algebra

During a manufacturing process, a metal part in a machine is exposed to varying temperature conditions. The manufacturer of the machine recommends that the temperature of the machine part remain below 141°F. The temperature T in degrees Fahrenheit x minutes after the machine is put into operation is modeled by T = – 0.005x2 + 0.45x + 125. Will the temperature of the part ever reach or exceed 141°F? Use the discriminant of a quadratic equation to decide.

yes
no

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  3. 👁 4,030
  1. Substitute T = 141 to the equation:
    141 = –0.005x^2 + 0.45x + 125
    Simplify:
    –0.005x^2 + 0.45x + 125 - 141 = 0
    –0.005x^2 + 0.45x - 16 = 0

    Recall that discriminant is just
    D = b^2 - 4ac
    if
    D < 0 : imaginary root
    D = 0 : real, equal root
    D > 0 : two real, unequal roots

    Substituting (a = -0.005 , b = 0.045 c = -16),
    D = 0.045^2 - 4(-0.005)(-16)
    D = -0.317975

    Therefore, it will NOT reach the temperature.

    Hope this helps :3

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  2. answer: no

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  3. The whole quick check is
    1. A
    2. C
    3. A
    4. B (no)

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    2. 👎 0
  4. everything is right except for 3
    3 is c

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    2. 👎 15
  5. Blank was 100% correct 3 is actually A don't listen to @bono

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    2. 👎 0

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