1. Math Help

    Hello! Can someone please check and see if I did this right? Thanks! :) Directions: Find the exact solutions of the equation in the interval [0,2pi] cos2x+sinx=0 My answer: cos2x+sinx=cos^2x-sin^2x+sinx =1-sin^2x-sin^2x+sinx =-2sin^2x+sinx+1=0
  2. Trig--check answer

    Solve the equation of the interval (0, 2pi) cosx=sinx I squared both sides to get :cos²x=sin²x Then using tri indentites I came up with cos²x=1-cos²x Ended up with 2cos²x=1 Would the answer be cos²x=1/2???
  3. math

    the problem is 2cos^2x + sinx-1=0 the directions are to "use an identity to solve each equation on the interval [0,2pi). This is what i've done so far: 2cos^2x+sinx-1=0 2cos^2x-1+sinx=0 cos2x + sinx =0 1 - 2sin^2x + sinx = 0 -2sin^2x+sinx-1=0 2sin^2x-sinx+1=0 I think i'm ...
  4. math

    cos2x-sinx=0. Factor and solve for sinx
  5. Precalculus

    Please help!!!!!!!!!!! Find all solutions to the equation in the interval [0,2π). 8. cos2x=cosx 10. 2cos^2x+cosx=cos2x Solve algebraically for exact solutions in the interval [0,2π). Use your grapher only to support your algebraic work. 24. cos2x+sinx=0
  6. Math - Trig - Double Angles

    Prove: sin2x / 1 - cos2x = cotx My Attempt: LS: = 2sinxcosx / - 1 - (1 - 2sin^2x) = 2sinxcosx / - 1 + 2sin^2x = cosx / sinx - 1 = cosx / sinx - 1/1 = cosx / sinx - sinx / sinx -- Prove: 2sin(x+y)sin(x-y) = cos2y - cos2x My Attempt: RS: = 1 - 2sin^2y - 1 - 2sin^2x = 1 - 1 - ...
  7. Trigonometry

    solve Sinx=Cos2x-1 for 0¡Üx<2¦Ð
  8. trig

    how do you solve: find cos2x if sinx is equal to 1/5
  9. math

    solve for sinx=cos2x (between 0 and 2pi)
  10. Trig

    Solve Sinx=Cos2x-1 for all values between 0 and 2pi
  11. maths

    solve for x for angles between o and 360 degrees (i)cos2x+sinx=0
  12. Calculus grade 12

    solve for (<_ = less than or equal to / pie = pie sign / -pie = negative pie) 3 sin²x = cos²x ; 0 <_ x < 2pie cos²x - sin²x = sinx ; -pie < x <_ pie
  13. Trig Help

    Prove the following: [1+sinx]/[1+cscx]=tanx/secx =[1+sinx]/[1+1/sinx] =[1+sinx]/[(sinx+1)/sinx] =[1+sinx]*[sinx/(sinx+1)] =[sinx+sin^2x]/[sinx+1] =[sinx+(1-cos^2x)]/[sinx+1] =??? This is where I'm stuck. Can someone help me. Please check what I got is right so far it's ...
  14. Calculus

    Solve identity, (1-sin2x)/cos2x = cos2x/(1+sin2x) I tried starting from the right side, RS: =(cos²x-sin²x)/(1+2sinxcosx) =(cos²x-(1-cos²x))/(1+2sinxcosx) and the right side just goes in circle. May I get a hint to start off?
  15. trig

    sinx = 4/5 and x terminates in Quadrant II Find sin2x and cos2x How to get the answers, which are sin2x = -24/25, cos2x = -7/25?
  16. Trig

    If sinx = 1/4 Find the exact value of cos2x I used the formula for double angle identities : cos2x = 1-2sin^2x and got the answer 1/2 The book says the answer is 7/8 How would they get to that conclusion?
  17. Math please help quick

    Which of the following are identities? Check all that apply. (Points : 2) sin2x = 1 - cos2x sin2x - cos2x = 1 tan2x = 1 + sec2x cot2x = csc2x - 1 Question 4. 4. Which of the following equations are identities? Check all that apply. (Points : 2) Question 5. 5. The expression ...
  18. Math (Trig) a.s.a.p, thanks!

