# integral

2,003 results

**calc asap!**

can you help me get started on this integral by parts? 4 S sqrt(t) ln(t) dt 1 please help! thanks! Integral t^(1/2)Ln(t)dt = 2/3 t^(3/2)Ln(t)- 2/3 Integral t^(1/2) dt = 2/3 t^(3/2)Ln(t) - 4/9 t^(3/2) Simpler method: Integral t^(a)dt = t^(a+1)/(a+1) Integral d/da [t^(a)]dt = d/...

**Calculus**

If f(x) and g(x) are continuous on [a, b], which one of the following statements is true? ~the integral from a to b of the difference of f of x and g of x, dx equals the integral from a to b of f of x, dx minus the integral from a to b of g of x dx ~the integral from a to a of...

**calc**

how do you start this problem: integral of xe^(-2x) There are two ways: 1) Integration by parts. 2) Differentiation w.r.t. a suitably chosen parameter. Lets do 1) first. This is the "standard method", but it is often more tedious than 2) You first write the integral as: ...

**Calculus**

Find the volume of the solid whose base is the region in the xy-plane bounded by the given curves and whose cross-sections perpendicular to the x-axis are (a) squares, (b) semicircles, and (c) equilateral triangles. for y=x^2, x=0, and y=0 (a) integral (x^2)^2 from 0 to 2=32/5...

**Quick calc question**

If f(x) and g(x) are continuous on [a, b], which one of the following statements is false? the integral from a to b of the sum of f of x and g of x, dx equals the integral from a to b of f of x, dx plus the integral from a to b of g of x dx the integral from a to b of the ...

**Integral**

That's the same as the integral of sin^2 x dx. Use integration by parts. Let sin x = u and sin x dx = dv v = -cos x du = cos x dx The integral is u v - integral of v du = -sinx cosx + integral of cos^2 dx which can be rewritten integral of sin^2 x = -sinx cos x + integral of (...

**Calculus II/III**

A. Find the integral of the following function. Integral of (x√(x+1)) dx. B. Set up and evaluate the integral of (2√x) for the area of the surface generated by revolving the curve about the x-axis from 4 to 9. For part B of our question , the surface of revolution ...

**calculus (please with steps and explanations)**

consider the function f that is continuous on the interval [-5,5] and for which the definite integral 0(bottom of integral sign) to 5(top of integral sign) of f(x)dx=4. Use the properties of the definite integral to evaluate each integral: (a) definite integral from 0(on the ...

**Calculus (urgent help)**

consider the function f that is continuous on the interval [-5,5] and for which the definite integral 0(bottom of integral sign) to 5(top of integral sign) of f(x)dx=4. Use the properties of the definite integral to evaluate each integral: (a) definite integral from 0(on the ...

**Math/Calculus**

How would I solve the following integral with the substitution rule? Integral of: [(x^3)*(1-x^4)^5]dx Put 1-x^4 = y Then -4x^3 dx = dy Integral is then becomes: Integral of -1/4 y^5 dy ok, thanks a lot! I got it now.

**Calculus II**

Integrate using integration by parts (integral) (5-x) e^3x u = 5-x du = -dx dv = e^3x v = 3e^3x I wonder if this is right so far. = uv - (integral) v du = (5-x)(3e^3x) - (integral) (-3e^3x) =(5-x)(3e^3x) + (integral) (3e^3x) = (5-x)(3e^3x) + 9e^3x + C

**calculus**

consider the function f that is continuous on the interval [-5,5] and for which the definite integral 0(bottom of integral sign) to 5(top of integral sign) of f(x)dx=4. Use the properties of the definite integral to evaluate each integral: (a) definite integral from 0(on the ...

**Calc 121**

How do you integrate using substitution: the integral from 1 to 3 of: ((3x^2)+(2))/((x^3)+(2x)) There is a trick to this one that grealy simplifies the integral. Let u = x^3 + 2x. Then du = (3x^2 + 2)dx The integral then bemoces just the integral of du/u, which is ln u = ln (x...

