Use implicit differentiation to find the equation of the tangent line to the curve xy^3+xy=5 at the point (4,1) . The equation of this tangent line can be written in the form y = mx+b where m is:?

159,267 results

  1. COLLEGE CALCULUS.

    Use implicit differentiation to find the equation of the tangent line to the curve xy^3+xy=5 at the point (4,1) . The equation of this tangent line can be written in the form y = mx+b where m is:? and where b is:?
  2. math calculus

    Use implicit differentiation to find the equation of the tangent line to the curve xy^3+2xy=9 at the point (31). The equation of this tangent line can be written in the form y=mx+b where m is
  3. math

    Use implicit differentiation to find the equation of the tangent line to the curve xy3+xy=14 at the point (7,1) . The equation of this tangent line can be written in the form y=mx+b i don't seem to no how to find m or b
  4. Calculus

    I am unsure of how to take the derivative of this equation. It may be the exponents that are giving me trouble but I'm not sure exactly. Find the equation of the tangent line to the curve 4e^xy = 2x + y at point (0,4). On the left side, is the "xy" the exponent of e, or do you...
  5. Calculus

    Use implicit differentiation to find an equation of the tangent line to the curve y^2 = x^3 (26 − x) at the point (1, 5).
  6. Calculus

    Use implicit differentiation to find an equation of the tangent line to the curve y^2 = x^3 (26 − x) at the point (1, 5).
  7. Calculus

    Use implicit differentiation to find an equation of the tangent line to the curve at the given point x^2 + xy + y^2 = 3, (1,1)
  8. calculus

    use implicit differentiation to find an equation of the tangent line to the curve at the given point. 9x^2+xy+9y^2=19, (1,1) (ellipse)
  9. calculus

    Use implicit differentiation to find an equation of the tangent line to the curve 3xy^3+4xy=63 at the point (9,1)(9,1).
  10. Calculus 1

    Use implicit differentiation to find an equation of the tangent line to the curve at the given point. x^2+y^2=(2x^2+4y^2−x)^2 (0, 0.25) (cardioid)
  11. Calculus 1

    Use implicit differentiation to find an equation of the tangent line to the curve at the given point. x^2+2xy-y^2+x=6 , (2,4) (hyperbola)
  12. Calculus 1

    Use implicit differentiation to find an equation of the tangent line to the curve at the given point. x^2/3 +y^2/3 =4 (-3sqrt(3),1) (astroid)
  13. Calculus AB

    Could someone please help me with these tangent line problems? 1) Find the equation of the line tangent to the given curve at the indicated point: 3y^3 + 2x^2 = 5 at a point in the first quadrant where y=1. 2) Show that there is no point on the graph of x^2 - 3xy + y^2 = 1 ...
  14. calculus

    Use implicit differentiation to find an equation of the tangent line to the curve at the given point. x2 + 2xy − y2 + x = 17, (3, 5) (hyperbola)
  15. Math, Calc

    Use implicit differentiation to find an equation of the tangent line to the curve at the given point x^2+2xy+4y^2=12. Point (2,1). (Eclipse)
  16. Calculus AB

    Sorry but I've got a lot of problems that I don't understand. 1) Let f(x)= (3x-1)e^x. For which value of x is the slope of the tangent line to f positive? Negative? Zero? 2) Find an equation of the tangent line to the oven curve at the specified point. Sketch the curve and the...
  17. Calculus

    If f(x)=(3x)/(1+x^2) find f′(4). Use this to find the equation of the tangent line to the curve y=3x1+x2 at the point (4,0.70588). The equation of this tangent line can be written in the form y=mx+b where m is: and where b is:
  18. calculus

    If f(x)=4x^(5/2), find f'(4) Use this to find the equation of the tangent line to the curve y=4x^(5/2) at the point (4,f(4)) . The equation of this tangent line can be written in the form y=mx+b where m is______ and where b is _____
  19. Calculus

    If F(x)=x^3−7x+5, use the limit definition of the derivative to find FŒ(5), then find an equation of the tangent line to the curve y=x^3−7x+5 at the point (5, 95). FŒ(5)= The equation of the tangent line is y = x + . Check your answer for yourself by graphing...
  20. Calculus. I need help!