    verify the identities: 1.) 2tanx-(1+tanx)^2 = -secx 2.) cos(x-330degrees)=1/2(ã3cosx-sinx) *the ãis only over the 3* 3.) 1+cos2x/sinx=cotx any help is greatly appreciated!!
  19. Trig

    Verify the identity: tanx(cos2x) = sin2x - tanx Left Side = (sinx/cosx)(2cos^2 x -1) =sinx(2cos^2 x - 1)/cosx Right Side = 2sinx cosx - sinx/cosx =(2sinxcos^2 x - sinx)/cosx =sinx(2cos^2 x -1)/cosx = L.S. Q.E.D.
  20. Advanced Math

    Could someone help me with those two questions. I need to know how to do them without calculator solve for the interval [0,2pie] 1) cos^2*x-cos2x=0 2) tan(x/2)-sinx=0
  21. math

    solve each equation for 0=/<x=/<2pi sin^2x + 5sinx + 6 = 0? how do i factor this and solve? 2sin^2 + sinx = 0 (2sinx - 3)(sinx +2) sinx = 3/2, -2 how do I solve? These are not part of the special triangles. 2cos^2 - 7cosx + 3 = 0 (2cosx - 1)(cosx - 3) cosx = 1/2, 3 x= pi...
  22. trig

    how does this work? (Sin2x+cos2x+2sin²x)/(sinx+cosx) = (sinx+cosx
  23. Math

    prove identity Sin2x - sinx/cosx + cos2x= sinx/cosx + 1
  24. Trig

    Prove the following functions: (sinx+sin2x)/(1+cosx+cos2x)=tan x (cos3x/sinx)+(sin3x/cosx)=2cot2x tan2x=(2/cotx-tanx) theses are due in the am. Fastness would be great?
  25. Math

    Solve the equation 2cos2x = √3 for 0°≤x≤360° I did this: cos2x = √3 /2 2x=30 x=15 x=15, 165, 195, 345 Is this correct? Solve the equation √3 sin2x + cos2x = 0 for -π≤x≤π No idea how to approach this one Thanks a bunch for the help!
  26. Trig.

    Can someone please help me with this? Find all solutions to the equation in the interval [0,2pi) cos2x=sinx I know I have to use some sort of identity, but I have no idea how to go about to solve this.
  27. Trig........

    I need to prove that the following is true. Thanks (cosx / 1-sinx ) = ( 1+sinx / cosx ) I recall this question causing all kinds of problems when I was still teaching. it requires a little "trick" L.S. =cosx/(1-sinx) multiply top and bottom by 1+sinx, (creating the difference ...
  28. Math 12

    Simplify #1: cscx(sin^2x+cos^2xtanx)/sinx+cosx = cscx((1)tanx)/sinx+cosx = cscxtanx/sinx+cosx Is the correct answer cscxtanx/sinx+cosx? Simplify #2: sin2x/1+cos2X = ??? I'm stuck on this one. I don't know what I should do. Simplify #3: cosx-sin(90-x)sinx/cosx-cos(180-x)tanx = ...
  29. Trigonometry

    Simplify #1: cscx(sin^2x+cos^2xtanx)/sinx+cosx = cscx((1)tanx)/sinx+cosx = cscxtanx/sinx+cosx Is the correct answer cscxtanx/sinx+cosx? Simplify #2: sin2x/1+cos2X = ??? I'm stuck on this one. I don't know what I should do. Simplify #3: cosx-sin(90-x)sinx/cosx-cos(180-x)tanx = ...
  30. Math/Calculus

    Please take a look at my work below and provide a good critique: Solve the differential equation using the method of undetermined coefficients or variation of parameters. y'' - 3y' + 2y = sin(x) yc(x)= c1*e^2x+c2*e^x y"-3y'+2y=sin(x) r^2-3r+2=0 (r-1)(r-2)=0 r1=1, r2=2 yp(x)=...
  31. trig

    Find the general solution for x if cos2x + sin3x = sinx
  32. trig

    Find the solutions to the equation cos2x=sinx and 2cos^2x-3cosx-3=0
  33. Math

    Find the exact solution of cos2x+sinx=0 in the interval [0,2pi)
  34. maths please answer NOW!!!!!

