An animal-rescue plane flying due east at
40 m/s drops a bale of hay from an altitude of 73 m .
The acceleration due to gravity is
9.81 m/s^2.
If the bale of hay weighs 177 N , what is the momentum of the bale the moment it strikes the ground?
Please help!
The downward speed is v = √(2as) = 37.84
The total speed is thus √(37.84^2 + 40^2) = 55 m/s
The momentum is mv = 9735 kg-m/s
To find the momentum of the bale the moment it strikes the ground, we can use the formula:
Momentum = mass * velocity.
The mass of the bale can be calculated using the formula:
Weight = mass * gravity.
Therefore, we can rearrange the equation to solve for mass:
mass = Weight / gravity.
Given that the Weight of the bale is 177 N and the acceleration due to gravity is 9.81 m/s^2, we can determine the mass of the bale:
mass = 177 N / 9.81 m/s^2.
Now that we have the mass of the bale, we can use the formula for momentum:
Momentum = mass * velocity.
The velocity of the bale is given as the speed of the plane, which is 40 m/s since the plane is flying horizontally.
Now, substituting the values:
Momentum = (177 N / 9.81 m/s^2) * 40 m/s.
Now you can calculate the momentum of the bale the moment it strikes the ground using a calculator:
Momentum = (177 / 9.81) * 40.
Solving this equation will give you the answer to the question.