
A particle that undergoes simple harmonic motion has a period of 0.4 s and an amplitude of 12 mm. The maximam velocity of the particle is?

A 10kg particle undergoes simple harmonic motion with an amplitude of 2.0mm, a maximum acceleration of 8.0x10^3 m/s^2, and an unknown phase constant (phi) What are: a.) the period of the motion b.) the maximum speed of the particle c.) total mechanical energy of the oscillator...

A 10kg particle undergoes simple harmonic motion with an amplitude of 2.0mm, a maximum acceleration of 8.0x10^3 m/s^2, and an unknown phase constant (phi) What are: a.) the period of the motion b.) the maximum speed of the particle c.) total mechanical energy of the oscillator...

A 10 g particle undergoes Simple Harmonic Motion with an amplitude of 2.0 mm, a maximum acceleration of magnitude 8.0 X 10^3 m/s^2, and an unknown phase constant, theta. What are a.) the period of the motion, b.) the maximum speed of the particle, and c.) the total mechanical ...

A 10kg particle undergoes simple harmonic motion with an amplitude of 2.0mm, a maximum acceleration of 8.0x10^3 m/s^2, and an unknown phase constant (phi) What are: a.) the period of the motion b.) the maximum speed of the particle c.) total mechanical energy of the oscillator...


A particle is oscillating in simple harmonic motion. The time required for the particle to travel through one complete cycle is equal to the period of the motion, no matter what the amplitude is. But how can this be, since larger amplitudes mean that the particle travels farther?

A particle executes simple harmonic motion such that at t = 0 it is at the amplitude of oscillation A = 22.5 cm. The period of the oscillation is 0.25 s. When is the first time this particle will be at x = 1/2 the amplitude, moving away from equilibrium?

A particle executing simple harmonic motion of amplitude 5 cm and period 2 s. Find the speed of the particle at a point where its acceleration is half of its maximum value

A particle of mass 1kg undergoes simple harmonic motion and its potential energy U changes with displacement x from a fixed point as shown below. Determine a) amplitude b) period Help me guys...

If an equation of motion of a particle is given by s(t)= Acos(ùt + ä), the particle is said to undergo simple harmonic motion. Find the velocity of the particle at time t. When is the velocity 0?

A particle in simple harmonic motion has a period of 0.4s. If the maximum speed attained during the motion is 0.3s, what is the amplitude of the motion?

A particle executes simple harmonic motion with an amplitude of 10 cm and time period 6 s. At t=0 it is at position x=5 cm going towards positive x direction . Write the equation for the displacement x at time t. Find the magnitude of the acceleration of the particle at t=4s.

If a particle moves in simple harmonic motion with a frequency of 3.00 Hz and an amplitude of 5.00 cm through what total distance does the particle move during one cycle of its motion, what is its maximum speed, where does this maximum speed occur and what and where does the ...

A particle with a mass of 3.00 1020 kg is oscillating with simple harmonic motion with a period of 7.00 105 s and a maximum speed of 4.50 103 m/s. (a) Calculate the angular frequency of the particle. rad/s (b) Calculate the maximum displacement of the particle. m

1. A particle moving with simple harmonic motion has maximum displacement of 50 cm angular velocity of 1.02rad/s. Calculate the (a) the maximum velocity (b) maximum acceleration of the particle (c) the speed and acceleration of the particle when it is 30cm from the center of ...


If the equation of motion of a particle is given by s = A cos(ωt + δ), the particle is said to undergo simple harmonic motion. (a) Find the velocity of the particle at time t. s'(t) =  A ω sin(ωt + δ) I figured out how to do part a, but I don't know ...

A particle moving in simple harmonic motion passes through the equilibrium point (x=0) 8 times per second. At t=0 its velocity at x=0.015m is negative. It travels 0.6m in a complete cycle. The particle's position as a function of time is described by the following function: x(...

