# 1) Find all the solutions of the equation in the interval (0,2pi). sin 2x = -sqrt3/2 I know that the angles are 4pi/3 and 5pi/3 and then since it is sin I add 2npi to them. 2x = 4pi/6 +

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1) Find all the solutions of the equation in the interval (0,2pi). sin 2x = -sqrt3/2 I know that the angles are 4pi/3 and 5pi/3 and then since it is sin I add 2npi to them. 2x = 4pi/6 + 2npi 2x = 5pi/3 + 2npi Now I know that I have to divide by 2 but that

1) Find all the solutions of the equation in the interval (0,2pi). sin 2x = -sqrt3/2 I know that the angles are 4pi/3 and 5pi/3 and then since it is sin I add 2npi to them. 2x = 4pi/6 + 2npi 2x = 5pi/3 + 2npi Now I know that I have to divide by 2 but that
3. ## Pre-Cal

Find all the soultions of the equation in the interval (0,2pi) sin 2x = -sqrt3 /2 sin -sqrt3 /2 is 4pi/3 and 5pi/3 in the unit circle 2x= 4pi/3 + 2npi 2x=5pi/3 + 2npi I do not know what to do at this point.

Find all the soultions of the equation in the interval (0,2pi) sin 2x = -sqrt3 /2 sin -sqrt3 /2 is 4pi/3 and 5pi/3 in the unit circle 2x= 4pi/3 + 2npi 2x=5pi/3 + 2npi I do not know what to do at this point
5. ## Math

1. On the interval [0, 2pi] what are the solutions to the equation sin3xcos2x = -cos3xsin2x + 1? pi/10 and pi/2? 2. What is the value of tan75degrees? √(3) + 1)/(1 - √(3))? 3. Value of cos(130degrees)cos(130degrees) +
6. ## maths

Please can you help me with this question? Choose the option which is a false statement: A arctan(tan2/3pi))=-1/3pi B arccos(cos(3/4pi))=3/4pi C sin(arcsin(-1/2pi))=-1/2pi D arcsin(1/2squareroot3)=1/3pi E arcsin(sin(3/4pi))=1/4pi F arccos
7. ## trig

1. 3cot^2 (x) - 1 = 0 My answer: pi/3, 2pi/3, 4pi/3, 5pi/3 2. 4cos^2 (x) - 1 = 0 My answer: pi/3, 2pi/3, 5pi/3, 4pi/3 3. 2sin (x) + csc (x) = 0 My answer: unknown lol i got to the part: sin^2 (x) = -1/2 4. 4sin^3 (x) + 2sin^2 (x) - 2sin^2 (x) = 1
8. ## Trig

Find all solutions in the interval [0,2pi) 4sin(x)cos(x)=1 2(2sinxcosx)=1 2sin2x=1 2x=1/2 x= pi/6, and 5pi/6 Then since its 2x i divided these answers by 2 and got pi/12 and 5pi/12 However, when i checked the answer key there solutions 13pi/12 and 17pi/12
9. ## Precalculus check answers help!

1. Which expression is equivalent to cos 2theta for all values of theta ? cos^2 theta – sin^2 theta ~ cos^2 theta – 1 1 – 2 sin^2 theta 2 sin theta cos theta 2. Use a half–angle identity to find the exact value of sin 105°. -1/2(sqrt)(2 + Sqrt3)
10. ## Trigonometry

Find all solutions of 4(sin(x)**2)-8cos (x) -8 = 0 in the interval (2pi, 4pi). (Leave your answers in exact form and enter them as a comma-separated list.)
11. ## math

determine all co terminal angles that lie in the interval -4pi less thank or equal to theta less than or equal to 4pi, for the following angles. a) 3pi/2 b) -5pi/3
12. ## math

use exact values of the sin,cos and tan of (pi/3) and (pi/6)(which I have found)and the symmetry of the graphs of sin,cos and tan to find the exact values of sin(-pi/6), cos(5pi/3) and tan (4pi/3). I know that sin -(pi/6) = -1/2 and cos (5pi/30 = 1/2 and
13. ## Calc

