
Find an equation of parabola that has the indicated vertex and whose graph passes through the given point. Vertex (3,5) Point (6,1)

Find an equation of the parabola that has the indicated vertex and whose graph passes through the given point Vertex:2,1 Point:4,3

umm suppose a parabola has a vertex at (0,2) and points (1,1) how would I derive the equation and focus, i've been trying to understand this for so long, I can't get it. Does this parabola have the equation (y2)^2 = x and a focus of 1/4?? Is that correct?? I searched Google ...

how do i find out the the equation of the line of symmetry for f(x)=ax^2+bx+c ? please explain it do me thanks! The line of symmetry runs through the vertex. so the x of the vertex is b/(2a) and the equation of the line of symmetry is x = b/(2a) e.g. for f(x) = 2x^2  12x + ...

Find the vertex of the function y = –x2 + 2x + 8. It is where the derivative 2x + 2 = 0. Since you probably haven't learned about derivatives, do it this way: Rewrite is as x^2 +2x +8 = (x1)^2 + 7 Now look at the form of the formula on the right. It can never be greater ...


determine the vertex for the function y=2x^2+5x3 for y = ax^2 + bx + c, the x value of the vertex is b/(2a) sub that x into your equation to find the y. Another way is to complete the square. so for yours, x = 5/4 etc. a third way, if you know Calculus, is to find the ...

Find the equation for the parabola with the given vertex that passes through the given points. vertex (4,2) point (3,0) please show work!!!

Write an equation for the translation so the graph has the given vertex. 1. y=x vertex (5,0) 2. y=2x vertex (4,3) 3. y=x vertex (p,q) I really have no idea how to even begin these, but I do know the answer to # 2 is y=2x+11 and #3 is y=xp+q Thanks in advance. ...

Find the vertex of the function y = –x2 + 2x + 8. it shows me different points as the answer. Im not sure how to find that point. Here are the points: (1,7) or (1,9) or (4,2) or (1,9) Answered in a previous post. Here it is again: Here's a quick way to find the vertex. ...

I am creating a project for math in which I have to draw an object using: parabolas, hyperbolas, circles,etc. We use conic section equations to identify where they are on the graph. I have confusion about writing the equation of parabolas. I know the equation is 4px=y^2 but I ...

What is the center of the conic whose equation is x^2 + 2y^2  6x + 8y = 0 2.Which one of the following equations represents a hyperbola? (5 points) A) 3x^2 + y^2 + 12x  7 = 0 B) 3x^2 + 3y^2 + 12x  7 = 0 C) 3x^2 + y + 12x  7 = 0 D) 3x^2  3y^2 + 12x  7 = 0 E) x^2 + y^2 + ...

write the equation in vertex form, of a parabola with vertex (5, 1) and that passes through the point (6, 8)

Find the quadratic function that has the indicated vertex and whose graph passes through the given point. Vertex: (2,3) Point: (0,2) I do not know how to do this! Please explain!! Thank You

Find the quadratic function that has the indicated vertex and whose graph passes through the given point. Vertex: (2,3) Point: (0,2) I do not know how to do this! Please explain!! Thank You

Write an equation of an ellipse in standard form with center at the origin and with the given vertex and covertex vertex at (3,0) and covertex at (0.2)


for the parametric curve defined by x=32t^2 and y=52t ...sketch the curve using the parametric equation to plot of the point. use an arrow to indicate the direction of the curve for o<t<1. Find an equation for the line tangent to the curve at the point where t=1. x=3...

Find the vertex of the functions given below. 1. y=(x4)(x+2) 2. y=2x^24x+1 The midpoint of the xintercepts of a parabola has the same x value as the vertex. the xintercepts are obviously x=4 and x=2 so the x value of the vertex is...... sub that back into the equation to ...

How do I find a and b given the equation ax^2 + bx 4 and a vertex point of (1,6)?

Find an equation of the parabola with vertex at the origin that passes through the point (36, 2) and opens to the left. I believe you start with (xh)^2 = 4p(yk) and plug in the given point and (0,0), and solve for p. I got y^2 = 144x. Is this correct? Thank you!

write the standard form equation of the parabola with vertex (2,2) that goes through point (1,0) y= a (xb)^2 + c b has to be 2, that gives the shift to the left. y=a( x+2)^2 + c when x=2, y=2, that makes c 2 y=a( x+2)^2 2 finally, put the point 1,0 in to find a.

