solve Sinx=Cos2x1 for 0¡Üx<2¦Ð
24,842 results

Math Help
Hello! Can someone please check and see if I did this right? Thanks! :) Directions: Find the exact solutions of the equation in the interval [0,2pi] cos2x+sinx=0 My answer: cos2x+sinx=cos^2xsin^2x+sinx =1sin^2xsin^2x+sinx =2sin^2x+sinx+1=0 
Trigcheck answer
Solve the equation of the interval (0, 2pi) cosx=sinx I squared both sides to get :cos²x=sin²x Then using tri indentites I came up with cos²x=1cos²x Ended up with 2cos²x=1 Would the answer be cos²x=1/2??? 
math
the problem is 2cos^2x + sinx1=0 the directions are to "use an identity to solve each equation on the interval [0,2pi). This is what i've done so far: 2cos^2x+sinx1=0 2cos^2x1+sinx=0 cos2x + sinx =0 1  2sin^2x + sinx = 0 2sin^2x+sinx1=0 2sin^2xsinx+1=0 I think i'm ... 
math
cos2xsinx=0. Factor and solve for sinx 
Precalculus
Please help!!!!!!!!!!! Find all solutions to the equation in the interval [0,2π). 8. cos2x=cosx 10. 2cos^2x+cosx=cos2x Solve algebraically for exact solutions in the interval [0,2π). Use your grapher only to support your algebraic work. 24. cos2x+sinx=0 
Math  Trig  Double Angles
Prove: sin2x / 1  cos2x = cotx My Attempt: LS: = 2sinxcosx /  1  (1  2sin^2x) = 2sinxcosx /  1 + 2sin^2x = cosx / sinx  1 = cosx / sinx  1/1 = cosx / sinx  sinx / sinx  Prove: 2sin(x+y)sin(xy) = cos2y  cos2x My Attempt: RS: = 1  2sin^2y  1  2sin^2x = 1  1  ... 
Trigonometry
solve Sinx=Cos2x1 for 0¡Üx<2¦Ð 
trig
how do you solve: find cos2x if sinx is equal to 1/5 
math
solve for sinx=cos2x (between 0 and 2pi) 
Trig
Solve Sinx=Cos2x1 for all values between 0 and 2pi 
maths
solve for x for angles between o and 360 degrees (i)cos2x+sinx=0 
Calculus grade 12
solve for (<_ = less than or equal to / pie = pie sign / pie = negative pie) 3 sin²x = cos²x ; 0 <_ x < 2pie cos²x  sin²x = sinx ; pie < x <_ pie 
Trig Help
Prove the following: [1+sinx]/[1+cscx]=tanx/secx =[1+sinx]/[1+1/sinx] =[1+sinx]/[(sinx+1)/sinx] =[1+sinx]*[sinx/(sinx+1)] =[sinx+sin^2x]/[sinx+1] =[sinx+(1cos^2x)]/[sinx+1] =??? This is where I'm stuck. Can someone help me. Please check what I got is right so far it's ... 
Calculus
Solve identity, (1sin2x)/cos2x = cos2x/(1+sin2x) I tried starting from the right side, RS: =(cos²xsin²x)/(1+2sinxcosx) =(cos²x(1cos²x))/(1+2sinxcosx) and the right side just goes in circle. May I get a hint to start off? 
trig
sinx = 4/5 and x terminates in Quadrant II Find sin2x and cos2x How to get the answers, which are sin2x = 24/25, cos2x = 7/25? 
Trig
If sinx = 1/4 Find the exact value of cos2x I used the formula for double angle identities : cos2x = 12sin^2x and got the answer 1/2 The book says the answer is 7/8 How would they get to that conclusion? 
Math please help quick
Which of the following are identities? Check all that apply. (Points : 2) sin2x = 1  cos2x sin2x  cos2x = 1 tan2x = 1 + sec2x cot2x = csc2x  1 Question 4. 4. Which of the following equations are identities? Check all that apply. (Points : 2) Question 5. 5. The expression ... 
