how many grams of chromium are required to react with 125 mL of 0.75M CuSO4?
You have to write a balanced equation first, do that, then look at the mole balance. You have .125*.75 moles of copperII sulfate.
To determine the number of grams of chromium (Cr) required to react with 125 mL of 0.75 M CuSO4, we need to use stoichiometry.
Step 1: Write the balanced chemical equation for the reaction between chromium and copper(II) sulfate:
Cr + CuSO4 → Cr2(SO4)3 + Cu
Step 2: Determine the molarity of CuSO4.
Molarity (M) = moles/Liter
Given:
Volume (V) of CuSO4 = 125 mL = 0.125 L
Molarity of CuSO4 = 0.75 M
Number of moles of CuSO4 = Molarity × Volume = 0.75 M × 0.125 L = 0.09375 moles
Step 3: Use stoichiometry to find the number of moles of Cr needed.
From the balanced chemical equation:
1 mole of Cr reacts with 1 mole of CuSO4
Therefore, the number of moles of Cr needed is also 0.09375 moles.
Step 4: Convert moles of Cr to grams.
Molar mass of Cr = 52 g/mol (approx.)
Number of grams of Cr = moles × molar mass = 0.09375 moles × 52 g/mol ≈ 4.87 grams
So, approximately 4.87 grams of chromium are required to react with 125 mL of 0.75 M CuSO4.
To determine how many grams of chromium (Cr) are required to react with 125 mL of 0.75M CuSO4, you need to use stoichiometry and the balanced chemical equation for the reaction.
First, let's write the balanced chemical equation for the reaction between chromium and copper(II) sulfate:
Cr + CuSO4 -> Cr2(SO4)3 + Cu
According to the balanced equation, the molar ratio between Cr and CuSO4 is 1:1. This means that for every 1 mole of Cr, you need 1 mole of CuSO4.
Now let's calculate the number of moles of CuSO4 in 125 mL of 0.75M solution:
Molarity (M) is defined as moles of solute per liter of solution. Therefore, we can calculate the number of moles of CuSO4 as follows:
Moles = Molarity x Volume (in liters)
Moles = 0.75 mol/L x 0.125 L
Moles = 0.09375 moles
Since the molar ratio between Cr and CuSO4 is 1:1, the number of moles of Cr required is also 0.09375 moles.
Finally, we need to convert the moles of Cr to grams. The molar mass of chromium (Cr) is approximately 52 g/mol.
Grams of Cr = Moles x Molar mass
Grams of Cr = 0.09375 moles x 52 g/mol
Grams of Cr = 4.875 grams
Therefore, approximately 4.875 grams of chromium are required to react with 125 mL of 0.75M CuSO4.