt(13)/13]j b. u=3[sqrt(5)/5]i+2[sqrt(5)/5]j c. u=3[sqrt(5)/5]i2[sqrt(5)/5]j d.

algebra,math,help
Use Property 2 to simplify each of the following radical expressions. sqrt (10)/ sqrt(49) My answer: sqrt (10) / (7) THis next one i need help: Use the properties for radicals to simplify each of the following expressions. Assume that all variables

Calculus
Could someone please explain this to me? Differentiate. h(u)= 10^(sqrt(u)) h'(u)= 10^(sqrt(u))*log(10)(d/du(sqrt(u))) h'(u)= 10^(sqrt(u))*((1)/(2*sqrt(u)))*log(10)

math calculus please help!
l = lim as x approaches 0 of x/(the square root of (1+x)  the square root of (1x) decide whether: l=1 or l=0 or l=1 Let me make sure I understand the question. Do we have lim x>0 x/[sqrt(1+x)  sqrt(1x)] ? If so then multiply the expression by

Mathematics
sqrt 6 * sqrt 8 also sqrt 7 * sqrt 5 6.92820323 and 5.916079783 So you can see the steps — sqrt 6 * sqrt 8 = sqrt 48 sqrt 7 * sqrt 5 = sqrt 35 I hope this helps a little more. Thanks for asking.

Calculus 3
I need help writing the series 4 + 1/5 + .3 + 1/(3 + sqrt 2) + 1/(9+ sqrt 3) + 1/(27 + sqrt 4) + 1/(81 + sqrt 5 .... I have played with using irrational numbers, natural log and a vast variety of exponential arrangements. Any help to get me going in the

Algebra
Solve for s: h=(square root of 3)times s/2 and solve for h V= (pi)r squared h / 3 Solve for s: h=(square root of 3)times s/2 Multiply both sides by 2. 2h = (sqrt 3)*s*2/2 which cancels the 2 on the right. 2h = (sqrt 3)*s Now divide the right side by

some algebra help (radicals)
I hope I am writing this down right.. I am trying to do some practice questions to learn 10^5 (sqrt)2y  4^5 (sqrt)2y I am trying to figure out how to solve this They gave us some answers to choose from, but I am clueless on how to solve this 6y ^5 (sqrt)2

math help
15sqrt8x^15/5sqrt2x^4 remember that sqrt(a)/sqrt(b) = sqrt(a/b) simplify the inside. also notice that sqrt(x^11) = sqrt(x^10) * sqrt(x) = x^5 * sqrt(x)

Algebra
Multiplying sq rts sqrt18a^7b times sqrt27a^8b^6 Jake 1214 18 = 9 * 2 then sqrt 18 = 3sqrt2 sqrt a^7 = a^3 * sqrt a 27 = 9 * 3 then sqrt 27 = 3 sqrt3 sqrt a^8 = a^4 sqrt b^6 = b^3 Now just multiply the liketerms together. 3sqrt6 and sqrt2a^4?

linear algebra check
Use the GramSchmidt process to transform the basis [1 1 1] , [0 1 1] , [2 4 3] for the Euclidean space R3 into an orthonormal basis for R3. (Enter each vector in the form [x1, x2, ...]. Enter your answers as a commaseparated list.) so i went through the

math
how would you simplify this equation: y = (x+3)/[(4sqrt(16+h))] please help me! you have three variables. I am not certain "simplify" is an appropriate term here. ohhhh it was my mistake. I meant: y = h/[(4sqrt(16+h))] y = h/[(4sqrt(16+h))] rationalize

Algebradrwls please check!
Posted by Megan on Tuesday, October 12, 2010 at 3:44pm. I have a question if someone could help, please explain it. Given b = 1 and h = 1, what is the equation of the graph if the parent function is y = sqrt (x) Answers: a.y = sqrt(x1) b.y = sqrt (x+1)

calculus
prove that d/dx 4x .√(x + √x) = 6x+5 (x)1/2/√(x + √x) solution is d/dx 4x.[x+(x)1/2]1/2 = d/dx 4x.[x+(x)^1/2]^1/2 d/dx 4x.[x+(x)^1/2]^1/2 Product Rule = 4x[1/2(x+(x)^1/2)^1/2 * (1+1/2x^1/2) +[x+(x)^1/2]^1/2*4 d/dx(4 x sqrt(x+sqrt(x))) = (2 (1/(2

Algebra
I have a question if someone could help, please explain it. Given b = 1 and h = 1, what is the equation of the graph if the parent function is y = sqrt (x) Answers: a.y = sqrt(x1) b.y = sqrt (x+1) c.y =  sqrt (x1) d.y = sqrt(x1) I think it is "b"