Math (Trig) a.s.a.p, thanks!
verify the identities: 1.) 2tanx(1+tanx)^2 = secx 2.) cos(x330degrees)=1/2(ã3cosxsinx) *the ãis only over the 3* 3.) 1+cos2x/sinx=cotx any help is greatly appreciated!! 
Trig
Verify the identity: tanx(cos2x) = sin2x  tanx Left Side = (sinx/cosx)(2cos^2 x 1) =sinx(2cos^2 x  1)/cosx Right Side = 2sinx cosx  sinx/cosx =(2sinxcos^2 x  sinx)/cosx =sinx(2cos^2 x 1)/cosx = L.S. Q.E.D. 
Advanced Math
Could someone help me with those two questions. I need to know how to do them without calculator solve for the interval [0,2pie] 1) cos^2*xcos2x=0 2) tan(x/2)sinx=0 
math
solve each equation for 0=/<x=/<2pi sin^2x + 5sinx + 6 = 0? how do i factor this and solve? 2sin^2 + sinx = 0 (2sinx  3)(sinx +2) sinx = 3/2, 2 how do I solve? These are not part of the special triangles. 2cos^2  7cosx + 3 = 0 (2cosx  1)(cosx  3) cosx = 1/2, 3 x= pi... 
trig
how does this work? (Sin2x+cos2x+2sin²x)/(sinx+cosx) = (sinx+cosx 
Math
prove identity Sin2x  sinx/cosx + cos2x= sinx/cosx + 1 
Trig
Prove the following functions: (sinx+sin2x)/(1+cosx+cos2x)=tan x (cos3x/sinx)+(sin3x/cosx)=2cot2x tan2x=(2/cotxtanx) theses are due in the am. Fastness would be great? 
Math
Solve the equation 2cos2x = √3 for 0°≤x≤360° I did this: cos2x = √3 /2 2x=30 x=15 x=15, 165, 195, 345 Is this correct? Solve the equation √3 sin2x + cos2x = 0 for π≤x≤π No idea how to approach this one Thanks a bunch for the help! 
Trig.
Can someone please help me with this? Find all solutions to the equation in the interval [0,2pi) cos2x=sinx I know I have to use some sort of identity, but I have no idea how to go about to solve this. 
Trig........
I need to prove that the following is true. Thanks (cosx / 1sinx ) = ( 1+sinx / cosx ) I recall this question causing all kinds of problems when I was still teaching. it requires a little "trick" L.S. =cosx/(1sinx) multiply top and bottom by 1+sinx, (creating the difference ... 
Math 12
Simplify #1: cscx(sin^2x+cos^2xtanx)/sinx+cosx = cscx((1)tanx)/sinx+cosx = cscxtanx/sinx+cosx Is the correct answer cscxtanx/sinx+cosx? Simplify #2: sin2x/1+cos2X = ??? I'm stuck on this one. I don't know what I should do. Simplify #3: cosxsin(90x)sinx/cosxcos(180x)tanx = ... 
Trigonometry
Simplify #1: cscx(sin^2x+cos^2xtanx)/sinx+cosx = cscx((1)tanx)/sinx+cosx = cscxtanx/sinx+cosx Is the correct answer cscxtanx/sinx+cosx? Simplify #2: sin2x/1+cos2X = ??? I'm stuck on this one. I don't know what I should do. Simplify #3: cosxsin(90x)sinx/cosxcos(180x)tanx = ... 
