A beaker contains 100 grams of 1.20 M NaCl. If you transfer 50% of the solution to another beaker, what is the molarity of the solution remaining in the first beaker?
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Plese tell me if these are right. A 15.0mL sample of NaCl solution has a mass of 15.78g. After the NaCl is evaporated to dryness, the dry salt residue has a mass of 3.26g. Calculate the following concentrations for the NaCl solution. a. %(m/m)= 3.26 x 100

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The molarity of a solution prepared by dissolving 15.0 grams of NaCl in 100 mL water is 0.15 M. True or False

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A beaker contains 100 grams of 1.20 M NaCl. If you transfer 50% of the solution to another beaker, what is the molarity of the solution remaining in the first beaker?

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Silver nitrate (AgNO3) reacts with sodium chloride as indicated by the equation AgNO3 + NaCl → AgCl + NaNO3 . How many grams of NaCl would be required to react with 132 mL of 0.719 M AgNO3 solution? Answer in units of grams.

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Complete the following table by replacing question marks with the correct numbers: (Note: Each horizontal row is a separate example, so in row #1, 175.32 grams of NaCl is how many moles of NaCl and how many molecules of NaCl does it contain?)Grams of NaCl

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Complete the following table by replacing question marks with the correct numbers: (Note: Each horizontal row is a separate example, so in row #1, 175.32 grams of NaCl is how many moles of NaCl and how many molecules of NaCl does it contain?) Grams NaCl

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You have 120.0 mL of a 0.245 M solution of NaCl in an open beaker. After several days, you test the solution and find that it now has a concentration of 0.348 M. How much water must have evaporated from the beaker given the new concentration?

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1. Not sure of how to do the calculations... Make a 0.200 m solution of NaCl in a 100. mL volumetric flask. ... Solution A's question or statement is the same but with M (molarity) Is this right? The small m means molality. If it were changed to capital M,

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1) If exactly 100.0 grams of NaCl (mm=58.44g/mol) are dissolved in 300 grams of water (mm=18.02g/mol), the mole fraction of NaCl is? a) 1.71 b) 0.0932 c) 0.250 d) 0.103 e) 4.75 I did 100g / 100g + 300g = 100/40 = 0.250. Did I do this correctly?

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If there are 0.561 g of NaCl left in a beaker that originally contained 75.0 mL of saltwater, what must have been the molar concentration of the original solution? The molar mass of NaCl is 58.44 g/mol. Give your answer to 3 decimal places

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If exactly 100.0 grams of NaCl (molecular mass = 58.44 g/mol) are dissolved in 300 grams of water (molecular mass = 18.02 g/mol), the mole fraction of NaCl is a) 1.71 b) 0.0932 c) 0.250 d) 0.103 e) 4.75

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A student makes a solution by dissolving 55.8 grams of potassium hydroxide in 875.0 grams of water. The resulting solution has a density of 1.07 grams per milliliter. 1. What is the volume of this solution? 2. Calculate the % concentration of this

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Calculate the mass of NaCl required to cause dissolution of 0.010 moles of AgCl in 100 mL of solution. Consider that the addition of NaCl does not cause increased volume in the solution KSP (AgCl) = 1.0 x 10 ^ 10 KF (AgCl2) = 3.0 x 10 ^ 5 Answer This

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A student makes a solution by dissolving 55.8 grams of potassium hydroxide in 875.0 grams of water. The resulting solution has a density of 1.07 grams per milliliter. 1. What is the volume of this solution? 2. Calculate the % concentration of this

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A student makes a solution by dissolving 55.8 grams of potassium hydroxide in 875.0 grams of water. The resulting solution has a density of 1.07 grams per milliliter. 1. What is the volume of this solution? 2. Calculate the % concentration of this

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A student makes a solution by dissolving 55.8 grams of potassium hydroxide in 875.0 grams of water. The resulting solution has a density of 1.07 grams per milliliter. 1. What is the volume of this solution? 2. Calculate the % concentration of this