Given the function f(x) =2^x and g(x) =x-2 and h(x) =2x-3 what compositions of function will result into

y= 2^(x+1)-5

g(f) = 2^x - 2

so, h(g(f)) = 2(2^x - 2) - 3 = 2^(x+1)-7
y = (h◦g◦f)(x) + 2