
integrate from 0 to pi/4 (sec^2x)/((1+7tanx)^2)^1/3 integrate form pi^2/36 to pi^2/4 (cos(x^1/2))/(xsin(x^1/2))^1/2 integrate from 0 to pi/3 (tanx)/(2secx)^1/2

Question: Prove that [integrate {x*sin2x*sin[π/2*cos x]} dx] /(2xπ) } from (0π) = [ integrate {sin x*cos x*sin[π/2*cos x} dx ] from (0π). My thoughts on the question: We know that integrate f(x) dx from (0a) = integrate f(ax) dx from (0a) From that and by sin(2x)=...

1) Integrate Cos^n(x) dx 2) Integrate e^(ax)Sinbx dx 3) Integrate (5xCos3x) dx I Will be happy to critique your thinking on these. 1) Derive a recursive relation. 2) Simplest by replacing sin(bx) by Exp[i b x] and taking imaginary part at the end. 3) First integrate sin(yx) ...

Please can anyone help with the following problems  thanks. 1) Integrate X^4 e^x dx 2) Integrate Cos^5(x) dx 3) Integrate Cos^n(x) dx 4) Integrate e^(ax)Sinbx dx 5) Integrate 5xCos3x dx The standard way to solve most of these integrals is using partial integration. So, look ...

Please do help solve the followings 1) Integrate e^4 dx 2) Integrate dx/sqrt(90^24x^2) 3) Integrate (e^x+x)^2(e^x+1) dx 4) Integrate xe^x2 dx e^4 is a constant. 3) let u= e^x + x du= (e^x + 1)dx 4) let u= x du=dx v= e^x dv= e^x dx


6.] Replace the integral in exercise 5 (int. (1/ 1 – t) dt a = 0, b = 1/2with ?1/(1+t) dt with a = 0, b = 1, and repeat the four steps. a. integrate using a graphing utility b. integrate exactly c. integrate by replacing the integrand with a Taylor series and integrate term ...

Justify, with a written explanation or a mathematical reasoning and with a sketch of at least two different cases, the following properties of integrals: a) If f(x) is less than or equal to g(x) for a<=x<=b then integrate from a to b of f(x)dx is less than or equal to ...

integrate du/3u and integrate x/x^2 dx it might be simple...i just need a head start...tnx

How do you integrate [(x^2)(cos(2(x^3)))]? I tried to integrate by parts but I'm going in circles yet again...

integrate cos^3x dx tnk U

dy/dx = 2y^2 Integrating...y=2/3 y^3 + C put 1,1 into the equation, and solve for C. Then find the y for x=2 if y= a^uhttp://math2.org/math/integrals/tableof.htm see exponential functions. dy/dx=2y^2 and if y=1 when x=1, then when x=2, y=? how do i get x in the equation. do ...

Integrate sqrt(x^2 + 1) dx over [0,2*pi] I can substitute u=arctan x to get: Integrate (sec u)^3 du over [0,arctan(2*pi)] From there, I'm stuck. (thanks Count Iblis for your last help)

Find the greatest value of a,so that integrate [x*root{(a^2x^2)/(a^2+x^2)} ] from 0a<=(π2) Let I =integrate{ [x*root{(a^2  x^2)/(a^2+x^2)}]dx } from 0a I used the substitution u=root[x^2+a^] to simplify the further. After substituting and changing limits I got, I=...

Calculate the area bounded by the xaxis and the function f(x)= (xa)(xb), where a<b and a and b are constants. Please do it out in steps so I can understand it, and try to simplify the final answer and leave it in factored form. Frankly, I would multiply out the ...

integrate x(xsin(x)dx from 0 to pi


integrate xsin(2x)dx=

Integrate: f (x)/(2x + 1) dx let f represent integrate sign let u = x, du = dx => dx = du = f (u)/(2u + 1) du = f u (2u + 1)^(1) du = (1/2)u^2 (ln2u + 1) + c = (1/2)x^2 (ln2x + 1) + c ...what did I do wrong? The correct answer is (1/2)x  (1/4)ln2x + 1 + c

how do i integrate 2u du /u2+2u^2 so i used subsitution rule? or can i used integration by parts and how? thanks in adnvace

Calc length of arc of y=ln(x) from x=1 to x=2  So far: Definite Integral over x=(1,2) of sqrt(1 + 1/x) dx 1/x = tan^2 t x = 1/tan^2 t sqrt(1+1/x) = sqrt(1+tan^2 t) = sec t dx = 2 * tan^3 t * sec^2 t dt Integrate over x=(1,2): sec^3 t / tan^3 t dt Integrate over x=(1,2): ...