Let f(x)=sqrt(x) and g(x)=sin(x). Find f*g and determine where f*g is continuous on the interval (-4pi, 4pi)
14. ## Math

Find the solution. 1. sqrt2 sin x + 1 = 0 My ans: x = 5pi/4 + 2npi and 7pi/4 + 2npi 2. sec x - 2 = 0 My ans: x = pi/3 + 2npi and 5pi/3 + 2npi
15. ## Maths

Eq of curve is y=b sin^2(pi.x/a). Find mean value for part of curve where x lies between b and a. I have gone thus far- y=b[1-cos(2pi x/a)/2]/2 Integral y from a to b=b/2(b-a)-ab/4pi[sin(2pi b/a)-sin2pi) MV=b/2-[ab sin(2pi b/a)]/(b-a) Ans given is b/a. I
16. ## Pre Cal---Fix to the question below

Let P be the point on the unit circle U that corresponds to t. Find the coordinates of P and the exact values of the trigonometric functions of t, whenever possible. (If there is no solution, enter NO SOLUTION.) 4pi = ( , ) sin(4pi) = cos(4pi) = tan(pi) =
17. ## math

use exact values of the sin,cos and tan of (pi/3) and (pi/6)(which I have found)and the symmetry of the graphs of sin,cos and tan to find the exact values of sin(-pi/6), cos(5pi/3) and tan (4pi/3). I know that sin -(pi/6) = -1/2 and cos (5pi/30 = 1/2 and

Approximate the equation's solutions in the interval (0,2pi) sin2x sinx = cosx 2cos(x) (1/2-sin^2x) = 0 Then I got 3pi/2, pi/2, pi/6 and 5pi/6 Then I substituted 0-3 and got 3pi/2 , 5pi/2 , 9pi/2 , pi/2, pi/6, 7pi/6, 13pi/6 , 19pi/6 , 5pi/6 , 11pi/6 ,
19. ## Algebra 2

What values for theta(0 <= theta <= 2pi) satisfy the equation? 2 sin theta cos theta + sqrt 3 cos theta = 0 a. pi/2, 4pi/3, 3pi/2, 5pi/3 b. pi/2, 3pi/4, 3pi/2, 5pi/3 c. pi/2, 3pi/4, 3pi/2, 5pi/4 d. pi/2, pi/4, 3pi/2, 5pi/3 I have spent hours on this
20. ## calculus

Find complete length of curve r=a sin^3(theta/3). I have gone thus- (theta written as t) r^2= a^2 sin^6 t/3 and (dr/dt)^2=a^2 sin^4(t/3)cos^2(t/3) s=Int Sqrt[a^2 sin^6 t/3+a^2 sin^4(t/3)cos^2(t/3)]dt =a Int Sqrt[sin^4(t/3){(sin^2(t/3)+cos^2(t/3)}]dt=a Int
21. ## math

Use the exact values of the sin, cos and tan of pi/3 and pi/6, and the symmetry of the graphs of sin, cos and tan, to find the exact values of si -pi/6, cos 5/3pi and tan 4pi/3. I have found the answers to the first three using the special tables
22. ## math

Use the exact values of the sin, cos and tan of pi/3 and pi/6, and the symmetry of the graphs of sin, cos and tan, to find the exact values of sin -pi/6, cos 5/3pi and tan 4pi/3. I have found the answers to the first three using the special tables sin pi/6
23. ## math

find the trigonometric form of -12-12(square root)3i a. 24(cos2pi/3 + isin 2pi/3) b. 24(cos4pi/3 + isin 4pi/3) c. 12(cos 4pi/3 + isin 4pi/3) d. 12(cos12pi/3 + isin 2pi/3) e. 12(squareroot) 2 (cos4pi/3 + isin 4pi/3)
24. ## Pre Cal.

