Physics

A 68.0 kg ice skater moving to the right with a velocity of 2.55 m/s throws a 0.16 kg snowball to the right with a velocity of 27.5 m/s relative to the ground.

(a) What is the velocity of the ice skater after throwing the snowball? Disregard the friction between the skates and the ice.

(b) A second skater initially at rest with a mass of 60.50 kg catches the snowball. What is the velocity of the second skater after catching the snowball in a perfectly inelastic collision?

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  1. if the ice skate was skating with the snowball initially, then
    initial momentum=final momentum
    68*2.55+.16*2.55=68*vf+.16*27.5
    solve for vf.

    b.initial monetum=final momentum
    60.50*0+.16*27.5=(60.50+.16)Vf
    solve for vf

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  2. Thanks!
    I am having trouble rearranging the formula. Could you please try to explain it to me?

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  3. No, I won't do the algebra for you.

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