A woman wearing high-heeled shoes stands on a wooden floor. Her total weight is 480N and acts equally on each foot.

What weight acts on one of her feet?

240N

A woman wearing high-heeled shoes stands on a wooden floor. Her total weight is 480N and acts equally on each foot.

Sometimes all this weight acts on the soles of her shoes. What is the pressure under her soles?

Weight on one foot =480/2=240 N

Pressure under her soles =Weight/area =
=240/area of one sole

To find the weight that acts on one of the woman's feet, we need to divide the total weight by the number of feet. In this case, she has two feet.

Weight acting on one foot = Total weight / Number of feet

Therefore, Weight acting on one of her feet = 480N / 2

Weight acting on one of her feet = 240N

So, the weight that acts on one of her feet is 240N.