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pre calculous
use the properties of logarithms to write the expression as a sum or difference of logarithms or multiples of logarithms. show your work ln x^2/y^3 Assuming x,y AND z are positive use properties of logariths to write the
asked by kevin on June 12, 2011 
math
write as a single logarithm: 2logbase3(1/x)+(1/3)logbase3(square root of x) please show the steps to solving this. thanx. remember that 1 log (AxB) = log A + Log B (same base) 2 log (A/B) = log A  log B 3 log A^n = n log A use
asked by michelle on February 25, 2007 
Maths
Log base2(x+2)+log base4(y+10)=2 Log base4(x+2)+log base2(y+10)=5/2 Solve simultaneously
asked by Rhonick on May 8, 2018 
math
write as a single logarithm: ln(x/x1)+ ln(x+1/x) ln(x^21) please show me the steps. thanx Michelle, I hope you know the three main rules of logs. 1. log (AB) = log A + log B 2. log (A/B) = log A  log B 3 log A^n  n log A
asked by michelle on March 13, 2007 
math
Logarithm!!! Select all of the following that are true statements: (a) log(2x) = log(2) + log(x) (b) log(3x) = 3 log(x) (c) log(12y) = 2 log(2) + log(3y) (d) log(5y) = log(20y) – log(4) (e) log(x) = log(5x) – log(5) (f) ln(25)
asked by Simon on April 16, 2010 
Precalculus
Evaluate log(base4)8 + log(base4)(1/8 log(base4)=(8x1/8) =1 I got 1 but the back of the book says 0...?
asked by Matthew on January 30, 2012 
Algebra
How would I write 12log(7)x as a single logarithm Choices: log(7) x^2/7 log(7) 7x^2 log(7) 7/x^2 log (7) x^2 Thank you
asked by Jesse on November 15, 2010 
PrecalculusVerify
log(base2)xlog(base2)6= log(base2)5+ 2log(base2)3 log(x/6)=3log15 (x/6)=15^3 6*(x/6)=15^3*6 x=15^3*6 =20,250 Answer is 270.... What did I do wrong...
asked by Melinda on January 30, 2012 
Math (precelc 12)
Write the expression as a single logarithm: 3log(a)log(b)(1/2)log(c) I want to check my answer. I got log(a^3/bc^(1/2))
asked by Jana on May 30, 2016 
college algebra
Write expression as one logarithm and simplify if appropriate. log 3√x + log x^4  log x^3 4 log (x+3)  5 log (x^2+4) + 1/3 log y I have these who problems but I don't know where to start. HELP Please.
asked by Deb on April 17, 2013