Hi, a particle is moving in simple harmonic motion such that a = 4x. ( x in metres, t in seconds) Find the maximum speed at which the particle is travelling. Velocity = 6cos2t. My teacher said to put t = 0 and sub it into velocity equation above, but I don't know why? Thanks!

An object has a mass of 0.5 kg. It undergoes a simple harmonic motion. The amplitude of that motion is 0.07 m and the period is 0.31 s. What is the total energy of the object?

A particle vibrates in Simple Harmonic Motion with amplitude. What will be its displacement in one timeperiod if you attach a mass to the spring from its initial equilibrium position, it vibrates forever in simple harmonic motion. Why doesn't it come to rest after stretching ...

Q 2) A particle executes simple harmonic motion with an amplitude of 10 cm. At what distance from the mean position are the kinetic and potential energies equal ?

If the equation of motion of a particle is given by s = A cos(ωt + δ), the particle is said to undergo simple harmonic motion. s'(t) = Aω sin(ωt + δ) When is the velocity 0? (Use n as the arbitrary integer.) t= _____________ I thought it was 0, but it...

for a particle executing simple harmonic motion the displacement is 8 cm at the instant the velocity is 6cm\sec and the displacement is 6 cm at the instant the velocity is 8 cm\sec calculate the amplitude?

a simple harmonic motion is represented by x=4sin[3t+3.14/4].find the angular frequency and amplitude and what is the velocity and acceleration at t=1 second.

An object has a mass of 0.3 kg. It undergoes a simple harmonic motion. The amplitude of that motion is 0.09 m and the period is 0.36 s. What is the total energy of the object? my answer: 4.11 J period=1/f.  omega=2*pi*f=17.45 only kinetic energy therefore Etotal=1/2mv^2=1/2*...


The midpoint of a guitar string executes simple harmonic motion with motion following the form x(t) = A sin(ωt + φ). Amplitude (A)=1.60mm, Angular Velocity (w)=2760 and phase constant (o) = pi/2. How do I find the initial displacement, velocity and acceleration of the ...

A particle moving in simple harmonic motion passes through the equilibrium point (x=0) 9 times per second. At t=0t=0 its velocity at x=−0.01 m is negative. It travels 0.4 m in a complete cycle. The particle's position as a function of time is described by the following ...

The displacement (in meters) of a particle moving in a straight line is given by the equation of motion s = 5/t2, where t is measured in seconds. Find the velocity of the particle at times t = a, t = 1, t = 2, and t = 3. (a) Find the average velocity during each time period. (...

A 50g mass is attached to a spring and undergoes simple harmonic motion. Its maximum acceleration is 15m/s2 and its maximum speed is 3.5m/s . Determine the angular frequency. Determine the spring constant. Determine the amplitude of the motion.

A particle executes simple harmonic motion with an amplitude of 9.00 cm. At what positions does its speed equal two thirds of its maximum speed?

Two particles A and B are in uniform circular motion about a common center. The acceleration of particle A is 4.7 times that of particle B. Particle B takes 2.4 times as long for a rotation as particle A. Th ratio of the radius of the motion of particle A is that of particle B...

The equation of motion of a particle in vertical SHM is given by y = (17 cm) sin 0.70t. (a) What is the particle's displacement at t = 1.1 s? (b) What is the particle's velocity at t = 1.1 s?(c) What is the particle's acceleration at t = 1.1 s?

The equation of motion of a particle in vertical SHM is given by y = (10 cm) sin 0.80t. (a) What is the particle's displacement at t = 1.1 s? (b) What is the particle's velocity at t = 1.1 s? (c) What is the particle's acceleration at t = 1.1 s?

A charged particle is moving in a uniform magnetic field. Which of the following statements concerning the magnetic force exerted on the particle is false? A) It does not change the kinetic energy of the particle. B) It can act only on a particle in motion. C) It increases the...