    HARDER PARTS WAS 3(x^2+y^2)^2=26(y^2+y^2) Find the equation of the tangent line to the curve (a lemniscate) 3(x^2+y^2)^2=26(y^2+y^2) at the point (-4,2). The equation of this tangent line can be written in the form y=mx+b where m is:? and where b is:?
  21. math

    Find the equation of the tangent line to the curve y=5xcosx at the point (pi,–5pi). The equation of this tangent line can be written in the form y=mx+b where m= and b=
  22. calculus

    -find the equation of the tangent line to the curve y=5xcosx at the point (pi,-5pi) -the equation of this tangent line can be written in the form y=mx+b where m= and b= -what is the answer to m and b?
  23. Math (Implicit Differention)

    use implicit differentiation to find the slope of the tangent line to the curve of x^2/3+y^2/3=4 at the point (-1,3sqrt3)
  24. Calculus

    Find the equation of the tangent line to the curve y=2sinx at the point ((pi/6), 1). The equation of the tangent line can be written in y=mx+b form, where m=sqrt3. What is b?
  25. math

    Find the equation of the tangent line to the curve y=6tanx at the point (pi/4,6). The equation of this tangent line can be written in the form y=mx+b where m is: and where b is:
  26. Math please help!

    Find the equation of the tangent line to the curve: 2(x^2+y^2)^2 = 25(x^2-y^2) at the point ( 3 , 1 ). The equation of this tangent line can be written in the form y = mx+b
  27. Calculus

    If f(x)=(3x)/(1+x2) find f′(4)______. Use this to find the equation of the tangent line to the curve y=(3x)/(1+x2) at the point (4,0.70588). The equation of this tangent line can be written in the form y=mx+b where m is: ________ and where b is:______
  28. Math

    Find the equation of the tangent line to the curve: 2(x^2+y^2)^2 = 25(x^2-y^2) at the point ( 3 , 1 ). The equation of this tangent line can be written in the form y = mx+b
  29. Math Cal

    Use implicit differentiation to find an equation of the tangent line to the cardioid at the point (0, 0.5). x^2 + y^2 = (2x^2 + 2y^2 - x)^2
  30. Math / Calculus

    Use implicit differentiation to find an equation of the tangent line to the cardioid at the point (0,0.5) x^2+y^2=(2x^2+2y^2-x)^2 Y=
  31. Math (equation of tangent line)

    Consider the implicit equation 2xy-1=(x+y+1)^2 a) Compute and solve for the derivative dy/dx as a function of x and y. b) Find the equation of the tangent line to the graph of the above when y=-1. For part a, I found the derivative being equal -(x+1)/(y+1) but how would I find...
  32. calculus

    Use implicit differentiation to find the slope of the tangent line to the curve (y/x+8y)=x^8 +9 at the point (1,10/-79).
  33. CAL

    use implicit differentiation to find the slope of the tangent line to the curve (y)/(x-7y)=x^6+5 at the point (1,6/43)
  34. math

    use implicit differentiation to find the slope of the tangent line to the curve (y)/(x-7y)=x^6+5 at the point (1,6/43)
  35. Calculus

    (y/(x+9y))= (x^2)-7 at the point (1, -6/55) Use implicit differentiation to find the slope of the tangent line to the curve
  36. Calculus ap

    Use implicit differentiation to find the slope of the tangent line to the curve XY^3 + XY = 5 at the point (3,2) .
  37. Math

    Use implicit differentiation to find the slope of the tangent line to the curve y/( x + 4 y) = x^4 – 4 at the point (1,-3/13)
  38. Math