Math
Hello! If you can help me with these 3 questions I would love it! 1. How do you simplify sqrt5 + 6 sqrt 5? I think that it is 5 sqrt10. Am I correct? 2. 5 sqrt 7 +2 sqrt 175. I think the answer is 7 sqrt 182 3. What is the domain of this function y = sqrt

Calculus check
Given f(x)=x^4(2x^215). On what interval(s) is the graph of f concave upwards? A. (0, sqrt(3)) B. (sqrt(3), 0) C. (sqrt(3), 0) and (0, sqrt(3)) D. (sqrt(3), sqrt(3)) E. (Negative infinity, sqrt(3)) and (sqrt(3), infinity) I got E

math problem
I'm trying to get a handle on what square roots are (I think that's what they are called). Here is an example. 4(almost like a division sign but it is more like a check mark)3. I don't understand what it is, its a square root? and How do I deal with these

algebra
Simplify 11 sqrt 112. 44 sqrt 7******** 176 sqrt 7 27 sqrt 7 4 sqrt 7 Is this right? and I need to show my work, idk the steps

radical equation
2^x+20=15+3^x A)1 B)16 C)5 D)25 I chose c but i got it wrong i am having a problem understanding it. Let me rewrite the question in a more standard format. 2* sqrt(x)+20=15 + 3*sqrt(x) where * means multiply, and sqrt means the square root. Your use of ^

math,correction
simplify: sqrt ((7)/(100)) my work: 7 = 1sqrt (7) 100= 10 sqrt (1) (1)/(10) sqrt (7) my answer: (sqrt (7))/(10) Your answer is right but your statements: 7 = 1sqrt (7) 100= 10 sqrt (1) make no sense. how can sqrt(7)=7 ? you are saying 2.6457..=7 and

math
solve 2x^2+3x+8=0 and express the solutions in a+bi form. Let's use the quadratic formula to solve for x and express those solutions in a+bi form. x = [b + or  sqrt(b^2  4ac)]/2a Note: sqrt = square root. a = 2, b = 3, and c = 8 from your problem.

Algebra
1 last square root : Rationalize the denominator 5/sqrt[3]+sqrt[5]= 5*sqrt[3]sqrt[5]/ sqrt[3]sqrt5[5]*sqrt[3]sqrt[5]= 5sqrt[3]5sqrt[5]/sqrt[9]sqrt[15]+sqrt[15] sqrt[25]= 5sqrt[3]5sqrt[5]/16 = 5sqrt[3]5sqrt[5]/ 2

Math:)
1. Evaluate tan[sin^1(a)]. a. [sqrt(1a^2)]/1a^2 b. [sqrt(1a^2)]/a c. sqrt(1a^2) d. {a[sqrt(1a^2)]}/1a^2 I do not know the steps to find this answer and am not provided with a textbook. I have researched online some what, but I cannot seem to

Math
Find of g(f(x)) when f(x)=sqrt(x+3) and g(x)=(x^2+2)/x. a. g(f(x))=(x^2+2)(sqrt(x+3))/x b. g(f(x))=(x+5)/(sqrt(x+3)) c. g(f(x))=(x^2+6x+11)/(sqrt(x+3)) d. g(f(x))=(sqrt(((x^2+2)/x)+3) Every time I work this problem, I get some crazy answer. Can someone

algebra
simplify by combining like terms: x sqrt(18)  3 sqrt(8x)sqrd If means [sqrt(8x)]^2, then that also equals 8x. So x sqrt(18)  3 sqrt(8x)sqrd = x[sqrt(9*2)3*8] = 3x(sqrt 2 3

Calculus URGENT test tonight
Integral of: __1__ (sqrt(x)+1)^2 dx The answer is: 2ln abs(1+sqrt(x)) + 2(1+sqrt(X))^1 +c I have no clue why that is! Please help. I used substitution and made u= sqrt(x)+1 but i don't know what happened along the way! Your first step was a good one.

math,correction
the problem reads: evaluate sqrt (4) if possible. my answer: sqrt (4)

algebra
simplify: square root of 5 + square root of 20  square root of 27 + square root of 147. simplify: 6/4square root of 2 sqrt 5 + sqrt 20  sqrt 27 + sqrt 147 = sqrt 5 + sqrt (4*5)  sqrt (3*9) + sqrt (49*3) = 3 sqrt 5  3 sqrt 3 + 7 sqrt 3 = 3 sqrt 5 + 4

Real Analysis (Math)
Prove: [1/sqrt(2)] [sqrt(a) + sqrt(b)]