    solve algebreically the equation cos2x=1-sinx also cosx=cosx-1 and please also sin2x=3sinx
  35. calculus

    Could someone check my reasoning? thanx Find the derivative of the function. sin(sin[sinx]) I need to use the chain rule to solve. So I take the derivative sin(sin[sinx) first. Then multiply that by the inside which is the derivative of sin[sinx]. And multiply that by ...
  36. Trig

    help please!: (sinx + sin2x +sin3x) / (cosx + cos2x + cos3x) = tan2x
  37. Identities

    Verify the following identity cos2x/sin2x+sinx/cosx=csc2x
  38. Calculus

    In the interval (0 is less than or equal to x which is less than or equal to 5), the graphs of y=cos(2x) and y=sin(3x) intersect four times. Let A, B, C, and D be the x-coordinates of these points so that 0<A<B<C<D<5. Which of the definite integrals below ...
  39. Pre Calculus

    Establish the following identity sin 2x/sinx - cos2x/cosx = secx
  40. Trigonometry

    find sin2x, cos2x, and tan2x if sinx= -2/sqrt 5 and x terminates in quadrant III
  41. Math

    Use a double-angle formula to find the exact value of cos2x when sinx = 3/5, where pi/2 < x < pi. -(7/25) or 7/25?
  42. calc

    Where do I start to prove this identity: sinx/cosx= 1-cos2x/sin2x please help!! Hint: Fractions are evil. Get rid of them. Well, cos2x = cos2x - sin2x, so 1-coscx = 1 - cos2x - sin2x = 1 - cos2x + sin2x You should be able to simplify this to 2*something squared. The ...
  43. Trig

    solve to four decimals places 5.0118 sinx - 3.1105=0 :for all real x values I will be happy to critique your work. Solve for sinx, then arcsinx
  44. Trigonometry

    Simplify the expression using trig identities: 1. (sin4x - cos4x)/(sin2x -cos2x) 2. (sinx(cotx)+cosx)/(2cotx)
  45. Trigonometry.

    ( tanx/1-cotx )+ (cotx/1-tanx)= (1+secxcscx) Good one! Generally these are done by changing everything to sines and cosines, unless you see some obvious identities. Also generally, it is best to start with the more complicated side and try to change it to the "easier" side. so...
  46. Pre-Calculus

    Find all solutions to the equation in the interval [0, 2pi) cos4x-cos2x=0 So,this is what i've done so far: cos4x-cos2x=0 cos2(2x)-cos2x (2cos^2(2x)-1)-(2cos^2(x)-1) No idea what to do next.
  47. Math

    Solve the integral from [0,pi] of x*sinx*cosx*dx I don't understand how to solve this problem because if I let u =x and du =1 and dv=sinx*cosx, I can't find v. How do you solve this?
  48. Mathematics - Trigonometric Identities

    Prove: (tanx)(sinx) / (tanx) + (sinx) = (tanx) - (sinx) / (tanx)(sinx) What I have so far: L.S. = (sinx / cosx) sinx / (sinx / cosx) + sinx = (sin^2x / cosx) / (sinx + (sinx) (cosx) / cosx) = (sin^2x / cosx) / (cosx / sinx + sinxcosx)
  49. Trig.......

    I need to prove that the following is true. Thanks (2tanx /1-tan^x)+(1/2cos^2x-1)= (cosx+sinx)/(cosx - sinx) and thanks ........... check your typing. I tried 30º, the two sides are not equal, they differ by 1 oh , thank you Mr Reiny I'll tell my teacher this Question is ...
  50. Trig Help