    Use implicit differentiation to find the slope of the tangent line to the curve y/( x + 4 y) = x^4 – 4 at the point (1,-3/13)
  39. Implicit Differentiation

    Use implicit differentiation to find the slope of the tangent line to the curve y/x+6y=x^2–6 at the point (1,–5/31) . Again i think i'm messing up with the algebra here. I used quotient rule to get [(x+6y)(y')-(y)(1+6y')]/(x+6y)^2=2x I don't know how to go from here to ...
  40. Calculus

    Use implicit differentiation to find an equation of the tangent line to the graph at the given point. x + y − 1 = ln(x^5 + y^5), (1, 0)
  41. Calculus

    Use implicit differentiation to find the slope of the tangent line to the curve –2x^2–2xy–1y^3=–3 at the point (–1–1).
  42. Rodriguez

    use implicit differentiation to find the slope of the tangent line to the curve of x^2/3+y^2/3=4 at the point (-1,3sqrt3)
  43. Calculus

    f(x)=(5x)/(1+2x^2). f'(4)=-75/289 f'(x)=(5-5x^2)/1+2x^2+x^4) Use this equation of the tangent line to the curve y=5x/(1+x^2) at the point (4, 1.17647). The equation of the tangent line can be written in the form y=mx+b. m=-75/289. What is b?
  44. Math

    Suppose f(x)=5/(x-2). f'(5)=-5/9. Use this to find the equation of the tangent line to the curve y=5/x-2 at the point (5,(5/3)). write your answer in the form y=mx+b where m is the slope and b is the y-intercept. The equation of the tangent line is.....
  45. Calculus 251

    The slope of the tangent line to the curve y= 3x^3 at the point (-1,-3) is:? The equation of this tangent line can be written in the form y=mx+b where m is:? and where b is:?
  46. Calculus

    the slope of the tangent line to the curve y=(3/x) at the point (6,0.5000) is? the equation of this tangent line can be written in the form y=mx+b where m is? and where b is?
  47. Implicit Differentiation (Please HELP)

    Write the equation of the line tangent to the curve x^2 − 4y^2 + 192 = 0 at (8, 8) Thank You
  48. Math (Calculus)

    Use implicit differentiation to find the slope of the tangent line to the curve y/(x–9y)=x^6–2 at the point (1,-1/-8). Can someone please help me? I don't understand
  49. Calculus

    Use implicit differentiation to write the slope-intercept equation of the tangent line to the graph of (x^2+4)y=8 at the point (2,1):
  50. Calculus

    Use implicit differentiation to write the slope-intercept equation of the tangent line to the graph of (x^2+4)y=8 at the point (2,1):
  51. Calculus Please help!

    Use implicit differentiation to find the slope of the tangent line to the curve at the point (1,3) -4x^2+4xy-2y^3=-46 m=____? ty guys so much!
  52. calculus

    Consider the curve defined by 2y^3+6X^2(y)- 12x^2 +6y=1 . a. Show that dy/dx= (4x-2xy)/(x^2+y^2+1) b. Write an equation of each horizontal tangent line to the curve. c. The line through the origin with slope -1 is tangent to the curve at point P. Find the x – and y – ...
  53. Help Calc.!

    original curve: 2y^3+6(x^2)y-12x^2+6y=1 dy/dx=(4x-2xy)/(x^2+y^2+1) a) write an equation of each horizontal tangent line to the curve b) the line through the origin with the slope .1 is tangent to the curve at P. Find x and y of point P.
  54. please help; calc

    original curve: 2y^3+6(x^2)y-12x^2+6y=1 dy/dx=(4x-2xy)/(x^2+y^2+1) a) write an equation of each horizontal tangent line to the curve b) the line through the origin with the slope .1 is tangent to the curve at P. Find x and y of point P.
  55. calculus; implicit differentiation

