physics

A 15 kg mass, tied to the end of a 0.5 m long steel wire, is whirled in a vertical circle. The cross- section of the wire is 0.02 cm2. When the mass is at the bottom of the circle, its angular velocity is 2 rev s i. Find the elongation of the wire at this point.

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asked by badar
  1. Y=2•10¹¹ Pa
    ω=2πf =2π•2=4π rad/s.

    ma=T-mg
    m ω²R =T – mg
    T=m(ω²R+g) =m(16π²R +g)=…

    T/A =Y•ΔL/L
    ΔL=TL/AY =…

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    posted by Elena

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