trig

From a tower 57 ft high two objects in a straight line from it are sighted at angles of depression of 27degrees and 40degrees5' respectively. Find the distance between the two objects.

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asked by renzkie
  1. 40° 5' = (40 + 5/60) = 481/12 °

    You will have two right-angled triangle
    For the distance of the closer object
    tan (481/12)° = 57/d1
    d1 = 57/tan(481/12)°

    For the distance of the farther away object
    tan 27 = 57/d2
    d2 = 57/tan27°

    distance between objects = d2 - d1 = .....

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    posted by Reiny

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