A straight copper wire that is 1 milimeter in diameter carries a current of 20 miliamps. Whas the magnitude of the largest magnetic field created by this wire in Tesla?

To find the magnitude of the largest magnetic field created by the wire, you can use the formula for calculating the magnetic field around a straight wire, known as Ampere's law.

Ampere's law states that the magnitude of the magnetic field at a distance r from a straight, infinitely long wire carrying current I is given by:

B = (μ₀ * I) / (2π * r)

Where:
B is the magnetic field in Tesla,
μ₀ (mu naught) is the permeability of free space, which is a constant equal to 4π × 10⁻⁷ T·m/A,
I is the current in Amperes,
r is the distance from the wire in meters.

In this case, we are given the following information:
- The diameter of the wire is 1 millimeter, which means the radius (r) is 0.5 millimeters or 0.0005 meters.
- The current flowing through the wire is 20 milliamps, which is 0.02 Amperes.

Plugging these values into the formula, we can calculate the magnitude of the largest magnetic field:

B = (4π × 10⁻⁷ T·m/A * 0.02 A) / (2π * 0.0005 m)
B = (8π × 10⁻⁸ T·m) / (0.001 m)
B = 8 × 10⁻⁵ T

Therefore, the magnitude of the largest magnetic field created by this wire is 8 × 10⁻⁵ Tesla.