1)Write an equation for the parabola with focus (4,0) and directrix y=2 4c(y  k) = (x  h)^2 4(1)(y  1) = (x  4)^2 4y + 4 = (x  4)^2 4y = (x  4)^2  4
57,961 results
Pre Cal
write the equations of the parabola, the directrix, and the axis of symmetry. vertex: (4,2) focus: (4,6) if someone could explain how to do this problem then that would be great! thanks in advance! Formats to help you find the equation for a parabola: (x

pre cal
What is the center of the conic whose equation is x^2 + 2y^2  6x + 8y = 0 2.Which one of the following equations represents a hyperbola? (5 points) A) 3x^2 + y^2 + 12x  7 = 0 B) 3x^2 + 3y^2 + 12x  7 = 0 C) 3x^2 + y + 12x  7 = 0 D) 3x^2  3y^2 + 12x  7

algebra
Can someone check my answers please and if Im wrong please explain. 1) graph 4x^2+4y^2=64. what are the domain and range? domain;all real numbers range;4

Algebra 2
The equation of a parabola is 12y=(x1)^248. Identify the vertex, focus, and directrix of the parabola.

Math
Write an equation in standard form for each parabola. Vertex (0, 0) and directrix y = 6. y = 1/24x^2?

calculus
write the vertex form equation of each parabola. 1) Vertex:(5,8), Focus:(21/4, 8) 2) Vertex:(6,9), Directrix: x= 47/8 3)Vertex(8,1) y intercept: 17 4) Open left or right, Vertex: (7, 6), passes through:(11,9) 5)Focus(63/8, 7), Directrix: x= 65/8

algebra
Write an equation for a parabola with vertex at (3, 6) and focus at (3, 4)

maths
Given that the equation of the parabola is 5y^2 + 24x = 0. Find (1)The Axis and vertex of the parabola (ii)The focus and the directrix (iii)The distance from the directrix to the focus

precalculus
Find the focus, directrix, and focal diameter of the parabola. x2 = 5y focus (x, y) = 0, 5/4 directrix:y=5/4 focal diameter=5 Sketch its graph? my answers seem to be correct but i cannnot sketch the graph correctly.

Math
Please Check My Answers!!! What is the type of conic section is given by the equation x^29y^2=900 and what is the domain and range? Answer: Type is hyperbola, Domain is all real values of x, not sure what the range is. Please explain how to find these

Math
Write an equation for the parabola with focus (0, 0) and directrix y = 1. I got x^2  2y + 1, but how do I get it in the form y  k = 1/4p(x  h)^2?

MATH
What is the equation of the parabola with a directrix at y = 4 and focus (0, 4).

algebra
Write the equation for a parabola with vertex ( 2, 3) and focus ( 2, 1

algebra
6. Find the equation of each parabola described below. a) parabola with vertex (0,0) and the focus (0,7) b) parabola with focus (3,0) and directrix x=3 c) parabola with vertex (3,3) and directrix x=1 d) parabola with focus (2,1) and directrix y=5 e)

precalculus
Find the focus, directrix, and focal diameter of the parabola. 9x + 7y2 = 0 my answers were focus = 9/28,0 fd =9/7 directrix= 9/28 (this ans. is incorrect) what am I missing? pls help

precalculus
Find the focus, directrix, and focal diameter of the parabola. y2 = 8x

math
Write the standard equation for the parabola with the given characteristics. vertex:(0,0) directrix:y= 1.

Geometry
A parabola has a focus of F(2,8.5) and a directrix of y=9.5. The point P(x,y) represents any point on the parabola, while D(x,9.5) represents any point on the directrix. Maria was asked to use the distance formula to write an equation to represent this

Algebra 2
Use the distance formula to find the equation of a parabola. Focus: (6,0) and directrix X = 3 I know the distance formula is: √(xx1)^2+(yy1)^2 = √(xx2)^2+(yy2)^2 I know I need to sub (6,0) for x1,y1 and (3,y) for x2,y2 √(x6)^2+(y0)^2 =

Algebra2
Write an equation of a parabola with a vertex at the origin and a directrix at y=5. my answer is focus 6,0, directrix =6

precalculs
Explain what each of the following represents, and how equations (a) and (b) are equivalent. (a) y = a(x  h)2 + k, a ≠ 0 (b) (x  h)2 = 4p(y  k), p ≠ 0 (c) (y  k)2 = 4p(x  h), p ≠ 0 can you check my work and explain how equations (a) and (b) are

Math
Find the vertex, focus, and directrix of the parabola. x^2  2x + 8y + 9 = 0 x^2  2x +1 = 8y + 9+ 1 (x1)^2 = 8(y1.25) vertex:(1,1.25) focus:(1,.75) directrix: y=3.25 My teacher said that I have sign errors. I do not know where I went wrong.

math
Find the equation of the parabola with it's focus at (4,7) and directrix y=1 Is y+4=1/12(x4)^2 Right or is it y7=1/24(x=a)^2 y4=1/12(x+4)^2 y3=1/24(x+4)^2

CAlculuss
Find, in standard form, the equation of : the parabola with focus at (3,5) and directrix at x=1

Math
Find the vertex, focus and directrix of the parabola. 4x  y^2  2y  33 = 0 y^2+2y+1 = 4x+33+1 (y+1)^2 = 4(x+8.5) vertex:(1,8.5) focus:(2,8.5) Directrix: x=0 Is this correct?