A 0.125 kg mass is attached to a spring and undergoes simple harmonic motion with a pe riod of 0.41 s. The total energy of the system is 2.5 J. Find the amplitude of the motion. Answer in units of m.


we know that a particle in Harmonic Motion is moving at v1 @ position x1 and v2 @ position x2. What is A (Amplitude) and w (omega) ?

A particle executes simple harmonic motion with an amplitude 4cm. At what displacement it's energy is half kinetic energy and half potential

8. Write the equation for simple harmonic motion given that the amplitude is 5 centimeters and the frequency is 2/ ð cycles per second. Assume that the maximum displacement occurs when t = 0. a. y = 5sin4t b. y = 5cos2t c. y = 5cos4t d. y = 5sin2t 9. Write the equation for ...

A block of unknown mass is attached to a spring with a spring constant of 6.00 N/m and undergoes simple harmonic motion with an amplitude of 12.0 cm. When the block is halfway between its equilibrium position and the end point, its speed is measured to be 33.0 cm/s a)Calculate...

velocity of a particle the displacement s (in meters) of a particle moving in a straight line is given by the equation of motion s=4t^3+6t+2, where t is measured in seconds. Find the velocity of the particle s at times t=a t=1 t=2 t=3

A objectspring system undergoes simple harmonic motion with an amplitude of A. Does the total energy change if the mass is doubled but the amplitude is not changed? Do the kinetic and potential energies depend on the mass? Explain. Thanks in advance

Uugghhh help please. The velocity of a 4.6 kg particle is given by vector v=(4t{i}+7t^2{j}), where v is in m/s and t is in seconds. At the instant when the net force on the particle has a magnitude of 40 N, what is the angle between the particle's acceleration and the particle...

An object undergoes simple harmonic motion. During that motion the object needs 1.1 seconds to reach one point of zero velocity from the previous such point. If the distance between those points is 0.3 m, calculate the period.

Directly below on the floor is a stationary 428Hz source of sound. The microphone vibrates up and down in simple harmonic motion with a period of 2.3 s. The difference between the maximum and minimum sound frequencies detected by the microphone is 2.2 Hz. Ignoring any ...

A small ball is set in horizontal motion by rolling it with a speed of 3.00 m/s across a room 12.0m long, between two walls. Assume that the collisions made with each wall are perfectly elastic and that the motion is perpendicular to the two walls. (a)Show that the motion is ...


A 0.500 kg particle moves in a circle of R=0.0150 m at constant speed. The time for 20 complete revolutions is 31.7 s. What is the period T of the motion? What is the speed of the particle? What is the centripetal acceleration of the particle? What is the centripetal force on ...

An object in simple harmonic motion has an amplitude of 0.202 m and an oscillation period of 0.620 s. Determine the maximum speed of the motion

An object in simple harmonic motion has an amplitude of 0.202 m and an oscillation period of 0.620 s. Determine the maximum speed of the motion.

a particle moves in a straight line such that its position x from a fixed point 0 at time 't' is given by x= 5 + 8sin2t + 6cos2t 1. Find the period and amplitude of the particle. 2. Find the greatest speed of the particle. Thanks

a particle 100g attach with a horizontal spring moving s.h.m.with amplitude 5cm .when this particle is passes through mid point a small particle placed on it then both moving s.h.m.with amplitude 4cm.find the mass of small particle .

A particle executes simple harmonic motion with an amplitude of 9.00 cm. At what positions does its speed equal two thirds of its maximum speed? I got: v2 +ω^2x^2 =ω^2A^2 vmax =ω A and v = ωA/2?

Simple Harmonic Motion Problem Amplitude=10cm=0.1m , period=1s, angular frequency= 6.28 rad What is the maximum speed of the mass during this motion?

A clown is rocking on a rocking chair in the dark. His glowing red nose moves back and forth a distance of 0.42m exactly 30 times a minute in a simple harmonic motion. (a) what is the amplitude of this motion? (b) what is the period of this motion? (c) what is the frequency of...

