# Relative to the center of the Earth, the position of the Moon can be approximated by (t) = r [cos (ωt) + sin (ωt) ], where r = 3.84 108 m and ω = 2.46 10-6 radians/s. (a) Find the

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### Physics

Relative to the center of the Earth, the position of the Moon can be approximated by (t) = r [cos (ωt) + sin (ωt) ], where r = 3.84 108 m and ω = 2.46 10-6 radians/s. (a) Find the magnitude and direction of the Moon's average velocity between t = 0 and t = 3.12 ...

### Physics Classical Mechanics

The mean distance from the center of the earth to the center of the moon is rem = 3.84 × 108 m. The mass of the earth is me = 5.98 × 1024 kg and the mass of the moon is mm = 7.34 × 1022 kg. The mean radius of the earth is re = 6.37 × 106 m. The mean radius of the moon is ...

### Calculus Physics

Imagine a spaceship on its way to the moon from the earth. Find the point, as measured from the center of the earth, where the force of gravity due to the earth is balanced exactly by the gravity of the moon. This point lies on a line between the centers of the earth and the ...

### Physics

A spaceship of mass 175,000 kg travels from the Earth to the Moon along a line that passes through the center of the Earth and the center of the Moon. At what distance from the center of the Earth is the force due to the Earth twice the magnitude of the force due to the Moon? ...

### Physics

The velocity of the Moon relative to the center of the Earth can be approximated by varrowbold(t) = v [−sin (ωt) xhatbold + cos (ωt) yhatbold], where v = 945 m/s and ω = 2.46 multiplied by 10−6 radians/s. (The time required for the Moon to complete ...

### Physics

A spacecraft is on a journey to the moon. At what point, as measured from the center of the earth, does the gravitational force exerted on the spacecraft by the earth balance that exerted by the moon? This point lies on a line between the centers of the earth and the moon. The...

### physics help please!

A spacecraft is on a journey to the moon. At what point, as measured from the center of the earth, does the gravitational force exerted on the spacecraft by the earth balance that exerted by the moon? This point lies on a line between the centers of the earth and the moon. The...

### physics

A spacecraft is on a journey to the moon. At what point, as measured from the center of the earth, does the gravitational force exerted on the spacecraft by the earth balance that exerted by the moon? This point lies on a line between the centers of the earth and the moon. The...

### Physics

A. Use the relation 2 m m m GM g R ƒ to find the acceleration due to gravity on the surface of the Moon. You can use the following data: Mass of the Moon m M = 7.35 ¡Ñ 1022 kg. Radius of the Moon m R = 1.74 ¡Ñ 106 m. B. How does this value compare with the acceleration ...

### Easy physics...having trouble with part b

Moon effect. Some people believe that the Moon controls their activities. If the Moon moves from being directly on the opposite side of Earth from you to being directly overhead, by what percentage does (a) the Moon's gravitational pull on you increase and (b) your weight (as ...

### Physics

Some people believe that the Moon controls their activities. The Moon moves from being directly on the opposite side of Earth from you to be being directly overhead. Assume that the Earth-Moon (center-to-center) distance is 3.82 multiplied by 108 m and Earth's radius is 6.37 ...

### Physics

How far is the center of mass of the Earth-Moon system from the center of the Earth? The Earth's mass is 5.97×1024 kg, the Moon's mass is 7.4×1022 kg, and the distance between their centers is 3.8×108 m.

### Physics

You are flying to the Moon. Find the point at which the gravitational attractions of Earth and Moon on you will be equal and opposite. Given: radius of the moon: 1.74*10^6 m radius of the earth: 6.38*10^6 m orbital radius of the moon: 3.8*10^8 m Not enough information has been...

### Physics

A spaceship of mass m travels from the Earth to the Moon along a line that passes through the center of the Earth and the center of the Moon. (a) At what distance from the center of the Earth is the force due to the Earth five times the magnitude of the force due to the Moon? ...