How do I integrate tanx (1+sec^4 x)^3/2 dx My daughter is doing surface area problems, and all the examples assume she knows how to finish it off once we get to the integration....

Please help me integrate this equation using partial fractions: Integrate [(x^2+5)/(x^3x^2+x+3)]dx. Thank you very much.

how do u integrate 1+u/3u+2u^2 please help me get started ...tnk u

integrate (3+x)x^(1/2)dx=? please help I have no idea how to integrate this problem

what do you get when you: integrate 10sin^4xcosx dx when you integrate 9x^2e^6x^3 dx

Hello im trying to integrate tan^3 dx i have solved out the whole thing but it doesnt match up with the solution.. this is what i did: first i broke it up into: integral tan^2x (tanx) dx integral (sec^2x1)(tanx) dx then i did a u substitution u = secx du = secxtanx dx (dx = ...


Hello im trying to integrate tan^3 dx i have solved out the whole thing but it doesnt match up with the solution.. this is what i did: first i broke it up into: integral tan^2x (tanx) dx integral (sec^2x1)(tanx) dx then i did a u substitution u = secx du = secxtanx dx (dx = ...

Did I do this problem right? Find the first and second derativesimplify your answer. y=xtanx y'= (x)(sec^2 x)+(tanx)(1) y'= xsec^2 x + tanx y"= (x)(2secx)(secxtanx)+sec^2 x + sec^2 x y"=2xsec^2 x tanx + 2 sec^2 x

I need help with integrating these two problems. Im stuck. 1. integrate (sin^1)dx/((1x^2)^3/2) sin^1 aka arcsin 2. integrate dx/((1x^2)^3/2) by using 1/z Any and all help will be appreciated!

integrate by parts integrate (4+x^2)^1/2

integrate by parts integrate (4+x^2)^1/2

1) Integrate (e^x+x)^2(e^x+1) dx 2) Integrate xe^x2 dx Let u=(e^x+x) du=(e^x +1) dx I will be happy to critique your work or thinking. You are posting work for me to do, and I am not inclined to do that, it will not help you for me to do it. I think I gave you strong hints on ...

But how do we integrate ln1+tanx da X=theta =int.[lncos xdx] +int.[sin x dx ]  int.[lncos x dx] ?

Integrate from 1 to 5 of (3x5)^5 dx = Integrate from a to b of f(u) du where (I have solved this part) u = 3x5 du = 3 a = 0 b = 12 The original value of the integral is 165888 via calculator here's my last question, and it has to be in terms of u: f(u) = ? (Again, in terms ...

Consider the area between the graphs x+y=16 and x+4= (y^2). This area can be computed in two different ways using integrals. First of all it can be computed as a sum of two integrals integrate from a to b of f(x)dx + integrate from b to c of g(x)dx What is the value of a, b, c...

Sketch the regions enclosed by the given curves. Decide whether to integrate with respect to x or y. Draw a typical approximating rectangle and label its height and width. integrate with either respect to x or y, then find area S of the region given that y=sqrt(x), y=x/2, and ...


Sketch the regions enclosed by the given curves. Decide whether to integrate with respect to x or y. Draw a typical approximating rectangle and label its height and width. integrate with either respect to x or y, then find area S of the region given that y=sqrt(x), y=x/2, and ...

integrate t*(t^2  1)^(1/3) dt over (0,3) I substitute u = t^2  1 du = 2t dt which leads to integrate (1/2) u^(1/3) du over(1,8) = (3/8) * u^(4/3) over (1/8) = 3/8 * [8^(4/3)  (1)^(4/3)] I would guess that (1)^(4/3) is +1, since the cube root of 1 is 1 and taking that ...

Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y. Then find the area of the region. 2y=4x^1/2,y=5,2y+1x=5 Do you really mean "2y+1x=5" ? It is not customary to use the coefficient 1 in front of a variable. It is unnecessary. ...

i need to integrate: (secx)^4 dx let u = sec x dv =sec^3 x dx Start with this. Then, you will have to deal with the integral of sec. You should be able to solve it after a few steps. Looks a little messy.

I had to integrate [(x^2+1)/(x^2x)]dx with partial fractions. My answer was 2ln abs(x1) ln abs(x)+C. But the answer on the answer sheet has an extra +x that I did not account for. Is that a typo or did I integrate incorrectly?

Find the area bounded by the parabola y^2=4x and the line y=2x4. Use vertical representative rectangles (integrate with respect to x) and horizontal representative rectangles (integrate with respect to y). the answer is 9 square units ... i just need to know how to get to that.