    Given that cos2x=7/12 and "270 equal or < 2x equal or < 360", find sinx. Please help and Thank you
  51. your preciouss helpp please

    how can you condense these cos^3x* cos2x^2 cos^3x+ cos2x^2 cos^3x- cos2x^2 Thank you soo much
  52. Precal

    show that: (1-tanx)/(1+tanx)= (1-sinx)/(cos2x)
  53. math

    sin*sin=1.732*sinx*cos2x
  54. trig

    I keep trying to find the power reducing formula for sin^4(x), but I can't seem to get all the fractional parts correct. The answer I should be getting is: sin^4(x)=(1/8)cos4x-(1/2)cos2x+(3/8) I can only get this far knowing feeling confident. When I go further I start making ...
  55. trigonometry

    can i use factoring to simplify this trig identity? the problem is sinx + cotx * cosx i know the answer is cscx and i know how to get it but i want to know if i can do factoring to get it bc i tried to but it wont give me the answer . this is the step i went through: 1) sinx...
  56. math

    solve sinx/2,cosx/2 & tanx/2 of the following:- (a)sinx=1/4 & x lies in second quadrant.
  57. Pre-cal

    1) Solve the equation sinx(sinx+1) = 0 I am having trouble with the first step. Could I do sin x^2 + 1 =0?
  58. Mathematics - Trigonometric Identities

    Prove: sinx + tanx = tanx (1 + cosx) What I have so far: LS: = sinx + tanx = sinx + (sinx / cosx) = (sinx) (cosx) + sinx / cos = tanx (cosx + sinx) I don't know what to do now
  59. Trig

    solve to four decimal places 1.3224sinx + 0.4732=0 :for all real x values solve for sinx, then arcsinx. solve for sinx, then arcsinx. so its sinx= -.4732/1.3224 and i get -.36594 but how do you get the other values for a real x Ok, use your calculator. Sinx is negative in the ...
  60. Math C30

    Equations containing circular functions and unit circle... solve 2cosx sinx + sinx = 0
  61. drwls

    My previous question: Verify that (secx/sinx)*(cotx/cscx)=cscx is an identity. (secx/sinx)*(cotx/cscx) = (secx/cscx)(cotx/sinx) = (sinx/cosx)*cotx*(1/sinx) "The last steps should be obvious" Not to me. I can convert (sinx/cosx) to tanx if that's even what I'm suppose to do. Is...
  62. Mathj C30

    Solving Equations Containing Circular Functions : Solve 2cosx sinx + sinx = 0 when x is between 0 and 2pi
  63. trig

    solve equation for exact solution if possible leave answer in degree sinx/2=square root of 2- sinx/2
  64. Maths

    If y=Sinx^Sinx^Sinx.......infinity then prove that dy/dx=2ycotx/1-ylog(sinx).?
  65. Math - Pre- Clac

    Prove that each of these equations is an identity. A) (1 + sinx + cos x)/(1 + sinx + cosx)=(1 + cosx)/sinx B) (1 + sinx + cosx)/(1 - sinx + cosx)= (1 + sin x)/cosx Please and thankyou!
  66. Trigonometry Check

    Simplify #3: [cosx-sin(90-x)sinx]/[cosx-cos(180-x)tanx] = [cosx-(sin90cosx-cos90sinx)sinx]/[cosx-(cos180cosx+sinx180sinx)tanx] = [cosx-((1)cosx-(0)sinx)sinx]/[cosx-((-1)cosx+(0)sinx)tanx] = [cosx-cosxsinx]/[cosx+cosxtanx] = [cosx(1-sinx]/[cosx(1+tanx] = (1-sinx)/(1+tanx) Is ...
  67. Math (trigonometric identities)

    I was given 21 questions for homework and I can't get the last few no matter how hard and how many times I try. 17. Sinx-1/sinx+1 = -cos^2x/(sinx+1)^2 18. Sin^4x + 2sin^2xcos^2x + cos^4x = 1 19. 4/cos^2x - 5 = 4tan^2x - 1 20. Cosx - sinx - cos^3x/Cosx = sin^2 - tanx 21. Sin^2x...
  68. Math

    Im really struggling with these proving identities problems can somebody please show me how to do these? I'm only aloud to manipulate one side of the equation and it has to equal the other side of the equation at the end Problem 1. Sinx/(cotx+1) + cosx/(tanx+1) = 1/(sinx+cosx...
  69. Math

