What is the time taken for an object to fall from a height of 50 meters, ignoring air resistance?

Answers:

• To calculate the time taken for an object to fall from a height of 50 meters, we can use the kinematic equation for uniformly accelerated motion. Since we are ignoring air resistance, we can assume that the only force acting on the object is gravity.

  The equation we can use is:

  [ d = \frac{1}{2} g t^2 ]

  where:

  • (d) is the distance fallen (50 meters),
  • (g) is the acceleration due to gravity (approximately (9.81 , \text{m/s}^2)),
  • (t) is the time in seconds.

  Rearranging the equation to solve for (t):

  [ t^2 = \frac{2d}{g} ]

  Substituting the values:

  [ t^2 = \frac{2 \times 50 , \text{m}}{9.81 , \text{m/s}^2} ]

  [ t^2 = \frac{100}{9.81} \approx 10.19 ]

  Now, taking the square root:

  [ t \approx \sqrt{10.19} \approx 3.19 , \text{s} ]

  Therefore, the time taken for an object to fall from a height of 50 meters, ignoring air resistance, is approximately 3.19 seconds.