**Calculus**

integral -oo, oo [(2x)/(x^2+1)^2] dx (a) state why the integral is improper or involves improper integral *infinite limit of integration (b) determine whether the integral converges or diverges converges? (c) evaluate the integral if it converges I know f(x)=arctan->f'(x)=1...

**calc**

find integral using table of integrals ) integral sin^4xdx this the formula i used integral sin^n xdx =-1/n sin^n-1xcosx +n-1/n integral sin^n-2 using the formula this is what i got: integral sin^4xdx=-1/4sin^3xcosx+3/4 integral sin^2xdx= -1/2sinxcosx+1/2 integral 1 dx can ...

**calculus**

8). Part 1 of 2: In the solid the base is a circle x^2+y^2=16 and the cross-section perpendicular to the y-axis is a square. Set up a definite integral expressing the volume of the solid. Answer choices: integral from -4 to 4 of 4(16-y^2)dy, integral from -4 to 4 of (16+y^2)dy...

**calculus**

1. integral -oo, oo [(2x)/(x^2+1)^2] dx 2. integral 0, pi/2 cot(theta) d(theta) (a) state why the integral is improper or involves improper integral (b) determine whether the integral converges or diverges converges? (c) evaluate the integral if it converges CONFUSE: how would...

**Calculus**

Use the symmetry of the graphs of the sine and cosine functions as an aid in evaluating each definite integral. (a) Integral of sinx*dx from -pi/4 to pi/4 (b) Integral of cosx*dx from -pi/4 to pi/4 (c) Integral of cosx*dx from -pi/2 to pi/2 (d) Integral of sinx*cosx*dx from -...

**Math**

Find the integrals. (show steps) (integral sign) xe^(4x^2) I think this how is how its done: (integral sign) xe^(4x^2) it's a u du problem let u=4x^2 so, du=8x dx now you have an x already so all u need is 8 inside and and 1/8 outside the integral [1/8] (integral sign) [8]xe^(...

**Integral Help**

I need to find the integral of (sin x)/ cos^3 x I let u= cos x, then got -du= sin x (Is this right correct?) I then rewrote the integral as the integral of -du/ u^3 and then rewrote that as the integral of - du(u^-3). For this part, I wasn't sure how to finish. I was hoping to...

**double integral**

1. Sketch the region of integration & reverse the order of integration. Double integral y dydz... 1st (top=1, bottom =0)... 2nd(inner) integral (top=cos(piex), bottom=(x-2)... 2. Evaluate the integral by reversing the order of integration. double integral sqrt(2+x^3) dxdy... ...

**integration by parts**

s- integral s ln (2x+1)dx ? = ln(2x+1)x - s x d( ln (2x+1)) = ln(2x+1)x- s x [(2x+1)'/ (2x+1)] dx = ln(2x+1)x- s x [(2)/ (2x+1)] ?... then i'm confused... "ln(2x+1)x- s x [(2)/ (2x+1)] ?... then i'm confused..." x [(2)/ (2x+1)] = 2x/(2x+1) = (2x+1-1)/(2x+1) = 1-1/(2x+1) B.t.w...

**calculus**

LEt f and g be continous functions with the following properties i. g(x) = A-f(x) where A is a constant ii. for the integral of 1 to 2 f(x)dx= the integral of 2 to 3 of g(x)dx iii. for the integral from 2 to 3 f(x)dx = -3A a find the integral from 1 to 3 of f(x)dx in terms of ...

**calculus**

LEt f and g be continous functions with the following properties i. g(x) = A-f(x) where A is a constant ii. for the integral of 1 to 2 f(x)dx= the integral of 2 to 3 of g(x)dx iii. for the integral from 2 to 3 f(x)dx = -3A a find the integral from 1 to 3 of f(x)dx in terms of ...

**math**

LEt f and g be continous functions with the following properties i. g(x) = A-f(x) where A is a constant ii. for the integral of 1 to 2 f(x)dx= the integral of 2 to 3 of g(x)dx iii. for the integral from 2 to 3 f(x)dx = -3A a find the integral from 1 to 3 of f(x)dx in terms of ...