    1) evaluate without a calculator: a)sin(3.14/4) b) cos(-3(3.14)/4) c) tan(4(3.14)/3) d) arccos(- square root of three/2) e) csctheata=2 2) verify the following identities: a) cotxcosx+sinx=cscx b)[(1+sinx)/ cosx] + [cosx/ (1+sinx)]= 2secx c) (sin^2x + 2sinx+1)/cos^2x= (1+sinx...
  70. Math trignometry

    how can you condense these cos^3x* cos2x^2 cos^3x+ cos2x^2 cos^3x- cos2x^2 Thanks a lot :)
  71. Trigonometic

    Solving Trigonometic Equations solve for x and give the answers as a equations : ( by radian) 1)cos(sinx)=1 <<<and thanks >>> We know sin 2x = 2(sinx)(cosx) so (sinx)(cos)=1/2(sin 2x) So we can change your equation from (sinx)(cosx)=1 to 1/2(sin 2x) = 1 (sin ...
  72. Pre-Calc

    Trigonometric Identities Prove: (tanx + secx -1)/(tanx - secx + 1)= tanx + secx My work so far: (sinx/cosx + 1/cosx + cosx/cosx)/(sinx/cos x - 1/cosx + cosx/cosx)= tanx + cosx (just working on the left side) ((sinx + 1 - cosx)/cosx)/((sinx - 1 + cosx)/cosx) ((sinx + 1 - cosx)/...
  73. Pre calc

    Please help me proof the identity. This isn't even math to me, I can not understand it so please show all work. God bless A)1-cos2x/sin2x=tanx B) sin4x/sinx=4cosxcos2x
  74. Math (Integrals) (Using given method)

    I would like to solve the ∫sin^2(pix) dx Using the given substitution identity: sin^2(x) = (1/2)(1-cos2x) This is what I did so far: ∫sin^2(pix) let u = pix du = pi dx (1/pi)∫sin^2(u)du Applying the identity is where I'm lost on how to continue further.. (1/pi)∫(1/2)(1...
  75. Maths

    Prove that cos3x/cosx-cos6x/cos2x=2(cos2x-cos4x)
  76. trig

    tanx = 5/12 and sinx<0 Find sin2x and cos2x How to get the answers of sin2x = 120/169 and cos 2x = 119/169?
  77. Math

    I'm only aloud to manipulate one side of the problem and the end result has to match the other side of the equation Problem 1. sinx + cosx + sinx + tanx + cosxcotx = secx + cscx Problem 2. ((sinx + cosx)/(1 + tanx))^2 + ((sinx - cos^2x)/(1 - cotx))^2 = 1 Problem 3. ((1 + sinx...
  78. maths - trigonometry

    I've asked about this same question before, and someone gave me the way to finish, which I understand to some extent. I need help figuring out what they did in the second step though. How they got to the third step from the second. [sinx + tanx]/[cosx + 1] = tanx LS=[sinx+tanx...
  79. Trigonometry

    I can't remember what formula to use for these. Note- the X's may be replaced by a theta symbol. I just didn't have one on my keyboard. Use the given information to find sin2X, cos2X and tan2X if 0< X <pi/2 1. sinX=12/13 2. cosX=3/5 3. tanX=2/3
  80. math

    tanx+secx=2cosx (sinx/cosx)+ (1/cosx)=2cosx (sinx+1)/cosx =2cosx multiplying both sides by cosx sinx + 1 =2cos^2x sinx+1 = 2(1-sin^2x) 2sin^2x + sinx-1=0 (2sinx+1)(sinx-1)=0 x=30 x=270 but if i plug 270 back into the original equation i get undefined because tan 270 is ...
  81. Math

    How do I solve this? tan^2x= 2tanxsinx My work so far: tan^2x - 2tanxsinx=0 tanx(tanx - 2sinx)=0 Then the solutions are: TanX=0 and sinX/cosX = 2 sin X Divide through by sinX: we have to check this later to see if allowed (ie sinX is not zero) cosX=1/2 Now, if CosX=1/2, then ...
  82. advanced functions

