Comicbook superheroes are sometimes able to punch holes through steel walls. (a) If the ultimate shear strength of steel is taken to be 3.00 x 10^9 Pa, what force is required to punch through a steel plate 1.90 cm thick?
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Physics (Stress & Strain)
A hole 3cm in diameter is to be punched out of a steel plate 8cm thick. The shear stress of the material is 670GPa. What load is required on the punch? 3cm = 0.03m 8cm = 0.08m Lateral surface area (As) = pi*D*h = 3.1416 * .03m * .08m = 3.1416 * .0024m =

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A die is designed to punch holes of radii 2.17 x 102 m in a metal sheet that is 5.53 x 103 m thick. To punch through the sheet, the die must exert a shearing stress of 3.5 x 108 Pa. What force must be applied to the die? (Hint: Consider carefully which

physics
Comicbook superheroes are sometimes able to punch holes through steel walls. (a) If the ultimate shear strength of steel is taken to be 3.00 x 10^9 Pa, what force is required to punch through a steel plate 1.90 cm thick? Assume the superhero's fist has

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What is the factor of safety of a steel hanger having an ultimate strength of 630.000MPa and supporting a load of 65000.000N. The steel hanger in question has a cross sectional area of 5.300cm. ANS = (Round to 3 decimal places) Load = 65000.000N ultimate

Physics (Stress & Strain)
What is the factor of safety for a steel hanger having an ultimate strength of 70000N per cm^2 and supporting a load of 87500N. The hanger has a cross sectional area of 5cm^2. Factor of safety = ultimate stress/ allowable stress = 70000/87500 = 0.8 Have I

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1.A 500.0 g mass is placed on a 20.0 cm cube of gelatin. The 500.0 g mass (a 5.00 cm diameter disk) depresses the gelatin 0.243 mm. What is Young's modulus for this gelatin? ____________N/m^2 Later, a 2.00 kg mass disk (5.00 cm in diameter) is placed on

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1.A 500.0 g mass is placed on a 20.0 cm cube of gelatin. The 500.0 g mass (a 5.00 cm diameter disk) depresses the gelatin 0.243 mm. What is Young's modulus for this gelatin? ____________N/m^2 Later, a 2.00 kg mass disk (5.00 cm in diameter) is placed on

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Physics (Stress & Strain)
A hole 3cm in diameter is to be punched out of a steel plate 8cm thick. The shear stress of the material is 670GPa. What load is required on the punch? First find the area: A = pi*d^2/ 2 = 3.1416 * 3cm^2/ 2 = 3.1416 * 9/ 2 = 28.2744/ 2 = 7.0686cm Stress =

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Comicbook superheroes are sometimes able to punch holes through steel walls. (a) If the ultimate shear strength of steel is taken to be 2.90 109 Pa, what force is required to punch through a steel plate 2.10 cm thick? Assume the superhero's fist has

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If the ultimate shear strength of steel is taken to be 2.00 109 Pa, what force is required to punch through a steel plate 1.60 cm thick? Assume the superhero's fist has crosssectional area of 1.20 102 cm2 and is approximately circular. answer in Newtons

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Assume that if the shear stress in steel exceeds about 4.00 108 N/m2, the steel ruptures. (a) Determine the shearing force necessary to shear a steel bolt 1.40 cm in diameter. (b) Determine the shearing force necessary to punch a 1.75cmdiameter hole in a

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help my son's math
Sofia had 20 comic book and gave some of them to Heather.She uses a calculator to figure out that she gave away 0.15 of her comic book.How many comic book did she give to Heather!

math
Marco purchased a large box of comic books for $300. He gave his brother 15 comic books and sold the rest on the internet for $330, making a profit of $1.50 on each one. How many comic books were in the box? What was the original price of each comic book,

physics
1.A 500.0 g mass is placed on a 20.0 cm cube of gelatin. The 500.0 g mass (a 5.00 cm diameter disk) depresses the gelatin 0.243 mm. What is Young's modulus for this gelatin? ____________N/m^2 Later, a 2.00 kg mass disk (5.00 cm in diameter) is placed on

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A steel bar with a cross sectional area of 25cm2 is found to shear fracture when subjected to a tensile load of 400kN. calculate the limiting shear stress of the bar.

mechanics of materials
A steel bar with a cross sectional area of 25cm2 is found to shear fracture when subjected to a tensile load of 400kN. calculate the limiting shear stress of the bar.

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What is the factory of safety of a steel hanger having an ultimate strength of 630.000MPa and supporting a load of 61000.000N. The steel hanger in question has a cross sectional area of 6.500cm^2. ANS = (Round to 3 decimal places) 6.500cm = 0.065m Load =

Physics(Stress&Strain)
What is the factor of safety of a steel hanger having an ultimate strength of 630.000MPa and supporting a load of 65000.000N. The steel hanger in question has a cross sectional area of 5.300cm. ANS = (Round to 3 decimal places) Load = 65000.000N ultimate

Physics
What is the factor of safety of a steel hanger having an ultimate strength of 630.000MPa and supporting a load of 65000.000N. The steel hanger in question has a cross sectional area of 5.300cm. ANS = (Round to 3 decimal places) Load = 65000.000N ultimate

Physics
What is the factor of safety of a steel hanger having an ultimate strength of 630.000MPa and supporting a load of 65000.000N. The steel hanger in question has a cross sectional area of 5.300cm. ANS = (Round to 3 decimal places) Load = 65000.000N ultimate

Physics
What is the factor of safety of a steel hanger having an ultimate strength of 630.000MPa and supporting a load of 65000.000N. The steel hanger in question has a cross sectional area of 5.300cm. ANS = (Round to 3 decimal places) Load = 65000.000N Ultimate

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What is the factor of safety of a steel hanger having an ultimate strength of 550.000MPa and supporting a load of 79000.000N. The steel hanger in question has a cross sectional area of 7.000cm^2. ANS = (Round to 3 decimal places) ultimate strength =

Physics (Stress & Strain)
What is the factor of safety of a steel hanger having an ultimate strength of 550.000MPa and supporting a load of 79000.000N. The steel hanger in question has a cross sectional area of 7.000cm^2. ANS = (Round to 3 decimal places) ultimate strength =

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A hole 3cm in diameter is to be punched out of a steel plate 8cm thick. The shear stress of the material is 670GPa. What load is required on the punch? 3cm = 0.03m 8cm = 0.08m Lateral surface area (As) = pi*D*h = 3.1416 * .03m * .08m = 3.1416 * .0024m =

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What is the factor of safety of a steel hanger having an ultimate strength of 550.000MPa and supporting a load of 64000.000N. ANS= Round to 3 decimal places Where do I begin?

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The Ultimate strength of a round steel rod is 630.000MPa. If a factor of safety of 5.000 is required, what is the maximum permissible load for the rod if it has a diameter of 3.000cm? ANS = kN (Round to 3 decimal places) Safety = 5.000 Rod diameter =

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The ultimate strength of a steel rod is 600.000MPa. if the factor of safety 3.000 is required, what is the maximum permissible load for the rod if it has a diameter of 6.000cm? ANS = kN (Round to 3 decimal place) Ultimate strength = 600.000MPa =