CO2(g) + H2(g) equilibrium reaction arrow CO(g) + H2O(g)

Calculate the equilibrium concentration of each compound if 2.00 moles of CO2 and 2.40 moles of H2 are placed in a 3.90 liter container at 300°C. Kc = 2.30 for the reaction at this temperature.
[CO2] = M
[H2] = M
[CO] = M
[H2O] = M

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  1. 2.00/3.90 = about 0.512M = (CO2)
    2.40/3.90 = about 0.615M = (H2)

    .......CO2(g) + H2(g) ==> CO(g) + H2O(g)

    Substitute the E line into the Kc expression and solve for x and go from there.

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