    Use implicit differentiation to find the slope of the tangent line to the curve at the point (4,1) -1x^2 - 4xy + 3y^3 = -29 I differentiated both sides and solved for dy/dx and got 2x-4y/9y^2-4x. Then I plugged in X and Y and got -4/7 but when i enter my answer it's wrong. ...
  56. calc

    for the parametric curve defined by x=3-2t^2 and y=5-2t ...sketch the curve using the parametric equation to plot of the point. use an arrow to indicate the direction of the curve for o<t<1. Find an equation for the line tangent to the curve at the point where t=-1. x=3...
  57. Calculus

    If ln(x^2-15y)=x-5+5 and y(-4)=1 find Y prime(-4) by implicit differentiation thus the equation of the tangent line to the graph at the point (-4,1) is y=
  58. Calculus

    Please help this is due tomorrow and I don't know how to Ive missed a lot of school sick Consider the curve given by the equation x^3+3xy^2+y^3=1 a.Find dy/dx b. Write an equation for the tangent line to the curve when x = 0. c. Write an equation for the normal line to the ...
  59. Calculus

    If G(x)=(x)/(1+2x), find G'(a) and use it to find an equation of the tangent line to the curve y=(x)/(1+2x) at the point (-1/4,-1/2). My answer: G'(a)=1/(1+2x)^2 Equation of tangent line: y= 4x+0.5
  60. Calculus

    1) An equation of the line contains points (7/9, 7) and (-7/9) is 2) Find the slope of the line tangent to the curve y=x^2 at the point (-0.6, 0.36) and find the corresponding equation of the tangent line
  61. Calculus

    Use implicit differentiation to find the slope of the tangent line to the curve 2(x^2) + 2xy + 2(y^3)= -18
  62. Calculus

    using implicit differentiation find the equation of the tangent line to the graph of the following function at the indicated point x^2 y^3 -y^2+xy-1=0 at (1,1)
  63. Calc.

    Find the area of the region bounded by the parabola y=x^2, the tangent line to this parabola at (1,1) and the x-axis. I don't really get what this question is asking. It looks like the area of right triangle to me...try the graph, and shade the area under the tangent. Find out...
  64. calculus

    Consider line segments which are tangent to a point on the right half (x>0) of the curve y = x^2 + 1 and connect the tangent point to the x-axis. If the tangent point is close to the y-axis, the line segment is long. If the tangent point is far from the y-axis, the line ...
  65. Calculus AP

    implicit differentiation Find the slope of the tangent line to the curve xy^3 + 2y - 0.76 =0 at the point (-3, o.7) I'm lost. so 3xy^2 * y' + 2y = 0 right?
  66. calc

    Find an equation of the tangent line to the curve at the given point. y = 6 x sin x P= (pi/2 , 3pi) i know the slope of a tangent line is equal to the first derivative. For that I got 6xcosx + 6sinx but idk how to put that into the y-y1=m(x-x1) formula to make the equation
  67. calculus

    find an equation of the tangent line to the curve at the given point. graph the curve and the tangent line y=x/x-1 at (2,2) )
  68. maths

    find the equation of the tangent to the curve 3xy^2 -4+2y=29 at the point (1,3)using implicit differentiation.
  69. AP AB Calculus

    Linear approximation: Consider the curve defined by -8x^2 + 5xy + y^3 = -149 a. find dy/dx b. write an equation for the tangent line to the curve at the point (4,-1) c. There is a number k so that the point (4.2,k) is on the curve. Using the tangent line found in part (b), ...
  70. Calculus

    Consider line segments which are tangent to a point on the right half (x>0) of the curve y = x^2+7 and connect the tangent point to the x-axis. If the tangent point is close to the y-axis, the line segment is long. If the tangent point is far from the y-axis, the line ...
  71. Calculus

    Find an equation of the tangent line to the curve at the given point. (Assume the tangent line form to be f(x) = mx + b.) y= e^x/x (1,e) I got m= 0 nd b=e could anyone tell if its right?
  72. Need help fast on calc

    original curve: 2y^3+6(x^2)y-12x^2+6y=1 dy/dx=(4x-2xy)/(x^2+y^2+1) a) write an equation of each horizontal tangent line to the curve b) the line through the origin with the slope .1 is tangent to the curve at P. Find x and y of point P. -when plugging y as 2 in original, it ...
  73. Math