1. Use half-angle identity to find the exact value of cos165. MY ANSWER: (-1/2)sqrt(2+sqrt(3)) 2. Solve 2 sin x + sqrt(3) < 0 for 0<= x<2pi. MY ANSWER: (4pi/3)< x < (5pi/3) 3.Write the equation 2x+ 3y-5=0 in normal form? (-2sqrt(13)/13)x -
25. ## trig

Find all solutions of the equation. Leave answers in trigonometric form. x^5-1024=0 I got 4(cos tehta + i sin tehta), tehta = 0, 2pi/5, 4pi/5, 6pi/5, 8pi/5 is this right
26. ## Trig

Find the exact value of csc 4pi/3 What I have determined thus far: 4pi/3 = 60 degrees sin = square root of 3/2
27. ## Trigonometry

Solve the equation for solutions in the interval 0<=theta<2pi Problem 1. 3cot^2-4csc=1 My attempt: 3(cos^2/sin^2)-4/sin=1 3(cos^2/sin^2) - 4sin/sin^2 = 1 3cos^2 -4sin =sin^2 3cos^2-(1-cos^2) =4sin 4cos^2 -1 =4sin Cos^2 - sin=1/4 (1-sin^2) - sin =1/4
28. ## calc

i did this problem and it isn't working out, so i think i'm either making a dumb mistake or misunderstanding what it's asking. A particle moves along the x axis so that its velocity at any time t greater than or equal to 0 is given by v(t) = 1 -
29. ## Trig/PreCalc

Teach me how to express 5sqrt3 - 5i in polar form please. I don't want you to do the work for me. Just show me the steps I need to do the work properly on my own. Otherwise I will not pass this class or the exam when I enter college, and I do not want to
30. ## Calculus

1. Determine whether Rolle's Theorem applied to the function f(x)=((x-6)(x+4))/(x+7)^2 on the closed interval[-4,6]. If Rolle's Theorem can be applied, find all numbers of c in the open interval (-4,6) such that f'(c)=0. 2. Determine whether the Mean Value
31. ## Pre-Cal

Find all the solutions of the equation in the interval (0,2pip) sin(x + pi/6) - sin(x -pi/6) = 1/2 I am only stuck on the last part. I have 2sinx(sqrt3/2) = 1/2 Does the 2 cancel out with the sqrt 3/2. I am not sure what to do.
32. ## Pre-Cal(Urgent!!)

Find all the solutions of the equation in the interval (0,2pip) sin(x + pi/6) - sin(x -pi/6) = 1/2 I am only stuck on the last part. I have 2sinx(sqrt3/2) = 1/2 Does the 2 cancel out with the sqrt 3/2. I am not sure what to do.
33. ## Math

3. find the four angles that define the fourth root of z1=1+ sqrt3*i z = 2 * (1/2 + i * sqrt(3)/2) z = 2 * (cos(pi/3 + 2pi * k) + i * sin(pi/3 + 2pi * k)) z = 2 * (cos((pi/3) * (1 + 6k)) + i * sin((pi/3) * (1 + 6k))) z^(1/4) = 2^(1/4) * (cos((pi/12) * (1 +
34. ## Trig

Find all solutions of the equation in the interval [0,2pi) 2 cos^2 x-cos x = 0 -2cos^2 + cosx + 0 (x+1/2) (x+0/2) (2x+1) (x+0) -1/2,0 2Pi/3, 4pi/3, pi/2, 3pi/2 my teacher circled pi/2 and 3pi/2 What did I do wrong? I don't understand...
35. ## Math

what are the indicated powers of these complex numbers: a. (2 – 3i )^2 b. (3 + 4i )^3 c. [2 cis(300°)]^5 d. ( cos (4pi/3) + i sin (4pi/3)) ^4
36. ## Pre-Calc

Find all solutions of the equation in the interval [0, 2pi). Show all work. sin(x+(pi/6))-sin(x-((pi/6))=1/2
37. ## Calculus

