Physics 221

An electron is accelerated by a uniform electric field (1000 V/m) pointing vertically upward. Use energy methods to get the magnitude and direction of its velocity after it moves 0.10 cm form rest. Does the electron gain or lose potential energy?

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  1. E=Δφ/Δx
    PE->W(work of electric field) -> KE
    W=e•Δφ=e•E•Δx
    KE= mv²/2
    mv²/2= e•E•Δx
    v=sqrt{2•e•E•Δx/m}=
    =sqrt{2•1.6•10⁻¹⁹•1000•0.001/9.1•10⁻³¹}=
    =5.93•10⁵ m/s.

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