### Physics

The Moon causes tides because the gravitational force it exerts differs between the side of the Earth nearest the Moon and that farthest from the Moon. Find the difference in the accelerations toward the Moon of objects on the nearest and farthest sides of the Earth. (The mass...

### WSU PHY

The Moon causes tides because the gravitational force it exerts differs between the side of the Earth nearest the Moon and that farthest from the Moon. Find the difference in the accelerations toward the Moon of objects on the nearest and farthest sides of the Earth. (The mass...

### TRIG!

Posted by hayden on Monday, February 23, 2009 at 4:05pm. sin^6 x + cos^6 x=1 - (3/4)sin^2 2x work on one side only! Responses Trig please help! - Reiny, Monday, February 23, 2009 at 4:27pm LS looks like the sum of cubes sin^6 x + cos^6 x = (sin^2x)^3 + (cos^2x)^3 = (sin^2x+cos...

### physics

A spaceship of mass m travels from the Earth to the Moon along a line that passes through the center of the Earth and the center of the Moon. (a) At what distance from the center of the Earth is the force due to the Earth three times the magnitude of the force due to the Moon?

### tigonometry

expres the following as sums and differences of sines or cosines cos8t * sin2t sin(a+b) = sin(a)cos(b) + cos(a)sin(b) replacing by by -b and using that cos(-b)= cos(b) sin(-b)= -sin(b) gives: sin(a-b) = sin(a)cos(b) - cos(a)sin(b) Add the two equations: sin(a+b) + sin(a-b) = ...

### math

Can you please check my work. A particle is moving with the given data. Find the position of the particle. a(t) = cos(t) + sin(t) s(0) = 2 v(0) = 6 a(t) = cos(t) + sin(t) v(t) = sin(t) - cos(t) + C s(t) = -cos(t) - sin(t) + Cx + D 6 = v(0) = sin(0) -cos(0) + C C=7 2= s(0) = -...

### Mathematics - Trigonometric Identities

Let y represent theta Prove: 1 + 1/tan^2y = 1/sin^2y My Answer: LS: = 1 + 1/tan^2y = (sin^2y + cos^2y) + 1 /(sin^2y/cos^2y) = (sin^2y + cos^2y) + 1 x (cos^2y/sin^2y) = (sin^2y + cos^2y) + (sin^2y + cos^2y) (cos^2y/sin^2y) = (sin^2y + cos^2y) + (sin^2y + cos^2y)(sin^2y) / (sin^...

### physics

magine a straight line connecting the centers of the earth and the moon. At some point along this line the gravitational forces pulling a spacecraft towards the moon and towards the earth exactly balance each other, and the craft could just sit there in (an unstable) ...

### Physics

The average distance separating Earth and the Moon (center to center) is 384 000 km. Use the data in Table 7.3 to find the net gravitational force exerted by Earth and the Moon on a 3.00 multiplied by 104 kg spaceship located halfway between them (Earth mass kg: 5.98 x 10^24, ...

### algebra

Can someone please help me do this problem? That would be great! Simplify the expression: sin theta + cos theta * cot theta I'll use A for theta. Cot A = sin A / cos A Therefore: sin A + (cos A * sin A / cos A) = sin A + sin A = 2 sin A I hope this will help. in my algebra ...

### physics

Calculate the magnitude of the gravitational force between the Earth and an m = 6.00 kg mass on the surface of the Earth. The distance to the center of the Earth from the surface is 6.37×103 km and the mass of the Earth is 5.98×1024 kg. B)Calculate the magnitude of the ...

### physics

Suppose that the attraction between the moon and the earth were due to Coulomb forces rather than gravitational force. What would be the magnitude of the charge required if equal but opposite charges resided on both earth and moon? Mass of earth = 5.98×1024 kg; mass of moon...

### Physics

The Moon orbits the Earth at a distance of 3.85 x 108 m. Assume that this distance is between the centers of the Earth and the Moon and that the mass of the Earth is 5.98 x 1024 kg. Find the period for the Moon's motion around the Earth. Express the answer in days. The unit ...

