Factor 16x(a + b + c) + 7y(a + b + c) + 8w(a + b + c). Please show the steps for how you get the answer. Thanks
To factor out the common term "(a + b + c)" from each of the terms in the expression "16x(a + b + c) + 7y(a + b + c) + 8w(a + b + c)", you can use the distributive property. Here are the steps:
Step 1: Identify the common factor "(a + b + c)".
Step 2: Apply the distributive property to each term by multiplying the common factor with the coefficient of each term.
16x(a + b + c) + 7y(a + b + c) + 8w(a + b + c) becomes:
(16x * (a + b + c)) + (7y * (a + b + c)) + (8w * (a + b + c)).
Step 3: Multiply each coefficient with the common factor.
(16x * (a + b + c)) + (7y * (a + b + c)) + (8w * (a + b + c)) becomes:
16ax + 16bx + 16cx + 7ay + 7by + 7cy + 8aw + 8bw + 8cw.
Step 4: Rearrange the terms for clarity.
16ax + 16bx + 16cx + 7ay + 7by + 7cy + 8aw + 8bw + 8cw.
Therefore, the factored form of the given expression is 16ax + 16bx + 16cx + 7ay + 7by + 7cy + 8aw + 8bw + 8cw.
well, first off, note that there's an (a+b+c) everywhere, so factor that out to get
(16x+7y+8w)(a+b+c)