Find the area bounded by the parabola y^2=4x and the line y=2x4. Use vertical representative rectangles (integrate with respect to x) and horizontal representative rectangles (integrate with respect to y). the answer is 9 square units ... i just need to know how to get to that.

dy/dx = 4ye^(5x) a) Separate the differential equation, then integrate both sides. b) Write the general solution as a function y(x). For the second part, I got y(x)=e^((5e^(5x))/(5)) + C but I don't understand how to separate differential equations and/or integrate both sides...

Problems, once again. 1. Compute the average value of: f(x} = x/(x+3) over the interval [a,a] 2. Find the area of the region bounded by the graph of: y = 2√(x^2 + 1) X axis Y axis Line x = 1 On the first, integrate, then divide the integral by 2a. On the second, ...

Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y. Then find the area of the region. 2y=5x , y=3 and 2y+1x=6 It is easier to integrate with respect to the variable Area = Help!!!!


integrate sec^2(3x)(e^(tan3x))

I cannot for the life of me figure this out. Please help me. How do I integrate the function f(x) = 0.1 * e ^ (0.2 * x) from neg. Infinity to pos. Infinity? I seem to only be able to get 0, but the answer is 1. I think it is the x that is throwing me off. Please Hlep! ...

Integrate (6x^2cos(2x))dx??

integrate Cos^7(2x)

I've been working on this hw problem for a while now, but I'm stuck in the integration process. I'm pretty sure I made an error, cause I can't seem to be able to integrate the right side of the equation. Q: (1/(x^(2)+1))y' + xy = 3 using the equation d/dx(ry)=f(x)r(x) I found ...

Integrate [sinx/(1+cos^2(x))] from pi/2 to pi.

integrate sinx/ã4+cos^2x dx

Integrate (sin^2(t)+1)/(cos^4(t))dt

how do you integrate (cos^2 x)^4

dz =(−sinx + 2xy^2)dx +(2x^2 y)dy Integrate the differential to find the function z. Would I say that z was equal to two separate differentials and integrate the first part of the function with respect to x and the second part with respect to y? z = cosx + x^2 y^2 + x^2 ...


integrate sqrt(2((sin(x))^2 + 50((cos(x))^2  10sin(x)cos(x))

How do we integrate [(cosx)^2(nx)(sin(nx))]/[a(cos(nx))] dx?

Integrate Cos^7(2x) Explanation would be helpful

Integrate: Cos^7(2x) Explanation would be helpful

Integrate: ∫(cos^3 x)^2 dx

i have to integrate using u substitution, but i am not sure if i did it correct. çtan^3(5x)sec^2(5x)dx u=5x du=5dx 1/5du=dx 1/5çtan^3(u)sec^2(u)du 1/5tanusec^2u+c 1/5tan(5x)sec^2(5x)+c

Why does cos^2(x)= 1/2cos(2x)+1/2? I am trying to integrate, but the answer key says to first rewrite the expression like the above. I don't get how to change cos^2(x) into that. Explain?

integrate (sin^8 x  cos^8 x)/(1  2sin^2 x * cos^2 x) w.r.t. x

integrate 2/xln^4(x)...plz help me..give me an idea on how to start..plz The derivative of the ln(x) function is 1/x and this is multiplying the ln^4(x). You can thus write the integral as: 2 * 1/5 ln^5(x) + constant. is that the answer? wut about the x infront of ln^(x)......

integrate it by integrating factor (cos^3x)dy/dx +ycosx=sinx


Can someone help me to integrate by substitution the indefinite integral: (sinx)/ (1+cos(^2)x)?

i keep getting stuck and i think im missing something integrate by parts e^(bx) cos x dx thanks

Find the exact total of the areas bounded by the following functions: f(x) = sinx g(x) = cosx x = 0 x = 2pi I set my calculator to graph on the xaxis as a 2pi scale. The two functions appear to cross three times between x = 0 and 2pi. (including 2pi) Now, from top to bottom, ...

How do I derive the secant reduction formula? Am I asking this question wrong? Integrate: (sec x)^n dx

should i use substitution?? if yes how should should i use it? plz i need some directions? k plz someone?...so far i used trig. substitution. i got a=8, so i used x=asin(è)so according to this substitution i got x=8sin(è) and dx=8cos(è) dè...then i used used the plug them ...