### trig

Reduce the following to the sine or cosine of one angle: (i) sin145*cos75 - cos145*sin75 (ii) cos35*cos15 - sin35*sin15 Use the formulae: sin(a+b)= sin(a) cos(b) + cos(a)sin(b) and cos(a+b)= cos(a)cos(b) - sin(a)sin)(b) (1)The quantity = sin(145-75) = sin 70 = cos 20 note that...

### Physics

Consider a spaceship located on the Earth-Moon center line (i.e. a line that intersects the centers of both bodies) such that, at that point, the tugs on the spaceship from each celestial body exactly cancel, leaving the craft literally weightless. Take the distance between ...

### physics

Calculate the magnitudes of the gravitational forces exerted on the Moon by the Sun and by the Earth when the two forces are in direct competition, that is, when the Sun, Moon, and Earth are aligned with the Moon between the Sun and the Earth. (This alignment corresponds to a ...

### physics

What is the net gravitational field due the sun and earth at the center of the moon? You are given that the mass of the sun in 1.99 x 10^30 and the mass of the earth is 5.97 x 10^24. The distance from the center of the sun to the center of the earth is 1.496 x 10^8 and the ...

### geometry

A total solar eclipse occurs when the moon passes between the earth and the sun, and the darkest shadow cast by the moon, called the umbra, hits the surface of the earth. If the umbra does not hit the surface, as shown in the following figure, then a total solar eclipse is not...

### Physics

Calculate the position of the center of mass of the following pairs of objects. Use acoordinate system where the origin is at the center of the more massive object. Give youranswer not in meters but as a fraction of the radius as requested. Get data from insidethe front cover ...

### Physics Please help!

Calculate the position of the center of mass of the following pairs of objects. Use acoordinate system where the origin is at the center of the more massive object. Give youranswer not in meters but as a fraction of the radius as requested. Get data from insidethe front cover ...

### PHYSICS

Consider a spaceship located on the Earth-Moon center line (i.e. a line that intersects the centers of both bodies) such that, at that point, the tugs on the spaceship from each celestial body exactly cancel, leaving the craft literally weightless. Take the distance between ...

### Quantitative Reasoning (math)

Your weight on the moon is relative to your weight on Earth. Neil Armstrong weighed 360 lbs. in his moon gear while on Earth, but on the moon he only weighed 60 lbs. What is the ratio of the Earth weight to the moon weight? How much would you weigh (approximately) on the moon?

### Physics

The mass of the Moon is 7.35x10 to the 22nd Kg. At some point between the Earth and the Moon, the for of Earth's gravitational attraction on an object is cancelled by the Moon's force of gravitational attraction. If the distance between Earth and the Moon (centre to centre) is...

### physics hey damon one more please! =]

Consider a spaceship located on the Earth-Moon center line (i.e. a line that intersects the centers of both bodies) such that, at that point, the tugs on the spaceship from each celestial body exactly cancel, leaving the craft literally weightless. Take the distance between ...

### Physics

The moon is a satellite that orbits the earth at a radius of 3.85 × 108 m. The mass of the earth is 5.98 × 1024 kg. What is the orbital speed of the moon?

### Physics

I still cannot solve this problem: Consider a spaceship located on the Earth-Moon center line (i.e. a line that intersects the centers of both bodies) such that, at that point, the tugs on the spaceship from each celestial body exactly cancel, leaving the craft literally ...

### Physic

Given that the distance between the Earth and the Moon is d = 3.84 108 m, show that a satellite located exactly in-between the Earth and the Moon at a distance of 90% d from the Earth experiences no net force (at least when only the gravitational force due to the ...

### physics

still cant get this one? so damon i know you wanna help! or anyone else im open for suggestions haha Consider a spaceship located on the Earth-Moon center line (i.e. a line that intersects the centers of both bodies) such that, at that point, the tugs on the spaceship from ...

### Physics

The Earth has a mass of 5.97 x10^24 kg and the Moon has a mass of 7.36 x10^22kg. The average distance between the center of the Earth and the center of the moon is 3.84 x10^8m. (a) How far away would the Moon need to be for the magnitude of the gravitational force acting on it...