Math/Calculus
Please take a look at my work below and provide a good critique: Solve the differential equation using the method of undetermined coefficients or variation of parameters. y''  3y' + 2y = sin(x) yc(x)= c1*e^2x+c2*e^x y"3y'+2y=sin(x) r^23r+2=0 (r1)(r2)=0 r1=1, r2=2 yp(x)=... 
trig
Find the general solution for x if cos2x + sin3x = sinx 
trig
Find the solutions to the equation cos2x=sinx and 2cos^2x3cosx3=0 
Math
Find the exact solution of cos2x+sinx=0 in the interval [0,2pi) 
maths please answer NOW!!!!!
solve algebreically the equation cos2x=1sinx also cosx=cosx1 and please also sin2x=3sinx 
calculus
Could someone check my reasoning? thanx Find the derivative of the function. sin(sin[sinx]) I need to use the chain rule to solve. So I take the derivative sin(sin[sinx) first. Then multiply that by the inside which is the derivative of sin[sinx]. And multiply that by ... 
Trig
help please!: (sinx + sin2x +sin3x) / (cosx + cos2x + cos3x) = tan2x 
Identities
Verify the following identity cos2x/sin2x+sinx/cosx=csc2x 
Calculus
In the interval (0 is less than or equal to x which is less than or equal to 5), the graphs of y=cos(2x) and y=sin(3x) intersect four times. Let A, B, C, and D be the xcoordinates of these points so that 0<A<B<C<D<5. Which of the definite integrals below ... 
Pre Calculus
Establish the following identity sin 2x/sinx  cos2x/cosx = secx 
Trigonometry
find sin2x, cos2x, and tan2x if sinx= 2/sqrt 5 and x terminates in quadrant III 
Math
Use a doubleangle formula to find the exact value of cos2x when sinx = 3/5, where pi/2 < x < pi. (7/25) or 7/25? 
calc
Where do I start to prove this identity: sinx/cosx= 1cos2x/sin2x please help!! Hint: Fractions are evil. Get rid of them. Well, cos2x = cos2x  sin2x, so 1coscx = 1  cos2x  sin2x = 1  cos2x + sin2x You should be able to simplify this to 2*something squared. The ... 
Trig
solve to four decimals places 5.0118 sinx  3.1105=0 :for all real x values I will be happy to critique your work. Solve for sinx, then arcsinx 
Trigonometry
Simplify the expression using trig identities: 1. (sin4x  cos4x)/(sin2x cos2x) 2. (sinx(cotx)+cosx)/(2cotx) 
Trigonometry.
( tanx/1cotx )+ (cotx/1tanx)= (1+secxcscx) Good one! Generally these are done by changing everything to sines and cosines, unless you see some obvious identities. Also generally, it is best to start with the more complicated side and try to change it to the "easier" side. so... 
PreCalculus
Find all solutions to the equation in the interval [0, 2pi) cos4xcos2x=0 So,this is what i've done so far: cos4xcos2x=0 cos2(2x)cos2x (2cos^2(2x)1)(2cos^2(x)1) No idea what to do next. 
Math
Solve the integral from [0,pi] of x*sinx*cosx*dx I don't understand how to solve this problem because if I let u =x and du =1 and dv=sinx*cosx, I can't find v. How do you solve this? 
Mathematics  Trigonometric Identities
Prove: (tanx)(sinx) / (tanx) + (sinx) = (tanx)  (sinx) / (tanx)(sinx) What I have so far: L.S. = (sinx / cosx) sinx / (sinx / cosx) + sinx = (sin^2x / cosx) / (sinx + (sinx) (cosx) / cosx) = (sin^2x / cosx) / (cosx / sinx + sinxcosx) 
Trig.......
I need to prove that the following is true. Thanks (2tanx /1tan^x)+(1/2cos^2x1)= (cosx+sinx)/(cosx  sinx) and thanks ........... check your typing. I tried 30º, the two sides are not equal, they differ by 1 oh , thank you Mr Reiny I'll tell my teacher this Question is ... 