    Given that x²cos y-sin y=0 ,(0,π): a)verfiy that given point is on the curve. b)use implicit differentiation to find the slope of the above curve at the given point. c)find the equation for tangent and normal to the curve at that point.
  74. Math (Pre Cal)

    Hi, I am studying for a precalculus quiz and I do not understand this hw problem: "The tangent line to a circle may be defined as the point that intersects a circle in a single point... If the equation of the circle is x^2+y^2=r^2 and the equation of the tangent line is y=mx+b...
  75. Equation of the Tangent Line

    Find the equation of a line tangent to te curve xy = sqrt(xy - x) + 1 at the point (1, 2).
  76. maths

    given the equation of the curve as y=8-2x^2 (a) find equations of tangent and the normal to this curve at the point where x=a. (b) find the value of a for which this tangent is parallel to the line with equation 3x-y+6=0
  77. calculus

    Alright so implicit differentiation is just not working out for me. Use implicit differentiation to find the slope of the tangent line to the curve at point (4,1). y / (x-2y) = x^3 + 4 Tried quotient rule to get the derivative of the left side, then got derivative of right ...
  78. Math

    In this problem we consider drawing some straight lines which form a nice pattern. Consider joining the point (0.1,0) to the point (0,0.9) by a line segment; then joining (0.2,0) to (0,0.8) by a line segment; and so on. In general, consider joining the points (a,0) and (0,b) ...
  79. cal

    find the equation of a quadratic function whose graph is tangent at x=1 to the line whose slope8, tangent at x=-2 to solve the line with slope-4 and tangent to the line y=-8 find the equation of the tangent lines at x=1 and x=-2 graph the quadratic function obtained and the 3 ...
  80. Tangent Lines-Calculus

    a line is tangent to the curve y= (x^2 + 3)/ (x+3)^1/2 at the point where x=1. write the equation of this line i get y= 3x-1 yet it's wrong. please explain thank you
  81. Calc.

    sketch the curve using the parametric equation to plot the points. use an arrow to indicate the direction the curve is traced as t increases. Find the lenghth of the curve for o<t<1. Find an equation for the line tangent to the curve at the point where t=-t. the equation...
  82. math

    Find the equation of the line tangent to the curve 2(x^2+y^2)^2=25(x^2+y^2) at a point (3,-1) written in the form y = mx+b
  83. Calc

    The slope of the tangent line to the parabola y=4x2–3x+5 at the point where x=–5 is: (-43) The equation of this tangent line can be written in the form y=mx+b where m is: (-43) and where b is:_____________?
  84. Calculus

    Suppose f(x) is differentiable at x=a. What does tangent line approximation, y=, mean? Select all that apply (A) Local linearization (B) y=f(x)-f(a)-f'(a)(x-a) (C) The best liner approximation of f(x) near a (D) After zooming y is a good approxiamtion to f(x) (E) f(x)~y=f(a...
  85. Calculus

    Suppose f(x) is differentiable at x=a. What does tangent line approximation, y=, mean? Select all that apply (A) Local linearization (B) y=f(x)-f(a)-f'(a)(x-a) (C) The best liner approximation of f(x) near a (D) After zooming y is a good approxiamtion to f(x) (E) f(x)~y=f(a...
  86. Calculus

    Suppose f(x) is differentiable at x=a. What does tangent line approximation, y=, mean? Select all that apply (A) Local linearization (B) y=f(x)-f(a)-f'(a)(x-a) (C) The best liner approximation of f(x) near a (D) After zooming y is a good approxiamtion to f(x) (E) f(x)~y=f(a...
  87. Calculus