### Trig

Find sin(s+t) and (s-t) if cos(s)= 1/5 and sin(t) = 3/5 and s and t are in quadrant 1. =Sin(s)cos(t) + Cos(s)Sin(t) =Sin(1/5)Cos(3/5) + Cos(-1/5)Sin(3/5) = 0.389418 Sin(s-t) =sin(s)cos(t) - cos(s)sin(t) =sin(-3/5)cos(1/5) - cos(1/5)sin(3/5) =Sin-3/5 cos-3/5 = -0.46602 HELP ...

### Math

A series circuit contains a resistor with R = 24 , an inductor with L = 2 H, a capacitor with C = 0.005 F, and a generator producing a voltage of E(t) = 12 sin(10t). The initial charge is Q = 0.001 C and the initial current is 0. Find the charge at time t...

### Physics

1.Halley's comet moves about the sun in an elliptical orbit with its closest approach to the sun being 0.59 A.U. and its furthest distance being 35 A.U. [1 Astronomical Unit (A.U.) is the Earth-Sun distance.] If the comet's speed at closest approach is 54 km/s, what is its ...

### Physics

How far is the center of mass of the Earth-Moon system from the center of the Earth? The Earth's mass is 5.97e24 Kg, the Moon's mass is 7.4e22 Kg, and the distance between their centers is 3.8e8m.

### Math, Geomertry

A total solar eclipse occurs when the moon passes between the earth and the sun, and the darkest shadow cast by the moon, called the umbra, hits the surface of the earth. If the umbra does not hit the surface, as shown in the following figure, then a total solar eclipse is not...

### Physics [Help, need answer in 10 min]

During a solar eclipse, the moon (of mass 7.36 × 1022 kg), Earth (of mass 5.98 × 1024 kg), and Sun (of mass 1.99 × 1030 kg) lie on the same line, with the moon between Earth and the Sun. What gravitational force is exerted on the moon by the Sun? The universal gravitational...

### Trig

Given: cos u = 3/5; 0 < u < pi/2 cos v = 5/13; 3pi/2 < v < 2pi Find: sin (v + u) cos (v - u) tan (v + u) First compute or list the cosine and sine of both u and v. Then use the combination rules sin (v + u) = sin u cos v + cos v sin u. cos (v - u) = cos u cos v + ...

### Physics

Consider a spaceship located on the Earth-Moon center line (i.e. a line that intersects the centers of both bodies) such that, at that point, the tugs on the spaceship from each celestial body exactly cancel, leaving the craft literally weightless. Take the distance between ...

### physics

On the way from a planet to a moon, astronauts reach a point where that moon’s gravitational pull transitions from being weaker than that of the planet to being stronger than that of the planet. The masses of the planet and the moon are, respectively, 5.93 × 1024 kg and 7....

### Physics

Many astronomers argue that the Earth and Moon should be considered a double planet,since the gravitational force by the sun on the Moon is approximately as big as that by the Earth on the moon.Using the data below for the Earth and Moon at the particular point in their orbits...

### pre-cal

Simplify the given expression........? (2sin2x)(cos6x) sin 2x and cos 6x can be expressed as a series of terms that involve sin x or cos x only, but the end result is not a simplification. sin 2x = 2 sinx cosx cos 6x = 32 cos^6 x -48 cos^4 x + 18 cos^2 x - 1 I assume you are ...

### physic

The drawing (not to scale) shows one alignment of the sun, earth, and moon. The gravitational force SM that the sun exerts on the moon is perpendicular to the force EM that the earth exerts on the moon. The masses are: mass of sun = 1.99 1030 kg, mass of earth = 5.98 1024 kg, ...

### physics

The drawing (not to scale) shows one alignment of the sun, earth, and moon. The gravitational force SM that the sun exerts on the moon is perpendicular to the force EM that the earth exerts on the moon. The masses are: mass of sun = 1.99 1030 kg, mass of earth = 5.98 1024 kg, ...