    Use the Pythagorean identity to show that the double angle formula for cosine can be written as a) cos2x = 1 - 2sin^2x b) cos2x = 2cos^2x - 1
  83. Pre-calc

    prove the identity: (cosx)(tanx + sinx cotx)=sinx+cos(squared)x i need steps to show how i got the answer generally, it is a good idea to change all trig ratios to sines and cosines, and start with the more complicated-looking side. so.... LS = cosx(sinx/cosx + sinx(cosx/sinx...
  84. Trig identies, Calculus

    Use the identities cos^2 x + sin^2 x =1 and cos2x=cos^2 x -sin^2 x to show that cos^4 x -sin^4 x = cos2x Im not sure how, I can solve my problem with half angle identities but im not sure where to start with this.
  85. Trig

    Simplify sin x cos^2x-sinx Here's my book's explanation which I don't totally follow sin x cos^2x-sinx=sinx(cos^2x-1) =-sinx(1-cos^2x) =-sinx(sin^2x) (Where does sine come from and what happend to cosine?) =-sin^3x
  86. trigonometry

    how do i simplify (secx - cosx) / sinx? i tried splitting the numerator up so that i had (secx / sinx) - (cosx / sinx) and then i changed sec x to 1/ cosx so that i had ((1/cosx)/ sinx) - (cos x / sinx) after that i get stuck
  87. Trig

    #1 (1/sinx)(sin^2x + cos^2x(sinx/cosx) )/(sinx + cosx) = (sinx + cosx)/(sinx+cosx) = 1 Reiny helped with this question but I don't how Reiny did it. Please explain
  88. Calculus

    If y=3/(sinx+cosx) , find dy/dx A. 3sinx-3cosx B. 3/(sinx+cosx)^2 C. -3/(sinx+cosx)^2 D. 3(cosx-sinx)/(sinx+cosx)^2 E. 3(sinx-cosx)/(1+2sinxcosx)
  89. math

    Solve for: 1+cosx/sinx + sinx/1+cosx = 1 My teacher said no solution, but I don't know how he got that.
  90. Calculus

    Find the derivative of y with respect to x: y=(1+cos²x)^6 y'=6(1+cos²x)^5 How do you derive inside the brackets? The answer says -sin2x, but wouldn't it be -2sinx, using the chain rule.
  91. Trigonometry

    4. Find the exact value for sin(x+y) if sinx=-4/5 and cos y = 15/17. Angles x and y are in the fourth quadrant. 5. Find the exact value for cos 165degrees using the half-angle identity. 1. Solve: 2 cos^2x - 3 cosx + 1 = 0 for 0 less than or equal to x <2pi. 2. Solve: 2 sinx...
  92. Math

    Differentiate (1- sinx) / (1 +sinx) How would I do this? The answer is (-2cosx)/ (1 + sinx)^2 Thanks in advance :)!!
  93. Pre-Calc

    Radical ((1-sinx)/(1+sinx))= (1-sinx)/cosx (absolute) Simplify
  94. Math-gr12

    How would I solve this equation for x in the interval 0<x<2pi tan^2x sinx - sinx/3 = 0 Please explain it step by step..ive been stuck on this question for far too long..sigh
  95. math

    y= 2sin^2 x y=1- sinx find values of x inthe interval 0<x<360 if 2sin^x = 1-sinx this can be arranged into the quadratic. 2sin^2 x + sin x -1=0 (2sinx -1)(sinx + 1)=0 or sinx = 1/2 and sin x=-1
  96. Trig

    cos2x(2cosx+1)=0 Solve for x.
  97. maths

    cos2x-cosx+1=0 solve this
  98. trigonometry

    Been trying this forever so it says: Simplify 1+sin2x+cos2x/1+sin2x-cos2x ive tried this problem so many times I need help with it...
  99. Calculus 2 Trigonometric Substitution

    I'm working this problem: ∫ [1-tan^2 (x)] / [sec^2 (x)] dx ∫(1/secx)-[(sin^2x/cos^2x)/(1/cosx) ∫cosx-sinx(sinx/cosx) ∫cosx-∫sin^2(x)/cosx sinx-∫(1-cos^2(x))/cosx sinx-∫(1/cosx)-cosx sinx-∫secx-∫cosx sinx-sinx-∫secx =-...
  100. calculus

    Solve for x on the interval (0, 2pi] (sin2x + cos2x)^2 = 1
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