Find an equation of a line tangent to y = 2sin x whose slope is a maximum value in the interval (0, 2π] I believe the equation is y=2x-4pi. How is the b-value -4pi?
38. ## Calc

Find the exact total of the areas bounded by the following functions: f(x) = sinx g(x) = cosx x = 0 x = 2pi I set my calculator to graph on the x-axis as a 2pi scale. The two functions appear to cross three times between x = 0 and 2pi. (including 2pi) Now,
39. ## Calculus

Breathing is cyclic and a full respiratory cycle from the beginning of inhalation to the end of exhalation takes about 5 seconds. The maximum rate of air flow into the lungs is about 0.5 L/s. This explains, in part, why the function
40. ## trigonometry

refer to the graph of y=sin(x) or cos(x) to find the exact values of (x) in the interval [0,4pi]that satisfy the equation. 4sin(x)=4
41. ## Math

Can I please get some help on these questions: 1. How many solutions does the equation,2sin^2 2 θ = sin2θ have on the interval [0, 2pi]? 4? ...what about 4cos2θ = 8cos^2 2θ? 2. True or False: sin^2 4x = 1 has 8 solutions on the interval
42. ## math

1)Find the amplitude of y=6cos4theta A)3/2 B)6 C)4 D)pi/2 I chose B 2)Find the period of y=tan5theta A)10pi B)2pi/5 C)5pi D)pi/5 I chose D 3)Find the phase shift of y=sin(theta-3pi/4). A)3pi/4 B)-3pi/4 C)4pi/3 D)-4pi/3 I chose A 4)Find the vertical shift
43. ## math

Can someone please check my answers and help me with the last question! 1. Solve sin2xcos2x = 4sin2x on the interval [0, 2pi] 0, pi, 2pi? 2. Exact value of sin(pi/12) - sin(5pi/12) root3/4? 3. Using factorial notation, 0! = 1 False? 4. Find the area of the
44. ## calculus

Find all relative extrema and points of inflection of the function: f(x) = sin (x/2) 0 =< x =< 4pi =< is supposed to be less than or equal to. I can find the extrema, but the points of inflection has me stumped. The inflection point is (2pi,0) but
45. ## Calculus

I need to find the exact solutions on the interval [0,2pi) for: 2sin^2(x/2) - 3sin(x/2) + 1 = 0 I would start: (2sin(x/2)-1)(sin(x/2)-1) = 0 sin(x/2)=1/2 and sin(x/2)=1 what's next? Ok, what angle has a sin equal to say 1/2 sin (x/2)=1 arc sin (1) = x/2
46. ## math

Find all solutions to the equation tan(t)=1/tan (t) in the interval 0<t<2pi. Solve the equation in the interval [0, 2pi]. The answer must be a multiple of pi 2sin(t)cos(t) + sin(t) -2cos(t)-1=0 Find all solutions of the equation 2cos3x=1
47. ## trig

2sin(x)cos(x)+cos(x)=0 I'm looking for exact value solutions in [0, 3π] So I need to find general solutions to solve the equation. But do I eliminate cos(x), like this... 2sin(x)cos(x)+cos(x)=0 2sin(x)cos(x)= -cos(x) 2sin(x) = -1 sin(x) = -1/2 at
48. ## Math

An Arc of length 6 cm subtends a 80 degree angle in a circle. What is the radius of the circle? Also what is the area of that sector? What I have so far: S=R*80 degree S= R*4pi/9 6 cm= r* 4pi/9 R=6/4pi/9 R= 6*9/4pi R=54/4pi HELP!
49. ## maths

Perform the operation shown below and leave the result in trigonometric form. [6(cos 5pi/6 + isin 5pi/6)] [3(cos 4pi/5 + isin 4pi/5)]
50. ## math