A right triangle has one leg on the xaxis. The vertex at the right end of that leg is at the point (3,0). The other vertex touches the graph os y=e^x. the entire triangle is to lie in the first quadrant. Find the maximum area of this triangle.Justify your answer. My work: A...

A satellite dish in storage has parabolic cross sections and is resting on its vertex. A point on the rim is 4 ft high and is 6 ft horizontally from the vertex. How high is a point which is 3 ft horiozntally from the vertex? Draw a sketch and solve.

find the equation of a parabola that has a vertex of (2,3) and contains the point (4,1).

Please help out. Thank you. A right triangle has one leg on the xaxis. The vertex at the right end of that leg is at the point (3,0). The other vertex touches the graph os y=e^x. the entire triangle is to lie in the first quadrant. Find the maximum area of this triangle....

1)Find the exact solutions to 3x^2=5x1 using the quadratic formula. answer=5 plus or minus the square root of 37 over 6 2)Use the discriminant to determine the number and type of roots for the equation 2x^27x+9=0 answer=2 complex 3)Identify the vertex,axis of symmetry,and ...


write an equation for the parabola with focus (1,3) and vetex (0,3) See the paragraph Analytic Geometry Equations. You will have a choice of equations, you did not state whether the axis of symettry was parallel to x or y axis. http://en.wikipedia.org/wiki/Parabola that was ...

How to find a point on the line? x cordinate is given as x. The diagram is like a rectangle is inscribed in an isosceles right triangle whose hypotneus is 2 units long. AB is another side of the right triangle and P is a point on it(also a vertex of the rectangle). How do I ...

For the given quadratic equation convert into vertex form, find the vertex, and find the value for x = 6. Show your work. y = 2x2 + 2x +2 (1/2)y = x^2  x  1 (1/2)y + 1 = x^2  x (1/2)y + 1 = (x  1/2)^2  1/4 (1/2)y = (x1/2)^2  5/4 y = 2(x1/2)^2 + 5/2 would this be ...

f(x)=x^2  3x Find the axis of symmetry, vertex, direction it opens, and write the equation in vertex form. If f(x) =x^2 + 2x g(x)= x9 h(x) = 3x  2 Find [f o g o h] (2) Please explain how you got it I'm really confused right now.

For the given quadratic equation convert into vertex form, find the vertex, and find the value for x = 6. Show your work. y = 2x2 + 2x +2 (1/2)y=x^2x1 (1/2)y+1=x^2x (1/2)y+1=(x1/2)^214 (1/2)y=(x1/2)^25/4 y=2(x1/2)^2+5/2 Is this right ?

A parabola passes through the point (3, 5) on its way to the vertex at (7, 11). Determine the equation in vertex form that represents this parabola.

Suppose a parabola has vertex (4,7) and also passes through the point (3,8), write the equation of the parabola in vertex form.

Suppose a parabola has a vertex (4,7) and also passes through the point (3,8) Write the equation of the parabola in vertex form. f(x)=a(xh)^2+k I believe h=4 k=7 Not sure what to do from here.

A quadratic function has its vertex at the point (9,8). The function passes through the point (9,4). When written in vertex form, the function is f(x)= a(xh)^2 +k, where a) h)9 k)8 4=a(9)^2+8 4=a(9+9)^2+8 4=a(18)^2+8 4=a(332) a=0.01204 I was able to find both h & k. but the...

find the equation of a parabola that opens to the right with given vertex: (0,3) and passes through the point: (2,1)


I need help in finding the vertex of a parabola using an equation in this form: Ax^2 + Bx+C I have a test on this tomorrow. For example: 3x^2 +1x  2 How would I find the vertex in this?

I have a graph which I need to find the equation of. It's an absolute value graph, the vertex/middle point is at (2, 5) and 2 points that lie on the graph are (1,10) and (5,10). It needs to be in 'y=' form. I'd appreciate it if you explained how to do find the equation, too.

4x^223 Put the equation in vertex form and find the vertex

Find the equation of the parabola with its vertex at (h,k). Vertex: (2.1) Focus: (5,1) I know I put it into (yk)^2=4(p)(xh) so (y1)^2=4(p)(x+2). How do I find the value of p?

Find the equation of the parabola with its vertex at (h,k). Vertex: (2.1) Focus: (5,1) I know I put it into (yk)^2=4(p)(xh) so (y1)^2=4(p)(x+2). How do I find the value of p?

1. Find the vertex of the parabola: 4y^2+4y16x=0 2. Find an equation of the parabola, opening down, with vertex (3,1) and solution point (4,5). 3. The main cables of a suspension bridge are 20 meters above the road at the towers and 4 meters above the road at the center. ...

