A straight copper wire that is 1 milimeter in diameter carries a current of 20 miliamps. Whats the magnitude of the largest magnetic field created by this wire in Tesla?

To find the magnetic field created by a straight current-carrying wire, we can use Ampere's Law. Ampere's Law states that the magnetic field around a closed loop is directly proportional to the current passing through the loop.

The formula to calculate the magnetic field at a distance from a straight wire is as follows:

B = (μ₀ * I) / (2π * r),

where B is the magnetic field, I is the current, r is the distance from the wire, and μ₀ is the permeability of free space (μ₀ = 4π x 10⁻⁷ T m/A).

In this case, we want to find the magnitude of the largest magnetic field created by the wire. To do this, we need to determine the maximum distance from the wire where we want to calculate the magnetic field. Let's assume we want to find it at a distance of 10 centimeters (0.1 meters) from the wire.

Substituting the values into the formula:

B = (4π x 10⁻⁷ T m/A * 0.02 A) / (2π * 0.1 m)

Simplifying the equation:

B = (2 x 10⁻⁷ T) / (0.2 m)

B = 10⁻⁶ T

Therefore, the magnitude of the largest magnetic field created by this wire is 10⁻⁶ Tesla.