Find the coterminal angles for 8pi/3. I found one: 8pi/3 - 2pi= 2pi/3 My textbook says that I should add subtract 4pi to find the other one and I'm very confused as to how you know what to add/ subtract.
51. ## Pre-Calculus

cos^2(x) + sin(x) = 1 - Find all solutions in the interval [0, 2pi) I got pi/2 but the answer says {0, pi/2, pi} Where does 0 and pi come from for solutions? When simplifying I just get sin(x)=1
52. ## Integration by Parts

integral from 0 to 2pi of isin(t)e^(it)dt. I know my answer should be -pi. **I pull i out because it is a constant. My work: let u=e^(it) du=ie^(it)dt dv=sin(t) v=-cos(t) i integral sin(t)e^(it)dt= -e^(it)cos(t)+i*integral cost(t)e^(it)dt do integration by
53. ## trig

Find all solutions of cos (x) + 1/2 sec (x) = -3/2 in the interval (2pi, 4pi) (Leave your answers in exact form and enter them as a comma-separated list.)
54. ## MATH

I am given arcsin (sin 4pi) do the arc sin and sin cancel out? How do we solve this?
55. ## trig

Find all solutions in the interval [0,2pi]. sin 2x + sin x = 0
56. ## math

Evaluate. 1. sin^-1(-1/2) 2. cos^-1[(-root 3)/2] 3. arctan[(root3)/3] 4. cos(arccos2/3) 5. arcsin(sin 2pi) 6. sin(arccos 1) I got these values as my answers: 1. -pi/6 2. 5pi/6 3. pi/6 4. 2/3 5. 2pi 6. 0 Can someone please tell me if they are right? thank
57. ## trig

cos/sin use 2npi and tan uses npi, but how do you know when to add 2npi or npi to the solution of the equation?
58. ## Math Help

Hello! Can someone please check and see if I did this right? Thanks! :) Directions: Find the exact solutions of the equation in the interval [0,2pi] cos2x+sinx=0 My answer: cos2x+sinx=cos^2x-sin^2x+sinx =1-sin^2x-sin^2x+sinx =-2sin^2x+sinx+1=0
59. ## trig

please help me with some questions I skipped on a review for our test coming up? solve 5-7 on the interval 0 greater than or equal to x less than or equal to 2pi. 5. sin x=sqrt3/2 6. cos x=-1/2 7. tan x=0 ---------------- 14. what is the exact value of
60. ## math

Eliminate the parameter (What does that mean?) and write a rectangular equation for (could it be [t^2 + 3][2t]?) x= t^2 + 3 y = 2t Without a calculator (how can I do that?), determine the exact value of each expression. cos(Sin^-1 1/2) Sin^-1 (sin 7pi/6)
61. ## trig

y= sin x/2, 0 less than equal to x less than equal to 4pi... the question says state the amplitude and period for each equation and graph it over the indicated interval
62. ## Math (Calc)

Find all solutions to the following equation on the interval 0<=x<=2PI 8cos^2(X)sin^2(X) + 2cos^2(X) - 3 = 0 There are 8 solutions. If somebody could show me how to do it and not give me the answers, that would be great.
63. ## Math

Prove that sin 13pi/3.sin 8pi/3+cos 2pi/3.sin 5pi /6=1/2.
64. ## trig

Find the exact solutions of the equation in the interval [0,2pi). sin(x/2)+cos(x)=0
65. ## Math

Directions: Find all solutions of the equation in the interval (0, 2pi) sin x/2=1-cosx
66. ## Math

Find all solutions on the interval (0, 2pi) of the equation: 2(sin^2)t-3sint+1=0 how do you get this one started?
67. ## Trigonometry

Find all solutions of the equation in the interval [0,2pi] algebraically. sin^2x + cosx + 1 = 0
68. ## Math

Hi! Okay so I started to attempt this math problem; 3cot^2x-1=0. However, I'm a little stuck. My teacher wants me to find the Location on The Unit Circle, Period, and General Solution. Can someone check what I have and help me with the rest? 3cot^2x-1=0
69. ## Math

Find all solutions of the given equation in the interval [0, 2pi) cos x/2 - sin x = 0 Hi, I am struggling with this question. Can anybody help me please? Thanks!
70. ## Trig functions