Trig Help
Given that cos2x=7/12 and "270 equal or < 2x equal or < 360", find sinx. Please help and Thank you 
your preciouss helpp please
how can you condense these cos^3x* cos2x^2 cos^3x+ cos2x^2 cos^3x cos2x^2 Thank you soo much 
Precal
show that: (1tanx)/(1+tanx)= (1sinx)/(cos2x) 
math
sin*sin=1.732*sinx*cos2x 
trig
I keep trying to find the power reducing formula for sin^4(x), but I can't seem to get all the fractional parts correct. The answer I should be getting is: sin^4(x)=(1/8)cos4x(1/2)cos2x+(3/8) I can only get this far knowing feeling confident. When I go further I start making ... 
trigonometry
can i use factoring to simplify this trig identity? the problem is sinx + cotx * cosx i know the answer is cscx and i know how to get it but i want to know if i can do factoring to get it bc i tried to but it wont give me the answer . this is the step i went through: 1) sinx... 
math
solve sinx/2,cosx/2 & tanx/2 of the following: (a)sinx=1/4 & x lies in second quadrant. 
Precal
1) Solve the equation sinx(sinx+1) = 0 I am having trouble with the first step. Could I do sin x^2 + 1 =0? 
Mathematics  Trigonometric Identities
Prove: sinx + tanx = tanx (1 + cosx) What I have so far: LS: = sinx + tanx = sinx + (sinx / cosx) = (sinx) (cosx) + sinx / cos = tanx (cosx + sinx) I don't know what to do now 
Trig
solve to four decimal places 1.3224sinx + 0.4732=0 :for all real x values solve for sinx, then arcsinx. solve for sinx, then arcsinx. so its sinx= .4732/1.3224 and i get .36594 but how do you get the other values for a real x Ok, use your calculator. Sinx is negative in the ... 
Math C30
Equations containing circular functions and unit circle... solve 2cosx sinx + sinx = 0 
drwls
My previous question: Verify that (secx/sinx)*(cotx/cscx)=cscx is an identity. (secx/sinx)*(cotx/cscx) = (secx/cscx)(cotx/sinx) = (sinx/cosx)*cotx*(1/sinx) "The last steps should be obvious" Not to me. I can convert (sinx/cosx) to tanx if that's even what I'm suppose to do. Is... 
Mathj C30
Solving Equations Containing Circular Functions : Solve 2cosx sinx + sinx = 0 when x is between 0 and 2pi 
trig
solve equation for exact solution if possible leave answer in degree sinx/2=square root of 2 sinx/2 
Maths
If y=Sinx^Sinx^Sinx.......infinity then prove that dy/dx=2ycotx/1ylog(sinx).? 
Math  Pre Clac
Prove that each of these equations is an identity. A) (1 + sinx + cos x)/(1 + sinx + cosx)=(1 + cosx)/sinx B) (1 + sinx + cosx)/(1  sinx + cosx)= (1 + sin x)/cosx Please and thankyou! 
Trigonometry Check
Simplify #3: [cosxsin(90x)sinx]/[cosxcos(180x)tanx] = [cosx(sin90cosxcos90sinx)sinx]/[cosx(cos180cosx+sinx180sinx)tanx] = [cosx((1)cosx(0)sinx)sinx]/[cosx((1)cosx+(0)sinx)tanx] = [cosxcosxsinx]/[cosx+cosxtanx] = [cosx(1sinx]/[cosx(1+tanx] = (1sinx)/(1+tanx) Is ... 
Math (trigonometric identities)
I was given 21 questions for homework and I can't get the last few no matter how hard and how many times I try. 17. Sinx1/sinx+1 = cos^2x/(sinx+1)^2 18. Sin^4x + 2sin^2xcos^2x + cos^4x = 1 19. 4/cos^2x  5 = 4tan^2x  1 20. Cosx  sinx  cos^3x/Cosx = sin^2  tanx 21. Sin^2x... 
Math
Im really struggling with these proving identities problems can somebody please show me how to do these? I'm only aloud to manipulate one side of the equation and it has to equal the other side of the equation at the end Problem 1. Sinx/(cotx+1) + cosx/(tanx+1) = 1/(sinx+cosx... 
