Find a point on the y axis that is equidistant from (1, 1) and (5, 5).

Would the answer be (-4,-4)

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  1. point is (x,0)

    (distance to first point)^2 = (x-1)^2 +1^1
    (distance to point two)^2 (x-5)^2 + 5^2

    x^2 -2x+1 + 1 = x^2 -10 x +25 + 25

    -2x+2 = -10 x + 50
    12 x = 48
    x = 4

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