1)Write the equation sin y= x in the form of an inverse function. A)y=Sin-1x B)x=Sin-1y C)y=sin-1x D)y=Sinx I chose A 2)Solve y=Arcsin1/2 A)-5pi/6 B)5pi/6 C)-pi/6 D)pi/6 I chose D 3)Find the value of Sin-1(-1/2) A)-30 degrees B)30 degrees C)150 degrees
71. ## Calculus

Consider the function f(x)=sin(1/x) Find a sequence of x-values that approach 0 such that (1) sin (1/x)=0 {Hint: Use the fact that sin(pi) = sin(2pi)=sin(3pi)=...=sin(npi)=0} (2) sin (1/x)=1 {Hint: Use the fact that sin(npi)/2)=1 if n= 1,5,9...} (3) sin
72. ## Calculus

Consider the function f(x)=sin(1/x) Find a sequence of x-values that approach 0 such that (1) sin (1/x)=0 {Hint: Use the fact that sin(pi) = sin(2pi)=sin(3pi)=...=sin(npi)=0} (2) sin (1/x)=1 {Hint: Use the fact that sin(npi)/2)=1 if n= 1,5,9...} (3) sin
73. ## Trig

the number of solutions of sin x= -sqrt3/2 for x between 0 and 2pi
74. ## Trigonometry

Use the half-angle identities to find all solutions on the interval [0,2pi) for the equation cos^2(x) = sin^2(x/2)
75. ## Trigonometry

Use the half-angle identities to find all solutions on the interval [0,2pi) for the equation sin^2(x) = cos^2(x/2)
76. ## Precalculs

I have no idea how to do these type of problems. -------Problem-------- Solve each equation on the interval 0 less than or equal to theta less than 2 pi 42. SQRT(3) sin theta + cos theta = 1 ---------------------- There is an example prior to the
77. ## Pre-Calc

I am really struggling with how to do these problems, I posted them a few minutes ago but the answers/work shown was incorrect. 1) a) Use an Addition or Subtraction Formula to write the expression as a trigonometric function of one number. cos 12° cos
78. ## Math

how many solutions does the equation sin(5x)=1/2 have on the interval [0,2pi]?
79. ## maths

hey, i would really appreciate some help solving for x when: sin2x=cosx Use the identity sin 2A = 2sinAcosA so: sin 2x = cos x 2sinxcosx - cosx = 0 cosx(2sinx - 1)=0 cosx = 0 or 2sinx=1, yielding sinx=1/2 from cosx=0 and by looking at the cosine graph, we
80. ## Math - complex numbers

These questions are related to de moivre's theorem: z^n + 1/z^n = 2cosntheta z^n - 1/z^n = 2 isin ntheta 1. Express sin^5theta in the form Asintheta + Bsin3theta + Csin5theta and hence find the integral of sin^5theta. 2. Express sin^6theta in multiples of
81. ## math

find all solution to the equation 3 cos(x+4)=1. in the interval of 0<x<2pi This is what I got: arccos (1/3)+4 but I cant figure the rest out Solve the following equation in the interval [0, 2pi]. (sin(t))^2=1/2. Give the answer as a multiple of pi.
82. ## precalculus

Evaluate the following expressions. Your answer must be an angle in radians and in the interval [(-pi/2),(pi/2)] . (a) sin^(-1)(0) = (b) sin^(-1)((-sqrt3)/2) = (c) sin^(-1)(-1/2) =
83. ## math

find all solutions in the interval [0,2 pi) sin(x+(3.14/3) + sin(x- 3.14/3) =1 sin^4 x cos^2 x Since sin (a+b) = sina cosb + cosb sina and sin (a-b) = sina cosb - cosb sina, the first problem can be written 2 sin x cos (pi/3)= sin x The solution to sin x =
84. ## trig