    Suppose f(x) is differentiable at x=a. What does tangent line approximation, y=, mean? Select all that apply (A) Local linearization (B) y=f(x)-f(a)-f'(a)(x-a) (C) The best liner approximation of f(x) near a (D) After zooming y is a good approxiamtion to f(x) (E) f(x)~y=f(a...
  88. calculus

    The slope of the tangent line to the parabola y=4x2–6x+6 at the point where x=5 is: The equation of this tangent line can be written in the form y=mx+b where m is: and where b is:
  89. Calculus

    Use implicit differentiation to find the slope of the tangent line to the curve sqrt of x + sqrt of y = 8
  90. Math (Calculus) (mean value theorem emergency)

    Consider the graph of the function f(x)=x^2-x-12 a) Find the equation of the secant line joining the points (-2,-6) and (4,0). I got the equation of the secant line to be y=x-4 b) Use the Mean Value Theorem to determine a point c in the interval (-2,4) such that the tangent ...
  91. Implicit Differentiation

    Find the slope of the tangent line to the curve (a lemniscate) 2(x^2+y^2)^2=25(x^2–y^2) at the point (–3,1) . I know that we are supposed to use chain rule for this problem but i think i am messing up on the algebra. Can someone please help me, i keep on getting m= (42x^3-...
  92. Calculus - Damon

    Find the line which passes through the point (0, 1/4) and is tangent to the curve y=x^3 at some point. So I found the derivative which is 3x^2. Let (a, a3) be the point of tangency. 3x^2 = (a3 - 1/4)/(a-0) I'm not sure how to solve for a. Yes, the point is (0,1/4) but it's not...
  93. calculas

    The point P(7, −4) lies on the curve y = 4/(6 − x). (a) If Q is the point (x, 4/(6 − x)), use your calculator to find the slope mPQ of the secant line PQ (correct to six decimal places) for the following values of x. (i) 6.9 mPQ = (ii) 6.99 mPQ = (iii) 6.999 mPQ = (iv) 6...
  94. Calc AB

    Suppose that f(x) is an invertible function (that is, has an inverse function), and that the slope of the tangent line to the curve y = f(x) at the point (2, –4) is –0.2. Then: (Points : 1) A) The slope of the tangent line to the curve y = f –1(x) at the point (–4, 2) ...
  95. calculus

    a.Find the slope of the tangent line to the curve y=9-2x^2 at the point (2,1) b.Find an equation of this tangent line.
  96. Calculus

    the curve: (x)(y^2)-(x^3)(y)=6 (dy/dx)=(3(x^2)y-(y^2))/(2xy-(x^3)) a) find all points on the curve whose x-coordinate is 1 and write an equation for the tangent line of each of these points b)find the x-coordinate of each point on the curve where the tangent line is vertical
  97. AP Calculus

    Suppose that f has a continuous second derivative for all x, and that f(0)=1, f'(0)=2, and f''(0)=0. A. Does f have an inflection point at x=0? Explain your answer. B. Let g'(x) = (3x^2 + 2)f(x) + (x^3 + 2x + 5)f'(x). The point (0,5) is on the graph of g. Write the equation of...
  98. Math

    Use linear approximation, i.e. the tangent line, to approximate 1.6^3 as follows: Let f(x) = x ^3. The equation of the tangent line to f(x) at x = 2 can be written as y=12x-16 Using this, we find our approximation for 1.6 ^3 is ???????
  99. Calculus

    Use linear approximation, i.e. the tangent line, to approximate 8.4^(1/3) as follows: Let f(x)= x^(1/3) . The equation of the tangent line to f(x) at x=8 can be written in the form y=mx+c where m=1/12 and c=4/3: Using this, find our approximation for 8.4^(1/3).
  100. Calculus

    Use linear approximation, i.e. the tangent line, to approximate 8.4^(1/3) as follows: Let f(x)= x^(1/3) . The equation of the tangent line to f(x) at x=8 can be written in the form y=mx+c where m=1/12 and c=4/3: Using this, find our approximation for 8.4^(1/3).
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