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25g of a sample of ferrous sulphate was dissolved in water contains dilute h2s04 and the volume made up to one litre. 25ml of this solution required 20ml of N/10 kmn04 solution for complete oxidation. Calculte the percentage of f2s04 7 h20 in the sample
My calculation
0.02 x 0.1 = 0.002
0.002 x 1000ml x 293g/mol / 25ml = 23.44
23.44/25g x 100% = 93.76% The right answer 88.96%

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