A 50g mass is attached to a spring and undergoes simple harmonic motion. Its maximum acceleration is 15m/s2 and its maximum speed is 3.5m/s .

A particle starts from the origin at t = 0 and moves along the positive x axis. A graph of the velocity of the particle as a function of the time is shown in the figure; the vaxis scale is set by vs = 7.0 m/s. (a) What is the coordinate of the particle at t = 5.0 s? (b) What ...


An object–spring system undergoes simple harmonic motion. If the mass of the object is doubled, what will happen to the period of the motion?

An object is attached to an ideal spring. It undergoes a simple harmonic motion with a total energy of E = 2.2 J. The amplitude of the motion is 0.7 m and the maximum speed of the object is 0.5 m/s. Find the spring constant.

A body weighing 150 N, moves with simple harmonic motion. The velocity and acceleration of the body when it is 200 mm from the centre of oscillation, are 5 m/s and 20 m/s2 respectively.Determine (a) amplitude of motion ,no. of vibrations per minute, Periodic time and angular ...

The displacement (in centimeters) of a particle moving back and forth along a straight line is given by the equation of motion s = 3sin(ðt) + 5cos(ðt), where t is measured in seconds. (Round all answers to the nearest hundredth.) (a) Find the average velocity during the time...

A massspring system undergoes simple harmonic motion with amplitude A.Does the total energy of the system change if the mass doubled but the amplitude is unchanged? Does the kinetic and potential energies depends on the mass? Explain.

The Question: A particle moves along the Xaxis so that at time t > or equal to 0 its position is given by x(t) = cos(√t). What is the velocity of the particle at the first instance the particle is at the origin? So far I was able to determine that the velocity of the ...

The displacement (in centimeters) of a particle moving back and forth along a straight line is given by the equation of motion s = 4 sin ¦Ðt + 3 cos ¦Ðt, where t is measured in seconds. (a)Find the average velocity during each time period. (i) [1, 2] (ii) [1, 1.1] (iii) [1...

A particle with a mass of 0.660 kg is attached to a horizontal spring with a force constant of 23.76 N/m. At the moment t = 0, the particle has its maximum speed of 15 m/s and is moving to the left. (Assume that the positive direction is to the right.) (a) Determine the ...

A microphone is attached to a spring that is suspended from the ceiling, as the drawing indicates. Directly below on the floor is a stationary 624Hz source of sound. The microphone vibrates up and down in simple harmonic motion with a period of 2.31 s. The difference between ...

A body weighing 150 N, moves with simple harmonic motion. The velocity and acceleration of the body when it is 200 mm from the centre of oscillation, are 5 m/s and 20 m/s2 respectively.Determine (a) amplitude of motion ,no. of vibrations per minute, Periodic time and angular ...


a) What do you understand by Simple Harmonic Motion? b) A simple harmonic motions is characterized by the equation x = (10 cm) sin (0.1t + ) where, x is in cm and t is in seconds Determine the i. amplitude and angular frequency. ii. linear frequency and period. iii. ...

A particle executes SHM such that at a given time it is at x= +1/4 the amplitude, moving away from equilibrium, and 0.7 seconds later the particle has 1/6 the maximum speed moving away from equilibrium. Find the period of the motion.

A particle executes SHM such that at a given time it is at x= +1/4 the amplitude, moving away from equilibrium, and 0.7 seconds later the particle has 1/6 the maximum speed moving away from equilibrium. Find the period of the motion.

A particle moves along the x axis. It is initially at the position 0.280 m, moving with velocity 0.080 m/s and acceleration 0.240 m/s2. Suppose it moves with constant acceleration for 3.10 s. (a) Find the position of the particle after this time. (b) Find its velocity at the ...

