A 2.0 kg rock is dropped from the top of a building. I lands 14.0 seconds later. How tall was the building?
h = (1/2) g t^2
mass is irrelevant
that is one tall building !
To determine the height of the building, we can use the equation of motion for free-falling objects:
h = v0*t + (1/2)at^2
Where:
h = height of the building
v0 = initial velocity of the rock (0 m/s as it is dropped)
t = time taken to land (14.0 seconds)
a = acceleration due to gravity (approximately 9.8 m/s^2)
Plugging in the values into the equation, we get:
h = 0*(14.0) + (1/2)*(9.8)*(14.0)^2
h = 0 + 0.5*(9.8)*(196)
h = 0 + 0.5*(9.8)*(196)
h = 0 + 0.5*(1960)
h = 0 + 980
h = 980 meters
Therefore, the height of the building is 980 meters.