Nine consecutive odd whole numbers sum to 243. Find the sum if the first and last whole numbers in this nine-addend ser.

Well, this is a little odd, isn't it? Pun intended. Let's see if we can solve this puzzle.

Let's call the first odd number in the series "x." Since there are nine consecutive odd numbers, we can express the nine numbers as x, x+2, x+4, x+6, x+8, x+10, x+12, x+14, and x+16.

Adding all these numbers together, we get:
x + (x+2) + (x+4) + (x+6) + (x+8) + (x+10) + (x+12) + (x+14) + (x+16) = 243

I'm not going to do all the math for you (I'm a clown, not a mathematician), but let's simplify this equation a bit:

9x + (2+4+6+8+10+12+14+16) = 243

And that gives us:
9x + 72 = 243

Now, just solve for x and the sum of the first and last number is just x + (x+16). Good luck with the math!

Let's call the first odd whole number in the series "x". Since we are looking for consecutive odd numbers, the second odd number in the series would be (x + 2), the third would be (x + 4), and so on.

The sum of nine consecutive odd numbers can be found using the formula:
sum = (number of terms) * (first term + last term)/2

In this case, the number of terms is 9, and we want to find the sum of the first and last number.

So, the sum of the first and last whole numbers is:

sum = (9) * [(x + x + 16)/2]

We know that the sum of these numbers is 243, so we can set up the equation:

243 = (9) * [(x + x + 16)/2]

Now, let's solve for x:

243 = (9) * [(2x + 16)/2]
243 = 9 * (2x + 16)/2
243 = (2x + 16)/2
486 = 2x + 16
2x = 486 - 16
2x = 470
x = 470/2
x = 235

Now that we have x, we can find the last odd number:

Last number = x + 16 = 235 + 16 = 251

Therefore, the sum of the first and last whole numbers (235 and 251) is:

Sum = 235 + 251 = 486

To find the sum of the first and last whole numbers in a series of nine consecutive odd whole numbers, we need to determine the first and last numbers in the series.

Let's assume the first odd number is 'x'. Since the numbers are consecutive, the second odd number would be 'x + 2', the third odd number would be 'x + 4', and so on, until the ninth odd number, which would be 'x + (2 * (9 - 1))'.

The sum of the series can be expressed as the sum of all nine terms:

Sum = x + (x + 2) + (x + 4) + ... + (x + (2 * (9 - 1)))

Now, we know that the sum of the series is 243, so we can set up the equation:

243 = x + (x + 2) + (x + 4) + ... + (x + (2 * (9 - 1)))

Simplifying the equation, we get:

243 = 9x + 2 + 4 + ... + (2 * 8)

243 = 9x + 2 + 4 + ... + 16

243 = 9x + 2 + 4 + 6 + 8 + 10 + 12 + 14 + 16

243 = 9x + 72

Subtracting 72 from both sides of the equation, we have:

171 = 9x

Dividing both sides by 9, we find:

x = 19

Therefore, the first odd number in the series is 19, and the last odd number is 19 + (2 * (9 - 1)) = 35.

To find the sum of the first and last numbers, we add them together:

Sum = 19 + 35 = 54

So, the sum of the first and last whole numbers in the nine-addend series is 54.

let the first odd whole number be

n-8
then the others are n-6, n-4 , n-2 , n , n+2, n+4, n+6, and n+8

their sum = 9n
(now wasn't that a clever way to define my numbers?)

9n = 243
n = 27

first = 27-8
last = 27 + 8
and that sum = 27+27 = 54