Math
1) evaluate without a calculator: a)sin(3.14/4) b) cos(3(3.14)/4) c) tan(4(3.14)/3) d) arccos( square root of three/2) e) csctheata=2 2) verify the following identities: a) cotxcosx+sinx=cscx b)[(1+sinx)/ cosx] + [cosx/ (1+sinx)]= 2secx c) (sin^2x + 2sinx+1)/cos^2x= (1+sinx... 
Math trignometry
how can you condense these cos^3x* cos2x^2 cos^3x+ cos2x^2 cos^3x cos2x^2 Thanks a lot :) 
Trigonometic
Solving Trigonometic Equations solve for x and give the answers as a equations : ( by radian) 1)cos(sinx)=1 <<<and thanks >>> We know sin 2x = 2(sinx)(cosx) so (sinx)(cos)=1/2(sin 2x) So we can change your equation from (sinx)(cosx)=1 to 1/2(sin 2x) = 1 (sin ... 
PreCalc
Trigonometric Identities Prove: (tanx + secx 1)/(tanx  secx + 1)= tanx + secx My work so far: (sinx/cosx + 1/cosx + cosx/cosx)/(sinx/cos x  1/cosx + cosx/cosx)= tanx + cosx (just working on the left side) ((sinx + 1  cosx)/cosx)/((sinx  1 + cosx)/cosx) ((sinx + 1  cosx)/... 
Pre calc
Please help me proof the identity. This isn't even math to me, I can not understand it so please show all work. God bless A)1cos2x/sin2x=tanx B) sin4x/sinx=4cosxcos2x 
Math (Integrals) (Using given method)
I would like to solve the ∫sin^2(pix) dx Using the given substitution identity: sin^2(x) = (1/2)(1cos2x) This is what I did so far: ∫sin^2(pix) let u = pix du = pi dx (1/pi)∫sin^2(u)du Applying the identity is where I'm lost on how to continue further.. (1/pi)∫(1/2)(1... 
Maths
Prove that cos3x/cosxcos6x/cos2x=2(cos2xcos4x) 
trig
tanx = 5/12 and sinx<0 Find sin2x and cos2x How to get the answers of sin2x = 120/169 and cos 2x = 119/169? 
Math
I'm only aloud to manipulate one side of the problem and the end result has to match the other side of the equation Problem 1. sinx + cosx + sinx + tanx + cosxcotx = secx + cscx Problem 2. ((sinx + cosx)/(1 + tanx))^2 + ((sinx  cos^2x)/(1  cotx))^2 = 1 Problem 3. ((1 + sinx... 
maths  trigonometry
I've asked about this same question before, and someone gave me the way to finish, which I understand to some extent. I need help figuring out what they did in the second step though. How they got to the third step from the second. [sinx + tanx]/[cosx + 1] = tanx LS=[sinx+tanx... 
Trigonometry
I can't remember what formula to use for these. Note the X's may be replaced by a theta symbol. I just didn't have one on my keyboard. Use the given information to find sin2X, cos2X and tan2X if 0< X <pi/2 1. sinX=12/13 2. cosX=3/5 3. tanX=2/3 
math
tanx+secx=2cosx (sinx/cosx)+ (1/cosx)=2cosx (sinx+1)/cosx =2cosx multiplying both sides by cosx sinx + 1 =2cos^2x sinx+1 = 2(1sin^2x) 2sin^2x + sinx1=0 (2sinx+1)(sinx1)=0 x=30 x=270 but if i plug 270 back into the original equation i get undefined because tan 270 is ... 
Math
How do I solve this? tan^2x= 2tanxsinx My work so far: tan^2x  2tanxsinx=0 tanx(tanx  2sinx)=0 Then the solutions are: TanX=0 and sinX/cosX = 2 sin X Divide through by sinX: we have to check this later to see if allowed (ie sinX is not zero) cosX=1/2 Now, if CosX=1/2, then ... 
advanced functions
Use the Pythagorean identity to show that the double angle formula for cosine can be written as a) cos2x = 1  2sin^2x b) cos2x = 2cos^2x  1 
Precalc
prove the identity: (cosx)(tanx + sinx cotx)=sinx+cos(squared)x i need steps to show how i got the answer generally, it is a good idea to change all trig ratios to sines and cosines, and start with the more complicatedlooking side. so.... LS = cosx(sinx/cosx + sinx(cosx/sinx... 
