Can a solution of a linear inequality lie on a dashed boundary line? Explain.

since the solution is a region of the plane, the dashed boundary line is not part of the solution.

So, I'd have to say "no" to the poorly worded question.

Yes, a solution of a linear inequality can lie on a dashed boundary line.

When graphing a linear inequality, the boundary line can be either solid or dashed, depending on the inequality symbol.

If the inequality is strict, such as < or >, the boundary line is dashed. This indicates that the points on the line are not included in the solution.

For example, if the inequality is y > 2x, the boundary line would be dashed because the points on the line, like (0,0) or (1,2), are not solutions to the inequality. Only the points above the line satisfy the inequality.

However, if the inequality is inclusive, such as ≤ or ≥, the boundary line is solid. This means that the points on the line are included in the solution.

So, in summary, a solution of a linear inequality can lie on a dashed boundary line if the inequality is strict.

Yes, a solution to a linear inequality can indeed lie on a dashed boundary line.

When graphing a linear inequality, we often represent the boundary line with either a solid line or a dashed line, depending on the type of inequality.

A solid line is used when the given inequality includes an equal sign, such as "<=" or ">=". This indicates that the points on the line itself are included in the solution set.

On the other hand, a dashed line is used when the inequality does not contain an equal sign, such as "<" or ">". In this case, the points on the line are not included in the solution set.

So, if a linear inequality is represented by a dashed boundary line, it means that the points on the line itself are not part of the solution set. The solution lies on one side of the line, determined by the direction of the inequality symbol (e.g., greater than or less than).

yea i pretty prety tperyalekhgnaop sure it is ;yassquen