### physics

The drawing (not to scale) shows one alignment of the sun, earth, and moon. The gravitational force that the sun exerts on the moon is perpendicular to the force that the earth exerts on the moon. The masses are: mass of sun=1.99 × 1030 kg, mass of earth=5.98 × 1024 kg, mass...

### Physics

The drawing (not to scale) shows one alignment of the sun, earth, and moon. The gravitational force SM that the sun exerts on the moon is perpendicular to the force EM that the earth exerts on the moon. The masses are: mass of sun = 1.99 1030 kg, mass of earth = 5.98 1024 kg, ...

### Physics

The drawing (not to scale) shows one alignment of the sun, earth, and moon. The gravitational force SM that the sun exerts on the moon is perpendicular to the force EM that the earth exerts on the moon. The masses are: mass of sun = 1.99 1030 kg, mass of earth = 5.98 1024 kg, ...

### Moon Science

What causes the phases of the moon as observed from the Earth? A) Filtering of the light from the moon due to the Earth's atmosphere. B) The tidal forces of the Earth's oceans change the appearance of the moon. C) Change in distance of the moon from the Earth as it orbits in ...

### science

The main cause of the changing location of the tides on earth is -rotation of the Earth on its' own axis - magnetic forces of the Moon - the revolution of the Moon around the Earth *** -the position of the Sun

### Physics

The mass of the Moon is 7.35 x 10^22 kg. At some point between Earth and the Moon, the force of Earth's gravitational attraction on an object is cancelled by the Moon's force of gravitational attraction. If the distance between Earth and the Moon (centre to centre) is 3.84 x ...

### physics

The mass of the Earth is 5.98x10^24 kg, and the mass of the Moon is 7.36x 10^22 kg. The distance of separation, measured between their centers, is 3.84x10^8 m. Locate the center of mass of the Earth-Moon system as measured from the center of the Earth. I tried using the ...

### physics

Locate the position of a spaceship on the Earth-Moon center line such that, at that point, the tug of each celestial body exerted on it would cancel and the craft would literally be weightless. What is the distance (in m from the moon)

### Calculus 12th grade (double check my work please)

1.)Find dy/dx when y= Ln (sinh 2x) my answer >> 2coth 2x. 2.)Find dy/dx when sinh 3y=cos 2x A.-2 sin 2x B.-2 sin 2x / sinh 3y C.-2/3tan (2x/3y) D.-2sin2x / 3 cosh 3yz...>> my answer. 2).Find the derivative of y=cos(x^2) with respect to x. A.-sin (2x) B.-2x sin (x^2...

### Physics

A canoe has a velocity of 0.480m/s southeast relative to the earth. The canoe is on a river that is flowing at 0.510m/s east relative to the earth. Find the magnitude of the velocity (V(C/R)) of the canoe relative to the river. Also, find the direction of the velocity of the ...

### Precal

I do not understand how to do this problem ((sin^3 A + cos^3 A)/(sin A + cos A) ) = 1 - sin A cos A note that all the trig terms are closed right after there A's example sin A cos A = sin (A) cos (A) I wrote it out like this 0 = - sin^6 A - cos^6 A + 2sin^3 A cos^3 A - 2sin^3 ...

### Math

Show that for real x that {[cos x + 2 sin x + 1]/[cos x + sin x] } cannot have a value between 1 and 2. Let y = [(cos x+2 sin x + 1)/(cos x + sin x) ] y(cos x + sin x) = (cos x + 2 sin x + 1) sin x(y-2) + cos x(y-1)=1 , I just feel that this isn't the way to do this.. Any ...

### phy.

Larry weighs 300 N at the surface of the earth. what is the weight of the earth in the gravitational field of Larry? -force= GMm/d^2 would i set it up like force= (9.8m/s^2)(300 N)? an astronaut lands on a planet that has twice the mass as earth and twice the diameter. how ...

### physics

calculate the force of gravity between earth (mass = 6.0 x 1024kg) and the moon (mass = 7.4 x 1022 kg). the average Earth-moon distance is 3.8 x 108 m.