Please help me the way through this sum Integrate Cos squared(3x) btwn x=pie/2 andx=0

integrate dy/dx=x(y^(1/2))(cos^2(y^(1/2))^2) I know I need to separate, and Iv'e moved dx to the right side with dy on the left. Don't know how to go on.

integrate cos^10xdx.. .plz show working i really wanna learn these thanks anyway

Solve it showing detail steps..please. Integrate : ∫(cos^3 x)^2 dx

Use Simpson's rule with n = 4 to approximate. Keep at least 2 decimal places accuracy. Integrate: (cos(x))/(x) x=1 to 5


Use the trapezoidal rule with n = 5 to approximate. Keep at least 2 decimal places accuracy. Integrate: (cos(x))/(x) from x=1 to 5

Consider the function f(x)=((x^2)/2)9. In this problem you will calculate integrate from 0 to 3 of ((x^2)/2)9)dx by using the definition integrate from a to b of (f(x))dx= lim as n approaches infinity of sum_(i=1)^n of (f(x_i))(delta x) The summation inside the brackets is...

How do you solve ∫sin(3x+4)dx? I got the cos(3x+4) part, but do you have to integrate the 3x+4 too? Does chain rule apply?

Integrate the following indefinite integral: (sin7x)^12 * (cos7x)^3 Hint: sin^2 + cos^2 = 1

integrate:cos^10xdx even with the previous hint a tutor here gave me i still don,t know it

the question asks to integrate cos(t)/ (5sin(t)+8)^2 the answer i got was xcos(t)/(5sin(t)+8)^2 this is not right i believe there is something wrong with the x in front of the cos.... please heplp

Integrate ( x^2cosx)/(1+sinx)^2 dx with limits form 0 ti pi/4

We are not going to do that work for you, but will be glad to help you. The unit sphere is the sphere with radius 1 centered in the origin. They give you the coordinates of a vector. Compute the dot product of the vector and the local surface area normal and integrate it over ...

Practice problem: A rocket sled for testing equipment under large accelerations starts at rest and accelerates according to the expression: a= (2.8 m/s^3)t + (3.9 m/s^2) How far does the rocket move in the time interval t=0 to t=0.81 s? This is just a practice problem to help ...

Integrate 1/sinx dx using the identity sinx=2(sin(x/2)cos(x/2)). I rewrote the integral to 1/2 ∫ 1/(sin(x/2)cos(x/2))dx, but I don't know how to continue. Thanks for the help.


Integrate (1/2)sin(x^(1/2))dx. I've tried using usubstitution, with u=sin(x^(1/2)). du would then = ((1/2)x^(1/2))(cos(x^(1/2))). As you can see, this only make the problem more complicated. I don't get what to do. Thank you in advance!

Q: If y=sinx/(1+tanx), find value of x not greater than pi, corresponding to maxima or minima value of y. I have proceeded thus Equating dy/dx=0 we get{ (1+tanx)cosxsinx.sec^2 x}/(1+tanx)^2=0……..(A) Or cosx+sinx=sinx.sec^2 x or cosx= sinx.sec^2sinx Or cosx=sinx.tan^2 x=...

resolve the partail fraction and then integrate.3x^234x+97/(x5)^3

Calculate the rotational inertia of a wheel that has a kinetic energy of 24,400 J when rotating at 677 rev/min. I know that I = mr^2 and that T = Ia; also I calculated 677rpm to be 70.9 radians/sec. But I don't understand how to integrate KE into this.

I have the function f(x) = cos(x) on the interval from 0 to pi and I need to comput the Fourier sine series. I have the integral of cos(x) multiplied by sin(nx), I can't figure out a way to integrate them! The "n" gets in the way, what do I do?

A) Assume the mass of a pendulum is 3kg. Calculate the work done by the pendulum on the mass from 0 degrees to 180 degrees ( you will need to integrate with respects to d(theta ) instead of dx given: the mass at the end of the string experiences a restoring force given by: F=...

1. (sec^2x6tanx+7/sec^2x5)=(tanx4/tanx+2) 2. (sin^3A+cos^3A/sinA+cosA)=1sinAcosA 3. csc^6xcot^6x+1+3csc^2xcot^2x please help

Given the triangle below, find sec X, tan X, and cos X in fraction form. *right triangle, hypotenuse goes from top right to bottom left, bottom side is longer than top side. Top right point is z, left point is X, bottom right angle (the right angle) is Y. The short side, ZY=15...

How do you integrate: 1/(x^21) dx ?

integrate (e^t + e^t)²


Integrate: x/(9+x^4)dx

Integrate:(3x^55)^3 dx thanks

integrate (2/3x^5)

Integrate from [0, 1/2]: 1/(4x^2+1)^(3/2) dx

how do you integrate x^2/(9+x^6)
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