The human eye responds to a light stimulus (generates a sensation of "light") upon receiving light energy of 10eV (and more). If we take 6000 angstroms as the average wavelength, how many photons must the eye receive to register a light sensation?

An eye doctor shines a bright light into a patient's eye. In one to two sentences, explain how the patient's brain perceives the bright light.(2 points) PLEASE ANSWER

How much energy do you have in 6000 A?

E = hc/wavelength (w must be in meters) and E is then energy/photon.

Then convert 10 eV to joules, and
Joules = E/photon x # photons and solve for # photons.

PLS dR bob cna explain beter bcs i cant understand......thanks in advance

Hello Bob,

I calculated it without converting to Joules by taking the planck constant with the eV as unit, but i get around 4.84 photons, which seems to be wrong. Any ideas?

Pete, the dimensional analysis is wrong. You should just convert the eV to joules.

even after converting to joules we get the same answer 4.835 which is wrong.

Guys, the mathematics is correct. Look at what is being asked. It's simple.

Right... I was thinking the same along the lines of light is "quantized". Thanks!

Determine the linear density of atoms (atoms/m) along the [111] direction of gold at 300K.

To calculate the number of photons required to register a light sensation, we can use the energy of each photon and then divide the total energy required by the energy of each photon.

First, let's convert the given wavelength of 6000 angstroms to meters:
1 angstrom = 10^(-10) meters

Therefore, 6000 angstroms = 6000 * 10^(-10) = 6 * 10^(-7) meters.

To calculate the energy of each photon, we can use the equation:
E = h * c / λ

Where:
E is the energy of a photon,
h is Planck's constant (6.626 x 10^(-34) J·s),
c is the speed of light (3.0 x 10^8 m/s), and
λ is the wavelength of light.

Substituting the values, we get:
E = (6.626 x 10^(-34) J·s * 3.0 x 10^8 m/s) / (6 * 10^(-7) meters)
= (1.988 x 10^(-25) J·m) / (6 * 10^(-7) meters)
= 3.313 x 10^(-19) J

Now, let's calculate the number of photons required to reach the energy of 10 eV:
1 eV = 1.6 x 10^(-19) J

Energy required = 10 eV * (1.6 x 10^(-19) J / 1 eV)
= 16 x 10^(-19) J = 1.6 x 10^(-18) J

Finally, we can calculate the number of photons using the equation:
Number of photons = Energy required / Energy per photon

Number of photons = (1.6 x 10^(-18) J) / (3.313 x 10^(-19) J)
= 4.835 photons ≈ 5 photons

Therefore, the human eye would need to receive approximately 5 photons to register a light sensation.