### trig

The expression 4 sin x cos x is equivalent to which of the following? (Note: sin (x+y) = sin x cos y + cos x sin y) F. 2 sin 2x G. 2 cos 2x H. 2 sin 4x J. 8 sin 2x K. 8 cos 2x Can someone please explain how to do this problem to me?

### physic

How long will a radio wave, with a wave length of 200 m takes to travel to and for the moon from the earth? (Distance of moon from earth = 3.9 x 108 m)

### Physics Classical Mechanics

A planet has a single moon that is solely influenced by the gravitational interaction between the two bodies. We will assume that the moon is moving in a circular orbit around the planet and that the moon travels with a constant speed in that orbit. The mass of the planet is ...

### math

Prove that for all real values of a, b, t (theta): (a * cos t + b * sin t)^2 <= a^2 + b^2 I will be happy to critique your work. Start on the left, square it, (a * cos t + b * sin t)^2 = a^2 (1 - sin^2t) + 2ab sin t cost+ b^2 (1 - cos^2 t)= a^2 + b^2 - (a sin t - b cos t)^2...

### Physics

You're tour director for a lunar trip, and want to award your passengers with certificates commemorating their crossing the point where the Moon's gravity becomes stronger than Earth's.How far from Earth should you award the certificate? Express your answer in meters.Express ...

### Physics

Starting from Newton’s law of universal gravitation, show how to find the speed of the moon in its orbit from the earth-moon distance of 3.9 × 108 m and the earth’s mass. Assume the orbit is a circle.

### physics

Consider a pulse of laser light aimed at the Moon that bounces back to Earth. The distance between Earth and the Moon is 3.84 * 108 m. Show that the round-trip time for the light is 2.56 s.

### physics

Consider a pulse of laser light aimed at the Moon that bounces back to Earth. The distance between Earth and the Moon is 3.84 * 108 m. Show that the round-trip time for the light is 2.56 s

### physics

Consider a pulse of laser light aimed at the Moon that bounces back to Earth. The distance between Earth and the Moon is 3.84 * 108 m. Show that the round-trip time for the light is 2.56 s.

### science

The pull of gravity keeps the Moon in orbit around Earth. The distance between the Earth and Moon is about 380,000 kilometers. A crew of astronauts leaves Earth on a Monday and lands on the Moon on a Thursday. They land on the side of the Moon facing away from the Earth. On ...

### relative velocity

A radar antenna is tracking a satellite orbiting the earth. At a certain time, the radar screen shows the satellite to be 159km away. The radar antenna is pointing upward at an angle of 59.3 from the ground.Fine the x and y components(in km) of the position of the satellite ...

### Calc.

Differentiate. y= (cos x)^x u= cos x du= -sin x dx ln y = ln(cos x)^x ln y = x ln(cos x) (dy/dx)/(y)= ln(cos x) (dy/dx)= y ln(cos x) = (cos x)^x * (ln cos x) (dx/du)= x(cos x)^(x-1) * (-sin x) = - x sin(x)cos^(x-1)(x) (dy/dx)-(dx/du)= [(cos^x(x))(ln(cos(x)))-(x sin(x)cos^(x-1...

### calculus

Differentiate. y= (cos x)^x u= cos x du= -sin x dx ln y = ln(cos x)^x ln y = x ln(cos x) (dy/dx)/(y)= ln(cos x) (dy/dx)= y ln(cos x) = (cos x)^x * (ln cos x) (dx/du)= x(cos x)^(x-1) * (-sin x) = - x sin(x)cos^(x-1)(x) (dy/dx)-(dx/du)= [(cos^x(x))(ln(cos(x)))-(x sin(x)cos^(x-1...

### Physics

What is the centripetal acceleration of the Moon? The period of the Moon's orbit about the Earth is 27.3 days, measured with respect to the fixed stars. The radius of the Moon's orbit is RM = 3.85 · 108 m.

### Physics

What is the centripetal acceleration of the Moon? The period of the Moon's orbit about the Earth is 27.3 days, measured with respect to the fixed stars. The radius of the Moon's orbit is RM = 3.85 · 108 m.