**Calc BC**

1. Find the indefinite integral. Indefinite integral tan^3(pix/7)sec^2(pix/7)dx 2. Find the indefinite integral by making the substitution x=3tan(theta). Indefinite integral x*sqrt(9+x^2)dx 3. Find the indefinite integral. Indefinite integral cos(x)sin^3(x)dx

**Integral calculus**

You have not proved to me that the Integral of lnsinx w.r.t.x from 0 to pi/2 is equal to:Integral of lnsinx w.r.t.x from 0 to pi/4 plus Integral of lncosx w.r.t.x from 0 to pi/4.

**calculus**

consider the function f(x) = e^x(sinNx) on the interval [0,1] where N is a positive integer. a) Compute the integral from 0 to 1 of f(x). Evaluate this integral when N=5, N=10, and N=100. B) What happens to the graph and to the value of the integral as N-->infinity? Does ...

**calculus**

consider the function f(x) = e^x(sinNx) on the interval [0,1] where N is a positive integer. a) Compute the integral from 0 to 1 of f(x). Evaluate this integral when N=5, N=10, and N=100. B) What happens to the graph and to the value of the integral as N-->infinity? Does ...

**Calc 2**

a. Integral (x^2)/(sqrt(1+(x^2))) Would I separate these two into 2 separate integrals? Like: Integral of x^2 and the other integral of 1/sqrt(1+(x^2)) b. Integral (x^7)/(ln(x^4))dx Do I use integration by parts for this? I put u= lnx du = 1/x dv = x^7 v = (x^8)/8 It doesn't ...

**Math(Please check)**

evaluate the integral integral of 3 to 2 x/(x^2-2)^2 dx u=x^2-2 du=2x dx 1/2 du = x dx integral of 1/u^2 du -1/(x^2-2) Then I plug in 3 and 2 and subtract them form each other -1/(3^2-2) - (-1/(2^2-2) Is this correct?

**Calculus 2**

The question is: Evaluate the improper integral for a>0. The integral is: the integral from 0 to infinity, of e^(-y/a)dy Can anyone help me solve this? When I try I get 'a', which apparently is incorrect. Thank you!

**math**

Evaluate the given integral, where C is the circle with positive orientation. Cauchy integral theorem, integral over C (2z-3)/(z^(2)-4)(z+2) dz, C:|z+3|=3

**math**

evaluate the double integral and reverse order of integration [(first integral 0 to 1)(second integral 9y to 9)e^(x^2)dx)dy

**math**

Evaluate the following indefinite integral by using the given substitution to reduce the integral to standard form integral 2(2x+6)^5 dx, u=2x+6

**Calculus**

Can someone look over my work and tell me if my steps look correct? I'm trying to correct some problems that looked wrong. Instructions: Find the total areas between the given curves. 1. x= (y^3) and x=(y^2) on the interval [0,1] (integral from 0 to 1 of) ((y^3)-(y^2))dy = (...

**Calculus**

Which of the following is a step in evaluating. (Integral) cos^2 5x dx A. (Integral) 1+cos10x/2 dx B. (Integral) 1-cos10x/2 dx C. (Integral) 1+cos10x/20 dx D. (Integral) 1-cos10x/20 dx

**Calculus**

evaluate the integral or state that it diverges. Check if I did it correctly. integral 0,1 dr/r^.999 lim b->0+ integral b, 1 1000r^.001 =-1000

**math**

Evaluate the following indefinite integral by using the given substitution to reduce the integral to standard form integral cos(9x) dx, u=9x

**math**

How do I derive the secant reduction rule? Integral (sec x)^n dx = Integral (sec x)^(n-2) * (sec x)^2 dx = Integral ((tan x)^2 + 1)^(n/2-1) * (sec x)^2 dx Doing a substitution with: u = tax x du = (sec x)^2 dx = Integral (u^2 + 1)^(n/2-1) * du At this point I'm stuck. Any ...

**Calculus - Integrals**

I have 3 questions, and I cannot find method that actually solves them. 1) Integral [(4s+4)/([s^2+1]*([S-1]^3))] 2) Integral [ 2*sqrt[(1+cosx)/2]] 3) Integral [ 20*(sec(x))^4 Thanks in advance.