Math
How would I do: sqrt32a^8b + sqrt50a^16b Are the exponents 8b and 16b or 8 and 16? I'll assume they are 8a and 16a sqrt 32 = sqrt (16*2) = 4 sqrt 2 sqrt 50 = sqrt (25*2) = 5 sqrt 2 sqrt32 a^(3b) + sqrt50a^(2b) = sqrt2*a^(8b)[4 + 5(a^8b)] There are many

differantiation
Determine dy/dx if: (i) Y= sqrt x^sqrt x (ii) Y= xarcsin(x) + sqrt(1x) Please show all steps. Thanks 1) http://www.analyzemath.com/calculus/Differentiation/first_derivative.html 2) an antiderivative of arcsin(x) is xarcsin(x)sqrt(1x^2); are you certain

Calculus (Area Between Curves)
Find the area of the region bounded by the curves y=x^(1/2), y=x^(2), y=1 and y=3. You get: a.) 1/2(sqrt(3)) + 4/3 b.) 2(sqrt(3))  8/3 c.) 1/2(sqrt(3)  32/3 d.) 2(sqrt(3))  32/3 e.) 8/3  2(sqrt(3))

algebra
simplify: sqrt (28) a) 4 sqrt (7) b) 7 sqrt (2) c) 2 sqrt (7) d) sqrt (7) c im just making show that they are correct sorry for posting up so many

Calc
1. The problem statement, all variables and given/known data cos(x) = 2 I was trying to solve that problem ignoring what people say about it not being defined and got a number strangely. I showed step by step so you can tell me what I did wrong as I don't

CALC
1. The problem statement, all variables and given/known data cos(x) = 2 I was trying to solve that problem ignoring what people say about it not being defined and got a number strangely. I showed step by step so you can tell me what I did wrong as I don't

math
d/dx x(1+y)^(1/2) + y(1+x)^(1/2)=0. Can some1 show me the calculation because i didn't get like the answer. [ans=1/(1+x)^2 but my calculation=(sqrt(y+1) (2 sqrt(x+1) sqrt(y+1)+y)/(sqrt(x+1) (2 sqrt(x+1) sqrt(y+1)+x)]

math
d/dx x(1+y)^(1/2) + y(1+x)^(1/2)=0. Can some1 show me the calculation because i didn't get like the answer. [ans=1/(1+x)^2 but my calculation=(sqrt(y+1) (2 sqrt(x+1) sqrt(y+1)+y)/(sqrt(x+1) (2 sqrt(x+1) sqrt(y+1)+x)]

Calculus
Evaluate the integral by changing to spherical coordinates. The outer boundaries are from 0 to 1. The middle one goes from sqrt(1x^2) to sqrt(1x^2) The inner one goes from sqrt(1x^2z^) to sqrt(1x^2z^) for 1/sqrt(x^2+y^2+z^2) dydzdx I don't

Calculus
Evaluate the integral by changing to spherical coordinates. The outer boundaries are from 0 to 1. The middle one goes from sqrt(1x^2) to sqrt(1x^2) The inner one goes from sqrt(1x^2z^) to sqrt(1x^2z^) for 1/sqrt(x^2+y^2+z^2) dydzdx I don't

Calculus
Graph the curve and find its exact length. x = e^t + e^t, y = 5  2t, from 0 to 3 Length = Integral from 0 to 3 of: Sqrt[(dx/dt)^2 + (dy/dt)^2] dx/dt = e^t  e^t, correct? dy/dt = t^2  5t, correct? So: Integral from 0 to 3 of Sqrt[(e^t  e^t)^2 +

algebra
1.what is the simplest form of the producy sqrt 50x^7y^7 * sqrt 6 xy^4 2. What is the simplest form of the radical expression 4^3 sqrt 3x + 5^3 sqrt 10x 3. What is the simplest form of the radical expression sqrt 2 + sqrt5 / sqrt 2  sqrt 5 if someone

Math  Complex Numbers
Could someone show me how to get the work for: 3/4 (sqrt)16/25 ? The answer says 3/5i. Could anybody tell me how to get there and work with complex fractions and simplify them? Thanks! 3/4 SQRT(16/25) 3/4 SQRT( 16/25*1) 3/4 *4/5 *SQRT( 1) but the sqrt

Math
For f(x) = 2sinx + (sinx)^3 + tanx find f'(pi/3). Ok, so what I tried was... f'(x) = 2cosx + cosx(3(sinx)^2) + (sinx/cosx) pi/3 = (1/2, sqrt(3)/2) therefore, 2(1/2) + 1/2(3(sqrt(3)/2)(sqrt(3)/2) + (sqrt(3)/2 (2/1)) 1 + .5(3 (3/4)) + sqrt(3) 1 + .5(9/4) +