Math
Find the vertex, focus, and directrix of the parabola. x^2  2x + 8y + 9 = 0 x^2  2x +1 = 8y + 9+ 1 (x1)^2 = 8(y1.25) vertex:(1,1.25) focus:(1,.75) directrix: y=3.25

Geometry
Prove that image of focus at any tangent to parabola lies on its directrix.

algebra
A few more question Id like for someone to check please. 1) what are the vertex, focus, and directrix of the parabola with the given equation? x^28x28y124=0 vertex (4,5) focus (0,7) directrix y=12 2) write an equation of a circle with given center and

precallcuslus
can you check my work and explain the last question because I do not uderstand. Explain what each of the following represents, and how y = a(x  h)2 + k, a ≠ 0 and (x  h)2 = 4p(y  k), p ≠ 0 are equivalent. The equation (x  h)2 = 4p(y  k), p ≠ 0

Algebra
I'm sure how to work the following problems cant anyone help? 1) Write an equation for the parabola with focus (4,0) and directrix y=2. What do I need to do before I graph the following equations? e1) 16x^2+9y^2=144 e2) x^2/9  (y+2)^2/9 = 1

Algebra
The directrix of a parabola is y=9 . The focus of the parabola is (2,5) . What is the equation of the parabola? y=−1/8(x−2)^2+7 y=1/8(x−2)^2−7 y=1/8(x−2)^2+7 y=−1/8(x−2)^2−7

CollegeCalc
a parabola has a focus of (3,4) and a directrix with equation: 3x4y25. Since the distance from the focus to a point (x,y) on the parabola is : squareroot (x+3)^2 +(74)^2 and is equal to the distance from the point (x.y) to the line which is 16x^2 +

precalculus
equation for parabola with focus (8,2) directrix x=4

precalculus
.Find the standard form of the equation of the parabola with focus(8,2) and directrix x=4

Math
Identify the equation of a parabola whose focus is at (5,1) and whose directrix is x=3. vertex=(5,1) p=6 4p=24 (x5)=(24)(y+1)^2 I got it wrong

Math
Identify th equation of the parabola whose focus is at (5,1) and whose directrix is x=3 I don't see any examples of this kind of problem. is this right? (x5)^2+(y+1)^2=(x3)^2 so 10x+25+y^2+2y+1=6x+9 4x=y^2+2y+17

math
write an equation for the parabola with focus (1,3) and vetex (0,3) See the paragraph Analytic Geometry Equations. You will have a choice of equations, you did not state whether the axis of symettry was parallel to x or y axis.

math
what will be the focus and directrix of parabola y*y = 16x.

math
If focus and directrix of a parabola are (3,4) and x+y+7=0 then its length of latuusrectum is?

algebra 2
Find the vertex, focus, axis, directrix and latus rectum of the parabola x^2+ y = 6x  14

maths
In case of parabola y= x^22x3 Find: a)Vertex: b)Axis: c)Focus: d)Directrix: e)Latus Rectum:

MATH! Urgent
umm suppose a parabola has a vertex at (0,2) and points (1,1) how would I derive the equation and focus, i've been trying to understand this for so long, I can't get it. Does this parabola have the equation (y2)^2 = x and a focus of 1/4?? Is that

algebra 2
Directions: The focus and directrix of a parabola are given. Write an equation for each parabola. (2,4) y = 6 May you explain the procedures on how to solve this equation? Please be detailed on each step.

Geometry
Can someone please help me with these? 1. What are the focus and directrix of the parabola with the equation y=1/12 xsquared 2. what is an equation of a parabola with a vertex at the origin and directrix y=19/4 3. What are the focus and directrix of the

PreCalculas check
Write the equation of the parabola 1.Vertex(2,5) Focus(2,3) 2.Directrix=x=3/4 Focus(5/4,3) For 1. i got(x2)^2=32(y5)^2 For 2. i got y=8x^220x61/60

PreCalculas
Write the equation of the parabola 1.Vertex(2,5) Focus(2,3) 2.Directrix=x=3/4 Focus(5/4,3) For 1. i got(x2)^2=32(y5)^2 For 2. i got y=8x^220x61/60

algebra
How would one write the equation of a parabola whose directrix is y=6 and location of the focus is (3,2)

Algebra 2
The focus of the parabola is (1, 9/4), and the directrix is the line y = 7/4. Show that the point (2,3) on the parabola is the same distance from the focus as from the directrix.