**Calculus - Integrals**

I have 3 questions, and I cannot find method that actually solves them. 1) Integral [(4s+4)/([s^2+1]*([S-1]^3))] 2) Integral [ 2*sqrt[(1+cosx)/2]] 3) Integral [ 20*(sec(x))^4 Thanks in advance.

**Calculus**

which of the following is equivalent to integral (a,b) k*f(x)+C)dx where k and C are constants k integral (a,b)(f(x)+C)dx ***** intergral (a,b)kdx + intergral (a,b)f(x)dx+ intergral (a,b) Cdx k integral (a,b)f(x)+ integral (a,b) Cdx integral (a,b) kdx * integral (a,b) f(x) dx...

**Calculus**

Evaluate the integral. 1/2 integral e^(t/2) (I'm not sure what the 1/2 on the left of the integral symbol means.)

**Calculus**

Hello, I'd appreciate any help with the following question below: Information: g(x)= 4 (x+1)^(-2/3) f(x)= ∫ g(t) dt The Question: What is f(26) ? (NOTE: I don't know how to do this on a key board, so I'll just say that while I did type an Indefinite integral for "f(x)" it is...

**calculus**

evaluate integral or state that it is diverges integral -oo, -2 [2/(x^2-1)] dx ----------------------------------- integral -oo, -2 [2/(x^2-1)] dx Through partial fractions, I came up with lim [ln(x-1)-ln(x+1)] b, -2 b->-oo I get (ln(3)-0)-(oo-oo)). The answer in the back ...

**Calculus integral**

evaluate the integral: integral from -pi/4 to 0 for the function 6sec^3x dx. it has to be an exact answer and i did it and keep getting it wrong. I got 4sqrt(2)-4ln(-sqrt(2)+1)

**calc check**

<<y=(1/A)*integral from a to b of: (1/2)[f(x)]^2 dx >> If that is the y value of the center of mass, I don't know why the factor (1/2) is there I also don't agree with your calculation of the x value, which should be 1/(ln 2). I agree with you that the area is ln 2...

**Math**

Identify u and du for the integral. 1. The integral of [(cosx)/(sin^(2)x)]dx 2. The integral of sec2xtan2xdx

**Quick calc question**

Which of the following definite integrals could be used to calculate the total area bounded by the graph of y = 1 – x2 and the x-axis? the integral from 0 to 1 of the quantity 1 minus x squared, dx plus the integral from 1 to 2 of the quantity 1 minus x square, dx the ...

**Quick calc question**

Which of the following definite integrals could be used to calculate the total area bounded by the graph of y = 1 – x2 and the x-axis? the integral from 0 to 1 of the quantity 1 minus x squared, dx plus the integral from 1 to 2 of the quantity 1 minus x square, dx the ...

**Quick calc question**

Which of the following definite integrals could be used to calculate the total area bounded by the graph of y = 1 – x2 and the x-axis? the integral from 0 to 1 of the quantity 1 minus x squared, dx plus the integral from 1 to 2 of the quantity 1 minus x square, dx the ...

**calc**

also: integral of tan^(-1)y dy how is integration of parts used in that? You write: arctan(y)dy = d[y arctan(y)] - y d[arctan(y)] Here we again have used the product rule: d(fg) = f dg + g df You then use that: d[arctan(y)] = 1/(1+y^2) dy So, the integral becomes: y arctan(y...

**Calculus**

Which of the following definite integrals could be used to calculate the total area bounded by the graph of y = 1 – x2 and the x-axis? the integral from 0 to 1 of the quantity 1 minus x squared, dx plus the integral from 1 to 2 of the quantity 1 minus x square, dx the ...

**Calc**

Evaluate the integral using any method: (Integral)sec^3x/tanx dx I started it out and got secx(1tan^2x)/tanx. I know I just have to continue simplifying and finding the integral, but I'm stuck on the next couple of steps. Also, I have another question witht he same directions...

**integral confusion**

integral of Sec[2x]Tan[2x] i know u is sec 2x du=2sec2xtan2x dx what would i have to multiply with du so it would equal tan 2x dx? if my question is confusing, then here's another example of what i'm talking about: integral of (3x-2)^30 dx u=3x-2 du=3 dx 1/3 du=dx (i need help...