Find the coordinates of th vertex and write the equation of the axis of symmetry given the function f(x)=x^23x2.Is the vertex a maximum or a minimum?

Find the coordinates of th vertex and write the equation of the axis of symmetry given the function f(x)=x^23x2.Is the vertex a maximum or a minimum?

Find the vertex of y^2 + 4y + 2x +10 = 0. Use completing the square to put the equation into standard form as your first step. Could you show me how to get the vertex? Thanks

Which of the following is not a step in graphing a quadratic function? A. Find the equation for the axis of symmetry. B. Find the slope. C. Find the coordinates for the vertex. D. Plug in values for x around the vertex to get values of y Is B correct?


the centre point of a circle is 5,3. the top most point of the circle is the vertex. the radius of the circle is 5 and one of the zeroes is 9. figure out the vertex. tehn figure out the equation and convert it in standard form? p.splz exaplain step to step process or detailed...

Find the standard form of the equation of the parabola with the given characteristics and vertex at the origin. Passes through the point (1, 1/8); vertical axis. There is no focus of the parabola or equation given, so how am I suppose to solve this problem?

Find the standard form of the equation of the parabola with the given characteristics and vertex at the origin. Passes through the point (5, 1/8); vertical axis. There is no focus of the parabola or equation given, so how am I suppose to solve this problem?

Find the equation to the cone whose vertex is the point (a,b,c) and whose generating lines intersects the conic px2 + qy2 = 1, z = 0.

Write the standard form of the quadratic function that has the indicated vertex and whose graph passes through the given point. Vertex: (2, 5) Point: (0, 9)

At the x axis, y is zero. So if the x intercept is (1,0) then (ya)^2=x + b (0a)^2=1 + b Now the vertex. (ya)^2=x +b (2a)^2= 0 + b or these two equations are.. a^2= 1+b or b= a^2  1 putting this into the second equation. 44a + a^2=a^21 solve for a, then go back and solve...

Find the coordinates of the vertex and the equation of the axis of symmetry of the parabola given by the equation. x = −1/3y^2+4 vertex (x, y) = axis of symmetry Sketch the graph.

An engineer designs a satellite dish with a parabolic cross section. The dish is 10 ft wide at the opening, and the focus is placed 8 ft from the vertex. a) Position a coordinate system with the origin at the vertex and the xaxis on the parabola's axis of symmetry...

An engineer designs a satellite dish with a parabolic cross section. The dish is 14 ft wide at the opening, and the focus is placed 4 ft from the vertex. a) Position a coordinate system with the origin at the vertex and the xaxis on the parabola's axis of symmetry...

Find the coordinates of the vertex and the equation of the axis of symmetry of the parabola given by the equation. x = − 13y^2 + 4 vertex (x, y) = axis of symmetry ____ Sketch the graph


Identify the vertex and the axis of symmetry for the graph of y=5(x2)^2 + 3. a) vertex (2,3); x = 2 b) vertex (2,3); x = 2 c) vertex (2,3); x = 2 d) vertex (2,3); x = 2 I have no idea how to solve this problem! Please help. Thank you! :)

Find the coordinates of the vertex and the equation of the axis of symmetry of the parabola with the given equation. y = 8x^2 + 48x − 3 vertex (x, y) = axis of symmetry ________

Find the coordinates of the vertex and the equation of the axis of symmetry of the parabola given by the equation. x = − 1/3^2+4 vertex (x, y) = axis of symmetry Sketch the graph.

Can you please help me with the below question: The vertex of a parabola is located at (12, 1). The parabola also passes through the point (10, 5). Write the equation of this parabola in both vertex form and standard form. Vertex form: Standard form: Thank you

The graph of a quadratic function has vertex(3,4) and passes through the point (4,1). Find the equation of the function in standard form. Rewrite the equation in general form. Could someone explain to me how to do this, just don't understand.

The graph of a quadratic function has vertex(3,4) and passes through the point (4,1). Find the equation of the function in standard form. Rewrite the equation in general form. Could someone explain to me how to do this, just don't understand.

write the equations of the parabola, the directrix, and the axis of symmetry. vertex: (4,2) focus: (4,6) if someone could explain how to do this problem then that would be great! thanks in advance! Formats to help you find the equation for a parabola: (x  h)^2 = 4p(y  k) ...

