Physics

A moving 3.20 kg block collides with a horizontal spring whose spring constant is 224 N/m.
The block compresses the spring a maximum distance of 5.50 cm from its rest position. The coefficient of kinetic friction between the block and the horizontal surface is 0.490. What is the work done by the spring in bringing the block to rest?
How much mechanical energy is being dissipated by the force of friction while the block is being brought to rest by the spring?
What is the speed of the block when it hits the spring?

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asked by Laura
  1. find energy stored in spring = work done by spring
    = (1/2) k x^2 = .5*224*(.055)^2 Joules

    friction force = .49 (3.2)(9.81)
    work dissipated in friction = F*d
    =.49 (3.2)(9.81)(.055)

    energy in block on arrival at spring
    = (1/2)m v^2 = energy stored in spring + work dissipated in friction

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    posted by Damon
  2. Why is the distance positive?? For friction? Isnt it going in the negatives direction?

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    posted by Malcolm

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