Calculus
Find the area cut off by x=4 from the hyperbola x^2/9y^2/4=1. Answer is 4.982 in the book. I have proceeded as under: Y=2/3*sqrt(x^29) and rhe reqd. area is double of integral 2/3*sqrt(x^29) from 3 to 4. Int= 2/3*[xsqrt(x^29)/2 –

is this correct? math
find the domain of the real valued function; f(x) = sqrt(5  (sqrtx)) my solution: 5  (sqrt x) >=0 (sqrt x) >= 5 (sqrt x)

Quantum Physics
I try to make a Quantum Fourier Transformation with N=6: w=e^(2*pi*7/6) so we have 6th roots: 1,w,w^2,1,w,w^2 My matrix is QFT6= 1/sqrt(6)* (1 1 1 1 1 1 ) (1 w w^2 1 w w^2) (1 w^2 w 1 w^2 w ) (1 1 1 1 1 1 ) (1 w w^2 1 w w^2 ) (1 w^2 w 1

horizontal tangent
f(x) = sqrt(x^2 + 0.0001) At x = 0, which of the statements is true. a)f is increasing b)f is discontinuous c)f has a horizontal tangent d)f' is undefined Answer is c but why? f(x,y) = sqrt(x^2 + y) g(x,y) = df/dx = 1/(2*sqrt[x^2 + y]) * 2x = x/sqrt[x^2 +

algebra
Rationalize the denominator, assume that all expressions under radicals represent postive numbers. sqrt:a  sqrt:b/sqrt:a + sqrt:b

algebra
I asked a question and it was answered by Steve. He had the numbers wrong. The problem should be sqrt of 18 over (sqrt of 8)3. not sqrt of 18 3. I got 2+sqrt of 8. Is it correct?

precal
Find the roots of the function f(x)= x^2+2x+2 Determine f(x) a) (x+1i)(x+1+i) b)(x+1i sqrt of 2)(x+1+i sqrt of 2) c)x1+i)(x1i) d)x1+i sqrt of 2) (x1i sqrt of 2) Please Help! For all of these, use the rule [f(x) + ai]*[(f(x)  ai} = [f(x)]^2 + a^2

math
determine the area of triangle abc when side ab= square root of x, side bc= square root of x, and side ca= the square root of the square root of x. So how do I solve it. How do I add the square root of x + the square root of x + the square root of the

Math/Calculus #2
Integrate: 1/(xsqrt(x+2) dx I came up with: (2/3)(2*ln((sqrt(x+2))2)+ln((sqrt(x+2))1)) but it keeps coming back the wrong answer even though I integrated correctly. Is there a way to simplify this answer, and if so, how? I found: Ln[xsqrt(x+2)] +

Math
Simplify the product. 9 sqrt 28a^2 * 1/3 sqrt 63a I came until 3 sqrt 49a^2 * sqrt 36a, but then I got confused...

Calculus  Integrating
Question: ∫(x^2)/sqrt(x^2+1) u=x^2+1 , x^2= u1, du=2xdx ∫(u1)/sqrt(u) , expand ∫u/sqrt(u)  1/sqrt(u) Integrate: 2/3(u^(3/2))  2u^(1/2) + c My answer: [ 2/3(x^2+1)^(3/2)  2(x^2+1) + c ] When I took the derivative of this to check my answer, it

Math
Use a halfangle identity to find the exact value of tan 15° a. √ 7+4 sqrt 2 b. √ 7+4 sqrt 3 c. √ 74 sqrt 2 d.√ 74 sqrt 3

Algebra  sqrts
Square roots. Woohoo. Want to check some work I did. 1. Perform indicated operations 3sqrt[3]+2sqrt[27]sqrt[12] 3sqrt[3]+2sqrt[3*9]sqrt[2*6] 3sqrt[3]+3*2sqrt[3]2sqrt[3] 3sqrt+6sqrt[3]2sqrt[3] = 7sqrt[3] 2.Simplify sqrt[49x^12y^4z^8] = 7x^6y^2z^4

Math
f(x)= 4x^2 and g(x)= sqrt (x) find the implied domain of fg(x) fg(x)= f(sqrt(x)) fg(x)= 4(sqrt(x))^2 fg(x)=4(sqrt x)(sqrt x) fg(x)=4x domain= (x:x=all real numbers) Am I correct?

Algebra 1
Combine the following into a single expression of the form a x sqrt b. Sqrt 6 + Sqrt 54 + Sqrt 150

radical expression
What is the radical expression of 1. (11)^3/2 2. 2^(1.5) Thanks I will do one. the exponent 3/2 means sqrt of something cubed. So (11)^3/2 = 1/(11)^ 3/2 =1/ sqrt 11^3 = 1/ sqrt (11^2 * 11)= 1/ (11 sqrt 11)