Find the vertex, focus, and axis of symmetry of the parabola x^210x8y+29 = 0. ==> I do it over and over and over, but I keep getting the same answers of (5,4) for the vertex, (5,6) for the focus, and x = 5 for the LOS, but according to this one website, everything except ...

A parabola has the equation y = 4(x3)^27 Choose 2 true statements: A) The parabola has a minimum value B) The parabola has a maximum value C) The parabola does not cross the yaxis D) The parabola does not cross the xaxis E) The vertex of the parabola is at the point with ...

3. Identify the vertex and the axis of symmetry of the graph of the function y = 3(x + 2)2 – 3. (1 point) A vertex: (2, –3); axis of symmetry: x = 2 B vertex: (–2, –3); axis of symmetry: x = –2 C vertex: (2, 3); axis of symmetry: x = 2 D vertex: (–2, 3); axis ...


Write an equation for the parabola with focus (1,3) and vertex (0,3). I cannot find any example in my book that works a problem with the vertex, all of the examples that I have to go by give only the focus and directrix. Thanks.

Write the standard form of the equation of the parabola whose vertex is 1,2 and passes through the point 0,0. The answer according to my book is 0=a(01)^2+2. But which 0 in the equation is the first 0 fromn (0,0) and which one is the second? Thanks!

For the graph of each function, find an equation of the line of symmetry and the coordinates of the vertex. Tell whether the value of the function at the vertex if a maximum or a minimum: a) y = x^2 + 4x  7; b) y = 2x^2 + 4x; c) y = 3x^2  18x + 5.

I would like to have some help on this problem please. I'm so post to find the vertex and axis of the parabola.Does anyone have an idea? Y=x²16x+63. A)vertex(8,1)axis=x=8 B)vertex(8,1)axis=x=8 C)vertex(8,1)axis=x=8 D)vertex(8,1)axis=x=8

Find the equation of a parabola with vertex(5,3)and the axis of symmetry is parallel to the yaxis and pass through the point(9,5)

I cannot for the life of me remember how to do this Find the vertex of the graphs of the functions: Function #1: y=(x4)(x+2) AND Function #2: y=2x^24x+1 Can someone help me get it PLz! OK  to find the vertex of these functions you must have them in quadratic form where the...

I started having trouble on part (c), and I need to know this before I can go onto the other problems. Plz help! The parabola shown at the right (no picture, sorry) is of the form y=x^2+bx+c. The graph's yintercept is (0,2), the axis of symmetry is 2.5 and the two points ...

Find the coordinates of the vertex and the equation of the axis of symmetry of the parabola with the given equation. y = 8x2 + 48x − 3 vertex (x, y) = _____________ axis of symmetry _____________

how do you find the vertex using two points, when no equation is given and neither points are the vertex? what formula can i use to find it?

A few more question Id like for someone to check please. 1) what are the vertex, focus, and directrix of the parabola with the given equation? x^28x28y124=0 vertex (4,5) focus (0,7) directrix y=12 2) write an equation of a circle with given center and radius. center(7,6...


A parabola has the equation y = 4(x3)^27 Choose 2 true statements: A) The parabola has a minimum value B) The parabola has a maximum value C) The parabola does not cross the yaxis D) The parabola does not cross the xaxis E) The vertex of the parabola is at the point with ...

1. Find the equation for a quadratic function whose vertex is (2,5) and whose graph contains the point (8,15). 2.What are the x and y intercepts for y=2x^2+x6 Plesee explai. I want to learn to learn how to do them.

THe directions state: (A)Complete the table, (B) describe the resulting graphs by identifying the vertex point, (C)the graph’s direction, (D) and any axis intercepts gleaned from the table or graph Problem #3 Equation : y = 2x^2 My answers: A) Table: (2, 8) (1 , 2) (0,0) (...

Sketech the graph of the equation y^2+4y+2x+10=0. Identify the vertex, the focus and the equation for the directrix. Use the completing the square to put the equation into standard form as your first step. This is what I did. y^2 + 4y = 2x10 y^2 + 4y + 4 = 2x6 (y+2)^2= 2(...

I need help with this question. Write the equation of the line which contains the point)0, 3) and whose slope is 4. A general line equation can be written as y = mx + c, where m is the slope and c a constant. so we can write this as y = 4x + c Substituting the point (0, 3) ...

I started having trouble on part (c), and I need to know this before I can go onto the other problems. Plz help! The parabola shown at the right (no picture, sorry) is of the form y=x^2+bx+c. The graph's yintercept is (0,2), the axis of symmetry is 2.5 and the two points ...