Trig identies, Calculus
Use the identities cos^2 x + sin^2 x =1 and cos2x=cos^2 x sin^2 x to show that cos^4 x sin^4 x = cos2x Im not sure how, I can solve my problem with half angle identities but im not sure where to start with this. 
Trig
Simplify sin x cos^2xsinx Here's my book's explanation which I don't totally follow sin x cos^2xsinx=sinx(cos^2x1) =sinx(1cos^2x) =sinx(sin^2x) (Where does sine come from and what happend to cosine?) =sin^3x 
trigonometry
how do i simplify (secx  cosx) / sinx? i tried splitting the numerator up so that i had (secx / sinx)  (cosx / sinx) and then i changed sec x to 1/ cosx so that i had ((1/cosx)/ sinx)  (cos x / sinx) after that i get stuck 
Trig
#1 (1/sinx)(sin^2x + cos^2x(sinx/cosx) )/(sinx + cosx) = (sinx + cosx)/(sinx+cosx) = 1 Reiny helped with this question but I don't how Reiny did it. Please explain 
Calculus
If y=3/(sinx+cosx) , find dy/dx A. 3sinx3cosx B. 3/(sinx+cosx)^2 C. 3/(sinx+cosx)^2 D. 3(cosxsinx)/(sinx+cosx)^2 E. 3(sinxcosx)/(1+2sinxcosx) 
math
Solve for: 1+cosx/sinx + sinx/1+cosx = 1 My teacher said no solution, but I don't know how he got that. 
Calculus
Find the derivative of y with respect to x: y=(1+cos²x)^6 y'=6(1+cos²x)^5 How do you derive inside the brackets? The answer says sin2x, but wouldn't it be 2sinx, using the chain rule. 
Trigonometry
4. Find the exact value for sin(x+y) if sinx=4/5 and cos y = 15/17. Angles x and y are in the fourth quadrant. 5. Find the exact value for cos 165degrees using the halfangle identity. 1. Solve: 2 cos^2x  3 cosx + 1 = 0 for 0 less than or equal to x <2pi. 2. Solve: 2 sinx... 
Math
Differentiate (1 sinx) / (1 +sinx) How would I do this? The answer is (2cosx)/ (1 + sinx)^2 Thanks in advance :)!! 
PreCalc
Radical ((1sinx)/(1+sinx))= (1sinx)/cosx (absolute) Simplify 
Mathgr12
How would I solve this equation for x in the interval 0<x<2pi tan^2x sinx  sinx/3 = 0 Please explain it step by step..ive been stuck on this question for far too long..sigh 
math
y= 2sin^2 x y=1 sinx find values of x inthe interval 0<x<360 if 2sin^x = 1sinx this can be arranged into the quadratic. 2sin^2 x + sin x 1=0 (2sinx 1)(sinx + 1)=0 or sinx = 1/2 and sin x=1 
Trig
cos2x(2cosx+1)=0 Solve for x. 
maths
cos2xcosx+1=0 solve this 
trigonometry
Been trying this forever so it says: Simplify 1+sin2x+cos2x/1+sin2xcos2x ive tried this problem so many times I need help with it... 
Calculus 2 Trigonometric Substitution
I'm working this problem: ∫ [1tan^2 (x)] / [sec^2 (x)] dx ∫(1/secx)[(sin^2x/cos^2x)/(1/cosx) ∫cosxsinx(sinx/cosx) ∫cosx∫sin^2(x)/cosx sinx∫(1cos^2(x))/cosx sinx∫(1/cosx)cosx sinx∫secx∫cosx sinxsinx∫secx =... 
calculus
Solve for x on the interval (0, 2pi] (sin2x + cos2x)^2 = 1