### Trigonometry

Solve the equation for solutions in the interval 0<=theta<2pi Problem 1. 3cot^2-4csc=1 My attempt: 3(cos^2/sin^2)-4/sin=1 3(cos^2/sin^2) - 4sin/sin^2 = 1 3cos^2 -4sin =sin^2 3cos^2-(1-cos^2) =4sin 4cos^2 -1 =4sin Cos^2 - sin=1/4 (1-sin^2) - sin =1/4 -Sin^2 - sin =-3/4 ...

### physics

Given the position function s(t) = t cos t, find the velocity function. Answer v(t) = -sin t v(t) = sin t v(t) = cos t - t sin t v(t) = cos t + t sin t

### physics

the moon orbits the earth in a circle (near enough) of radious 3.8x10^8 m, taking 27.3 days to make a complete orbit. what is the speed of the moon relative to the earth?

### Physics

A 54100 kg space ship has completed two thirds of its journey from the earth to the Moon. At this position, what magnitude force would the ship's engines have to supply to be the equilibrant? Assume the mass of the moon is 7.35E + 22 kg and the distance between the earth and ...

### math

Given that sin x + sin y = a and cos x + cos y =a, where a not equal to 0, express sin x + cos x in terms of a. attemp: sin x = a - sin y cos x = a - cos y sin x + cos x = 2A - (sin y + cos y)

### Physics

Help!! I would greatly appreciate help with this question. Consider a pulse of laser light aimed at the Moon that bounces back to Earth. The distance between Earth and the Moon is 3.84 * 108 m. Show that the round-trip time for the light is 2.56s.

### Physics

Starting from Newton’s law of universal gravitation, show how to find the speed of the moon in its orbit from the earth-moon distance of 3.9 × 108 m and the earth’s mass. Assume the orbit is a circle. So I calculated this and got 1.0 km/s, I was just wondering if anyone ...

### trig

it says to verify the following identity, working only on one side: cotx+tanx=cscx*secx Work the left side. cot x + tan x = cos x/sin x + sin x/cos x = (cos^2 x +sin^2x)/(sin x cos x) = 1/(sin x cos x) = 1/sin x * 1/cos x You're almost there. thanks so much! i could not figure...

### physics

The gravitational force that the sun exerts on the moon is perpendicular to the force that the earth exerts on the moon. The masses are: mass of sun=1.99 × 1030 kg, mass of earth=5.98 × 1024 kg, mass of moon=7.35 × 1022 kg. The distances shown in the drawing are rSM = 1.50...

### physics

The gravitational force that the sun exerts on the moon is perpendicular to the force that the earth exerts on the moon. The masses are: mass of sun=1.99 × 1030 kg, mass of earth=5.98 × 1024 kg, mass of moon=7.35 × 1022 kg. The distances shown in the drawing are rSM = 1.50...

### PHYSICSS!!!

still cant get this one? so damon i know you wanna help! or anyone else im open for suggestions haha Consider a spaceship located on the Earth-Moon center line (i.e. a line that intersects the centers of both bodies) such that, at that point, the tugs on the spaceship from ...

### science

A person who weighs 600 newtons on Earth would weigh only 100 newtons on the Moon. Which statement best explains why? A.The circumference of Earth is larger than that of the Moon. B.The density of Earth is greater than that of the Moon. C.The mass of Earth is greater than that...

### Physics

The drawing (not to scale) shows one alignment of the sun, earth, and moon. The gravitational force that the sun exerts on the moon is perpendicular to the force that the earth exerts on the moon. The masses are: mass of sun=1.99 × 1030 kg, mass of earth=5.98 × 1024 kg, mass...

### physics

The physics of energy and Earth's moon as a satellite. The moon is an Earth satellite of mass 7.35 x 10^22 kg, whose average distance from the centre of Earth is 3.85 x 10^8 m. a) What is the gravitational potential energy of the moon with respect to Earth? b) What is the ...