Math
Write the standard form of the equation of the parabola whose directrix is x=1 and whose focus is at (5,2)? a) (y+2)^2 = 12(x+2) b) y2 = 12(x+2) c) x+2 = 1/12(y+2)^2 d) x2 = 1/12(y+2)^2 I get A and D? confused!

Algebra II
Write an equation for the parabola with focus (1,3) and vertex (0,3). I cannot find any example in my book that works a problem with the vertex, all of the examples that I have to go by give only the focus and directrix. Thanks.

math
Let F=(0,0) be the focus and the line y=6 be the directrix. Plot several points P that are half as far from the focus as they are from the directrix. The configuration of all such points is an ellipse. Identify the four points where the ellipse crosses

Algebra
The focus of a parabola is (0,−4) . The directrix of the parabola is the line y=−5 . What is the equation of the parabola? y=−1/4x^2+4 y=1/2x^2−9/2 y=−1/2x^2−9/2 y=1/4x^2−4

Math
determine vertex, focus and directrix of parabola. then graph the parabola. first equation: y^2 2x8=0 second equation: y^2 4y 12x= 8 please show your work!

Math
determine vertex, focus and directrix of parabola. then graph the parabola. second equation: y^2 4y 12x= 8

math
determine vertex, focus and directrix of parabola. then graph the parabola. first equation: y^2 2x8=0 second equation: y^2 4y 12x= 8

Math
determine vertex, focus and directrix of parabola. then graph the parabola. second equation: y^2 4y 12x= 8 Please help me this is do 2day bc i forget to turn it in to my teacher

Algebra
The directrix of a parabola is y=−4 . The focus of the parabola is (−2,−2) . What is the equation of the parabola? y=1/4(x+2)^2−3 y=1/8(x−2)^2−3 y=−1/8(x+2)^2+3 y=−1/4(x−2)^2−3

Math Help
With the given information below, write the standard form equation for the parabola. 1.) Vertex: (1,2) Focus(1,0) 2.) Vertex: (2,1) Directrix x=1

Math
Find the equation of the parabola whose directrix is y = 1 and focus is (1, 1).

pre calc
fill out the equation of a parabola with the focus of (2,3) and the directrix is x=4

precalculus
Find the focus, directrix, and focal diameter of the parabola. x = −4y2 I answered everything right except the directrix. which my ans was 1/16.

Pre Cal Check
focus: (0,p) vertex: if not given, then it is assumed (0,0) Directrix: k+p or kp, i'm not sure I think these are the general equations for the focus, vertex, and directrix of a parabola, but i'm not sure. could someone please check this? thanks.

Trig
What are the focus and directrix of the parabola represented by the equation:8(y6)=(x+2)squared?

algebra problem
I need to find the equation of a parabola. I am not sure if this is the correct way or if I have the correct answer. Vertex at origin, focus is at (0,3) Equation of parabola vertex (0,0) focus (0,3) focus (h,k+p) (0,0+3) y=03 directrix y=3 a=(1/4)(p)

Algebra
Can someone tell me if I am right? I need to find the equation of a parabola. I am not sure if this is the correct way or if I have the correct answer. Vertex at origin, focus is at (0,3) Equation of parabola vertex (0,0) focus (0,3) focus (h,k+p) (0,0+3)

PreCalculus
How do I solve these equations? I need to create an equation given the characteristics? I have to be able to graph a parabola but first I need help solving this. 1.Focus (1.5,1); opens right; directrix x=0.5 2.Focus (1,4);opens down; contains (3,1)

trig
Find the focus, directrix and axis of the parabola with equation x= 2y^2+3? Thank you for helping me!

Advanced Math
Identify the equation of a parabola whose focus is at (5,1) and whose directrix is x=3. vertex=(5,1) p=6 4p=24 (x5)=(24)(y+1)^2 I got it wrong

precalc
Let F = (0,9) be the focus and the line y = 1 be the directrix. Plot several points P that are three times as far from the focus as they are from the directrix, including the vertices on the yaxis. The configuration of all such P is a hyperbola of

Precalc
i need help with this equation anything help will be greatly appreciated find the standard equation of a parabola with a focus (2,0) directrix x=3

Math/Algebra
Find the vertex, Focus,and Directrix of the parabola. Graph the equation. y^2=12x

math
if equation of directrix of a parabola is 2x+3=0, axis is 2y3=0 and length of latus rectum is 6 then what will be the focus?

math
The parabola whose equation is 4y^2+3x=2+8y, determine the coordinates of the focus, equation of the directrix and the length of the latus rectum?

