Car A with a mass of 1250 kg, is traveling at 30 m/s to the east. Car B is a truck with a mass of 2000 kg, traveling to the west at 25 m/s. assume these two vehicles experience an inelastic collision but do not stick together, and car A goes off 10 m/s to the west. what will be the resulting velocity of car B?

12700

M1*V1 + M2*V2 = M1*V3 + M2*V4.

1250*30 - 2000*25=-1250*10+2000*V4.
Divide both sides by 100:
12.5*30 - 20*25 = -12.5*10 + 20V4.
375 - 500 = -125 + 20V4.
-125 + 125 = 20V4.
V4 = 0. m/s = Velocity of B.

To find the resulting velocity of Car B after the collision, we can use the principle of conservation of momentum. According to this principle, the total momentum before the collision is equal to the total momentum after the collision.

The momentum of an object is calculated by multiplying its mass by its velocity. In this case, the initial momentum before the collision can be calculated as:

Car A momentum (before collision) = Mass of Car A * Velocity of Car A
= 1250 kg * 30 m/s
= 37500 kg m/s (to the east, since car A is traveling east)

Similarly, the initial momentum of Car B before the collision can be calculated as:

Car B momentum (before collision) = Mass of Car B * Velocity of Car B
= 2000 kg * (-25 m/s) (negative sign to represent westward direction)
= -50000 kg m/s (to the west)

Since the collision is inelastic but the cars do not stick together, the total momentum after the collision is the sum of the momenta of Car A and Car B.

Total momentum (after collision) = Car A momentum (after collision) + Car B momentum (after collision)

We are given that after the collision, Car A goes off at 10 m/s to the west. Let's assume the resulting velocity of Car B is v.

Car A momentum (after collision) = Mass of Car A * Velocity of Car A (after collision)
= 1250 kg * (-10 m/s) (negative sign to represent westward direction)
= -12500 kg m/s (to the west)

Car B momentum (after collision) = Mass of Car B * Velocity of Car B (after collision)
= 2000 kg * v

Now we can substitute these values into the momentum conservation equation:

37500 kg m/s + (-50000 kg m/s) = -12500 kg m/s + 2000 kg * v

Simplifying the equation:

-12500 kg m/s + 2000 kg * v = -12500 kg m/s

We can now solve for v:

2000 kg * v = 0

v = 0 m/s (to the west)

Therefore, the resulting velocity of Car B after the collision will be 0 m/s to the west.