I need to find all solutions of the given equations for the indicated interval. Round solutions to three decimal places if necessary. 1.) 3sin(x)+1=0, x within [0,2pi) 2.) 2sin(sq'd)(x)+cos(x)-1=0, x within R 3.) 4sin(sq'd)(x)-4sin(x)-1=0, x within R 4.)
85. ## Calculus II

With Taylor/Maclaurin polynomials Use the Remainder Estimation Theorem to find an interval containing x = 0 over which f(x) can be approximated by p(x) to three decimal-place accuracy throughout the interval. f(x) = sin x p(x) = x - 1/6 * x^3 The book

Approximate the equation's soultions in the interval (o, 2pi). If possible find the exact solutions. sin 2x sinx = cosx I do not know where to start.
87. ## Pre-Cal

Approximate the equation's soultions in the interval (o, 2pi). If possible find the exact solutions. sin 2x sinx = cosx I do not know where to start.

Jamie is forming a cylinder out of two circles and a rectangle. The area of each circle is 4 pi. The diameter of each circle is 4 cm. The height of the rectangle is 6 cm. Which shows how Jamie could calculate the surface area of the cylinder? a. 2(4pi)+
89. ## Trigonometry

Use inverse trigonometric functions to find the solutions of the equation that are in the given interval, and approximate the solutions to four decimal places. (Enter your answers as a comma-separated list.) 10 sin^2 x = 3 sin x + 4; [0, 2π)
90. ## Trigonometry

Use inverse trigonometric functions to find the solutions of the equation that are in the given interval, and approximate the solutions to four decimal places. (Enter your answers as a comma-separated list.) 10 sin^2 x = 3 sin x + 4; [0, 2π)
91. ## Trigonometry

Use inverse trigonometric functions to find the solutions of the equation that are in the given interval, and approximate the solutions to four decimal places. (Enter your answers as a comma-separated list.) 10 sin^2 x = 3 sin x + 4; [0, 2π)
92. ## Pre-Calc

1) Use an Addition or Subtraction Formula to write the expression as a trigonometric function of one number. cos 12° cos 18° − sin 12° sin 18° And Find its exact value. 2) Use an Addition or Subtraction Formula to write the expression as a
93. ## Trig

can I please have help with these 3 questions? 1. Solve this equation graphically on the interval [0, 2ð]. list the solutions. sin(2x)-1=tan x 2. solve sin x cos x= sqrt3/4 3. solve tan^2 x-3tan x+2=0 thank you! show step by step please.
94. ## Math

Find the exact solutions of the equation In The interval.. Sin 2x -sin x=0
95. ## Astronomy

In the equation 4pi^2/G/p^2 times a^3, what is the value of 4pi^2? Is it 39.47? or 157.913
96. ## Solving Trig Equations

Solve for x in the interval [-pi,0] a) sin^2x = 3/4 I know that you have +root3/2 and -root3/2 and the positive one gives you an error when doing the inverse of sin, but im confused about the -root3/2. I found that one of the answers of x is -pi/3 (-60
97. ## Calculus

Find the area in the first quadrant bounded by the arc of the circle described by the polar equation r = (2 sin theta)+(4 cos theta) A. 5pi/2 B. (5pi/2)+4 C. 5pi D. 5pi + 8
98. ## Math

The graph of f(x), a trigonometric function, and the graph of g(x) = c intersect at n points over the interval 0 <= x <= 2pi. There are m algebraic solutions to the equation f(x) = g(x), where m > n. Which of the following functions are most
99. ## trig integration

i'm having trouble evaluating the integral at pi/2 and 0. i know: s (at pi/2 and 0) sin^2 (2x)dx= s 1/2[1-cos(2x)]dx= s 1/2(x-sin(4x))dx= (x/2)- 1/8[sin (4x)] i don't understand how you get pi/4 You made a few mistakes, check again. But you don't need to
100. ## Math

Find all x, -4pi < x < 6pi, such that [cos(x/3)]^4 + [sin(x/3)]^4 = 1 PLEASEEE HELPP! :(