Math
Identify th equation of the parabola whose focus is at (5,1) and whose directrix is x=3 I don't see any examples of this kind of problem.

Calculus
What is the equation of the parabola, given the following equation: Directrix is the yaxis and focus at (3,5)

ALGEBRA 2 help please would appreciate
for the equation 4x8y^2=0,give the focus and directrix.then sketch the graph, showing both the focus and the directrix. please show all the step thank you.

alGEBRA 2 help please would appreciate
for the equation 4x8y^2=0,give the focus and directrix.then sketch the graph, showing both the focus and the directrix. please show all the step thank you.

Math
Identify th equation of the parabola whose focus is at (5,1) and whose directrix is x=3 I don't see any examples of this kind of problem. is this right? (x5)^2+(y+1)^2=(x3)^2 so 10x+25+y^2+2y+1=6x+9 4x=y^2+2y+17

Precal
Sketech the graph of the equation y^2+4y+2x+10=0. Identify the vertex, the focus and the equation for the directrix. Use the completing the square to put the equation into standard form as your first step. This is what I did. y^2 + 4y = 2x10 y^2 + 4y + 4

Pre calc
Find an equation of the parabola described and state the two points that define the latus rectum Focus at (0,4) ; Directrix the line y=4

precalculus
can you check my work I really do not understand. Find the standard form of the equation of the parabola with focus(8,2) and directrix x=4. answer= (y+2)^2=16(x12/8)

Algebra
I am supposed to write the standard equation of the parabola with the directrix x=1, and the vertex 6,2. I got y6=1/4p(x2)^2. Is this correct? I am supposed to graph y+3=1/12(x1)^2. I tried to find p, and I got 36. I don't think this could be correct,

Math
Using the following information for the Vertex and Directrix, write the standard form equation for the parabola with what is given below. Vertex: (2,1) Directrix: x=1

Algebra
What is the focus of a parabola? And can the directrix be anywhere not on the focus? I'm confused!

math
hi i was wondering how would you find the equation of a parabola with it's vertex at 2,0, and with no directrix or focus given. the parobala opens toward the left. the two choices in my multiple choice answer sheet that sound the most logical would be

math
Find the focus and directrix of the parabola: x=(1/8y^2)(1/2y)+(3/2)

MATH
Write the equation of a parabola with a vertex at (5, 2) and a directrix y = 1.

Math
Find the vertex focus directrix and axis of symmetry of each parabola y²–8x–6y–3=0

math
Find the focus and directrix for the parabola y=ax^2. What special meaning does the expression 1/(4a) have?

algebra
help please!! write an equation of a parabola with vertex at the origin and the given focus focus at (2,6)??? Please help im lost!!

Vertex, Focus, & Directrix of Parabolas
Find the Vertex, Focus, and Directrix of the parabola: x^2 12x48y+276=0 Thank you so much

Algebra
How do you find the standard equation for a parobala when you do not have the directrix? I do have the focus, but the thing is the focus is not a 0,p value, it is 2,5, so I don't see how it could really be a focus. I'm sorry I can't get the graph in this

algebra 2
I'm having troubles understanding how to find the directrix,focus and roots of the parabola y=x^25x+4. If you could explain it to me so I understand for myself I'd appreciate it.

Geometry
What formula should be used to derive the equation of a parabola given its focus and directrix? • The distance formula ?? • The midpoint formula • y = ax2 + bx + c • The area formula for a circle

algebra
1)What is the distance between the museum and sailing club.I cant post the graph or anything but I have my numbers right its 53 but I used the distance formula so its either 53 units or the square root of 53 units. 2)Write the equation of the parabola y=

Algebra 2
1)Write an equation for the parabola with focus (4,0) and directrix y=2 4c(y  k) = (x  h)^2 4(1)(y  1) = (x  4)^2 4y + 4 = (x  4)^2 4y = (x  4)^2  4 y = (1/4)(x  4)^2 + 1 2)Write an equation for the ellipse with end points of the major axis at

Algebra II
Hi! I really need help with my homework, but I don't have anybody to ask. The problem asks me to find the vertex, focus, and directrix of the parabola: x^212x48y+276=0. All help is apprectiated! Thank you.

Alg 2 (ASAP)
I have a parabola vertex (11,3) p is not given, focus pt is not given. I need to find the equation of the parabola. How would I do this w/o p value or focus pt? you cant. Þhere are an infinite number of parabolas that have that vertex.

Algebra 2
write a equation for each parabola. vertex(0,1),focus(0,5)

algebra 2
Write the equation for a parabola with vertex (2 , 3) and focus ( 2, 1).