A particle moves along the x axis. It is initially at the position 0.350 m, moving with velocity 0.110 m/s and acceleration 0.380 m/s2. Suppose it moves with constant acceleration for 3.50 s. (a) Find the position of the particle after this time. (b) Find its velocity at the ...

A particle is travelling with velocity (4i+5j)m/s. It undergoes an acceleration of magnitude 2.5m/s^2 in a direction given by the vector (3i4j). Find the velocity and displacement of the particle from its initial position after 4s.

The position of a particle is given by the expression x = 2.00 cos (6.00πt + π), where x is in meters and t is in seconds. (a) Determine the frequency. ______Hz (b) Determine period of the motion. ______s (c) Determine the amplitude of the motion. ______m (d) ...

A simple harmonic oscillator executes motion whose amplitude is 0.20 m and it completes 60 oscillations in 2 minutes. i) Calculate its time period and angular frequency. ii) If the initial phase is 45°, write expressions for instantaneous displacement, velocity and acceleration

The frequency of circular motion for a charged particle moving around in the presence of a uniform magnetic field does not depend on ... a)The radius of the circle b)The mass of the particle c)The charge of the particle d)The magnitude of the magnetic field e)Actually, it ...

A bungee jumper undergoes simple harmonic motion with amplitude 3.5 m and frequency 0.135 Hz. Assume the bungee jumper follows the simple harmonic motion equation x=Acos(wt). A. Determine the bungee jumper's velocity at 0.25 s B. Determine the bungee jumper's velocity at 0.50 ...


Which of the following statements is not true about a particle executing Simple Harmonic Motion? Choose one answer. a. Its velocity is maximum at the equilibrium position. b. Its acceleration depends only upon its displacement at that instant. c. Its velocity is zero at the ...

A block rides on a piston that is moving vertically with simple harmonic motion. (a) If the SHM has period 3.1 s, at what amplitude of motion will the block and piston separate? (b) If the piston has an amplitude of 9.6 cm, what is the maximum frequency for which the block and...

A 32.0 kg block at rest on a horizontal frictionless table is connected to the wall via a spring with a spring constant k= 32.0 N/m. A 2.00E2 kg bullet travelling with a speed of 5.500E+2 m/s embeds itself in the block. What is the amplitude of the resulting simple harmonic ...

a particle moves in a straight line such that its position x from a fixed point 0 at time 't' is given by x= 5 + 8sin2t + 6cos2t 1. Find the period and amplitude of the particle. 2. Find the greatest speed of the particle. Could you please explain the steps on how to get to ...

The length of a simple pendulum is 0.79m and the mass of the particle at the end of the cable is 0.24 kg. The pendulum is pulled away from its equilibrium position by an angle of 8.5 degrees and released from rest. Assume that friction can be neglected and that the resulting ...

The position vector r of a particle moving in the xy plane is r=2ti+2sin[(pi/4)t]j , with is in meters and t in seconds. (a) Calculate the x and y components of the particle's position at , and 4.0 s and sketch the particle's path in the plane for the interval . (b) Calculate ...

A body weighing 150 N, moves with simple harmonic motion. The velocity and acceleration of the body when it is 200 mm from the centre of oscillation, are 5 m/s and 20 m/s2 respectively.Determine (a) amplitude of motion ,no. of vibrations per minute, Periodic time and angular ...

A particle initially at the origin travels in uniform motion with velocity v=2ij2k. Find position venctor vector r(t) of a particle at time t. Find equatio for the plane passing through the origin and perp. to the tragectory of the particle. And find when and where the ...

A 200g block is attached to a horizontal spring and executes simple harmonic motion with a period of 0.250 s. If the total energy of the system is 2.00 J, find (a) The force constant of the spring and (b) The amplitude of the motion.

The velocity graph of a particle moving along the xaxis is shown. The particle has zero velocity at t=0.00s and reaches a maximum velocity, vmax, after a total elapsed time, t total. If the initial position of the particle is x0 =6.22m, the maximum velocity of the particle is...


