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Suppose that the endpoints of one leg of a 45°-45°-90° triangle are (0, 3) and (4, –1). What is the length of the hypotenuse?

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  1. The distance between the two points is √(16+16) = √32

    So, the hypotenuse is √32*√2 = √64 = 8

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    posted by Steve
  2. Find the distance EA for the points E(2, 3) and A(4, 2).

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