**Math/Calculus**

How would I evaluate the following integral by using integration by parts? Integral of: (t^3)(e^x)? You mean (x^3)(e^x)? x^3 exp(x) dx = x^3 d[exp(x)] = d[x^3 exp(x)] - exp(x) d[x^3] = d[x^3 exp(x)] - 3 x^2 exp(x) dx So, if you integrate this you get x^3 exp(x) - 3 Integral of...

**Calculus**

In the interval (0 is less than or equal to x which is less than or equal to 5), the graphs of y=cos(2x) and y=sin(3x) intersect four times. Let A, B, C, and D be the x-coordinates of these points so that 0<A<B<C<D<5. Which of the definite integrals below ...

**Integration by Parts**

integral from 0 to 2pi of isin(t)e^(it)dt. I know my answer should be -pi. **I pull i out because it is a constant. My work: let u=e^(it) du=ie^(it)dt dv=sin(t) v=-cos(t) i integral sin(t)e^(it)dt= -e^(it)cos(t)+i*integral cost(t)e^(it)dt do integration by parts again, then I ...

**Calc**

Hello im trying to integrate tan^3 dx i have solved out the whole thing but it doesnt match up with the solution.. this is what i did: first i broke it up into: integral tan^2x (tanx) dx integral (sec^2x-1)(tanx) dx then i did a u substitution u = secx du = secxtanx dx (dx = ...

**Calc**

Hello im trying to integrate tan^3 dx i have solved out the whole thing but it doesnt match up with the solution.. this is what i did: first i broke it up into: integral tan^2x (tanx) dx integral (sec^2x-1)(tanx) dx then i did a u substitution u = secx du = secxtanx dx (dx = ...

**intergrals**

find value of def integral with a=-2 and b=2sqrt(3) definite integral is : x^3 * sqrt(x^2+4) dx for integral i get 1/15 *((4+x^2)^(3/2)) (-8+3x^2) for value i get [1536- 64sqrt(2)]/15 but its' wrong. help please

**Calculus**

I need help with this integral. w= the integral from 0 to 5 24e^-6t cos(2t) dt. i found the the integration in the integral table. (e^ax/a^2 + b^2) (a cos bx + b sin bx) im having trouble finishing the problem from here.

**definite integral**

Use the Riemann Sums corresponding to 5 inscribed rectangles of equal width to approximate the integral a= 1, b= 3, (1/x)dx this is all for definite integral i just know x1=1.4, x2=1.8, x3=2.2, x4=2.6, x5=3.0 how do i continue

**Calculus: Integral**

I don't understand how to do this one integral problem that involves secant. I'm asked to find the integral of sec^4 (4x). I'm not really sure how to go about solving this problem.

**math, calculus**

if f(1)=12 and f' is continuous, what is the value of f(4)? integral from 1 to 4 of f'(x)dx = 17 IF the integral of f'(x) dx from 1 to 4 is 17, as you say, then the function f(x), which is the integral with an arbitrary constant, changes by 17 from 1 to 4. Then the value of f(...

**Calculus**

Evaluate the integral: 16csc(x) dx from pi/2 to pi (and determine if it is convergent or divergent). I know how to find the indefinite integral of csc(x) dx, but I do not know how to evaluate the improper integral.

**Calculus Help Please Urgent!!!**

Prove that the integral on the interval [a,b] of x is equal (b^2-a^2)/2 integral a to be (x)dx = (b^2-a^2)/2 using the definition of a Definite Integral. This is the limit of a sum approach. show steps please!!! Thank you!!!

**Calc II**

Perform long division on the integrand, write the proper fraction as a sum of partial fractions, and evaluate the integral: (integral of) 2y^4dy/y^3 - y^2 + y - 1 After long divison I get: (integral of)2ydy + 2(integral of)dy + (integral of) 2/y^3 - y^2 + y - 1 I keep getting ...