This is what the directions state to do: (A) Complete the table,(B)describe the resulting graphs by identifying the vertex point, (c) the graph’s direction, (d) and any axis intercepts gleaned from the table or graph. Problem #1 Equation is : y = x + 1 so These are my ...

Find an equation of the parabola with vertex at the origin. Passes through the point (4,6); horizontal axis. I know it has to be y^2=4px. But I don't know what to do with (4,6). Please show step by step. Thanks.

I have a test tomorrow with a few sample questions that are expected to be on the test that I do not know how to properly do. 1)Find the slope intercept equation of the line passing through the intersection of the lines 2x4y=1 & 3x+4y=4 and parallel to the line 5x+7y+3=0 2)...

Okay this is what i have to do but i think i am doing something wrong. directions are: Identify the axis of symmetry, create a suitable table of values, and sketch the graph (including the axis of symmetry). The problem is: y = x^2+6x2 so i did my table and looks like this x...


I have a test tomorrow with a few sample questions that are expected to be on the test that I do not know how to properly do. 1)Find the slope intercept equation of the line passing through the intersection of the lines 2x4y=1 & 3x+4y=4 and parallel to the line 5x+7y+3=0 2)...

Homework Help Forum: AlgebraPlease helpI'm confused Posted by Tom on Tuesday, September 21, 2010 at 8:09pm. This deals with quadratic functionsIf I have a graph with h = (5)and k =3 and they ask for the translation, would it be {5,3} or would the translation just be {5,3...

1.) Y=lx+1l+3 Are these correct? yintercept=(0,2) xintercept=(4,0) (2,0) vertex=(1,3) domain=all real numbers range: y<=3 2.) A parabola has vertex (2,3) and it contains (0,0)....find the equation of the sleeping parabola.

I have a parabola vertex (11,3) p is not given, focus pt is not given. I need to find the equation of the parabola. How would I do this w/o p value or focus pt? you cant. Þhere are an infinite number of parabolas that have that vertex.

What is a vertex? for example, there is a triangle with the point of it circled. the book asks if it's a vertex. i looked it up on google and dictionary, but i don't get it. thanks for any help!

Determine the quadratic function in vertex form (A) vertex at (3,10) passing through the point (2,5) Dow do I figure it out?

1 identify the coordinates of the vertex and the equation of the axis of summetry of the parabola x=2 (y1)^2+3 A. The vertex of the parabola is (1,3), and the equation of the axis of symmetry B. the vertex of the parabola is (3,1) and the equation of the axis of symmetry c. ...

How do you get the vertex of this absolute value? y = 2 4x  1 + 16 By vertex you mean the highest point. Find out where the expression inside the absolute value is 0. Since the absolute value is always positive, in this expression some quantity is being subtracted from 16...

When a chain hangs under its own weight, its shape is a catenary (from the Latin word for chain). The equation of a catenary with a vertex on the yaxis is . Find the length of the chain from . Then use the same technique from Problem #8 to find the length of the parabola with...

Find the Equation. Please check the answers and help. Thanks! 1.) Ellipse with center (0,0), foci on xaxis; x intercepts; major axis of length 12, minor acis of length 8. I got : x^2/144 + y^2/64 = 1 2.) A parabola with vertex (0, 0) and focus (5, 0). I got : y^2 = 20x 3.) ...


With the given information below, write the standard form equation for the parabola. 1.) Vertex: (1,2) Focus(1,0) 2.) Vertex: (2,1) Directrix x=1

Write an equation of the ellipse with center at (0, 0), vertex at (4, 0), and covertex at (0, 2)

1 ) Find the inverse of g(x) = 5x 2 2) the graph (x2)^2 + 3(y2)^2 = 25 is graph of a(an) ______ 3) which equation has a vertex (5, 4) a) y= (x+4)^2  5 c) y = (x5)^2 4 b) y = (x4)^2 +5 d) y=(x+5)^2 4 4) solve 8^x less than or equal to 25 5) name the axis to which the ...

Hey thanks for all your help but you kinda confused me on a few: 1)Determine whether f(x)=5x^210x+6 has a maximum or minimum value and find that value A.minimum 1 B.maximum 11 C.maximum 1 D.minimum 11 and you said the function opens up, so there is a minimum. it occurs ...

What is the standard form of the equation of the parabola that has a vertex at (4, 3) and passes through the point (4, 2)? Is it f(x) = 5/64(x  4)^2 + 3?
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