How much 0.10 M Base (in mL) is required to neutralize 8.00 mL of the 0.10 M acid?

Base Acid Base Volume (ml)
NaOH HCl ___________
NaOH HC2H3O2 ___________

How would the volume of base change from the problem above if the 8.00 mL of 0.10 M Acid was first diluted with 100 mL of water (like it will be in the experiment you perform in lab)?

A. The volume would decrease.
B. No change.
C. The volume would increase.
D. Not enough information is given to predict what would happen.

Technically, this problem can't be worked unless you give an equation or you know the ratio of acid to base. I ASSUME it is either NaOH + HCl ==> NaCl+ H2O OR

NaOH + HC2H3O2 ==> NaC2H3O2 + H2O in which case the mole ratio is 1:1 in either case.

mols acid used = M x L = 0.10 x 0.008 L = ??
Since the mol ratio is 1:1, then mols base used is the same.
Molarity base = mols/L.
You know mols and you know liters. Solve for molarity.

For the second part, use the concept shown in the problem above to logically answer the question but I will give you a hint. The indicator you are uses changes color when mols acid = mols base. Will the volume change affect the number of moles of either?

thank you. for the second part the increase in volume should not affect the number of moles right? so would i put no change?

That is exactly right. The volume has no effect on the end point. I remember very well when I did demonstrations to show students how solutions were titrated. Of course I used a wash bottle to periodically wash the sides down and I would wait for a student to ask, and they always did every year, doesn't the addition of wash water dilute the material in the beaker? And I always answered, yes it does but it also dilutes the material from the buret, too, by exactly the same amount. Then I would go through the mols routine. When students realize that its the mols vs mols, not concentration versus concentration, they understand.

To find the required volume of the base to neutralize a given volume of acid, we can use the concept of stoichiometry and the balanced chemical equation for the reaction.

The balanced chemical equation for the neutralization reaction between an acid and a base is:

Acid + Base -> Salt + Water

From the problem statement, we know that the acid is present in a concentration of 0.10 M and its volume is 8.00 mL.

To determine the volume of the base, we need to use the stoichiometry of the balanced equation. In this case, the stoichiometric ratio of acid to base is 1:1, meaning that one mole of acid reacts with one mole of base.

Using the given concentration of the acid, 0.10 M, we can calculate the number of moles of acid using the formula:

moles of acid = concentration of acid x volume of acid (in liters)

moles of acid = 0.10 M x (8.00 mL / 1000 mL/L) = 0.00080 moles

Since the stoichiometric ratio of acid to base is 1:1, we know that 0.00080 moles of base are required to neutralize the acid.

Now, to find the volume of the base, we need to use the concentration of the base. Given that the base concentration is also 0.10 M, we can use the formula:

moles of base = concentration of base x volume of base (in liters)

0.00080 moles = 0.10 M x (volume of base in liters)

Solving for the volume of base:

volume of base = 0.00080 moles / 0.10 M

volume of base = 0.0080 L = 8.0 mL (since 1 L = 1000 mL)

Therefore, 8.0 mL of the 0.10 M base is required to neutralize 8.00 mL of the 0.10 M acid.

Now, let's consider how the volume of base would change if the 8.00 mL of 0.10 M acid was first diluted with 100 mL of water.

When the acid is diluted with water, the total volume of the solution increases, but the concentration of the acid remains the same. This means that the moles of acid present in the solution will still be the same.

Since the stoichiometry of the reaction remains the same, the number of moles of base required to neutralize the acid will also remain the same.

Therefore, if the acid is diluted with water, the volume of base required to neutralize the acid will remain the same. This means the answer is B. No change.

There is enough information given to predict what would happen.