Ed recorded the following 2 distances in feet for 2 attempts by Carla at the long jump : 12 2/3 and 11 1/6. What was Carla's average distance in feet for the 2 attempts?

Add the two distances together and divide the sum by 2.

I divide 23 5/6 by 2 since 23 5/6 is my sum?

Yes.

143/12

No. Please try again.

To find Carla's average distance for the two attempts, we need to calculate the total distance and then divide it by the number of attempts.

First, let's convert the mixed fractions into improper fractions:

12 2/3 = (12 * 3 + 2) / 3 = 38/3
11 1/6 = (11 * 6 + 1) / 6 = 67/6

Now, we can find the total distance by adding the two distances together:

38/3 + 67/6

To add fractions, we need to have a common denominator. In this case, the least common multiple of 3 and 6 is 6. So, let's rewrite the fractions with a common denominator:

(38/3) * (2/2) = 76/6
67/6

Now, we can add the fractions:

76/6 + 67/6 = 143/6

To calculate the average, we divide the total distance by the number of attempts (which is 2 in this case):

143/6 / 2 = 143/6 * 1/2

To divide fractions, we simply multiply the numerator of the first fraction by the denominator of the second fraction and vice versa:

143/6 * 1/2 = (143 * 1) / (6 * 2) = 143/12

Therefore, Carla's average distance for the two attempts was 143/12 feet.