**Quick calc question**

Suppose the integral from 2 to 8 of g of x, dx equals 13, and the integral from 6 to 8 of g of x, dx equals negative 3, find the value of 2 plus the integral from 2 to 6 of g of x, dx. 16 18 8 32

**Quick calc question**

Suppose the integral from 2 to 8 of g of x, dx equals 13, and the integral from 6 to 8 of g of x, dx equals negative 3, find the value of 2 plus the integral from 2 to 6 of g of x, dx. 16 18 8 32

**calc II**

Express the integrals as the sum of partial fractions and evaluate the integral: (integral of) (x^2)dx/(x-1)(x^2 +2x+1) My work: The above integral is equal to x^2dx/(x+1)^2 (A/x-1) + (B/x+1) + (Cx+D)/(x+1)^2 = x^2 A(x+1)^2 + B(x-1)(x+1) + (Cx+d)(x-1) = x^2 Ax^2 + 2Ax + A + Bx...

**Calculus**

F(x) = cos(x) • the integral from 2 to x² + 1 of e^(u² +5)du Find F'(x). When i did this, i got: -2xsin(x)e^((x²+1)² + 5) But my teacher got: -sin(x) • the integral from x² + 1 of e^(u² +5)du + 2xcos(x)e^((x²+1)² + 5) Do you know why the integral is in his answer? ...

**Calculus II**

Evaluate using u-substitution: Integral of: 4x(tan(x^2))dx Integral of: (1/(sqrt(x)*x^(sqrt(x))))dx Integral of: (cos(lnx)/x)dx

**Calculus**

Suppose the integral from 2 to 8 of g of x, dx equals 5, and the integral from 6 to 8 of g of x, dx equals negative 3, find the value of the integral from 2 to 6 of 2 times g of x, dx . 8 MY ANSWER 12 16 4

**calculus**

a) Let f(z) = z^2 and γ(t) = 1 + it^3, t ∈ [0,1]. i) Write out the contour integral ∫γ f(z)dz as an integral with respect to t. You do not need to evaluate this integral. ii) Evaluate the integral ∫0,1+i z^2dz iii) What is the relationship between ...

**Calculus**

Evaluate the Integral 1. integral of (x^9+7x^6-1)/x^8 dx 2. integral of x^(1/3)*(42-x)^2 dx 3. integral of 9x+5/7x^3 dx

**calculus**

Evaluate the Integral 1. integral of (x^9+7x^6-1)/x^8 dx 2. integral of x^(1/3)*(42-x)^2 dx 3. integral of 9x+5/7x^3 dx

**calc 2**

Determine whether the integral converges or diverges. Find the value of the integral if it converges. The integral where b=2 and a=0 (x/x^2-1 dx).

**Calculus**

Suppose the integral from 2 to 6 of g of x, dx equals 12 and the integral from 5 to 6 of g of x, dx equals negative 3 , find the value of the integral from 2 to 5 of 3 times g of x, dx

**Calc**

Suppose the integral from 2 to 6 of g of x, dx equals 12 and the integral from 5 to 6 of g of x, dx equals negative 3 , find the value of the integral from 2 to 5 of 3 times g of x, dx

**Calculus (double integral) PLEASE HELP!**

Evaluate double integral ln((x-y)/(x+y)) dy dx where the double integral region is the triangle with vertices (1,0),(4,3), (4,1). Hint: use a transformation with the Jacobian.

**Physics, Calculus(alot of stuff together)= HELP!!**

A rod extending between x=0 and x= 14.0cm has a uniform cross- sectional area A= 9.00cm^2. It is made from a continuously changing alloy of metals so that along it's length it's density changes steadily from 2.70g/cm^3 to 19.3g/cm^3. a) Identify the constants B and C required ...

**Calculus**

Find the area of the region bounded by y = x^2, y = 0, x = -1, and x = 2. I tried the integral from -1 to 2 of x^2 and got 3 as the answer. I tried (integral from 0 to 1 of √y + 1) + (integral from 0 to 4 of 2 - √y) and got 13/3. What is wrong with the way the integrals ...

**calc: arc length**

find the exact length of this curve: y = ( x^3/6 ) + ( 1/2x ) 1/2 <or= x <or= 1 im looking over my notes, but i'm getting stuck. here's my work so far: A ( 1 , 2/3 ) B ( 1/2 , 49/48 ) y' = [1/6 (3x^2)] + [1/2 (-1x^-2)] y' = ( x^2 / 2 ) - ( x^-2 / 2 ) (y')^2 = [( x^2 / 2...

