At exactly 2:00 pm, Speedy the Snail crawls onto a meter stick at the 10 cm mark. If he reaches the 65 cm mark at exactly 2:10 pm, what is his speed?
Answer:
65 cm - 10 cm = 55 cm ÷ 10 min = 5.5 cm/min
That's correct. :)
the speed
To find Speedy the Snail's speed, we can use the formula "distance ÷ time."
First, we need to calculate the distance Speedy traveled.
Given that Speedy started at the 10 cm mark and reached the 65 cm mark in 10 minutes, we can subtract the initial position from the final position to find the distance traveled:
Distance = Final position - Initial position
Distance = 65 cm - 10 cm = 55 cm
Now, we can calculate Speedy's speed by dividing the distance traveled by the time it took:
Speed = Distance ÷ Time
Speed = 55 cm ÷ 10 min = 5.5 cm/min
Therefore, Speedy the Snail's speed is 5.5 cm per minute.
To calculate Speedy the Snail's speed, we need to determine the distance he traveled and the time it took him. In this case, we know that Speedy started at the 10 cm mark and reached the 65 cm mark in precisely 10 minutes, from 2:00 pm to 2:10 pm.
First, we need to find the distance traveled. This can be done by subtracting the initial position from the final position: 65 cm - 10 cm = 55 cm.
Next, we need to determine the time it took Speedy to cover this distance. Since the time interval is given as 10 minutes (from 2:00 pm to 2:10 pm), we can use this value directly.
Finally, to calculate the speed, we divide the distance traveled by the time it took: 55 cm ÷ 10 min = 5.5 cm/min.
Therefore, Speedy's speed is determined to be 5.5 centimeters per minute.