# algebra

During a manufacturing process, a metal part in a machine is exposed to varying temperature conditions. The manufacturer of the machine recommends that the temperature of the machine part remain below 141°F. The temperature T in degrees Fahrenheit x minutes after the machine is put into operation is modeled by T = – 0.005x2 + 0.45x + 125. Will the temperature of the part ever reach or exceed 141°F? Use the discriminant of a quadratic equation to decide.

yes
no

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1. Substitute T = 141 to the equation:
141 = –0.005x^2 + 0.45x + 125
Simplify:
–0.005x^2 + 0.45x + 125 - 141 = 0
–0.005x^2 + 0.45x - 16 = 0

Recall that discriminant is just
D = b^2 - 4ac
if
D < 0 : imaginary root
D = 0 : real, equal root
D > 0 : two real, unequal roots

Substituting (a = -0.005 , b = 0.045 c = -16),
D = 0.045^2 - 4(-0.005)(-16)
D = -0.317975

Therefore, it will NOT reach the temperature.

Hope this helps :3

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3. The whole quick check is
1. A
2. C
3. A
4. B (no)

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4. everything is right except for 3
3 is c

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5. Blank was 100% correct 3 is actually A don't listen to @bono

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