The perimeter of the rectangle is 24 cm, the long side is x + 2, the width side is x , if a new rectangle is created by doubling the lengths of the original rectangle's longest sides, what would the new rectangle's perimeter be ?

a. 17 cm^2
b. 24 cm^2
c. 31 cm^2
d. 38 cm^2
e. 48 cm^2

please answer and explain

2(x + x+2) = 24

4x+4=24
4x=20
x=5

the original rectangle is 5 by 7

take it from there

so, doubling the lenghts = 2x+4

14+14+5+5=38

answer d

Read your question more carefully, it said to double the original triangle's LONGEST sides

original longest side = 7
new longest side = 14

new recctangle is 5 by 14

new perimeter = 38

To find the answer, we need to first determine the lengths of the sides of the original rectangle.

Given that the perimeter of the rectangle is 24 cm, we know that the sum of all four sides is 24 cm.

The long side is described as x + 2, and the width side is described as x.

So, we can set up the equation:

x + x + x + 2 + x + 2 = 24

Simplifying this equation, we get:

4x + 4 = 24

Subtracting 4 from both sides, we have:

4x = 20

Dividing both sides by 4, we find:

x = 5

Therefore, the width side of the original rectangle is 5 cm, and the long side is x + 2 = 7 cm.

To find the perimeter of the new rectangle created by doubling the lengths of the original rectangle's longest sides, we calculate:

(2 * long side) + (2 * width side) = (2 * 7) + (2 * 5) = 14 + 10 = 24 cm

Therefore, the new rectangle's perimeter would be 24 cm.

So, the correct answer is (b) 24 cm^2.