A 0.38kg mass attached to a spring undergoes simple harmonic motion with a period of 0.63 s. What is the force constant of the spring?

particle 1 of mass m1 = 0.29 kg slides rightward along an x axis on a frictionless floor with a speed of 1.8 m/s. When it reaches x = 0, it undergoes a onedimensional elastic collision with stationary particle 2 of mass m2 = 0.40 kg. When particle 2 then reaches a wall at xw...

particle 1 of mass m1 = 0.29 kg slides rightward along an x axis on a frictionless floor with a speed of 1.8 m/s. When it reaches x = 0, it undergoes a onedimensional elastic collision with stationary particle 2 of mass m2 = 0.40 kg. When particle 2 then reaches a wall at xw...

particle 1 of mass m1 = 0.29 kg slides rightward along an x axis on a frictionless floor with a speed of 1.8 m/s. When it reaches x = 0, it undergoes a onedimensional elastic collision with stationary particle 2 of mass m2 = 0.40 kg. When particle 2 then reaches a wall at xw...

The acceleration, ams^2, of a particle is given by a =25 – 9t^2, where t is in seconds after the particle passes fixed point O. If the particle passes O, with velocity of 4 ms^1, find (a) An expression for velocity V, in terms of t (b) The velocity of the particle when t = 2

A 200g mass is attached to a spring and allowed to execute simple harmonic motion with a period of 0.25seconds. If the total energy of the system is 2.0 joules, find the force constant of the spring and the amplitude of the motion.

particle 1 of mass m1 = 0.29 kg slides rightward along an x axis on a frictionless floor with a speed of 1.8 m/s. When it reaches x = 0, it undergoes a onedimensional elastic collision with stationary particle 2 of mass m2 = 0.40 kg. When particle 2 then reaches a wall at xw...

A 50g mass is attached to a spring and undergoes simple harmonic motion. Its maximum acceleration is 15m/s2 and its maximum speed is 3.5m/s . Determine the angular frequency. Determine the spring constant. Determine the amplitude of the motion. how do I find these things?

A charged particle is projected into a uniform Bfield. Its velocity vector is perpendicular to the Bfield vector. What type of path will the particle travel? Neglect gravity. Answer straight line motion elliptical motion parabolic motion circular motion

5. A particle moves along the y – axis with velocity given by v(t)=tsine(t^2) for t>=0 . a. In which direction (up or down) is the particle moving at time t = 1.5? Why? b. Find the acceleration of the particle at time t= 1.5. Is the velocity of the particle increasing at ...


A particle moves along straight line such that its displacement S meters from a given point is S = t^3 – 5t^2 + 4 whee t is time in seconds. Find (a) The displacement of particle at t = 5 (b) The velocity of the particle when t = 5 (c) The values of t when the particle is ...

Question – 3: Consider a particle moving according to the velocity function, v(t) = 2a3exp(2t)+2/t+2,for t>0. (a) If the net distance,d,covered by the particle in the time interval,[0,3],is 20,find the value of a. What is the terminal velocity of the particle?. (b) Find...

A body weighing 150 N, moves with simple harmonic motion. The velocity and acceleration of the body when it is 200 mm from the centre of oscillation, are 5 m/s and 20 m/s2 respectively.Determine (a) amplitude of motion ,no. of vibrations per minute, Periodic time and angular ...

the velocity of a particle is given by v=[16t^2i+4t^3j +(5t+2)k]m/s, where t is in seconds. If the particle is at the origin when t=0, determine the magnitude of the particle's acceleration when t=2s. What is the x,y,z coordinate position of the particle at this instant.

particle 1 of mass m1 = 0.29 kg slides rightward along an x axis on a frictionless floor with a speed of 1.8 m/s. When it reaches x = 0, it undergoes a onedimensional elastic collision with stationary particle 2 of mass m2 = 0.40 kg. When particle 2 then reaches a wall at xw...
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