**Math**

Calculate the integrals if they converge. 10.) Integral from 1 to infinity of X/4+X^2 dx 14.) integral from Pi/2 to Pi/4 of Sin X / sqrt cos x dx 22.) integral from 0 to 1 of ln x/x dx I'm having problems with working these out to figure out if they converge or not. Any help ...

**math**

Note: You can get full credit for this problem by just answering the last question correctly. The initial questions are meant as hints towards the final answer and also allow you the opportunity to get partial credit. Consider the definite integral from pi/6 to pi/2 cos(z)/...

**Calculus**

I don't know if I did these problems correctly. Can you check them? Use Integration by parts to solve problems. integral x^3(lnx)dx u=lnx dv=x^3dx du=1/x v=x^4/4 Answer:(x^3)(lnx)-(x^4/16) integral xcosxdx x cosx 1 sinx 0 -cosx Answer: xcosx+cosx integral e^2x(sinx)dx u=e^2x ...

**math**

Sorry I posted this question earlier with a error. Can anyone help me solve this now? Can someone help me answer this? If a < 5 the define integral [a, 4] 2.4e^(1.4x)dx = 44 Find the value a Define integral = integral sign a = lower limit 5 = upper limit

**Calc**

If we know that the definite integral from -6 to -3 of f(x) equals 6, the definite integral from -6 to -5 equals 2 and the definite integral from -4 to -3 equals 4 then: What is the definite integral from -5 to -4? I know that this is zero. But then what can we say about the ...

**math**

Generalize this to fine a formula for the integral: sin(ax)cos(bx)dx Could someone tell me what they got for an answer so I can check it to see if my answer is right. My answer: -1/2sinasinbx^2-1/3acosaxcosbx^3+ integral 1/3 a^2cosbx^3sinax..I'm not sure hot to find the ...

**calculus**

how do you determine the convergence of : definite integral from 1--> infinity of lnx/(x^3)? i set the problem as lim (R--->infinity) of the integral of lnx/(x^3) from 1--->R, but i can't compute the integral.

**Math**

1. Evaluate the indefinite integral integral symbol[6x5+2sec(x) tan(x)]dx. 2. Integral symbol 8 at the top, 5 at the bottom 3x2+3x2 dx = Thanks

**math**

Can someone help me answer this? If a < 5 the define integral [a, 4] 2.4e^(1.4x)dx = 44 Find the value a Define integral = integral sign a = lower limit 4 = upper limit

**please help me calc. have test tom**

d/dx integral from o to x of function cos(2*pi*x) du is first i do the integral and i find the derivative right. by the fundamental theorem of calculus, if there is an integral from o to x, don't i just plug the x in the function. the integral of the problem is cos*2*pi*) is ...

**Calculus**

True or False If F(x) and G(x) are antiderivatives of f(x), then F(x)=G(x)+C If f'(x) = g(x) then integral g(x) dx = f(x) + C Integral f(x) * g(x)dx = integral f(x)dx * integral g(x)dx I have a feeling it's False True True

**Integral question**

1) find the integral from 1to -1 if(5sinx-2tanx+3x^5)dx 2) find the integral of x^3/(x^4+1)dx

**calculus**

how do you solve the integral of 1/[(square root of x)(lnx)] from 2 to infinity? i did the p- integral theorem with 1/square root of x and got it to be a divergent integral. however i was told this was the wrong way and that i should do it by integration by parts. but i can't ...

**Calculus check**

The functions f and g are given by f(x)=sqrt(x^3) and g(x)=16-2x. Let R be the region bounded by the x-axis and the graphs of f and g. A. Find the area of R. B. The region R from x=0 to x=4 is rotated about the line x=4. Write, but do not evaluate, an integral expression the ...

**Calculus**

Use the shell method to set up, but do not evaluate, an integral representing the volume of the solid generated by revolving the region bounded by the graphs of y=x^2 and y=4x-x^2 about the line x=6. I had the shell radius as (6-x) and the shell height as (4x-2x^2). My final ...