A spiral spring of natural length of 30.0cm and a constant force of 20N/m is compressed to 20cm. Calculate the energy stored in the spring.

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To calculate the energy stored in the spring, we can use the formula for the potential energy stored in a spring:

U = (1/2)kx^2

Where U is the potential energy, k is the spring constant, and x is the displacement from the equilibrium position.

In this case, the natural length of the spring is 30.0 cm, and it is compressed to 20 cm, so the displacement (x) is 30 cm - 20 cm = 10 cm = 0.1 m.

The spring constant, k, is given as 20 N/m.

Plugging these values into the formula, we get:

U = (1/2)(20 N/m)(0.1 m)^2

U = (1/2)(20 N/m)(0.01 m^2)

U = (1/2)(0.2 N)(0.01 m^2)

U = 0.01 J

So, the energy stored in the spring is 0.01 Joules.